How to display a sfWidgetFormSelectRadio item without showing the label - symfony1

Question

I am using Symfony 1.3.6 on Ubuntu 10.0.4.
I am using the sfWidgetFormSelectRadio to allow a user to select a picture from a list, in a form.
In the action, the pictures are set up like this:
$this->form->setWidget('chosenpic', new sfWidgetFormSelectRadio(array(
'choices' => $this->pictures,
'default' => $this->pictures[count($this->pictures)-1] ))
);
In the template, the widget is displayed like this:
<?php echo $form['chosenpic']->render(array('id'=>'check'.($i+1), 'value'=> ($i+1), 'width' => "80", 'height' => "80")); ?>
This generates the following output:
<ul class="radio_list"><li><input type="radio" width="80" height="80" id="check1" value="1" name="flowers[chosenpic]"> <label for="flowers_chosenpic_0">http://example.com/media/images/48408000/jpg/_48408794_009829449-1.jpg</label></li></ul>
I do no want the the label for appearing, as it messes up the form. Short of manually generating the HTML myself (using the form and widget names, is there a way that I can prevent the widget from displaying a 'label for' ?

Answer 1

You need to provide a custom formatter. In your form's configure function, do the following:
public function configure()
{
$this->setWidget('chosenpic', new sfWidgetFormSelectRadio(array(
'formatter' => array($this, 'pictureRadioFormatterCallback')
)));
}
Then, add a formatter that doesn't render labels to your form:
public function pictureRadioFormatterCallback($widget, $inputs)
{
$rows = array();
foreach ($inputs as $input)
{
$rows[] = $widget->renderContentTag('li', $input['input']);
}
return !$rows ?
'' :
$widget->renderContentTag('ul', implode($widget->getOption('separator'), $rows), array('class' => $widget->getOption('class')));
}
However, ideally, you should be using the labels to display the images, rather than displaying the images outside of the labels. Also, it's typically a bad idea to be configuring widgets inside of an action, can that code go in it's own form?

Answer 2

You can do the above -- or use CSS to hide the label generated by default ... something along the lines of:
ul.radio_list li input label { display: none; }
the form itself probably has an #id to help you better specify the CSS selector better. But if you like adding boilerplate PHP code to your app feel free :)