My problem is when I use the character ', Thymeleaf converts it to '.
I need to show the apostophes instead.
My string is saved in SQL like this:
"body" : "L'' autorizzazione di EUR [[${ #numbers.formatDecimal(#strings.replace(amount,'','',''.''),1,''POINT'',2, ''COMMA'')}]] in [[${date}]] ore [[${time}]] c/o presso [[${merchant}]] è stata negata. [[${ #strings.replace(refuseMessage,'',/'/g)}]]"
I tried string.replace but it doesn't work. Can somebody help me please?
Are you creating HTML? Then ' is correct, and you don't need to replace it.
If you are not creating HTML, then you need to make sure your template resolver is set to an appropriate template mode, for example, TEXT:
templateResolver.setTemplateMode(TemplateMode.TEXT);
Related
code:
Strings.arb
"priceSign": "S$",
i18n.dart
String priceSign(String ) => "S$";//Expected an identifier error
How can i add localization for such a string in flutter.I can't able to create such a String in arb file and generate i18n.
ANyone help me resolve this issue.
You can define as below.
"price_sign" : "\$"
Its show red under line but you can ignore it and run application. It will work.
In your ARB files you don't need to escape $, but in your dart getter code you should.
Strings.arb:
"priceSign": "S$",
i18n.dart:
String priceSign(String ) => "S\$";
If you use intl_translation tool, it will map it properly between those two formats.
For example for a string like :
"https://www.example.com/myname:abcd"
I want only the part before ":"
i.e i want an output as below:
"https://www.example.com/myname"
What you want is to extract the namespace of the resource.
resource.getNamespace() will do the trick ;)
In SPARQL:
REPLACE("https://www.example.com/myname:abcd", ":[^:]*$", "")
In code, use a plain java string operation.
I've stored a string in the database. When I save and retrieve the string and the result I'm getting is as following:
This is my new object
Testing multiple lines
-- Test 1
-- Test 2
-- Test 3
That is what I get from a println command when I call the save and index methods.
But when I show it on screen. It's being shown like:
This is my object Testing multiple lines -- Test 1 -- Test 2 -- Test 3
Already tried to show it like the following:
${adviceInstance.advice?.encodeAsHTML()}
But still the same thing.
Do I need to replace \n to or something like that? Is there any easier way to show it properly?
Common problems have a variety of solutions
1> could be you that you replace \n with <br>
so either in your controller/service or if you like in gsp:
${adviceInstance.advice?.replace('\n','<br>')}
2> display the content in a read-only textarea
<g:textArea name="something" readonly="true">
${adviceInstance.advice}
</g:textArea>
3> Use the <pre> tag
<pre>
${adviceInstance.advice}
</pre>
4> Use css white-space http://www.w3schools.com/cssref/pr_text_white-space.asp:
<div class="space">
</div>
//css code:
.space {
white-space:pre
}
Also make a note if you have a strict configuration for the storage of such fields that when you submit it via a form, there are additional elements I didn't delve into what it actually was, it may have actually be the return carriages or \r, anyhow explained in comments below. About the good rule to set a setter that trims the element each time it is received. i.e.:
Class Advice {
String advice
static constraints = {
advice(nullable:false, minSize:1, maxSize:255)
}
/*
* In this scenario with a a maxSize value, ensure you
* set your own setter to trim any hidden \r
* that may be posted back as part of the form request
* by end user. Trust me I got to know the hard way.
*/
void setAdvice(String adv) {
advice=adv.trim()
}
}
${raw(adviceInstance.advice?.encodeAsHTML().replace("\n", "<br>"))}
This is how i solve the problem.
Firstly make sure the string contains \n to denote line break.
For example :
String test = "This is first line. \n This is second line";
Then in gsp page use:
${raw(test?.replace("\n", "<br>"))}
The output will be as:
This is first line.
This is second line.
Bonjour, Hello,
I'm making this delphi application that I use to create word documents. I'm done with basic word operations (create/save, text, tables..etc).
What I need to do is to insert Page Numbers of headings as Cross Reference in the text. Something like :
"... and the process works as explained on page 23..."
where page number is a hyperlink to a heading. When I recorded a Macros in word it looks like:
Selection.InsertCrossReference ReferenceType:="Heading", _
ReferenceKind:=wdPageNumber, ReferenceItem:="49", InsertAsHyperlink:=True _
, IncludePosition:=False, SeparateNumbers:=False, SeparatorString:=" "
What would be the equivalent in Delphi please?
Thanks in advance!
Arjun.
Even when you're using Late Binding you still need to provide all of the parameters in the same order as the original declaration.
expression.InsertCrossReference(ReferenceType, ReferenceKind, ReferenceItem,
InsertAsHyperlink, IncludePosition, SeparateNumbers, SeparatorString)
If you aren't using a parameter then you can replace it with EmptyParam.
So I think your code will be:
Selection.InsertCrossReference('Heading', 7, '49', True, False, False, ' ');
(I think that wdPageNumber's value is 7).
I'm writing a site with a custom tweet button that uses the www.twitter.com/share function, however the problem I am having is including hash '#' characters within the tweet text.
For example:
http://www.twitter.com/share?url=www.example.com&text=I+am+eating+#branstonpickel+right+now
The tweet text comes out as 'I am eating' and omits the hash and everything after.
I had a quick look on the Twitter forums and learnt the hash '#' character cannot be part of the share url. On https://dev.twitter.com/discussions/512#comment-877 it was said that:
Hashes are special characters in the URL (they identify document fragments) so they, and anything following, does not get sent the server.
and
you need to URLEncode it, so use %23
When I tried the 2nd point in my test link:
www.twitter.com/share?url=www.example.com&text=I+am+eating+%23branstonpickel+right+now
The tweet text came out as 'I am eating %23branstonpickel right now' literally including %23 instead of converting it to a hash.
Sorry for the waffely question, but does anyone know what it is I'm doing wrong?
Any feedback would be greatly appreciated :)
It looks like this is the basic setup:
https://twitter.com/intent/tweet?
url=<url to tweet>
text=<text to tweet>
hashtags=<comma separated list of hashtags, with no # on them>
This would pre-built a tweet of: <text> <url> <hashtags>
The above example would be:
https://twitter.com/intent/tweet?url=http://www.example.com&text=I+am+eating+branston+pickel+right+now&hashtags=bransonpickel,pickles
There used to be a bug with the hashtags parameter... it only showed the first n-1 hashtags. Currently this is fixed.
you can use %23 instead of hash (#) in url eg
http://www.twitter.com/share?url=www.example.com&text=I+am+eating+%23branston+%23pickel+right+now
I may be wrong but i think the hashtag has to be passed as a separate variable that will appear at the end of your tweet ie:
http://www.twitter.com/share?url=www.example.com&text=I+am+eating+branston+pickel+right+now&hashtag=bransonpickel
will result in "I am eating branston pickel right now #branstonpickle"
On a separate note, I think pickel should be pickle!
Cheers
Toby
use encodeURIComponent to encode the url
If you're using PHP, you can use the following:
<?php echo 'http://www.twitter.com/share?' . http_build_query(array(
'url' => 'http://www.example.com',
'text' => 'I am eating #branstonpickel right now'
)); ?>
This will do all the URL encoding for you, and it's easy to read.
For more information on the http_build_query, see the PHP manual:
http://us2.php.net/http_build_query
For url with line jump, # , # and special unicode in it, the following works :
var lineJump = encodeURI(String.fromCharCode(10)),
hash = "%23", arobase="%40",
tweetText = 'https://twitter.com/intent/tweet?text=Le signe chinois '+hans+' '+item.pinyin+': '+item.definition.replace(";",",")+'.'
+lineJump+'Merci '+arobase+'Inalco_Officiel '+arobase+'CRIparis ❤️🇨🇳 '
+lineJump+hash+'Chinois '+hash+'MOOC'
+lineJump+'https://hanzi.cri-paris.org/',
tweetTxtUrlEncoded = tweetText+ "" +encodeURIComponent('#'+lesson+encodeURIComponent(hans));
urlencode
https://twitter.com/intent/tweet?text=<?= urlencode("I am eating #branstonpickel right now"); ?>"
You can just use this code and modify it
20% means space
23% means hashtag
In JS you can easily encode the special characters using encoreURIComponent.
(Warning: don't use encodeURI as "#" and "#" are not escaped.)
Here's an example with mention and hashtag:
const text = "Hello #world ! Go follow #StackOverflow";
const tweetUrl = `https://twitter.com/intent/tweet?text=${ encodeURIComponent(text) }`;