I am trying a sqlite select query statement as below:
SELECT IndicatorText
FROM Table
where IndicatorID in('13','25','64','52','13','25','328')
AND RubricID in('1','1','1','1','1','1','6')
This gives an output but the duplicate values are not displayed. I want to display all the values of IndicatorText even though it is duplicate.
Please help me with this query.
The two IN conditions are evaluated individually.
To check both values at once, you could concatenate them so that you have a single string to compare:
SELECT IndicatorText
FROM MyTable
WHERE IndicatorID || ',' || RubricID IN (
'13,1', '25,1', '64,1', '52,1', '13,1', '25,1', '328,6')
However, doing this operation on the column values prevents the query optimizer from using indexes, so this query will be slow if the table is big.
To allow optimizations, create a temporary table with the desired values, and join that with the original table:
SELECT IndicatorText
FROM MyTable
NATURAL JOIN (SELECT 13 AS IndicatorID, 1 AS RubricID UNION ALL
SELECT 25, 1 UNION ALL
SELECT 64, 1 UNION ALL
SELECT 52, 1 UNION ALL
SELECT 13, 1 UNION ALL
SELECT 25, 1 UNION ALL
SELECT 328, 6)
Related
I'm trying to get typeorm to generate a select query with group by clause, in which the parameters of the group by clause references the column in the select clause using its numeric order number:
SELECT SUBSTRING(A, 1, LENGTH(A)), some_expression(B), DISTINCT C
FROM table
GROUP BY 1, 2
Instead of
SELECT SUBSTRING(A, 1, LENGTH(A)), some_expression(B), DISTINCT C
FROM table
GROUP BY SUBSTRING(A, 1, LENGTH(A)), some_expression(B)
Is there an elegant way to do this? I'm using the QueryBuilder API to generate a sql query which is then used for some other purpose.
I really been working to solve this problem for quite a while, I have 2 tables with the same structure as follows:
registerationNumber int, CompanyName nvarchar, areaName nvarchar,phoneNumber int , email nvarchar, projectStatus nvarchar
All columns with data type nvarchar contains Arabic text except the email column,
tableA contains 675 rows and tableB contains 397 rows all exists in tableA
What I am trying to do is select the non matching rows from tableA,
they should be 675 - 398 = 277 rows
everytime I run the where clause I get all tables returned
The join clause I am writing is like this:
select a.registerationNumber
from tableA a left outer join tableB b
on a.registerationNumber = b.registerationNumber
but I am not getting any results, I tried all types of joins but I am getting the same results.
I created a sample database and inserted English data in the tables and it worked fine with the following clause:
select * from tblAllProjects a right join tblhalfProjects h
on a.registerationNumber = h.registerationNumber
which means that I am writing the correct the correct syntax,
I know that I should use the following syntax on selecting Arabic text:
Select * from tableA where comanyName like N'arabic_text'
Anyone knows what seems to be the problem ?
I meant to say that you should do:
select a.registerationNumber
from tableA a left outer join tableB b
on a.registerationNumber = b.registerationNumber
where b.registrationNumber is NULL
This should select all registrationNumbers from tableA, with no match in tableB.
another way to write this (but probably slower) is:
select a.registerationNumber
from tableA a
where a.registerationNumber not in (
select b.registerationNumber
from tableB )
You should/can use this second approach if there are only "a few" records returned from the sub-query.
--A=100,B=50,C=200
DECLARE #T1 TABLE (CAT1 VARCHAR(1),CAT2 VARCHAR(1),MinVal int)
INSERT INTO #T1
SELECT 'A','A',100
UNION ALL
SELECT 'A','B',50
UNION ALL
SELECT 'A','C',100
UNION ALL
SELECT 'B','A',50
UNION ALL
SELECT 'B','B',50
UNION ALL
SELECT 'B','C',50
Union all
SELECT 'C','A',100
UNION ALL
SELECT 'C','B',100
UNION ALL
SELECT 'C','C',200
select * from #T1
I have to calculate sum of MinValue
which should include only (AB,AC,BC) as whatever min of AB=BA so need to take one only.
so in result i want to get 3 rows out of 9.
Cat1|Cat2|MinVal
A|B|50
A|C|100
B|C|50
Any help will be highly appreciated.
Earlier i tried the things below but it did not work.
Select * from #T1 where Cat1<>Cat2 and ?
(what condition i need to write to avoid undesired combination.)
Here's a link
The following code gets all the residences which have all the amenities which are listed in id_list. It works with out a problem with SQLite but raises an error with PostgreSQL:
id_list = [48, 49]
Residence.joins(:listed_amenities).
where(listed_amenities: {amenity_id: id_list}).
references(:listed_amenities).
group(:residence_id).
having("count(*) = ?", id_list.size)
The error on the PostgreSQL version:
What do I have to change to make it work with PostgreSQL?
A few things:
references should only be used with includes; it tells ActiveRecord to perform a join, so it's redundant when using an explicit joins.
You need to fully qualify the argument to group, i.e. group('residences.id').
For example,
id_list = [48, 49]
Residence.joins(:listed_amenities).
where(listed_amenities: { amenity_id: id_list }).
group('residences.id').
having('COUNT(*) = ?", id_list.size)
The query the Ruby (?) code is expanded to is selecting all fields from the residences table:
SELECT "residences".*
FROM "residences"
INNER JOIN "listed_amenities"
ON "listed_amentities"."residence_id" = "residences"."id"
WHERE "listed_amenities"."amenity_id" IN (48,49)
GROUP BY "residence_id"
HAVING count(*) = 2
ORDER BY "residences"."id" ASC
LIMIT 1;
From the Postgres manual, When GROUP BY is present, it is not valid for the SELECT list expressions to refer to ungrouped columns except within aggregate functions or if the ungrouped column is functionally dependent on the grouped columns, since there would otherwise be more than one possible value to return for an ungrouped column.
You'll need to either group by all fields that aggregate functions aren't applied to, or do this differently. From the query, it looks like you only need to scan the amentities table to get the residence ID you're looking for:
SELECT "residence_id"
FROM "listed_amenities"
WHERE "listed_amenities"."amenity_id" IN (48,49)
GROUP BY "residence_id"
HAVING count(*) = 2
ORDER BY "residences"."id" ASC
LIMIT 1
And then fetch your residence data with that ID. Or, in one query:
SELECT "residences".*
FROM "residences"
WHERE "id" IN (SELECT "residence_id"
FROM "listed_amenities"
WHERE "listed_amenities"."amenity_id" IN (48,49)
GROUP BY "residence_id"
HAVING count(*) = 2
ORDER BY "residences"."id" ASC
LIMIT 1
);
I have two tables "CAR" -it's fields are- (car_id,name), the second table "CARSFORSALE" contains cars for sale (id,car_id,....)
How i can get 10 rows from "CARSFORSALE" table for each car_id in one query
that mean if i have 7 car_id my result will be <=70
select 1,car_id
union all
select 2,car_id
union all
select 3,car_id
union all
select 4,car_id
union all
select 5,car_id
union all
select 6,car_id
union all
select 7,car_id
union all
select 8,car_id
union all
select 9,car_id
union all
select 10,car_id