I have a populated fileset and I need to print the matching filenames into a text file.
I tried this:
<fileset id="myfileset" dir="../sounds">
<include name="*.wav" />
<include name="*.ogg" />
</fileset>
<property name="sounds" refid="myfileset" />
<echo file="sounds.txt">${sounds}</echo>
which prints all the files on a single line, separated by semicolons. I need to have one file per line. How can I do this without resorting to calling OS commands or writing Java code?
UPDATE:
Ah, should have been more specific - the list must not contain directories. I'm marking ChssPly76's as the accepted answer anyway, since the pathconvert command was exactly what I was missing. To strip the directories and list only the filenames, I used the "flatten" mapper.
Here is the script that I ended up with:
<fileset id="sounds_fileset" dir="../sound">
<include name="*.wav" />
<include name="*.ogg" />
</fileset>
<pathconvert pathsep="
" property="sounds" refid="sounds_fileset">
<mapper type="flatten" />
</pathconvert>
<echo file="sounds.txt">${sounds}</echo>
Use the PathConvert task:
<fileset id="myfileset" dir="../sounds">
<include name="*.wav" />
<include name="*.ogg" />
</fileset>
<pathconvert pathsep="${line.separator}" property="sounds" refid="myfileset">
<!-- Add this if you want the path stripped -->
<mapper>
<flattenmapper />
</mapper>
</pathconvert>
<echo file="sounds.txt">${sounds}</echo>
Since Ant 1.6 you can use toString:
<echo file="sounds.txt">${toString:myfileset}</echo>
Related
I have the below ant code which gives basename (for ex: abc_01142018.txt) of the file from location input.dir. When the file is available, it works as expected.But when there are no files in input.dir it is picking up a value which I am not passing. I am expecting it to be empty value.
I read about basename and its not mentioned anywhere about how basename works when the input parameter is empty.
<path id="ref-id">
<fileset dir="${input.dir}">
<include name="abc*.txt"/>
</fileset>
</path>
<property name="input.files" refid="ref-id"/>
<basename property="input.file" file="${input.files}" />
There's no need to use Ant's path type or basename task if all you want is a list of file names without parent directories. The fileset type already does this, so just reference its ID instead.
Example:
<target name="test">
<touch file="exists1.txt" />
<touch file="exists2.txt" />
<fileset dir="." id="exists">
<include name="exists*.txt" />
</fileset>
<fileset dir="." id="doesnotexist">
<include name="doesnotexist*.txt" />
</fileset>
<property name="exists" refid="exists" />
<property name="doesnotexist" refid="doesnotexist" />
<echo message="${exists}" />
<echo message="${doesnotexist}" />
</target>
While going through the scenario what i got is that folder collection of different extension file i have use resource count for all extension if i have 3 different extension file than try to get resource count of all file differ with extension
Eg:
<resourcecount property="firstfile">
<fileset dir="${basedir}">
<include name="*.xml" />
</fileset>
</resourcecount>
<echo message="There are ${firstfile} xml in This Folder ${basedir}" />
<resourcecount property="SecondFile">
<fileset dir="${basedir}">
<include name="*.jar" />
</fileset>
</resourcecount>
<echo message="There are ${SecondFile} xml in This Folder ${basedir}" />
How can i use the macrodef for this condition which help in count all file with it
You can do this in many ways, including using plugins, such as ant-contrib, or using ant language extensions. But all of them are overkill compared to this simple build script:
<target name="count">
<countresources type="xml" />
<countresources type="java" />
<countresources type="cpp" />
</target>
<macrodef name="countresources">
<attribute name="type" />
<sequential>
<resourcecount property="#{type}.count">
<fileset dir="${basedir}">
<include name="*.#{type}" />
</fileset>
</resourcecount>
<echo message="There are ${#{type}.count} #{type} files in folder ${basedir}" />
</sequential>
</macrodef>
Hope this helps.
I have 2 different filesets defined in Ant as follows:
<fileset id="fileset1" dir="${classes.dir}">
</fileset>
<zipfileset id="fileset2" src="myArchive.zip" includes="**/*.class">
</zipfileset>
I want to create a third fileset which is the union of both the above filesets
<fileset id="merged">
</fileset>
Can someone tell me how to do this ? Is it even possible to do something like that ?
Thanks in advance!
One way to do this is with Ant resource collections, in particular a union.
<fileset id="fileset1" dir="${classes.dir}" />
<zipfileset id="fileset2" src="myArchive.zip" includes="**/*.class" />
<union id="onion">
<resources refid="fileset1" />
<resources refid="fileset2" />
</union>
Then you can refer to the 'onion' anywhere you might use a fileset, e.g.
<copy todir="dest">
<resources refid="onion" />
</copy>
I recommend using generic resources elements rather than filesets for maximum flexibility.
Try this: I think it should work, since <fileset> is an implicit <patternset>.
<fileset id="fileset1" dir="${classes.dir}">
</fileset>
<zipfileset id="fileset2" src="myArchive.zip" includes="**/*.class">
</zipfileset>
EDIT: odd. This perhaps?
<patternset id="merged">
<patternset refid="fileset1" />
<patternset refid="fileset2" />
</patternset>
problem with fileset is, that it requires a directory as a base upon it applies the patternset. Which means you have to find a common base directory that is shared by all filesets.
A <pathconvert> Task can take filesets via refid. You can put several filesets (e.g. from various build targets to assemble a compound set in a root/main target for a modular build environment):
<project name="root" basedir="." xmlns:if="ant:if" xmlns:unless="ant:unless">
<!--
it's important to take the xmlns:features in your project head
otherwhise this code won't work
-->
<target name="init">
<!-- set some common prerequisites -->
<property name="prerequisite.property.xyz" value="xyz" />
</target>
<target name="targetA" depends="init">
<fileset dir="${common.basedir}${file.separator}${targetA.subdir}" id="targetA.fileset">
<include name="**/*.html" />
</fileset>
<property name="targetA.fileset.exists" value="true" />
</target>
<target name="targetB" depends="init">
<fileset dir="${common.basedir}${file.separator}${targetB.subdir}" id="targetB.fileset">
<include name="**/*.java" />
</fileset>
<property name="targetB.fileset.exists" value="true" />
</target>
<target name="targetC" depends="init">
<fileset dir="${common.basedir}${file.separator}${targetC.subdir}" id="targetC.fileset">
<include name="**/*.class" />
</fileset>
<property name="targetC.fileset.exists" value="true" />
</target>
<target name="root" depends="init">
<pathconvert property="all.files.as.commaseparated.path" pathsep="," dirsep="/">
<fileset refid="targetA.fileset" if:true="${targetA.fileset.exists}" />
<fileset refid="targetB.fileset" if:true="${targetB.fileset.exists}" />
<fileset refid="targetC.fileset" if:true="${targetC.fileset.exists}" />
<map from="${common.basedir}/" to="" />
</pathconvert>
<!-- assemble new fileset from paths as comma separated property string -->
<fileset id="new.refid" dir="${common.basedir}" includes="${all.files.as.commaseparated.path}" />
</target>
</project>
This can be called via command line like:
ant targetA targetB targetC root
or
ant targetA root
Be aware that root is always the last target being called.
When using concat with fileset in Ant, how do I make an action happen for each element in the fileset. Such as, adding a string:
<fileset dir="${project.path.scripts-library}"
excludes="!*.js, **/*.bak, **/dev.*"
>
<type type="file" />
<include name="**/0*.js" />
<include name="**/1*.js" />
<string>test</string>
</fileset>
Or echoing the current file name for each file in the fileset (and, how do I GET the file name for the current file???):
<fileset dir="${project.path.scripts-library}"
excludes="!*.js, **/*.bak, **/dev.*"
>
<echo file="${app.path.file}"
append="true"
message=",${the.file.name}" />
<type type="file" />
<include name="**/0*.js" />
<include name="**/1*.js" />
</fileset>
I think there is no such thing in default ant. The closest one is <apply>, but it's system specific:
<apply executable="echo"> <!-- run this command with each file name -->
<fileset dir="/tmp" includes="**/*.*"/>
</apply>
Also you can install ant-contrib to enable <for> task:
<taskdef resource="net/sf/antcontrib/antcontrib.properties"/>
<for param="file">
<path>
<fileset dir="/tmp" includes="**/*.*"/>
</path>
<sequential> <!-- run any task here -->
<echo>file [#{file}]</echo>
</sequential>
</for>
How to preserve file order in Ant concat?
Simple concat with fileset & includesfile produces rather "random" order, as order is not guaranteed:
<concat destfile="C:/targetdir/concatenated.file">
<fileset dir="C:/sourcedir/">
<includesfile name="C:/targetdir/includes.file" />
</fileset>
</concat>
What I need is concatenation in specific order that the files are listed in the includes file.
So far I've found resourcelist, which should preserve order, but I can't seem to be able to produce any concatenated file with it. :/
<concat destfile="C:/targetdir/concatenated.file">
<resourcelist>
<file file="C:/targetdir/includes.file"/>
<filterchain>
<striplinecomments>
<comment value="#"/>
</striplinecomments>
<prefixlines prefix="C:/sourcedir/"/>
</filterchain>
</resourcelist>
</concat>
Plus, the resourcelist can't seem to handle rows like
LibraryX/A/Stuff/Morestuff/*
Instead the row just produces a ".../Morestuff/* does not exist." -error
Includes file has list of relative paths:
LibraryX/A/Stuff/FileA.txt
LibraryX/A/Stuff/FileB.txt
LibraryX/A/Stuff/FileC.txt
LibraryX/A/Stuff/FileY.txt
I was able to get a filelist working pretty easily:
<concat destfile="C:/targetdir/concatenated.file">
<filelist dir="C:/sourcedir/">
<file name="i.txt" />
<file name="n.txt" />
<file name="o.txt" />
<file name="r.txt" />
<file name="d.txt" />
<file name="e.txt" />
<file name="r.txt" />
</filelist>
</concat>
Hope that helps!
If you are using Ant 1.7+, you can use the sort command
<concat destfile="C:/targetdir/concatenated.file">
<sort>
<fileset dir="C:/sourcedir/">
<include name="C:/targetdir/*.file" />
</fileset>
</sort>
</concat>
You can find the documentation of sort here
[On Ant 1.8.2+] You can also pass the fileset via a sort, and sort on filename, like below:
<concat destfile="./${dir.publish}/${dir.js}/b.main-${build.number}.debug.js">
<sort xmlns:rcmp="antlib:org.apache.tools.ant.types.resources.comparators">
<fileset dir="./${dir.publish}/">
<include name="**/${dir.js.main}/**/*.js"/>
<exclude name="**/${dir.js.main}/**/*.min.js"/>
</fileset>
<rcmp:name />
</sort>
</concat>
Couple of things to watch out for:
Directories are sorted before files
Capitals come before lowercase
UPDATE: Another alternative if you need to manually specify order:
<!-- create a ordered list of all the build files so that CIAPI & CIAPI.widget are built first
(can't find a smarter way to do this, since ant filesets are unordered) -->
<fileset id="a" dir="."><include name="CIAPI/build.project.xml"/></fileset>
<fileset id="b" dir="."><include name="CIAPI.widget/build.project.xml"/></fileset>
<fileset id="c" dir=".">
<include name="**/build.project.xml"/>
<exclude name="CIAPI/build.project.xml" />
<exclude name="CIAPI.widget/build.project.xml" />
</fileset>
<union id="all_build_files">
<fileset refid="a"/>
<fileset refid="b"/>
<fileset refid="c"/>
</union>
Ugly, but, erm, this is ant?
try this, put in alphabetical order
<project name="concatPath" default="full">
<target name="full">
<fileset id="fs" dir="./files" />
<pathconvert refid="fs" property="concatList" pathsep=";" targetos="unix"/>
<echo>${concatList}</echo>
</target>
</project>
this can be used with hierarchical structure of directories, and the order will be the exposed by David.
Remember that XML is not order-dependent, by definition.
To concatenate files in a sorted order, consider using <replace> instead.
Create an order file that defines the order. Then, in your build file:
Copy the order file to the destination file with <copy>
Concatenate your files together into a temporary file with <concat>
Load the files into properties with <loadfile>
Insert the text from those files into the destination file with <replace>
Example order file order_file.txt:
FILE_A_HERE
CONCAT_FILES_HERE
Example ant build file build.xml:
<copy file="order_file.txt" tofile="destination.txt" overwrite="yes">
<concat destfile="tempfile.txt">
<fileset dir="includes/">
<include name="*.txt">
<exclude name="fileA.txt">
</fileset>
</concat>
<loadfile property="fileA" srcFile="includes/fileA.txt" />
<loadfile property="concatFile" srcFile="tempfile.txt" />
<replace file="destination.txt" token="FILE_A_HERE" value="fileA" />
<replace file="destination.txt" token="CONCAT_FILES_HERE" value="concatFile" />