I'm trying to get typeorm to generate a select query with group by clause, in which the parameters of the group by clause references the column in the select clause using its numeric order number:
SELECT SUBSTRING(A, 1, LENGTH(A)), some_expression(B), DISTINCT C
FROM table
GROUP BY 1, 2
Instead of
SELECT SUBSTRING(A, 1, LENGTH(A)), some_expression(B), DISTINCT C
FROM table
GROUP BY SUBSTRING(A, 1, LENGTH(A)), some_expression(B)
Is there an elegant way to do this? I'm using the QueryBuilder API to generate a sql query which is then used for some other purpose.
Related
I got a table in this format
Name Datum
A 01.01.2019
B 17.03.2020
C 18.03.2020
C 01.04.2020
I get this table output from this query:
=QUERY(Anrufe!$1:$1000;"Select A,B where A is not null ORDER BY B ASC label A 'Name', B 'Datum'")
I am trying to change the query, so that it performs a group by. This is what it should look like
Name Datum count
A 01.01.2019 1
B 17.03.2020 1
C 01.04.2020 2
But when i add a group by and add a aggregation function to the select it still throws an error.
=QUERY(Anrufe!$1:$1000;"Select A,B, min(B) where A is not null group by A ORDER BY B ASC label A 'Name', B 'Datum'")
I want the query to choose the youngest Date, that is in the column B. But it seems that the QUERY-Parser forces me to add the column B to the group by. This results in the same problem, that i manually have to count the records with the same names.
Anyone has any idea how to solve that?
Already checked those links:
Google sheets query order by SUM
Google Sheets Query: Possible to Group / Order by without Select?
Google Sheets query - Multiple “where” conditions with “group by” and “order by”
I got this message (CANNOT_GROUP_WITHOUT_AGG) from a simple query
I think you want this:
=QUERY(Anrufe!$1:$1000,"Select A,min(B),count(A) where A is not null group by A ORDER BY min(B) ASC label A 'Name', min(B) 'Datum'")
When I run a distinct query on the influxdb, I get all results within one row. I need them all on different rows.
I've tried to select other fields however with distinct you can only select one field to query.
SELECT distinct("value_name") FROM "value_data"
name: value_data
time distinct
0 [TT_2028 TT_2090 TT_2216 TT_2217 TT_2237 TT_2238 TT_2239 TT_2240 TT_2241 TT_2243 TT_2248 TT_2249 TT_2250 TT_2251 TT_2252 TT_2253 james_test master testing_nightly_build test2]
I need the distinct values in new rows, not all on one row.
The docs show a distinct query with serrated rows
https://docs.influxdata.com/influxdb/v1.7/query_language/functions/#distinct
I think that you search for group by instead of distinct on string field.
Try something like this:
SELECT data1 FROM "value_data" GROUPBY value_name
I am writing a hive query to join two tables; table1 and table2. In the result I just need all columns from table1 and no columns from table2.
I know the solution where I can select all the columns manually by specifying table1.column1, table1.column2.. and so on in the select statement. But I have about 22 columns in table 1. Also, I have to do the same for multiple other tables ans its painful process.
I tried using "SELECT table1.*", but I get a parse exception.
Is there a better way to do it?
Hive 0.13 onwards the following query syntax works:
SELECT a.* FROM a JOIN b ON (a.id = b.id)
This query will select all columns from a. So instead of typing all the column names (making the query cumbersome), it is a better idea to use tablealias.*
The following code gets all the residences which have all the amenities which are listed in id_list. It works with out a problem with SQLite but raises an error with PostgreSQL:
id_list = [48, 49]
Residence.joins(:listed_amenities).
where(listed_amenities: {amenity_id: id_list}).
references(:listed_amenities).
group(:residence_id).
having("count(*) = ?", id_list.size)
The error on the PostgreSQL version:
What do I have to change to make it work with PostgreSQL?
A few things:
references should only be used with includes; it tells ActiveRecord to perform a join, so it's redundant when using an explicit joins.
You need to fully qualify the argument to group, i.e. group('residences.id').
For example,
id_list = [48, 49]
Residence.joins(:listed_amenities).
where(listed_amenities: { amenity_id: id_list }).
group('residences.id').
having('COUNT(*) = ?", id_list.size)
The query the Ruby (?) code is expanded to is selecting all fields from the residences table:
SELECT "residences".*
FROM "residences"
INNER JOIN "listed_amenities"
ON "listed_amentities"."residence_id" = "residences"."id"
WHERE "listed_amenities"."amenity_id" IN (48,49)
GROUP BY "residence_id"
HAVING count(*) = 2
ORDER BY "residences"."id" ASC
LIMIT 1;
From the Postgres manual, When GROUP BY is present, it is not valid for the SELECT list expressions to refer to ungrouped columns except within aggregate functions or if the ungrouped column is functionally dependent on the grouped columns, since there would otherwise be more than one possible value to return for an ungrouped column.
You'll need to either group by all fields that aggregate functions aren't applied to, or do this differently. From the query, it looks like you only need to scan the amentities table to get the residence ID you're looking for:
SELECT "residence_id"
FROM "listed_amenities"
WHERE "listed_amenities"."amenity_id" IN (48,49)
GROUP BY "residence_id"
HAVING count(*) = 2
ORDER BY "residences"."id" ASC
LIMIT 1
And then fetch your residence data with that ID. Or, in one query:
SELECT "residences".*
FROM "residences"
WHERE "id" IN (SELECT "residence_id"
FROM "listed_amenities"
WHERE "listed_amenities"."amenity_id" IN (48,49)
GROUP BY "residence_id"
HAVING count(*) = 2
ORDER BY "residences"."id" ASC
LIMIT 1
);
I am trying a sqlite select query statement as below:
SELECT IndicatorText
FROM Table
where IndicatorID in('13','25','64','52','13','25','328')
AND RubricID in('1','1','1','1','1','1','6')
This gives an output but the duplicate values are not displayed. I want to display all the values of IndicatorText even though it is duplicate.
Please help me with this query.
The two IN conditions are evaluated individually.
To check both values at once, you could concatenate them so that you have a single string to compare:
SELECT IndicatorText
FROM MyTable
WHERE IndicatorID || ',' || RubricID IN (
'13,1', '25,1', '64,1', '52,1', '13,1', '25,1', '328,6')
However, doing this operation on the column values prevents the query optimizer from using indexes, so this query will be slow if the table is big.
To allow optimizations, create a temporary table with the desired values, and join that with the original table:
SELECT IndicatorText
FROM MyTable
NATURAL JOIN (SELECT 13 AS IndicatorID, 1 AS RubricID UNION ALL
SELECT 25, 1 UNION ALL
SELECT 64, 1 UNION ALL
SELECT 52, 1 UNION ALL
SELECT 13, 1 UNION ALL
SELECT 25, 1 UNION ALL
SELECT 328, 6)