Rss20FeedFormatter is producing RSS that is not well formed - asp.net-mvc

I am using ASP.Net MVC2 and have a RSS feed for my blog. I am using out of the box functionality in System.ServiceModel.Syndication and Rss20FeedFormatter.
The feed works fine and can be read by Outlook as well as every browser I have tried. However when I submitted the RSS feed to google as a sitemap I got validation errors.
Out of curiosity I validated the feed with feedvalidator which reported similar issues.
Feed: http://www.chrispfarrell.com/Blog/Rss
If you pop this feed in at feedvalidator.org you will see the problems.
There is really no custom code going on to generate the RSS.
The controller action is
public FeedResult Rss()
{
const string baseUrl = "http://www.chrispfarrell.com/Blog/View/";
var blogs = _blogService.GetBlogs();
var feed = new SyndicationFeed
{
Title = new TextSyndicationContent("Chris Farrell"),
Copyright = new TextSyndicationContent("Copywrite Chris Farrell 2010")
};
var postItems = blogs.Take(25)
.Select(p => new SyndicationItem(p.Title,p.Body,new Uri(baseUrl + p.BlogUrl))
{
PublishDate = p.DateCreated,
});
feed.Items = postItems;
return new FeedResult(new Rss20FeedFormatter(feed));
}
Any comments as to why the feed would not be valid and well formed? I can post the code for FeedResult if needed but its pretty standard code.
Thanks
Chris Farrell

The Feed was missing the <link> element in the root <channel> element.
Rather than using an object initializer, I am using one of the constructors now which accepts 3 arguments(feed title, description and feed alternate link). The third argument for feed alternate link renders in the root channel <link> tag which makes the feed now valid.

Related

How to get link to third party site in 'about channel' section via python

I want to display information about links in the YouTube profile in a text document, I tried to do it through the requests library, but Google gave links to privacy and security, I did not find information about this in the YouTube API documentation. Who knows, you can help with this
This isn't possible to get using the YouTube API, I actually found myself needing to do the same thing as yourself and was not able to because the YouTube API lacked the necessary functionality (Hopefully, It will be added soon!)
I see you mentioned Python, My only solution is in Node but I will do a large explanation and you can base your code off of it. In order to get the banner links without the YouTube API, we need to scrape the data, since YouTube uses client-side rendering we need to scrape the JSON configuration from the source.
There's a variable defined inside a script called ytInitialData which is a big JSON string with a massive amount of information about the channel, viewer, and YouTube configurations. We can find the banner links by parsing through this JSON link.
const request = require("request-promise").defaults({
simple: false,
resolveWithFullResponse: true
})
const getBannerLinks = async () => {
return request("https://www.youtube.com/user/pewdiepie").then(res => {
if (res.statusCode === 200) {
const parsed = res.body.split("var ytInitialData = ")[1].split(";</script>")[0]
const data = JSON.parse(parsed)
const links = data.header.c4TabbedHeaderRenderer.headerLinks.channelHeaderLinksRenderer
const allLinks = links.primaryLinks.concat(links.secondaryLinks || [])
const parsedLinks = allLinks.map(l => {
const url = new URLSearchParams(l.navigationEndpoint.commandMetadata.webCommandMetadata.url)
return {
link: url.get("q"),
name: l.title.simpleText,
icon: l.icon.thumbnails[0].url
}
})
return parsedLinks
} else {
// Error/ratelimit - Handle here
}
})
}
The way the links are scraped is as follows:
We make a HTTP request to the channel's URL
We parse the body to extract the JSON string that the banner links are inside using split
We parse the JSON string into a JSON object
We extract the links from their JSON section (It's a big JSON object data.header.c4TabbedHeaderRenderer.headerLinks.channelHeaderLinksRenderer
Because there are two types of links (Primary, the one that shows the text and secondary, links that don't show the text) we have to concatenate them together so we can map through them
We then map through the links and use URLSearchParams to extract the q query parameter since YouTube encrypts their outgoing links (Most likely for security reasons) and then extract the name and icon too using their appropriate objects.
This isn't a perfect solution, should YouTube update/change anything on their front end this could break your program easily. YouTube also has rate limits for their software if you're trying to mass scrape you'll run into 429/403 errors.

Docusign API and printing documents

I am able to create an e-signature with a pdf on the docusign api that I have setup within the Docusign sandbox. However, one of the requirements for my project is to pre-populate the pdf on docusign and then render it into a browser for printing.
Whenever I create the document within the envelope for e-signature, all of the passed-in fields are in the document. However, if I only create the document, then try to view it, all of the fields I am passing in are blank.
How can I have these passed in fields to stay persistent within the envelope document and then show that document within a browser?
Without seeing your code it's hard to say what you're doing wrong.
I can tell you how it should be done. Not sure what lang you're using. in C# you can do this:
// Add the tabs model (including the SignHere tab) to the signer.
// The Tabs object wants arrays of the different field/tab types
// Tabs are set per recipient/signer
Tabs signer1Tabs = new Tabs
{
SignHereTabs = new List<SignHere> { signHere },
TextTabs = new List<Text> { textLegal, textFamiliar, textSalary }
};
signer1.Tabs = signer1Tabs;
Recipients recipients = new Recipients
{
Signers = new List<Signer> { signer1 }
};
(you can find the full code example and all the other languages in our code example on the Developer Center)

How to retrieve Medium stories for a user from the API?

I'm trying to integrate Medium blogging into an app by showing some cards with posts images and links to the original Medium publication.
From Medium API docs I can see how to retrieve publications and create posts, but it doesn't mention retrieving posts. Is retrieving posts/stories for a user currently possible using the Medium's API?
The API is write-only and is not intended to retrieve posts (Medium staff told me)
You can simply use the RSS feed as such:
https://medium.com/feed/#your_profile
You can simply get the RSS feed via GET, then if you need it in JSON format just use a NPM module like rss-to-json and you're good to go.
Edit:
It is possible to make a request to the following URL and you will get the response. Unfortunately, the response is in RSS format which would require some parsing to JSON if needed.
https://medium.com/feed/#yourhandle
⚠️ The following approach is not applicable anymore as it is behind Cloudflare's DDoS protection.
If you planning to get it from the Client-side using JavaScript or jQuery or Angular, etc. then you need to build an API gateway or web service that serves your feed. In the case of PHP, RoR, or any server-side that should not be the case.
You can get it directly in JSON format as given beneath:
https://medium.com/#yourhandle/latest?format=json
In my case, I made a simple web service in the express app and host it over Heroku. React App hits the API exposed over Heroku and gets the data.
const MEDIUM_URL = "https://medium.com/#yourhandle/latest?format=json";
router.get("/posts", (req, res, next) => {
request.get(MEDIUM_URL, (err, apiRes, body) => {
if (!err && apiRes.statusCode === 200) {
let i = body.indexOf("{");
const data = body.substr(i);
res.send(data);
} else {
res.sendStatus(500).json(err);
}
});
});
Nowadays this URL:
https://medium.com/#username/latest?format=json
sits behind Cloudflare's DDoS protection service so instead of consistently being served your feed in JSON format, you will usually receive instead an HTML which is suppose to render a website to complete a reCAPTCHA and leaving you with no data from an API request.
And the following:
https://medium.com/feed/#username
has a limit of the latest 10 posts.
I'd suggest this free Cloudflare Worker that I made for this purpose. It works as a facade so you don't have to worry about neither how the posts are obtained from source, reCAPTCHAs or pagination.
Full article about it.
Live example. To fetch the following items add the query param ?next= with the value of the JSON field next which the API provides.
const MdFetch = async (name) => {
const res = await fetch(
`https://api.rss2json.com/v1/api.json?rss_url=https://medium.com/feed/${name}`
);
return await res.json();
};
const data = await MdFetch('#chawki726');
To get your posts as JSON objects
you can replace your user name instead of #USERNAME.
https://api.rss2json.com/v1/api.json?rss_url=https://medium.com/feed/#USERNAME
With that REST method you would do this: GET https://api.medium.com/v1/users/{{userId}}/publications and this would return the title, image, and the item's URL.
Further details: https://github.com/Medium/medium-api-docs#32-publications .
You can also add "?format=json" to the end of any URL on Medium and get useful data back.
Use this url, this url will give json format of posts
Replace studytact with your feed name
https://api.rss2json.com/v1/api.json?rss_url=https://medium.com/feed/studytact
I have built a basic function using AWS Lambda and AWS API Gateway if anyone is interested. A detailed explanation is found on this blog post here and the repository for the the Lambda function built with Node.js is found here on Github. Hopefully someone here finds it useful.
(Updating the JS Fiddle and the Clay function that explains it as we updated the function syntax to be cleaner)
I wrapped the Github package #mark-fasel was mentioning below into a Clay microservice that enables you to do exactly this:
Simplified Return Format: https://www.clay.run/services/nicoslepicos/medium-get-user-posts-new/code
I put together a little fiddle, since a user was asking how to use the endpoint in HTML to get the titles for their last 3 posts:
https://jsfiddle.net/h405m3ma/3/
You can call the API as:
curl -i -H "Content-Type: application/json" -X POST -d '{"username":"nicolaerusan"}' https://clay.run/services/nicoslepicos/medium-get-users-posts-simple
You can also use it easily in your node code using the clay-client npm package and just write:
Clay.run('nicoslepicos/medium-get-user-posts-new', {"profile":"profileValue"})
.then((result) => {
// Do what you want with returned result
console.log(result);
})
.catch((error) => {
console.log(error);
});
Hope that's helpful!
Check this One you will get all info about your own post........
mediumController.getBlogs = (req, res) => {
parser('https://medium.com/feed/#profileName', function (err, rss) {
if (err) {
console.log(err);
}
var stories = [];
for (var i = rss.length - 1; i >= 0; i--) {
var new_story = {};
new_story.title = rss[i].title;
new_story.description = rss[i].description;
new_story.date = rss[i].date;
new_story.link = rss[i].link;
new_story.author = rss[i].author;
new_story.comments = rss[i].comments;
stories.push(new_story);
}
console.log('stories:');
console.dir(stories);
res.json(200, {
Data: stories
})
});
}
I have created a custom REST API to retrieve the stats of a given post on Medium, all you need is to send a GET request to my custom API and you will retrieve the stats as a Json abject as follows:
Request :
curl https://endpoint/api/stats?story_url=THE_URL_OF_THE_MEDIUM_STORY
Response:
{
"claps": 78,
"comments": 1
}
The API responds within a reasonable response time (< 2 sec), you can find more about it in the following Medium article.

Create Snapshot/Thumbnail of a blog entry using mvc

I need to generate a snapshot from multiple links of blogs.
What i have is a list of text like these
"Report: Twitter Will Release Music Discovery App This Month http://on.mash.to/10L1v49 via #mashable"
I want to show the links as snapshot of the blog, followed by its text in my view. Or at least i need to get the picture attached to the blog.
Using facebook debug, http://developers.facebook.com/tools/debug ,i am getting this..
fb:app_id: 122071082108
og:url: http://mashable.com/2013/03/13/twitter-music-app/
og:type: article
og:title: Report: Twitter Will Release Music Discovery App This Month
og:image:
og:description: Twitter is planning to release a standalone music app for iOS called Twitter Music as soon as the end of this month, according to CNET. CNET reports that Twitter Music will help...
og:site_name: Mashable
og:updated_time: 1363267654
I tried the same link from my c# code, accessed the link with parameter 'q' as my desired link. I got the same html as reply but i am unable to find the image associated as it is coming differently for different links.
Can anyone suggest a better method to do this in mvc?
My code in controller to access facebook debug :
var client = new RestClient
{
BaseUrl = "http://developers.facebook.com/tools/debug/og/object"
};
var request = new RestRequest
{
DateFormat = DataFormat.Xml.ToString(),
Resource = "Add",
Method = Method.GET
};
request.AddParameter("q", "http://on.mash.to/10L1v49");
IRestResponse response = client.Execute(request);
var content = response.Content; // raw content as string
What i understand from your question is, you need something like the preview of a link what we get on pasting some link on facebook share area.
Facebook debug method returns an html page which has the image of your blog entry from the link given.
Use HtmlAgilityPack to parse your html returned from facebook debug
HtmlAgilityPack.HtmlDocument doc = new HtmlAgilityPack.HtmlDocument();
doc.LoadHtml(content);
HtmlNode root = doc.DocumentNode;
var imageurl = doc.DocumentNode.SelectNodes("//img/#src").LastOrDefault();
string imagesrc = imageurl.OuterHtml.ToString();
int start = imagesrc.IndexOf("url=");
int to = imagesrc.IndexOf("\"", start + "url=".Length);
string s = imagesrc.Substring(
start + "url=".Length,
to - start - "url=".Length);
string a = Uri.UnescapeDataString(s);
and..there you have your image of the blog entry. Same function can be modified to retireve the title, description and the updated time of the blog entry.

WebRequest to download XML Feed

This is my first time working with a webservice and I tried looking up all the resources on the web but I wasn't able to get it to work.
I have to use this XML in my windows phone application and I want the application to retrieve it when the user wants to. I know how to parse the XML but I am just not able to get the XML from the XML feed.
There are lots of tutorials for this type of problem available on the wider web.
For example, try the 3 line solution from: http://www.codeproject.com/Articles/156610/WP7-WebClient-vs-HttpWebRequest
var client = new WebClient();
client.DownloadStringCompleted += (s, ev) => { responseTextBlock.Text = ev.Result; };
client.DownloadStringAsync(new Uri("http://www.sherdog.com/rss/news.xml"));

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