How to sum only the last row of a transposed query? - google-sheets

I am using this formula but it is summing everything within the range and I would like to sum only line J5 for example, this query needs to run on a list so every row will run this and sum only the 1 one row the function is located on.
=sum(transpose(query(Transpose($E$2:J5), " where Col1='A' ",1)))
You can see an example here:
https://docs.google.com/spreadsheets/d/1ynIiMrR3RHtpeY86Nc7QKcBNQ_A-fxdm6R1kefek-bI/edit#gid=0
Thanks!

So you want to sum the values of a row but only when the header matches a value.
The approach with a transposed query could work if your initial table contains only the first row and the current row. You can build it with curly brackets {} like this:
=SUM(transpose(query(Transpose({E$2:J$2;E5:J5}), " where Col1='A' ",1)))
However, it would be easier to just do:
=SUMPRODUCT(IF(E$2:J$2="A",E5:J5,0))

Related

Display results from filter formula in one row?

I am using a filter formula to output multiple results based on a condition. Each result contains 4 columns of data, each result is in a new row. However, I would like all results to be output one after the other (i.e. in one row). The data of each result takes up 4 columns and in the fifth column, the new result starts with 4 columns.
This is how it looks now:
This is how it should look:
To get this dynamically, follow these steps.
1 - in the sheet where you want the results on cell A2 past this formula.
=TRANSPOSE(FLATTEN(QUERY(Data!A2:D," Select * where A is not null ")))
TRANSPOSE because FLATTEN formula outputs a column.
QUERY to remove blank rows.
FLATTEN to convert all values from one or more ranges into a single column.
2 - to make the header dynamic you need to paste this formula in resault sheet in cell A1.
=SPLIT(REPT(JOIN(";",Data!A1:D1)&";",COUNTA(Data!A2:A)),";")
JOIN the header with ; so you can split it with the SPLIT formula after repeating the header rang n time with the REPT formula, to handel how many times the header repeated just use COUNTA to count how many rows are there.
Input example:
Output example:
You first need to use Flatten() to make it a one dimensional array since the spreadsheet data is in a nested array no matter how many rows/columns you have.
Then from here you can just transpose the data so instead of the data going down the rows it will be transposed to go horizontally to the columns.
Try:
=TRANSPOSE(FLATTEN(A2:D))
To combine it with your formula just replace the Range "A2:D" with your current formula.
Result:
References:
Transpose
Flatten

Google Sheets Fill Down with Formula

I have a very hard problem to solve, which must be completed with a formula (not a script).
Basically, the Raw input column needs to be dynamically filled down until it hits the next piece of text.
Here's an example file with includes the expected output.
https://docs.google.com/spreadsheets/d/1ibqCvY39NlhCRWsbBdxKITUUpVpp9wXdEz44T-pHDY0/
Is it even possible to achieve?
Thanks
This will work based on your ask, assuming that A2 is never blank, place this in the first row of data (not header):
=ArrayFormula(IF(A2:A<>"", A2:A, B1:B))
It checks to see if there is a value in column A, if there is, it fills that column, if not, it copies the cell above.
Delete everything in Column B (including the header) and place the following formula in B1:
=ArrayFormula({"Header";VLOOKUP(FILTER(ROW(A2:A),ROW(A2:A)<=MAX(FILTER(ROW(A2:A),A2:A<>""))),FILTER({ROW(A2:A),A2:A},A2:A<>""),2,TRUE)})
Here is a basic explanation of how this formula works:
A virtual array is created between the curly brackets { }; this virtual array contains a header and all results. You can change the header name to whatever you like.
VLOOKUP looks up every row number that is less than or equal to the highest row number that contains text in A2:A. Each of these qualifying rows is looked up in a second array that contains only the row numbers and Column-A data from non-blank rows, returning the data itself. Since rows are in perfect ascending order and the last parameter of VLOOKUP is set to TRUE, all blank rows in the first array will "fall backward" to find the most recent row that did have something in Column A.

Techniques to accommodate new entries in google sheets

As you can see I transpose codes into unique column headings so that debits and credits are analysed and summated. Summations are transposed in another sheet to create summary profit/loss account. I need help how to replicate the sum formula in column I to serve any expanded transposed unique codes and whether/how I should use arrayformula for the individual cell output.
EDIT
Actual output looks like this:
My problem is to how to automatically accommodate new entries/codes in the totals row and main body of cells. The data belongs to a residents' committee so I can only show anonymous data as image.
EDIT 2
Actual input is imported from bank records, then coded:
Query is pretty good for the SUM part.
Starting in column I, you can do:
=ArrayFormula(INDEX(QUERY(
0+OFFSET(I4,0,0,ROWS(F6:F),COUNTA(UNIQUE(F4:F))),
"select "&
JOIN(
",",
"sum(Col"&SEQUENCE(COUNTA(UNIQUE(F4:F)))&")"
)
),2))
The 0+ or the VALUE in the second one (they both do the same thing here) transforms the data cells to default to 0 if blank, otherwise the query fails. This also lets us refer to the columns by sequence number, which is what we do in the second argument. We build the query into something that looks like select sum(Col1),sum(Col2),...,sum(ColN). Since this gives us a header by default, we could relabel everything in the query statement, but that gives too much extra code, so the easier thing to do is use INDEX to select the sums.
The EQ part is fairly straightforward to Arrayify. Starting in I4:
=ArrayFormula(
(FILTER(F4:F,F4:F<>"")=FILTER(I2:2,I2:2<>""))*
IF(
Array_constrain(G4:G,COUNTA(FILTER(F4:F,F4:F<>"")),1),
G4:G,
-H4:H
)
)
The FILTERs just filter out the blank cells, and the Array_Constrain sizes the G column to the same size as the filtered F column.

Arrayformula sum one column until this row

I'm trying to make an array formula which sums up all the rows until this row.
For clarification column a will be the input and column b would be the output. I'm looking for a way to do this with an arrayformula.
a1:1 b1:1a2:2 b2:3a3:5 b3:8a4:3 b4:11
I tried to use =ARRAYFORMULA(SUM(INDIRECT("F1:"&ADDRESS(ROW(),COLUMN(F2:F))))) but this doesn't work.
How about
=arrayformula(sumif(row(A1:A4),"<="&row(A1:A4),A1:A4))
The sumif is evaluated separately for each value in the criteria part so:
In the first row of the output array you have
=sumif(row(A1:A4),"<=1",A1:A4)
giving you just the first row of column A.
In the second row of the output array you have
=sumif(row(A1:A4),"<=2",A1:A4)
giving you the sum of the first 2 rows and so on.
Since OP changed the question with a clarification, A different answer is submitted below:
B1:
=ARRAYFORMULA(MMULT(transpose(A1:A5)*--IF(row(1:5),COLUMN(A:E)<=row(1:5)),ROW(1:5)^0))

How to use INDEX() inside ARRAYFORMULA()?

I am trying to use the INDEX() formula inside an ARRAYFORMULA(). As a simple (non-sense) example, with 4 elements in column A, I expected that the following array formula entered in B1 would display all four elements from A in column B:
=ARRAYFORMULA(INDEX($A$1:$A$4,ROW($A$1:$A$4)))
However, this only fills field B1 with a the value found in A1.
When I enter
=ARRAYFORMULA(ROW($A$1:$A$4))
in B1, then I do see all numbers 1 to 4 appear in column B. Why does my first array formula not expand similar like the second one does?
The INDEX function is one that does not support "iteration" over an array if an array is used as one of its arguments. There is no documentation of this that I know of; it simply is what it is. So the second argument will always default to the first element of the array, which is ROW(A1).
One clumsy workaround to achieve what you require relies on a second adjacent column existing next to the source data* (although it is unimportant what values are actually in that second column):
=ArrayFormula(HLOOKUP(IF(ROW($A$1:$A$4);$A$1);$A$1:$B$4;ROW($A$1:$A$4);0))
or indeed something like:
=ArrayFormula(HLOOKUP(IF({3;2;4;1};$A$1);$A$1:$B$4;{3;2;4;1};0))
edit 2015-06-09
* This is no longer a requirement in the newest version of Sheets; the second argument in the HLOOKUP can just be $A$1:$A$4.
Here is a tip for using vlookup with an array, so that even if the columns are moved later on the formula will still work correctly....
In general, configure the vlookup so that it's reading only 2 columns and returning the second. This can be done by inputting only the 2 columns required, rather than a range and column index.
Example:
Replace the following formula which would fail if columns are moved
=arrayformula( vlookup(C:C, booking!$A:$E ,5 ,false) )
with this formula which will continue to work even if columns are moved
=arrayformula( vlookup(C:C, {booking!$A:$A,booking!$E:$E} ,2 ,false) )
Note, you can also simulate the index function using vlookup.
Example:
Column R:R contains the row index numbers for looking up data in column booking!$A:$A
=arrayformula(vlookup(R:R ,arrayformula({row(booking!$A:$A), booking!$A:$A}),2 , false))
It's a nested array, so it can be helpful to test in stages, eg just the inner part for one example, eg return entry in row 10:
=vlookup(10 ,arrayformula({row(booking!$A:$A), booking!$A:$A}),2 , false)

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