I'm using ByteCountFormatter for converting Byte to Appropriate String,
func sizeFormate(size: Int) -> String {
let bcf = ByteCountFormatter()
bcf.allowedUnits = [.useMB,.useGB]
bcf.countStyle = .binary
return bcf.string(fromByteCount: Int64(size))
}
for example:
sizeFormate(size: 763917940) // output: 728.5 MB
// what I need is 728 MB // digit should not have fraction part
How can we achieve this formate?
ByteCountFormatter have one property named: isAdaptive and by Default it is true. To hide fraction part just make this false
Updated code:
func sizeFormate(size: Int) -> String {
let bcf = ByteCountFormatter()
bcf.allowedUnits = [.useMB,.useGB]
bcf.countStyle = .binary
bcf.isAdaptive = false // change
return bcf.string(fromByteCount: Int64(size))
}
Note: keep that in mind that it round of from 0.5 to 1
it still shows fraction digits..
any other way?
Related
Below code works fine on iOS devices and watchOS simulator.
static func getEventDateTime(startDateTime: Date?) -> String {
if let startDateTime = startDateTime {
let startTimeInMillis = Int(startDateTime.timeIntervalSince1970 * 1000)
let fiveMinutesInMillis = 300000
let eventStartDateTime = Date(timeIntervalSince1970: TimeInterval((startTimeInMillis-fiveMinutesInMillis)/1000))
return convertDateToString(eventStartDateTime)
}
return ""
}
However when I run it on Apple Watch Series 3, I get the following error: double value cannot be converted to int because the result would be greater than int.max on line let startTimeInMillis = Int(startDateTime.timeIntervalSince1970 * 1000).
So I changed
let startTimeInMillis = Int(startDateTime.timeIntervalSince1970 * 1000) to let startTimeInMillis = Int64(startDateTime.timeIntervalSince1970 * 1000)
and
let eventStartDateTime = Date(timeIntervalSince1970: TimeInterval((startTimeInMillis-fiveMinutesInMillis)/1000)) to let eventStartDateTime = Date(timeIntervalSince1970: TimeInterval((Int(startTimeInMillis)-fiveMinutesInMillis)/1000)).
Now I am getting following error: Not enough bits to represent the passed value on line let eventStartDateTime = Date(timeIntervalSince1970: TimeInterval((Int(startTimeInMillis)-fiveMinutesInMillis)/1000))
How do I change the function to make it work on Apple Watch Series 3 or watchOS 7?
Updated function code:
static func getEventDateTime(startDateTime: Date?) -> String {
if let startDateTime = startDateTime {
let startTimeInMillis = Int64(startDateTime.timeIntervalSince1970 * 1000)
let fiveMinutesInMillis = 300000
let eventStartDateTime = Date(timeIntervalSince1970: TimeInterval((Int(startTimeInMillis)-fiveMinutesInMillis)/1000))
return convertDateToString(eventStartDateTime)
}
return ""
}
Use the Calendar API to add/subtract time units (doesn't support milliseconds, but does support nanoseconds, which can be converted from): https://developer.apple.com/documentation/foundation/calendar.
func getEventDateTimeCal(startDateTime: Date?) -> String {
if let startDateTime = startDateTime,
let date = Calendar.current.date(byAdding: .minute, value: -5, to: startDateTime) {
return convertDateToString(date, startDateTime)
}
return ""
}
But also, if you don't need millisecond precision, subtract seconds from TimeInterval. Note that TimeInterval is typealias TimeInterval = Double and always represents seconds.
func getEventDateTime(startDateTime: Date?) -> String {
if let startDateTime = startDateTime {
let fiveMinutesInSeconds = 5.0 * 60
let eventStartDateTime = Date(timeIntervalSince1970: startDateTime.timeIntervalSince1970 - fiveMinutesInSeconds)
return convertDateToString(startDateTime, eventStartDateTime)
}
return ""
}
I have a variable fileData of Data type and I am struggling to find how to print the size of this.
In the past NSData you would print the length but unable to do that with this type.
How to print the size of a Data in Swift?
Use yourData.count and divide by 1024 * 1024. Using Alexanders excellent suggestion:
func stackOverflowAnswer() {
if let data = #imageLiteral(resourceName: "VanGogh.jpg").pngData() {
print("There were \(data.count) bytes")
let bcf = ByteCountFormatter()
bcf.allowedUnits = [.useMB] // optional: restricts the units to MB only
bcf.countStyle = .file
let string = bcf.string(fromByteCount: Int64(data.count))
print("formatted result: \(string)")
}
}
With the following results:
There were 28865563 bytes
formatted result: 28.9 MB
If your goal is to print the size to the use, use ByteCountFormatter
import Foundation
let byteCount = 512_000 // replace with data.count
let bcf = ByteCountFormatter()
bcf.allowedUnits = [.useMB] // optional: restricts the units to MB only
bcf.countStyle = .file
let string = bcf.string(fromByteCount: Int64(byteCount))
print(string)
You can use count of Data object and still you can use length for NSData
Swift 5.1
extension Int {
var byteSize: String {
return ByteCountFormatter().string(fromByteCount: Int64(self))
}
}
Usage:
let yourData = Data()
print(yourData.count.byteSize)
Following accepted answer I've created simple extension:
extension Data {
func sizeString(units: ByteCountFormatter.Units = [.useAll], countStyle: ByteCountFormatter.CountStyle = .file) -> String {
let bcf = ByteCountFormatter()
bcf.allowedUnits = units
bcf.countStyle = .file
return bcf.string(fromByteCount: Int64(count))
}}
Enter your file URL in the following code to get file size in MB, I hope this helps you.
let data = NSData(contentsOf: FILE URL)!
let fileSize = Double(data.count / 1048576) //Convert in to MB
print("File size in MB: ", fileSize)
A quick extension for getting Data size in megabytes as Double.
extension Data {
func getSizeInMB() -> Double {
let bcf = ByteCountFormatter()
bcf.allowedUnits = [.useMB]
bcf.countStyle = .file
let string = bcf.string(fromByteCount: Int64(self.count)).replacingOccurrences(of: ",", with: ".")
if let double = Double(string.replacingOccurrences(of: " MB", with: "")) {
return double
}
return 0.0
}
}
If you want to just see number of bytes, printing the data object directly can give that to you.
let dataObject = Data()
print("Size is \(dataObject)")
Should give you:
Size is 0 bytes
In other words, .count won't be necessary in newer Swift 3.2 or higher.
To get the size of a string, adapted from #mozahler's answer
if let data = "some string".data(using: .utf8)! {
print("There were \(data.count) bytes")
let bcf = ByteCountFormatter()
bcf.allowedUnits = [.useKB] // optional: restricts the units to MB only
bcf.countStyle = .file
let string = bcf.string(fromByteCount: Int64(data.count))
print("formatted result: \(string)")
}
func sizeInMB(data: Data) -> String {
let bytes = Double(data.count)
let megabytes = bytes / (1024 * 1024)
return String(format: "%.2f MB", megabytes)
}
The following takes in a Data object as an argument and calculates the size of that Data in megabytes. The size is then returned as a String with a maximum of 2 decimal places.
count should suit your needs. You'll need to convert bytes to megabytes (Double(data.count) / pow(1024, 2))
I have a double:
let value = 0.99720317490866084
And a Double extention function:
extension Double {
func stringWithFixedFractionDigits(min: Int, max: Int) -> String {
let formatter = NumberFormatter()
formatter.minimumFractionDigits = min
formatter.maximumFractionDigits = max
formatter.minimumIntegerDigits = 1
let numberObject = NSNumber(value: self)
return formatter.string(from: numberObject) ?? "\(self)"
}
}
If I use:
value.stringWithFixedFractionDigits(min: 2, max: 2)
I get 1.00 but I would like to get 0.99
What can I change?
You just need to set your NumberFormatter rounding mode property to .down:
formatter.roundingMode = .down
Note that you don't need to create a new NSNumber object, you can safely cast from Double to NSNumber or use string(for: Any) method instead. As an alternative you can extend the protocol FloatingPoint to make it available to all Float types :
extension Formatter {
static let number = NumberFormatter()
}
extension FloatingPoint {
func formattedWithFractionDigits(minimum: Int = 2, maximum: Int = 2, minimumIntegerDigits: Int = 1, roundingMode: NumberFormatter.RoundingMode = .halfEven) -> String {
Formatter.number.roundingMode = roundingMode
Formatter.number.minimumFractionDigits = minimum
Formatter.number.maximumFractionDigits = maximum
Formatter.number.minimumIntegerDigits = minimumIntegerDigits
return Formatter.number.string(for: self) ?? ""
}
}
0.9972031749.formattedWithFractionDigits() // 1.00
0.9972031749.formattedWithFractionDigits(roundingMode: .down) // "0.99"
0.9972031749.formattedWithFractionDigits(minimumIntegerDigits: 0, roundingMode: .down) // ".99"
I am using
UIImagePickerControllerDelegate,
UINavigationControllerDelegate,
UIPopoverControllerDelegate
these delegates for choosing image from my gallery or my camera. So, how can I get image file size after choosing an image?
I want to use this:
let filePath = "your path here"
var fileSize : UInt64 = 0
do {
let attr : NSDictionary? = try NSFileManager.defaultManager().attributesOfItemAtPath(filePath)
if let _attr = attr {
fileSize = _attr.fileSize();
print(fileSize)
}
} catch {
}
but here I need a path, but how can I get without a path, just by image file?
Please check the google for 1 kb to bytes it will be 1000.
https://www.google.com/search?q=1+kb+%3D+how+many+bytes&oq=1+kb+%3D+how+many+bytes&aqs=chrome..69i57.8999j0j1&sourceid=chrome&ie=UTF-8
So while getting the proper size I’ve added multiple scenario by adding image in App Bundle and in photos in simulator.
Well the image which I took from my Mac was of 299.0 KB.
Scenario 1: Adding image to Application Bundle
On adding image in your Xcode the size of the image will remain same in project directory. But you get it from its path the size will be reduced to 257.0 KB. Which is the actual size of the image used in the device or simulator.
guard let aStrUrl = Bundle.main.path(forResource: "1", ofType: "png") else { return }
let aUrl = URL(fileURLWithPath: aStrUrl)
print("Img size = \((Double(aUrl.fileSize) / 1000.00).rounded()) KB")
extension URL {
var attributes: [FileAttributeKey : Any]? {
do {
return try FileManager.default.attributesOfItem(atPath: path)
} catch let error as NSError {
print("FileAttribute error: \(error)")
}
return nil
}
var fileSize: UInt64 {
return attributes?[.size] as? UInt64 ?? UInt64(0)
}
var fileSizeString: String {
return ByteCountFormatter.string(fromByteCount: Int64(fileSize), countStyle: .file)
}
var creationDate: Date? {
return attributes?[.creationDate] as? Date
}
}
Scenario 2: Adding image to Photos in Simulator
On adding image to photos in simulator or device the size of the image increased from 299.0 KB to 393.0 KB. Which is the actual size of the image stored in the device or simulator’s document directory.
Swift 4 and earlier
var image = info[UIImagePickerControllerOriginalImage] as! UIImage
var imgData: NSData = NSData(data: UIImageJPEGRepresentation((image), 1))
// var imgData: NSData = UIImagePNGRepresentation(image)
// you can also replace UIImageJPEGRepresentation with UIImagePNGRepresentation.
var imageSize: Int = imgData.count
print("size of image in KB: %f ", Double(imageSize) / 1000.0)
Swift 5
let image = info[UIImagePickerController.InfoKey.originalImage] as! UIImage
let imgData = NSData(data: image.jpegData(compressionQuality: 1)!)
var imageSize: Int = imgData.count
print("actual size of image in KB: %f ", Double(imageSize) / 1000.0)
By adding .rounded() it will give you 393.0 KB and without using it it will give 393.442 KB. So please check the image size manually once using the above code. As the size of image may vary in different devices and mac. I've check it only on mac mini and simulator iPhone XS.
extension UIImage {
public enum DataUnits: String {
case byte, kilobyte, megabyte, gigabyte
}
func getSizeIn(_ type: DataUnits)-> String {
guard let data = self.pngData() else {
return ""
}
var size: Double = 0.0
switch type {
case .byte:
size = Double(data.count)
case .kilobyte:
size = Double(data.count) / 1024
case .megabyte:
size = Double(data.count) / 1024 / 1024
case .gigabyte:
size = Double(data.count) / 1024 / 1024 / 1024
}
return String(format: "%.2f", size)
}
}
Usage example : print("Image size \(yourImage.getSizeIn(.megabyte)) mb")
Swift 3/4:
if let imageData = UIImagePNGRepresentation(image) {
let bytes = imageData.count
let kB = Double(bytes) / 1000.0 // Note the difference
let KB = Double(bytes) / 1024.0 // Note the difference
}
Please note the difference between kB and KB. Answering here because in my case we had an issue while we considered kilobyte as 1024 bytes but server side considered it as 1000 bytes which caused an issue. Link to learn more.
PS. Almost sure you'll go with kB (1000).
Details
Xcode 10.2.1 (10E1001), Swift 5
Solution
extension String {
func getNumbers() -> [NSNumber] {
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
let charset = CharacterSet.init(charactersIn: " ,.")
return matches(for: "[+-]?([0-9]+([., ][0-9]*)*|[.][0-9]+)").compactMap { string in
return formatter.number(from: string.trimmingCharacters(in: charset))
}
}
// https://stackoverflow.com/a/54900097/4488252
func matches(for regex: String) -> [String] {
guard let regex = try? NSRegularExpression(pattern: regex, options: [.caseInsensitive]) else { return [] }
let matches = regex.matches(in: self, options: [], range: NSMakeRange(0, self.count))
return matches.compactMap { match in
guard let range = Range(match.range, in: self) else { return nil }
return String(self[range])
}
}
}
extension UIImage {
func getFileSizeInfo(allowedUnits: ByteCountFormatter.Units = .useMB,
countStyle: ByteCountFormatter.CountStyle = .file) -> String? {
// https://developer.apple.com/documentation/foundation/bytecountformatter
let formatter = ByteCountFormatter()
formatter.allowedUnits = allowedUnits
formatter.countStyle = countStyle
return getSizeInfo(formatter: formatter)
}
func getFileSize(allowedUnits: ByteCountFormatter.Units = .useMB,
countStyle: ByteCountFormatter.CountStyle = .memory) -> Double? {
guard let num = getFileSizeInfo(allowedUnits: allowedUnits, countStyle: countStyle)?.getNumbers().first else { return nil }
return Double(truncating: num)
}
func getSizeInfo(formatter: ByteCountFormatter, compressionQuality: CGFloat = 1.0) -> String? {
guard let imageData = jpegData(compressionQuality: compressionQuality) else { return nil }
return formatter.string(fromByteCount: Int64(imageData.count))
}
}
Usage
guard let image = UIImage(named: "img") else { return }
if let imageSizeInfo = image.getFileSizeInfo() {
print("\(imageSizeInfo), \(type(of: imageSizeInfo))") // 51.9 MB, String
}
if let imageSizeInfo = image.getFileSizeInfo(allowedUnits: .useBytes, countStyle: .file) {
print("\(imageSizeInfo), \(type(of: imageSizeInfo))") // 54,411,697 bytes, String
}
if let imageSizeInfo = image.getFileSizeInfo(allowedUnits: .useKB, countStyle: .decimal) {
print("\(imageSizeInfo), \(type(of: imageSizeInfo))") // 54,412 KB, String
}
if let size = image.getFileSize() {
print("\(size), \(type(of: size))") // 51.9, Double
}
Swift 3
let uploadData = UIImagePNGRepresentation(image)
let array = [UInt8](uploadData)
print("Image size in bytes:\(array.count)")
try this for getting size from url
func fileSize(url: URL) -> String? {
var fileSize:Int?
do {
let resources = try url.resourceValues(forKeys:[.fileSizeKey])
fileSize = resources.fileSize!
print ("\(String(describing: fileSize))")
} catch {
print("Error: \(error)")
}
// bytes
if fileSize! < 999 {
return String(format: "%lu bytes", CUnsignedLong(bitPattern: fileSize!))
}
// KB
var floatSize = Float(fileSize! / 1000)
if floatSize < 999 {
return String(format: "%.1f KB", floatSize)
}
// MB
floatSize = floatSize / 1000
if floatSize < 999 {
return String(format: "%.1f MB", floatSize)
}
// GB
floatSize = floatSize / 1000
return String(format: "%.1f GB", floatSize)
}
Use Example
let sizeInString = fileSize(url: url)
print("FileSize = "+sizeInString!)
let selectedImage = info[UIImagePickerControllerOriginalImage] as! UIImage
let selectedImageData: NSData = NSData(data:UIImageJPEGRepresentation((selectedImage), 1))
let selectedImageSize:Int = selectedImageData.length
print("Image Size: %f KB", selectedImageSize /1024.0)
let data = UIImageJPEGRepresentation(image, 1)
let imageSize = data?.count
Duplicate of How to get the size of a UIImage in KB?
let imageData = UIImageJPEGRepresentation(image, 1)
let imageSize = imageData?.count
UIImageJPEGRepresentation — returns the Data object for the specified image in JPEG format. The value 1.0 represents the least compression (close to original image).
imageData?.count — return data length (chars count equals bytes).
Important! UIImageJPEGRepresentation or UIImagePNGRepresentation will not return the original image. But if use given Data as source for uploading - than file size be the same as on the server (even using compression).
Swift 4.2
let jpegData = image.jpegData(compressionQuality: 1.0)
let jpegSize: Int = jpegData?.count ?? 0
print("size of jpeg image in KB: %f ", Double(jpegSize) / 1024.0)
Try this code (Swift 4.2)
extension URL {
var attributes: [FileAttributeKey : Any]? {
do {
return try FileManager.default.attributesOfItem(atPath: path)
} catch let error as NSError {
print("FileAttribute error: \(error)")
}
return nil
}
var fileSize: UInt64 {
return attributes?[.size] as? UInt64 ?? UInt64(0)
}
var fileSizeString: String {
return ByteCountFormatter.string(fromByteCount: Int64(fileSize), countStyle: .file)
}
var creationDate: Date? {
return attributes?[.creationDate] as? Date
}
}
And use example
guard let aStrUrl = Bundle.main.path(forResource: "example_image", ofType: "jpg") else { return }
let aUrl = URL(fileURLWithPath: aStrUrl)
print("Img size = \((Double(aUrl.fileSize) / 1000.00).rounded()) KB")
//Swift 4
if let pickedImage = info[UIImagePickerControllerOriginalImage] as? UIImage {
///check image Size
let imgData = NSData(data: UIImageJPEGRepresentation((pickedImage), 1)!)
let imageSize: Int = imgData.count
print("size of image in KB: %f ", Double(imageSize) / 1024.0)
print("size of image in MB: %f ", Double(imageSize) / 1024.0 / 1024)
}
I make work around data units conversion :
Bytes -> KB -> MB -> GB -> ... -> Extremest Monster Data
enum dataUnits:CaseIterable {
case B //Byte
case KB //kilobyte
case MB //megabyte
case GB //gigabyte
case TB //terabyte
case PB //petabyte
case EB //exabyte
case ZB //zettabyte
case YB //yottabyte
case BD //Big Data
case BBx // Extra Big Bytes
case BBxx // 2 time Extra Big Bytes
case BBxxx // 3 time Extra Big Bytes
case BBxxxx // 4 time Extra Big Bytes
case MBB // Monster Big Bytes
}
func convertStorageUnit(data n:Double,inputDataUnit unitLevel:Int,roundPoint:Int = 2,nG:Double = 1000.0)->String{
if(n>=nG){
return convertStorageUnit(data:n/1024,inputDataUnit:unitLevel+1)
}else{
let ut = unitLevel > dataUnits.allCases.count + 1 ? "Extreme Monster Data" : dataUnits.allCases.map{"\($0)"}[unitLevel]
return "\(String(format:"%.\(roundPoint)f",n)) \(ut)"
}
}
print(
convertStorageUnit(data:99922323343439789798789898989897987945454545920,
inputDataUnit:dataUnits.allCases.firstIndex(of: .B)!,roundPoint: 0)
)
output : 8.87 PB
Note: Input data length should be less than 64-bit OR Change data type According
Try this
import Darwin
...
let size = malloc_size(&_attr)
What is the function that removes trailing zeros from doubles?
var double = 3.0
var double2 = 3.10
println(func(double)) // 3
println(func(double2)) // 3.1
You can do it this way but it will return a string:
var double = 3.0
var double2 = 3.10
func forTrailingZero(temp: Double) -> String {
var tempVar = String(format: "%g", temp)
return tempVar
}
forTrailingZero(double) //3
forTrailingZero(double2) //3.1
In Swift 4 you can do it like that:
extension Double {
func removeZerosFromEnd() -> String {
let formatter = NumberFormatter()
let number = NSNumber(value: self)
formatter.minimumFractionDigits = 0
formatter.maximumFractionDigits = 16 //maximum digits in Double after dot (maximum precision)
return String(formatter.string(from: number) ?? "")
}
}
example of use: print (Double("128834.567891000").removeZerosFromEnd())
result: 128834.567891
You can also count how many decimal digits has your string:
import Foundation
extension Double {
func removeZerosFromEnd() -> String {
let formatter = NumberFormatter()
let number = NSNumber(value: self)
formatter.minimumFractionDigits = 0
formatter.maximumFractionDigits = (self.components(separatedBy: ".").last)!.count
return String(formatter.string(from: number) ?? "")
}
}
Removing trailing zeros in output
This scenario is good when the default output precision is desired. We test the value for potential trailing zeros, and we use a different output format depending on it.
extension Double {
var stringWithoutZeroFraction: String {
return truncatingRemainder(dividingBy: 1) == 0 ? String(format: "%.0f", self) : String(self)
}
}
(works also with extension Float, but not Float80)
Output:
1.0 → "1"
0.1 → "0.1"
0.01 → "0.01"
0.001 → "0.001"
0.0001 → "0.0001"
Formatting with maximum fraction digits, without trailing zeros
This scenario is good when a custom output precision is desired.
This solution seems roughly as fast as NumberFormatter + NSNumber solution from MirekE, but one benefit could be that we're avoiding NSObject here.
extension Double {
func string(maximumFractionDigits: Int = 2) -> String {
let s = String(format: "%.\(maximumFractionDigits)f", self)
for i in stride(from: 0, to: -maximumFractionDigits, by: -1) {
if s[s.index(s.endIndex, offsetBy: i - 1)] != "0" {
return String(s[..<s.index(s.endIndex, offsetBy: i)])
}
}
return String(s[..<s.index(s.endIndex, offsetBy: -maximumFractionDigits - 1)])
}
}
(works also with extension Float, but not Float80)
Output for maximumFractionDigits: 2:
1.0 → "1"
0.12 → "0.12"
0.012 → "0.01"
0.0012 → "0"
0.00012 → "0"
Note that it performs a rounding (same as MirekE solution):
0.9950000 → "0.99"
0.9950001 → "1"
In case you're looking how to remove trailing zeros from a string:
string.replacingOccurrences(of: "^([\d,]+)$|^([\d,]+)\.0*$|^([\d,]+\.[0-9]*?)0*$", with: "$1$2$3", options: .regularExpression)
This will transform strings like "0.123000000" into "0.123"
All the answers i found was good but all of them had some problems like producing decimal numbers without the 0 in the beginning ( like .123 instead of 0.123). but these two will do the job with no problem :
extension Double {
func formatNumberWithFixedFraction(maximumFraction: Int = 8) -> String {
let stringFloatNumber = String(format: "%.\(maximumFraction)f", self)
return stringFloatNumber
}
func formatNumber(maximumFraction: Int = 8) -> String {
let formatter = NumberFormatter()
let number = NSNumber(value: self)
formatter.minimumFractionDigits = 0
formatter.maximumFractionDigits = maximumFraction
formatter.numberStyle = .decimal
formatter.allowsFloats = true
let formattedNumber = formatter.string(from: number).unwrap
return formattedNumber
}
}
The first one converts 71238.12 with maxFraction of 8 to: 71238.12000000
but the second one with maxFraction of 8 converts it to: 71238.12
This one works for me, returning it as a String for a text label
func ridZero(result: Double) -> String {
let value = String(format: "%g", result)
return value
}
Following results
ridZero(result: 3.0) // "3"
ridZero(result: 3.5) // "3.5"