We are doing our damnedest to NOT use RenderPartial but instead to use EditorFor and DisplayFor in 100% of cases. However, there is one scenario that we haven't been able to get to work so far: When the partial view needs the entire ViewModel, or in other words, when it needs to be Html.DisplayFor(m => m, "MyTemplateThatNeedsTheEntireViewModel"). It works fine if it's Html.DisplayFor(m => m.Prop, "MyTemplateThatOnlyNeedsTheOneProperty") but we can't pass the entire ViewModel in.
Is there a way to achieve this that will work both with DisplayFor and EditorFor?
What I see now is that either nothing (or perhaps whitespace) is rendered to my markup. However, both the compiler and ReSharper seem to think my syntax is just fine. Changing my code to call RenderPartial works perfectly, but this is what I'm trying to avoid.
I try these three lines. The RenderPartial works perfectly, the EditorFors do not work (eventual markup is an empty string or whitespace):
<% Html.EditorFor(m => m, "RetailPriceRequests/PriceRequest/PriceRequestLoadGrid"); %>
<%= Html.EditorFor(m => m, "RetailPriceRequests/PriceRequest/PriceRequestLoadGrid") %>
<% Html.RenderPartial("~/Views/Shared/EditorTemplates/RetailPriceRequests/PriceRequest/PriceRequestLoadGrid.ascx", Model); %>
If your DisplayTemplate is:
<%# Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<ExampleModel>" %>
DisplayFor(m => m, "ExampleModel")
should work
<%# Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<ExamplePropertyModel>" %>
DisplayFor(m => m.ExampleProperty, "ExamplePropertyModel")
should work
One issue you could be that something is null, in which case it probably shouldn't be hitting the View at all, but you can get around this by writing:
RenderPartial("ExampleModel", Model ?? new ExampleModel());
or
RenderPartial("ExampleModel",
(Model ?? new ExampleModel() { ExampleProperty = new ExampleProperty() })
.ExampleProperty ?? new ExampleProperty());
Related
I am using EditorFor() helper to render edit template in my view and I would like to call the DisplayFor() inside this template to render out the Display template.
Like this
this is inside the /Shared/EditorTemplates/Client.ascx
<%# Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<BusinessNext.Models.Ef.Client>" %>
<%: Html.DisplayFor(client=>client) %>
In the DisplayFor template I render out client's properties. DisplayFor template works perfectly fine when called from everywhere else but from EditorFor template it doesn't render out anything. It seems that the DisplayFor() call never actually gets to the DisplayFor template.
I am afraid that the only way is to use a partial:
<%= Html.Partial("~/Views/Home/DisplayTemplates/Client.ascx", Model) %>
It can be debatable if it is a good idea to template complicated objects, or if my approach to nested templates is a hack or not. The advantage of this is having a single template for the parent and child can both have templates rather than having to choose/use partial views.
All that aside, templated views can be nested, if you use a partial view as an go between.
The outside template will have something like below where you want to place the inner template:
Html.RenderPartial("SharedDisplayGoBetweenForFoo", item);
The shared partial would look like this:
#model Foo
#Html.DisplayFor(a => a);
The inner template would then be called and would look like any other.
I would like to do something like this:
<!--#include file="../stuff/foo/box.aspx"-->
But doing this in an ASP.Net MVC application it just feels wrong. Is there a better way of achieving the same thing in a ASP.Net MVC project ?
<%: Html.Partial("~/Views/foo/box.ascx") %>
or:
<% Html.RenderPartial("~/Views/foo/box.ascx"); %>
or the best of them all use an editor template (if this partial contains inputs for editing the view model property):
<%: Html.EditorFor(x => x.MyModelProperty) %>
or a display template (if this partial contains only display of view model property):
<%: Html.DisplayFor(x => x.MyModelProperty) %>
and their Razor equivalence
#Html.Partial("~/Views/foo/box.ascx")
#{Html.RenderPartial("~/Views/foo/box.ascx");}
#Html.EditorFor(x => x.MyModelProperty)
#Html.DisplayFor(x => x.MyModelProperty)
You should make a partial view.
You can use
Html.RenderPartial('~/Views/Login/Box.ascx');
RenderPartial allows to render part of the page using the same context. If you want to render using new context, use
Html.RenderAction("Box","Login"); //Box - Action, Login - Controller
After so many years using ASP.Net, I’m still trying to figure out how to achieve the same results using MVC.
I have a materpage with a control that is strongly type to something. When I navigate to a view of a different strongly type model ...and click on the button to execute something, I get "The model item passed into the dictionary is of type Site.Models.RegisterModel', but this dictionary requires a model item of type Site.Models.LogOnModel'".
For the sake of this example, we can take the Default MVC app that is provided with VS 2010, let’s imagine I want to change the “LogonUserControl.ascx” so that it either tells me the logged user (as it works currently) OR allow me to login from there, showing me the text boxes for username and password (therefore in this case from the home page).
So I take the control and strongly type it as:
<%# Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<Gioby.Models.LogOnModel>" %>
<%
if (Request.IsAuthenticated) {
%>
Welcome <b><%: Page.User.Identity.Name %></b>
[ <%: Html.ActionLink("Log Off", "LogOff", "Account")%> ]
<%
}
else {
%>
<% using (Html.BeginForm()) { %>
<div id="logon">
<div class="editor-label">
<%: Html.LabelFor(m => m.UserName)%>
<%: Html.TextBoxFor(m => m.UserName)%>
<%: Html.ValidationMessageFor(m => m.UserName, "*") %>
<%: Html.LabelFor(m => m.Password)%>
<%: Html.PasswordFor(m => m.Password)%>
<%: Html.ValidationMessageFor(m => m.Password, "*") %>
<input type="submit" value="Log On" />
</div>
<div class="editor-label">
<%: Html.ActionLink("Register here", "Register", "Account")%>
<%: Html.CheckBoxFor(m => m.RememberMe, new { #class = "pad-left" })%>
<%: Html.LabelFor(m => m.RememberMe) %>
</div>
</div>
<% } %>
<%
}
%>
Then on the HomeController, I add a procedure as:
[HttpPost]
public ActionResult Index(LogOnModel model, string returnUrl)
{
if (ModelState.IsValid)
{
// ==>> Check Login against your DB
// Now check if param returnUrl is empty
if (!String.IsNullOrEmpty(returnUrl))
return Redirect(returnUrl);
return RedirectToAction("Index", "Home");
}
// If we got this far, something failed, redisplay form
return View(model);
}
I tested it from the home page … it works !!!
BUT when I navigate to the “Register” view (remember that the “LogonUserControl.ascx” is located inside the “MasterPage”, therefore visible from the Register view).
So when I click on the Register button, I get the error:
The model item passed into the dictionary is of type Site.Models.RegisterModel', but this dictionary requires a model item of type Site.Models.LogOnModel'.
QUESTION:
Does that mean that I will never be able to different pieces together into one view?
Let’s say I want to write an eCommerce site and on the home page I want to see “Most used Tags”, “Most bought products”, “Product of the Month”, “List of Categories” …all within the same view and each one with his own HTTP POST action.
If this is possible using MVC?
If I'm understanding the problem correctly, you have two Views that use the same MasterPage, but which are strongly typed against different ViewModels. The master page is able to include a Partial View that is also strongly typed, as long as its expected ViewModel is the same as that of the parent view. However, if you're using a view with a different ViewModel type, it doesn't know what to do.
Consider the following:
<% Html.RenderPartial("LogOn") %>
The above code implicitly includes the model data for the current view being rendered. It's exactly the same as if you had said:
<% Html.RenderPartial("LogOn", Model) %>
So this will only work if Model is a LogOnModel. Remember that the MasterPage is really a part of whatever View inherits it, so even if you're putting this in the MasterPage, it's as if you'd put the same code in every view that inherits it. So if your View's Model is not the same as the PartialView's Model, this won't work. One alternative is to use inheritance to ensure that every ViewModel will include all the information required by the Master Page. This approach is described in detail here.
But that approach means that you have to always use a factory to produce your view model, and every view model has to be somewhat aware of which master page it will use. In our product, we can use a different master page on the same view depending on what mode the user is viewing the site in, so it doesn't make sense to tie the ViewModel to that of the Master Page. We accomplish what you're describing using the RenderAction method, which allows you to render an entire controller action as if it were just a part of the larger view. Some of the advantages of this approach are discussed here.
So now you can have your MasterPage include whatever little partial views you want, but you separate the logic for building the ViewModel of each of these Views into an individual controller action that's responsible for that particular Partial View:
<% Html.RenderAction("LogOnBox") %>
The Action:
public ActionResult LogOnBox()
{
LogOnModel model = GetLogOnModel();
return PartialView("LogOnUserControl", model);
}
Now, regardless of what model your current view uses, your Master Page can include “Most used Tags”, “Most bought products”, “Product of the Month”, “List of Categories”, etc. Better still, these portions of the page can leverage output caching so they don't have to be regenerated with every page load if they don't change very often.
I've seen plenty of examples (NerdDinner, Sanderson's Sports Store, etc.) where a view is bound to a collection of objects. The syntax in the view is usually something like this...
<%# Page... Inherits="System.Web.Mvc.ViewPage<IEnumerable<MyViewModel>>" %>
...
<% foreach (var myViewModel in Model) { %>
I've also seen plenty of examples of inserts or updates where the controller automatically binds the model parameter to the form elements in the view.
I'm looking for a mix of the two techniques where my view has form elements pertaining to a collection of myViewModels where each myViewModel has 3-4 properties. The intent is to allow the user to enter a set of these in one take.
Assuming this is possible, can anyone help me with the syntax? I can't figure out how to label the form elements to make the binding work.
This is possible through the built-in model binder, but you have to do a little bit of convention-based naming of your form objects. First, your action needs to take a collection:
[HttpPost]
public ActionResult CreateFoos(List<Foo> foos)
{
// I have a list of the foo objects that were posted
}
And then, in the view, let's say you wanted to make a form for each object:
<% for (int i = 0; i < Model.Count; i++) { %>
<%: Html.TextBoxFor(x => x[i].Property1) %>
<%: Html.TextBoxFor(x => x[i].Property2) %>
<%: Html.TextBoxFor(x => x[i].Property3) %>
<% } %>
Pay attention to how the controls are rendered in the HTML, because in your "create" view, you might want to have a javascript button that allows the user to add another record, and you'll have to increase the index for each additional control. It's not too hard, but I just wanted to warn you to pay attention to the source it actually generates.
The definitive answer is here: http://haacked.com/archive/2008/10/23/model-binding-to-a-list.aspx
You need to name each field as if it were part of an array: "PropertyName[i]"
I have a search page that if there is results in the list it passes this list to a view.
However if there are no results I want to send the searched text to a no results found view.
How would I go about this?
You will need to have the searched text available as part of the model that is returned to the view. Then you have two options -
Using the RenderPartial will pass the returned view to the partial view so you can access the value you want from there.
Html.RenderPartial("PartialView");
Alternatively, you can pass the string as the model for the partial view using
Html.RenderPartial("PartialView", Model.SearchedText);
Which might make sense if you want to use the no results partial view with different models.
<%Html.RenderPartial("SimpleTrustGridViewer", ViewData["departmentGrid"]); %>
this passes an object ViewData["departmentGrid"] (this comes from viewdata of the non-partial view) to the partial view SimpleTrustGridViewer.
simplified:
<%Html.RenderPartial("myUserControl", myString); %>
And your partial view inherits like this:
<%# Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<string>" %>
Then, in your partial view 'Model' will be the passed string.
The ViewDataDictionary passed from the controller to the view will be the same passed from the View to the Partial View. So if the string you want to pass is in the ViewDataDictionary you don't have to pass it.
<%=Html.RenderPartial("NorResultFound")) %>
But you can use the same view whether there were results or not:
<%if (Model.ResultCount!=0){ %>
<%foreach(var result in Model){ %>
<%= // display results %>
<%}}%>
<%else {%>
<p>There is no results for <%=ViewData["keyword"]%> </p>
<%} %>
I tried this and couldn't get it to work. Say I have
<div id="SearchBar">
<% using (Html.BeginForm("IndexNoJavaScript", "Home"))
{%>
<%= Html.TextBox("SearchTextBox", ViewData["SearchText"]) %>
<input type="submit" value="Search" /> <% } %>
</div>
<% Html.RenderPartial("SearchResults"); %>
And when I try to display the search text in this view like so:
<%= Html.TextBox("SearchedText", ViewData["SearchText"] ) %>
My text box is blank.
You can use jquery and load() action on div tag , insted of using partial; the result is similar.
The load() ajax method call on controller with the text that you want.
like:
$('#divId').load('url/'+ serch content );
Partial view unless you pass to it something else explicitly, has the same Model as parent view.
Two ways (you are talking about views, not partial views right?)
1) in your controller just call a different view in case of no results passing a string as model
2) create a model containing a search status (found x items, no match found, etc...) and a list of results to the same view, allowing the view to render the different results with a switch statement.