I'm importing SVGs with imagick using this syntax
$graphic = new Imagick($this->img);
The problem is this image is imported with a white background. How can I change the white background to a transparent one, or make imagick keep then transparent background when importing the SVG.
I can't help you with imagick. However, I know that an SVG with a transparent background gets converted to a PDF with transparent background if I use this ImageMagick ClI command:
convert -background none some.svg some.pdf
and if I use
convert -background gray some.svg some.pdf
the PDF indeed has a gray background.
Related
I'm using a GraphicsMagick package for image processing
When converting Illustrator (.ai) files to .png files, I end up losing transparency so the background ends up white.
I don't have this problem when using the same options and converting with ImageMagick, but I need a solution to make it work with GraphicsMagick specifically.
I don't have much experience with GraphicsMagick, but I would assume that the behavior of -background is the same as ImageMagick's:
gm convert -background transparent source.ai out.png
Note: This works by defining the background before reading the vector graphic
I want to add a tiled background to a transparent image.
According to the docs this should do it:
convert test.png -texture paper.png result.png
I also tried other variations (with -composite, -flatten, -tile, etc.) but result.png is either still transparent or just gets a white background.
ImageMagick-6.8.7-5 on Windows.
I got it to work with
convert -size 4096x4096 tile:paper.png test.png -flatten result.png
ImageMagick is premultiplying transparent pixels. This causes a gray outline to appear during subsequent transformations.
For example:
$ convert -size 1085x558 xc:"rgba(0,0,0,0)" PNG32:temp.png
$ composite -gravity center samples/logo_white.png temp.png PNG32:temp.png
Here are the source and resulting images.
Here is a video showing that the temp.png image has had its transparent pixels turned from white to black.
Is there a way to force ImageMagick to leave fully transparent pixels alone rather than changing them to black?
Just a quickie.
I have a series of images min*.png that I want to animate into a gif.
They are each fully transparent, except for some white dots on the area I want filled in for that frame.
Is there some way to create an animation from these such that the background is black (so that the whtie dots show up?)
I am interested in both:
black background, and paste each successive image on top of the previous ones (so frame i is the black background plus all of the dots up to image i)
each frame consists of just (image i on a black background)
I think for 1. I need to use -dispose none and for 2 I use -dispose background or -dispose previous, but various attempts at actually setting the background to black have failed (I have spent a lot of time reading this imagemagick page but am still learning).
e.g.
convert -background black -dispose background min*.png out.gif
various attempts with -background and -dispose have invariably produced a gif of my min*.png with a transparent background, not a black one. I think I'm close, but not sure.
This may be useful for the black background problem: starting from ImageMagick 6.7.5 you can remove transparency and replace it with a static color; you can read more about this command here
Hope this helps, unfortunately I have an older version of Imagemagick, so i can't try it myself
Example from ImageMagick documentation:
convert moon.png -background tan -alpha remove alpha_remove.png
The color "tan" replaces the transparent areas of the picture
Comment from mathematical.coffee
Using the above answer, I was able to generate the animations I wanted.
1: successive buildup of dots, all on a black background. Turned out to be as simple as creating a black background picture to put at the start of the animation, and using -coalesce:
# where bg.png is a black png of the appropriate size:
convert bg.png min*.png -coalesce out.gif
# in the below the first line creates the black background
# image, same size as my first min00.png image, for me:
convert min00.png -alpha Opaque +level-colors black \
min*.png -coalesce out.gif
2. use the method mentioned above:
convert min000*.png -background black -alpha remove out.gif
In both I was using imagemagick 6.7.something.
I'd like to use the ImageMagick convert tool to automatically generate a toolbar bitmap from several png images.
I'm using the following command line:
convert.exe -resize 32x32 #imagelist32.txt +append BMP3:toolbarlarge.bmp
with imagelist32.txt containing a list of png files (each one being one toolbar button).
This works, but the resulting bitmap uses black for the transparent color and white as the background color. I would need both colors to be RGB(192,192,192). Like if there was already an image with that background color, and the png images would be drawn on that background.
How can I do that? I've tried adding the -background #C0C0C0 and -transparent-color #C0C0C0 parameters but it didn't work - maybe I put them in the wrong order?
I know you've probably resolved it by your own, but I've been playing a bit with converter.exe some time ago, so I hope this is what you were looking for.
Set the -alpha parameter to the background flag, what means that every fully transparent pixel will be set to the background color, while leaving it fully transparent.
And set also the -background to a certain color RGB(192,192,192), so the previously transparent pixels will get this color.
convert.exe -resize 32x32 -alpha background -background RGB(192,192,192) #imagelist32.txt +append BMP3:toolbarlarge.bmp