Passing Interface's method as parameter - delphi

Question

Is it possible to pass interface's method as parameters?
I'm trying something like this:
interface
type
TMoveProc = procedure of object;
// also tested with TMoveProc = procedure;
// procedure of interface is not working ;)
ISomeInterface = interface
procedure Pred;
procedure Next;
end;
TSomeObject = class(TObject)
public
procedure Move(MoveProc: TMoveProc);
end;
implementation
procedure TSomeObject.Move(MoveProc: TMoveProc);
begin
while True do
begin
// Some common code that works for both procedures
MoveProc;
// More code...
end;
end;
procedure Usage;
var
o: TSomeObject;
i: ISomeInterface;
begin
o := TSomeObject.Create;
i := GetSomeInterface;
o.Move(i.Next);
// somewhere else: o.Move(i.Prev);
// tested with o.Move(#i.Next), ##... with no luck
o.Free;
end;
But it is not working because:
E2010 Incompatible types: 'TMoveProc' and 'procedure, untyped pointer or untyped parameter'
Of course I can do private method for each call, but that is ugly. Is there any better way?
Delphi 2006
Edit:
I know that I can pass whole interface, but then I have to specify which function use. I don't want two exactly same procedures with one different call.
I can use second parameter, but that is ugly too.
type
SomeInterfaceMethod = (siPred, siNext)
procedure Move(SomeInt: ISomeInterface; Direction: SomeInterfaceMethod)
begin
case Direction of:
siPred: SomeInt.Pred;
siNext: SomeInt.Next
end;
end;
Thanks all for help and ideas. Clean solution (for my Delphi 2006) is Diego's Visitor. Now I'm using simple ("ugly") wrapper (my own, same solution by TOndrej and Aikislave).
But true answer is "there is no (direct) way to pass interface's methods as parameters without some kind of provider.

Answer 1

If you were using Delphi 2009, you could do this with an anonymous method:
TSomeObject = class(TObject)
public
procedure Move(MoveProc: TProc);
end;
procedure Usage;
var
o: TSomeObject;
i: ISomeInterface;
begin
o := TSomeObject.Create;
i := GetSomeInterface;
o.Move(procedure() begin i.Next end);
The problem with trying to pass a reference to just the interface method is that you are not passing a reference to the interface itself, so the interface cannot be reference counted. But anonymous methods are themselves reference counted, so the interface reference inside the anonymous method here can be reference counted as well. That is why this method works.

Answer 2

I don't know the exact reason why you need to do that, but, personally, I think it would be better to pass the whole "Mover" object instead of one of its methods. I used this approach in the past, it's called "Visitor" pattern.
tiOPF, an object persistence framework, uses it extensively and gives you a good example of how it works: The Visitor Pattern and the tiOPF.
It's relatively long, but it proved very useful to me, even when I didn't use tiOPF. Note step 3 in the document, titled "Step #3. Instead of passing a method pointer, we will pass an object".
DiGi, to answer your comment: If you use Visitor pattern, then you don't have an interface implementing multiple methods, but just one (Execute). Then you'd have a class for each action, like TPred, TNext, TSomething, and you pass an instance of such classes to the object to be processed. In such way, you don't have to know what to call, you just call "Visitor.Execute", and it will do the job.
Here you can find a basic example:
interface
type
TVisited = class;
TVisitor = class
procedure Execute(Visited: TVisited); virtual; abstract;
end;
TNext = class(TVisitor)
procedure Execute (Visited: TVisited); override;
end;
TPred = class(TVisitor)
procedure Execute (Visited: TVisited); override;
end;
TVisited = class(TPersistent)
public
procedure Iterate(pVisitor: TVisitor); virtual;
end;
implementation
procedure TVisited.Iterate(pVisitor: TVisitor);
begin
pVisitor.Execute(self);
end;
procedure TNext.Execute(Visited: TVisited);
begin
// Implement action "NEXT"
end;
procedure TPred.Execute(Visited: TVisited);
begin
// Implement action "PRED"
end;
procedure Usage;
var
Visited: TVisited;
Visitor: TVisitor;
begin
Visited := TVisited.Create;
Visitor := TNext.Create;
Visited.Iterate(Visitor);
Visited.Free;
end;

Answer 3

Although the wrapper class solution works, I think that's an overkill. It's too much code, and you have to manually manage the lifetime of the new object.
Perhaps a simpler solution would be to create methods in the interface that returns TMoveProc
ISomeInterface = interface
...
function GetPredMeth: TMoveProc;
function GetNextMeth: TMoveProc;
...
end;
The class that implements the interface can provide the procedure of object and it will be accessible through the interface.
TImplementation = class(TInterfaceObject, ISomeInterface)
procedure Pred;
procedure Next;
function GetPredMeth: TMoveProc;
function GetNextMeth: TMoveProc;
end;
...
function TImplementation.GetPredMeth: TMoveProc;
begin
Result := Self.Pred;
end;
function TImplementation.GetNextMeth: TMoveProc;
begin
Result := Self.Next;
end;

Answer 4

How about this:
type
TMoveProc = procedure(const SomeIntf: ISomeInterface);
TSomeObject = class
public
procedure Move(const SomeIntf: ISomeInterface; MoveProc: TMoveProc);
end;
procedure TSomeObject.Move(const SomeIntf: ISomeInterface; MoveProc: TMoveProc);
begin
MoveProc(SomeIntf);
end;
procedure MoveProcNext(const SomeIntf: ISomeInterface);
begin
SomeIntf.Next;
end;
procedure MoveProcPred(const SomeIntf: ISomeInterface);
begin
SomeIntf.Pred;
end;
procedure Usage;
var
SomeObj: TSomeObject;
SomeIntf: ISomeInterface;
begin
SomeIntf := GetSomeInterface;
SomeObj := TSomeObject.Create;
try
SomeObj.Move(SomeIntf, MoveProcNext);
SomeObj.Move(SomeIntf, MoveProcPred);
finally
SomeObj.Free;
end;
end;

Answer 5

Here is another solution that is working in Delphi 20006. It is similar to the idea of #Rafael, but using interfaces:
interface
type
ISomeInterface = interface
//...
end;
IMoveProc = interface
procedure Move;
end;
IMoveProcPred = interface(IMoveProc)
['{4A9A14DD-ED01-4903-B625-67C36692E158}']
end;
IMoveProcNext = interface(IMoveProc)
['{D9FDDFF9-E74E-4F33-9CB7-401C51E7FF1F}']
end;
TSomeObject = class(TObject)
public
procedure Move(MoveProc: IMoveProc);
end;
TImplementation = class(TInterfacedObject,
ISomeInterface, IMoveProcNext, IMoveProcPred)
procedure IMoveProcNext.Move = Next;
procedure IMoveProcPred.Move = Pred;
procedure Pred;
procedure Next;
end;
implementation
procedure TSomeObject.Move(MoveProc: IMoveProc);
begin
while True do
begin
// Some common code that works for both procedures
MoveProc.Move;
// More code...
end;
end;
procedure Usage;
var
o: TSomeObject;
i: ISomeInterface;
begin
o := TSomeObject.Create;
i := TImplementation.Create;
o.Move(i as IMoveProcPred);
// somewhere else: o.Move(i as IMoveProcNext);
o.Free;
end;

Answer 6

You can't. Because of the scoping of Interfaces it would be possible (perhaps?) for the Interface to be released before you called the .Next function. If you want to do this you should pass the whole interface to your method rather than just a method.
Edited...
Sorry, this next bit, specifically the "Of Interface" bit was meant in jest.
Also, and I could be wrong here, i.Next is not a method Of Object, as per your type def, it would be a method Of Interface!
Redefine your function
TSomeObject = class(TObject)
public
procedure Move(Const AMoveIntf: ISomeInterface);
end;
Procedure TSomeObject.Move(Const AMoveIntf : ISomeInterface);
Begin
....;
AMoveIntf.Next;
end;
O.Move(I);
Hope this helps.

Answer 7

You currently have TMoveProc defined as
TMoveProc = procedure of object;
Try taking out the "of object" which implies a hidden "this" pointer as first parameter.
TMoveProc = procedure;
That should allow a normal procedure to be called.