TI TMS320C64xx : add a PRD function - signal-processing

I have to add a function that will run every specified period. it seems straight forward as Code composer has a GUI tool to do that : DSP/BIOS Condig->PRD->
alt text http://bauhaus.ece.curtin.edu.au/~iain/c54-tutorial/images/Image33.gif
in the properties form I can fill in the function name that gets called with every clk interrupt, but the GUI rejects my functions as "undefined labels'
the function I want to call is a C++ static function : static void MyClass::func1()
what am i missing here ?

You definitely need to have it be an extern "C" function.

Related

FFI Metatype : "cannot change a protected metatable"

If a script uses ffi.metatype and crashes unexpectedly,the next script startup produces this error : “cannot change a protected metatable”,this makes debugging real hard as I have to restart my game each time,any way to circumvent this?
Here’s a test script that demonstrates this issue,make sure to run it twice.
ffi.cdef[[
typedef struct {
float x,y;
} Crash;
]]
local Crash_Metatype = ffi.metatype("Crash",{})
print(x + y)
You can't call ffi.metatype on the same C type twice. Either set a variable after doing so and don't do so again if it's already set, or wrap the call to it in pcall so you can ignore that error.

Null aware function invocation operator

In the same way we can have
nullableClassInstance?.method(blah)
Is there a way to do
nullableFunctionInstance?(blah)
In other words, is there an operator that checks whether a function instance is not null, if so, invoke the function all in one line?
Using the call method, you can achieve what you want with:
nullableFunctionInstance?.call(blah)
There's also the apply method if you want to pass arguments.
If you have a Function Object , you can use the call method and send all the parameters to that which works exactly as calling the function. Here , you can use the null aware member access operator.
void myFun(int a , int b){...}
var myVar = myFun ;
call
The function myVar will only get called if its not null as shown below.
myVar?.call( arg1 , arg2 );
apply
If your function is dynamic or you wish to control which function is being called at run time , you can use the apply static method of Function like so :
Function.apply(myVar , [arg1 , arg2]);
apply takes the function and a List of parameters that will be sent to the function.
Read more about call and apply :

Lua: How to call a function prior to it being defined?

What is the syntax to create the function, but then add it's implementation further down in code?
So roughly like this:
Define function doX
Call doX (further down in the code)
doX implemention (i.e. all functions down at the bottom of the file)
You only need to have a variable to reference. local funcName is sufficient for your purposes with one caveat. This will work:
local funcName
function callIt()
print(funcName())
end
function defineIt()
funcName = function() return "My Function" end
end
defineIt()
callIt()
As long as you define it (defineIt) before you call it (callIt), it should work as expected. You can't do something like this though (and this is the caveat):
local funcName
print(funcName())
funcName = function() return "My Function" end
You will get an error: attempt to call local 'funcName' (a nil value).
oh...so there's really no way to call funcName prior to having actually defined the function then? i.e. you still need to make sure defineIt is called before your first call to funcName itself?
I wanted to clarify this point, and I felt that an answer would be the better way than a comment.
Lua is a much simpler language than C or C++. It is built on some simple foundations, with some syntactic sugar to make parts of it easier to swallow.
There is no such thing as a "function definition" in Lua. Functions are first-class objects. They are values in Lua, just like the number 28 or the string literal "foo" are values. A "function definition" simply sets a value (namely, the function) into a variable. Variables can contain any kind of value, including a function value.
All a "function call" is is taking the value from a variable and attempting to call it. If that value is a function, then the function gets called with the given parameters. If that value is not a function (or a table/userdata with a __call metamethod), then you get a runtime error.
You can no more call a function that hasn't been set in a variable yet than you can do this:
local number = nil
local addition = number + 5
number = 20
And expect addition to have 25 in it. That's not going to happen. And thus, for the same reason, you can't do this:
local func = nil
func(50)
func = function() ... end
As Paul pointed out, you can call a function from within another function you define. But you cannot execute the function that calls it until you've filled in that variable with what it needs to contain.
As others have written, you cannot call a function at runtime that has not been assigned prior to the call. You have to understand that:
function myFunc() print('Something') end
Is just a syntax sugar for this:
myFunc = function() print('Something') end
Now, it makes sense that this kind of code would not work the way you want it to:
print(greeter(io.read())) -- attempt to call global 'greeter' (a nil value)
function greeter(name) return 'Hello '..name end
When you use the greeter variable, its value is nil, because its value is set only on the next line.
But if you want to have your "main" program on the top and the functions at the bottom, there is simple way to achieve this: create a "main" function and call it as the last thing on the bottom. By the time the function is called, all the functions will be set to the corresponding global variables:
-- start of program, your main code at the top of source code
function main()
local name = readName()
local message = greeter(name)
print(message)
end
-- define the functions below main, but main is not called yet,
-- so there will be no errors
function readName() io.write('Your name? '); return io.read() end
function greeter(name) return 'Hello, ' .. name end
-- call main here, all the functions have been assigned,
-- so this will run without any problems
main()

Callback to Lua member function

I have a lua "animation variable" which has a callback function used in an animation loop.
local av = AnimationVariable(ticker.Position.Y)
...
av:addCallback( ** animation function goes here **)
Skipping over details, this addCallback function is defined as follows in C++:
void LuaUIAnimationVariable::addCallback(luabind::object callback);
and when the animation variable is updated, the callback is executed as such (we call the function with one argument):
luabind::call_function<void>(boost::ref(callback), newValue);
My question is the following: How can I use a member function with addCallback? Assuming I have a Ticker:animate(ypos) function, using addCallback on a Ticker instance addCallBack(ticker:animate) does not compile, and addCallBack(ticker.animate) does not work. I understand that member functions in lua have an implicit "self" first parameter.
Any solution or am I forced to use a global function?
Not sure if I understand your question, but if you mean a Lua member function, you can use a closure:
av:addCallback(function(yval) ticker:animate(yval) end)

Calling Lua from C

I'm trying to call a user-defined Lua function from C. I've seen some discussion on this, and the solution seems clear. I need to grab the index of the function with luaL_ref(), and save the returned index for use later.
In my case, I've saved the value with luaL_ref, and I'm at a point where my C code needs to invoke the Lua function saved with luaL_ref. For that, I'm using lua_rawgeti as follows:
lua_rawgeti(l, LUA_REGISTRYINDEX, fIndex);
This causes a crash in lua_rawgeti.
The fIndex I'm using is the value I received from luaL_ref, so I'm not sure what's going on here.
EDIT:
I'm running a Lua script as follows:
function errorFunc()
print("Error")
end
function savedFunc()
print("Saved")
end
mylib.save(savedFunc, errorFunc)
I've defined my own Lua library 'mylib', with a C function:
static int save(lua_State *L)
{
int cIdx = myCIndex = luaL_ref(L, LUA_REGISTRYINDEX);
int eIdx = luaL_ref(L, LUA_REGISTRYINDEX);
I save cIdx and eIdx away until a later point in time when I receive some external event at which point I would like to invoke one of the functions set as parameters in my Lua script. Here, (on the same thread, using the same lua_State*), I call:
lua_rawgeti(L, LUA_REGISTRYINDEX, myCIndex);
Which is causing the crash.
My first suggestion is to get it working without storing the function in C at all. Just assign your function to a global in Lua, then in C use the Lua state (L) to get the global, push the args, call the function, and use the results. Once that's working, you've got the basics and know your function is working, you can change the way you get at the function to use the registry. Good luck!
As #Schollii mentioned, I was making this call after doing a lua_close(L).

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