How can i fetch the location in terms of IP address of a URL - quicktime

Can anyone tell me which APIs can be used to fetch link location of a radio server. Eg: if i enter following URL http://www.di.fm/mp3/electro.pls in Qt player it does not play. How can i get its link location which is playable.

Related

use wireshark to get video url from java application

i was asked recently if its possible to sniff the s3 playback url of a video that is shown in a Java application. So i loaded up wireshark and launched the Java app and started recording.
but i few question came up.
how would i filter for video url
how do i tell if the packet sniffed belongs to a video stream
how can i rebuild the aws s3 url that was picked up. i assume its a private url, would the query parameters providing the access key be picked up?
or if this is at all possible.
thank for any feedback or suggestions.

Retrieving phone geolocation when user tap NFC chip?

I am developing a software to remotely manage NFC tags - change their actions and track campaign performance such as:
No. of taps on individual NFC chips
date and time of taps on individual NFC chips
location of NFC chips when tapped
When the user tap the NFC, they are directed to our server which then redirect the phone's browser to the designated destination set in the campaign.
I have completed all of the above except for the location one as it gives me the inaccurate location.
At the moment, I'm using the site http://ipinfodb.com + their API to get the phone ip address and supposedly location, but it's innacurate.
Another, more accurate approach would be to "get" the phone's location via the GPS but not sure how to approach this.
Any suggestions would be much appreciated.
Probably an easier solution would be to get the data out of an analytics backend such as Google Analytics (relying on their accuracy ...)
Otherwise you need to ask the user's permission - but that needs to be done on the web site acting as the redirection target, as otherwise you would break the flow.

Display Phone Number or link based on Geolocation?

Does anyone know how to have a phone number & link to appear based on the visitors Geolocation or IP address? For instance, lets say I have 5 locations across 2 different states. I want to have the phone number in the header to show the phone number of the location that is closest to the person who is visiting the website.
You can pull some info from geolocation of the IP address. E.g. http://whois.arin.net/ui/
You can also ask the user's browser for their location: https://developers.google.com/web/fundamentals/native-hardware/user-location/
You would need to extend the above method using browser detection to include other browsers than just Chrome.

How to get the location coordinates at which we are present using program

I am working on a project which get the current location coordinates and sends them to a server where server gets the street address with the coordinates sent by Blackberry mobile. And this project is to be done on 8520 blackberry mobile without using GPS. Is it possible to get the location without using GPS and without depending on third party members? Please help me with a code if it is possible. Thank you
Please try the following links which gives very useful information about locations services in blackberry
Location-Based Services
Location APIs – Start to finish
Google provides location apis which you can use to find out the lat/longs. Its very easy. All you do is create a json request with your current cellid , and send the request to google. You get the lat/long from the google response.

Weather Channel API support for videos

I am developing an iPad application in which I will be displaying weather information for location entered by the user. I am using Weather channel API for this.
Is it possible to get the video that shows weather of near-by locations of the location entered. (The Weather Channel Application is showing the video of the location say 'Atlanta'. The video shows weather conditions of near-by locations.)
If possible, how exactly I can get this video URL.
Thanks in advance.
Regards,
Deepa

Resources