Address Error in Assembly (ColdFire MCF5307) - memory

Taking my first course in assembly language, I am frustrated with cryptic error messages during debugging... I acknowledge that the following information will not be enough to find the cause of the problem (given my limited understanding of the assembly language, ColdFire(MCF5307, M68K family)), but I will gladly take any advice.
...
jsr out_string
Address Error (format 0x04 vector 0x03 fault status 0x1 status reg 0x2700)
I found a similar question on http://forums.freescale.com/freescale/board/message?board.id=CFCOMM&thread.id=271, regarding on ADDRESS ERROR in general.
The answer to the question states that the address error is because the code is "incorrectly" trying to execute on a non-aligned boundary (or accessing non-aligned memory).
So my questions will be:
What does it mean to "incorrectly" trying to execute a non-aligned boundary/memory? If there is an example, it would help a lot
What is non-aligned boundary/memory?
How would you approach fixing this problem, assuming you have little debugging technique(eg. using breakpoints and trace)

First of all, it is possible that isn't the instruction causing the error. Be sure to see if the previous or next instruction could have caused it. However, assuming that exception handlers and debuggers have improved:
An alignment exception is what occurs when, say 32 bit (4 byte) data is retrieved from an address which is not a multiple of 4 bytes. For example, variable x is 32 bits at address 2, then
const1: dc.w someconstant
x: dc.l someotherconstant
Then the instruction
mov.l x, %r0
would cause a data alignment fault on a 68000 (and 68010, IIRC). The 68020 eliminated this restriction and performs the unaligned access, but at the cost of decreased performance. I'm not aware of the jsr (jump to subroutine) instruction requiring alignment, but it's not unreasonable and it's easy to arrange—Before each function, insert the assembly language's macro for alignment:
.align long
func: ...

It has been a long time since I've used a 68K family processor, but I can give you some hints.
Trying to execute on an unaligned boundary means executing code at an odd address. If out_string were at an address with the low bit set for example.
The same holds true for a data access to memory of 2 or 4 byte data. I'm not sure if the Coldfire supports byte access to odd memory addresses, but the other 68K family members did.
The address error occurs on the instruction that causes the error in all cases.
Find out what instruction is there. If the pc matches (or is close) then it is an unaligned execution. If it is a memory access, e.g. move.w d0,(a0), then check to see what address is being read/written, in this case the one pointed at by a0.
I just wanted to add that this is very good stuff to figure out. I program high end medical imaging devices in my day job, but occasionally I need to get down to this level. I have found and fixed more than one COTS OS problem by being able to track down just this sort of problem.

Related

Accessing other program's memory

I have been experimented around accessing memory used by other programs and I've encountered a little bit strange (to me) results.
First I have created a variable in my first program and gave it the value of 10. Then I looked at the address of it and asigned it manualy to a pointer in my second program. After that i tried to derefrence the pointer and (to my surprise) the program didn't crash. Instead it printed derefrenced pointer's value as 0
Next I created a few other programs to experiment with this. In my first program I created a pointer and asigned 'new int' to it. Then I checked the address of the int and manually asigned it to another pointer in my second program. Now when i tried to derefrence the ptr of my second program it did crash.
Could someone explain why the difference happened? And why was the derefrenced pointer 0?
Sorry for a possibly stupid question :/
This is because the addresses that your program prints for you to see are virtual addresses. Virtual addresses are relative to the memory space of each individual program. They get converted to physical memory addresses by the operating system during runtime.
So you didn't really access the real (physical) memory address of one of your programs from another one. This is also why the pointer value was set to 0.

Why is the memory address 0x0 reserved, and for what?

Why is the memory address 0x0 reserved, and for what? I am having trouble understanding for what exactly, thank you for helping
It is mostly a convention, and it is implementation specific.
The C language standard (C99 or C11) -and some other programming languages such as Lisp- has the notion of null pointer which cannot be dereferenced (that would be undefined behavior, segmentation fault) and is different of any other pointer (to some valid memory location). Tony Hoare modestly called that notion "my billion dollar mistake", and some languages (Haskell, Ocaml) have some tagged unions types (e.g. 'a option in Ocaml) instead.
Most implementations (but not all) represent the null pointer by address 0.
In practice, on a desktop, laptop or tablet, a user-mode C program runs in some virtual address space where the page containing the address 0 is not mapped. (On some Linux, you perhaps could mmap(2) with MAP_FIXED the address 0, but that would be poor taste...)
In some embedded microcontrollers (e.g. AVR), address 0 could be used.
In theory (and in the past), addresses might be more complex than a number... (in the 1980s, e.g. x86 memory segmentation on i286, and iAPX432 addressing, Rekursiv architecture, etc...)
Read several books and web pages on C programming, microprocessor architectures & instruction sets, operating system principles, virtual memory, MMUs.
It has been a common practice on paged memory systems not to map the first (zeroth) page by default. This is a convention normally enforced by the linker. When the program loader reads the executable file, it never gets an instruction to map the first logical page.
The reason for this is to detect null pointer errors.
int *whatever = 0 ;
. . . .
*whatever = 10 ;
will cause an access violation.
That said, it is usually possible for a process to map the first (zeroth) page after execution starts and, in some cases, you can specify linker options allowing program sections to be based there.

Heap overflow exploit

I understand that overflow exploitation requires three steps:
1.Injecting arbitrary code (shellcode) into target process memory space.
2.Taking control over eip.
3.Set eip to execute arbitrary code.
I read ben hawkens articles about heap exploitation and understood few tactics about how to ultimatly override a function pointer to point to my code.
In other words, I understand step 2.
I do not understand step 1 and 3.
How do I inject my code to the process memory space ?
During step 3 I override a function pointer with a
Pointer to my shellcode, How can I calculate\know what address
Was my injected code injected into ? (This problem is solved
In stackoverflow by using "jmp esp).
In a heap overflow, supposing that the system does not have ASLR activated, you will know the address of the memory chunks (aka, the buffers) you use in the overflow.
One option is to place the shellcode where the buffer is, given that you can control the contents of the buffer (as the application user). Once you have placed the shellcode bytes in the buffer, you only have to jump to that buffer address.
One way to perform that jump is by, for example, overwriting a .dtors entry. Once the vulnerable program finishes, the shellcode - placed in the buffer - will be executed. The complicated part is the .dtors overwriting. For that you will have to use the published heap exploiting techniques.
The prerequisites are that ASLR is deactivated (to know the address of the buffer before executing the vulnerable program) and that the memory region where the buffer is placed must be executable.
On more thing, steps 2 and 3 are the same. If you control eip, it's logic that you will point it to the shellcode (the arbitrary code).
P.S.: Bypassing ASLR is more complex.
Step 1 requires a vulnerability in the attacked code.
Common vulnerabilites include:
buffer overflow (common i C code, happens if the program reads an arbitrary long string into a fixed buffer)
evaluation of unsanitized data (common in SQL and script languages, but can occur in other languages as well)
Step 3 requires detailed knowledge of the target architecture.
How do I inject my code into process space?
This is quite a statement/question. It requires an 'exploitable' region of code in said process space. For example, Windows is currently rewriting most strcpy() to strncpy() if at all possible. I say if possible
because not all areas of code that use strcpy can successfully be changed over to strncpy. Why? BECAUSE ~# of this crux in difference shown below;
strcpy($buffer, $copied);
or
strncpy($buffer, $copied, sizeof($copied));
This is what makes strncpy so difficult to implement in real world scenarios. There has to be installed a 'magic number' on most strncpy operations (the sizeof() operator creates this magic number)
As coders' we are taught using hard coded values such as a strict compliance with a char buffer[1024]; is really bad coding practise.
BUT ~ in comparison - using buffer[]=""; or buffer[1024]=""; is the heart of the exploit. HOWEVER, if for example we change this code to the latter we get another exploit introduced into the system...
char * buffer;
char * copied;
strcpy(buffer, copied);//overflow this right here...
OR THIS:
int size = 1024;
char buffer[size];
char copied[size];
strncpy(buffer,copied, size);
This will stop overflows, but introduce a exploitable region in RAM due to size being predictable and structured into 1024 blocks of code/data.
Therefore, original poster, looking for strcpy for example, in a program's address space, will make the program exploitable if strcpy is present.
There are many reasons why strcpy is favoured by programmers over strncpy. Magic numbers, variable input/output data size...programming styles...etc...
HOW DO I FIND MYSELF IN MY CODE (MY LOCATION)
Check various hacker books for examples of this ~
BUT, try;
label:
pop eax
pop eax
call pointer
jmp label
pointer:
mov esp, eax
jmp $
This is an example that is non-working due to the fact that I do NOT want to be held responsible for writing the next Morris Worm! But, any decent programmer will get the jist of this code and know immediately what I am talking about here.
I hope your overflow techniques work in the future, my son!

CL_OUT_OF_RESOURCES for 2 millions floats with 1GB VRAM?

It seems like 2 million floats should be no big deal, only 8MBs of 1GB of GPU RAM. I am able to allocate that much at times and sometimes more than that with no trouble. I get CL_OUT_OF_RESOURCES when I do a clEnqueueReadBuffer, which seems odd. Am I able to sniff out where the trouble really started? OpenCL shouldn't be failing like this at clEnqueueReadBuffer right? It should be when I allocated the data right? Is there some way to get more details than just the error code? It would be cool if I could see how much VRAM was allocated when OpenCL declared CL_OUT_OF_RESOURCES.
I just had the same problem you had (took me a whole day to fix).
I'm sure people with the same problem will stumble upon this, that's why I'm posting to this old question.
You propably didn't check for the maximum work group size of the kernel.
This is how you do it:
size_t kernel_work_group_size;
clGetKernelWorkGroupInfo(kernel, device, CL_KERNEL_WORK_GROUP_SIZE, sizeof(size_t), &kernel_work_group_size, NULL);
My devices (2x NVIDIA GTX 460 & Intel i7 CPU) support a maximum work group size of 1024, but the above code returns something around 500 when I pass my Path Tracing kernel.
When I used a workgroup size of 1024 it obviously failed and gave me the CL_OUT_OF_RESOURCES error.
The more complex your kernel becomes, the smaller the maximum workgroup size for it will become (or that's at least what I experienced).
Edit:
I just realized you said "clEnqueueReadBuffer" instead of "clEnqueueNDRangeKernel"...
My answer was related to clEnqueueNDRangeKernel.
Sorry for the mistake.
I hope this is still useful to other people.
From another source:
- calling clFinish() gets you the error status for the calculation (rather than getting it when you try to read data).
- the "out of resources" error can also be caused by a 5s timeout if the (NVidia) card is also being used as a display
- it can also appear when you have pointer errors in your kernel.
A follow-up suggests running the kernel first on the CPU to ensure you're not making out-of-bounds memory accesses.
Not all available memory can necessarily be supplied to a single acquisition request. Read up on heap fragmentation 1, 2, 3 to learn more about why the largest allocation that can succeed is for the largest contiguous block of memory and how blocks get divided up into smaller pieces as a result of using the memory.
It's not that the resource is exhausted... It just can't find a single piece big enough to satisfy your request...
Out of bounds acesses in a kernel are typically silent (since there is still no error at the kernel queueing call).
However, if you try to read the kernel result later with a clEnqueueReadBuffer(). This error will show up. It indicates something went wrong during kernel execution.
Check your kernel code for out-of-bounds read/writes.

How does a program look in memory?

How is a program (e.g. C or C++) arranged in computer memory? I kind of know a little about segments, variables etc, but basically I have no solid understanding of the entire structure.
Since the in-memory structure may differ, let's assume a C++ console application on Windows.
Some pointers to what I'm after specifically:
Outline of a function, and how is it called?
Each function has a stack frame, what does that contain and how is it arranged in memory?
Function arguments and return values
Global and local variables?
const static variables?
Thread local storage..
Links to tutorial-like material and such is welcome, but please no reference-style material assuming knowledge of assembler etc.
Might this be what you are looking for:
http://en.wikipedia.org/wiki/Portable_Executable
The PE file format is the binary file structure of windows binaries (.exe, .dll etc). Basically, they are mapped into memory like that. More details are described here with an explanation how you yourself can take a look at the binary representation of loaded dlls in memory:
http://msdn.microsoft.com/en-us/magazine/cc301805.aspx
Edit:
Now I understand that you want to learn how source code relates to the binary code in the PE file. That's a huge field.
First, you have to understand the basics about computer architecture which will involve learning the general basics of assembly code. Any "Introduction to Computer Architecture" college course will do. Literature includes e.g. "John L. Hennessy and David A. Patterson. Computer Architecture: A Quantitative Approach" or "Andrew Tanenbaum, Structured Computer Organization".
After reading this, you should understand what a stack is and its difference to the heap. What the stack-pointer and the base pointer are and what the return address is, how many registers there are etc.
Once you've understood this, it is relatively easy to put the pieces together:
A C++ object contains code and data, i.e., member variables. A class
class SimpleClass {
int m_nInteger;
double m_fDouble;
double SomeFunction() { return m_nInteger + m_fDouble; }
}
will be 4 + 8 consecutives bytes in memory. What happens when you do:
SimpleClass c1;
c1.m_nInteger = 1;
c1.m_fDouble = 5.0;
c1.SomeFunction();
First, object c1 is created on the stack, i.e., the stack pointer esp is decreased by 12 bytes to make room. Then constant "1" is written to memory address esp-12 and constant "5.0" is written to esp-8.
Then we call a function that means two things.
The computer has to load the part of the binary PE file into memory that contains function SomeFunction(). SomeFunction will only be in memory once, no matter how many instances of SimpleClass you create.
The computer has to execute function SomeFunction(). That means several things:
Calling the function also implies passing all parameters, often this is done on the stack. SomeFunction has one (!) parameter, the this pointer, i.e., the pointer to the memory address on the stack where we have just written the values "1" and "5.0"
Save the current program state, i.e., the current instruction address which is the code address that will be executed if SomeFunction returns. Calling a function means pushing the return address on the stack and setting the instruction pointer (register eip) to the address of the function SomeFunction.
Inside function SomeFunction, the old stack is saved by storing the old base pointer (ebp) on the stack (push ebp) and making the stack pointer the new base pointer (mov ebp, esp).
The actual binary code of SomeFunction is executed which will call the machine instruction that converts m_nInteger to a double and adds it to m_fDouble. m_nInteger and m_fDouble are found on the stack, at ebp - x bytes.
The result of the addition is stored in a register and the function returns. That means the stack is discarded which means the stack pointer is set back to the base pointer. The base pointer is set back (next value on the stack) and then the instruction pointer is set to the return address (again next value on the stack). Now we're back in the original state but in some register lurks the result of the SomeFunction().
I suggest, you build yourself such a simple example and step through the disassembly. In debug build the code will be easy to understand and Visual Studio displays variable names in the disassembly view. See what the registers esp, ebp and eip do, where in memory your object is allocated, where the code is etc.
What a huge question!
First you want to learn about virtual memory. Without that, nothing else will make sense. In short, C/C++ pointers are not physical memory addresses. Pointers are virtual addresses. There's a special CPU feature (the MMU, memory management unit) that transparently maps them to physical memory. Only the operating system is allowed to configure the MMU.
This provides safety (there is no C/C++ pointer value you can possibly make that points into another process's virtual address space, unless that process is intentionally sharing memory with you) and lets the OS do some really magical things that we now take for granted (like transparently swap some of a process's memory to disk, then transparently load it back when the process tries to use it).
A process's address space (a.k.a. virtual address space, a.k.a. addressable memory) contains:
a huge region of memory that's reserved for the Windows kernel, which the process isn't allowed to touch;
regions of virtual memory that are "unmapped", i.e. nothing is loaded there, there's no physical memory assigned to those addresses, and the process will crash if it tries to access them;
parts the various modules (EXE and DLL files) that have been loaded (each of these contains machine code, string constants, and other data); and
whatever other memory the process has allocated from the system.
Now typically a process lets the C Runtime Library or the Win32 libraries do most of the super-low-level memory management, which includes setting up:
a stack (for each thread), where local variables and function arguments and return values are stored; and
a heap, where memory is allocated if the process calls malloc or does new X.
For more about the stack is structured, read about calling conventions. For more about how the heap is structured, read about malloc implementations. In general the stack really is a stack, a last-in-first-out data structure, containing arguments, local variables, and the occasional temporary result, and not much more. Since it is easy for a program to write straight past the end of the stack (the common C/C++ bug after which this site is named), the system libraries typically make sure that there is an unmapped page adjacent to the stack. This makes the process crash instantly when such a bug happens, so it's much easier to debug (and the process is killed before it can do any more damage).
The heap is not really a heap in the data structure sense. It's a data structure maintained by the CRT or Win32 library that takes pages of memory from the operating system and parcels them out whenever the process requests small pieces of memory via malloc and friends. (Note that the OS does not micromanage this; a process can to a large extent manage its address space however it wants, if it doesn't like the way the CRT does it.)
A process can also request pages directly from the operating system, using an API like VirtualAlloc or MapViewOfFile.
There's more, but I'd better stop!
For understanding stack frame structure you can refer to
http://en.wikipedia.org/wiki/Call_stack
It gives you information about structure of call stack, how locals , globals , return address is stored on call stack
Another good illustration
http://www.cs.uleth.ca/~holzmann/C/system/memorylayout.pdf
It might not be the most accurate information, but MS Press provides some sample chapters of of the book Inside Microsoft® Windows® 2000, Third Edition, containing information about processes and their creation along with images of some important data structures.
I also stumbled upon this PDF that summarizes some of the above information in an nice chart.
But all the provided information is more from the OS point of view and not to much detailed about the application aspects.
Actually - you won't get far in this matter with at least a little bit of knowledge in Assembler. I'd recoomend a reversing (tutorial) site, e.g. OpenRCE.org.

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