In addition to the model itself, I want to pass the product id in the partial model. How to do this?
#Model.product.id
<partial name="_Score" model="#Model.rating"/>
//Create a class and add two properties example like below
` public class Your_Class_Name{
public int CaseId
{
get;set;
}
public string PatientName
{
get;set;
}
//and call your partial view like
#Html.Partial("PartialPatientHeaderDetails", new YourClassName
{
CaseId= #Model.CaseId,PatientName= #havePatientName })
//finally change your return mode in partial View
#model Your_Class_Name
#{
}
#Model.CaseId
#Model.PatientName
Related
I am new to MVC, in my View I have :
#{
MyObjectType myNameObject=getMyNameObject();
}
<p>
Name : #myNameObject.firstName
</p>
Trying to implement desing when line "Name : #myNameObject.firstName" comes from database through Model or ViewBag and still pick up value of #myNameObject.firstName. Is that possible?
Thank you
Your Controller action method should get the data and pass it to the View. Using a ViewModel is usually the way to go, but ViewBag also works for one-off data. Something like this:
// View model.
public class MyViewModel
{
public string Name {get; set;}
}
// Controller method.
public ActionResult MyPage()
{
MyViewModel model = serviceLayer.GetMyData();
return View(model);
}
// MyPage View.
#model MyViewModel
<p>Name: #Model.Name</p>
your Model:
public class MyNameObject
{
public MyNameObject()
{
//getvalues from database
//this.FirstName = yourObjectFromDatabase.FirstName;
}
public string FirstName { get; set; }
}
in your views that you want to show the first name:
#using WebApplication1.Models; //put it at the top of the view
#{ Html.RenderPartial("FirstName", new MyNameObject()); }
your view:
#model WebApplication1.Models.MyNameObject
#{
ViewBag.Title = "FirstName";
}
<h2>Name : #Model.FirstName</h2>
Alright so i want to pass data from the view back to Post Method in the controller.
The View :
#model IEnumerable< MvcMobile.Models.Trips>
<p>Time : #ViewBag.titi</p>
<p>ID :#ViewBag.iid </p>
<p>From : #ViewBag.From</p>
<p>To :#ViewBag.To </p>
Avaibliabe Trips :
#foreach (var item in Model)
{
if ( item.Time==ViewBag.titi)
{
<p>#item.TripID</p>
}
}
My HttpGet Method in the controller :
[HttpGet]
public ActionResult Book2(MvcMobile.Models.TicketsBooked tik)
{
ViewBag.titi = tik.Time;
ViewBag.iid = tik.TicketID;
ViewBag.from = tik.From;
ViewBag.To = tik.To;
var TripsList = db.Trips.ToList();
return View(TripsList);
}
In This case i cant use a dynamic object to pass variable since the model is IEnumerable
i want to pass one or two textBoxes back to the controller, how can i do that ?
an alternative question would be how can i do the same functionality in the view without making the model IEnumberable ?
and thanks alot.
You should read up on using view models. Basically it's best practice to only pass relevant data to the view. So instead on passing a model of IEnumerable you would have a view model with a property of IEnumerable plus the extra properties you want to post back to your controller.
So for example:
public class ViewModel
{
public IEnumerable<MvcMobile.Models.Trips> Trips { get; set; }
public string ExtraValue { get; set; }
}
and your view would be:
#foreach(var trip in Model.Trips)
{
<p>Do stuff</p>
}
#Html.TextBoxFor(m => m.ExtraValue)
Your post method would then accept a ViewModel.
[HttpPost]
public ActionResult Book2(ViewModel viewModel)
{
}
You can read up more on view models here or by searching Google / SO. There are many, many examples.
I am developing an application. I have created a view and a controller. The view has a button, on the click of which I am supposed to do database operations. I have put the database operations in the model, I am creating the object of model in the controller. On clicking the button the action is handled by a method in the controller, and the object of the model is created to get the records from the database. I would like to know if there is any way to display this data in the view.Is the approach correct or the view is supposed to interact with model directly to get the data.
Following is the code in controller that gets invoked on the button click
public ActionResult getRecord()
{
DataModel f_DM = new DataModel();
DataTable f_DT = f_DM.getRecord();
return View();
}
DataModel is the model class with simply a method "getRecord".
Any help will be highly appreciated.
I would like to add that i am using vs2010 and mvc4
Regards
you should write the logic of retrieving data in your controller. Store all your data in view model and pass it to the view.
for eg.
Model
namespace Mvc4App.Models
{
public class Product
{
public string Name { get; set; }
}
public class ProductViewModel
{
public Product Product { get; set; }
public string SalesPerson { get; set; }
}
}
Controller
public class ProductController : Controller
{
public ActionResult Info()
{
ProductViewModel ProductViewModel = new ProductViewModel
{
Product = new Product { Name = "Toy" },
SalesPerson = "Homer Simpson"
};
return View(ProductViewModel);
}
}
View
#model Mvc4App.Models.ProductViewModel
#{ ViewBag.Title = "Info"; }
<h2>Product: #Model.Product.Name</h2>
<p>Sold by: #Model.SalesPerson</p>
This is the best known practice to pass data from controller to the view.
you may use other techniques also like,
1. ViewData
2. ViewBag
3. TempData
4. View Model Object
5. Strongly-typed View Model Object
Yes, it's possible, but actually now very logical way to to this.
Lets follow your way. You have some View were you have a button, that will trigger this action.
For ex:
public ActionResult Index()
{
return View();
}
Inside view you can have a Ajax link, that will trigget your getRecord method:
<div id="GetDataDiv"></div>
<div>
#Ajax.ActionLink("Get Record", "getRecord", "ControllerName", null, new AjaxOptions() { HttpMethod = "GET", UpdateTargetId = "GetDataDiv" })
</div>
In the getRecord method you should have:
public ActionResult getRecord()
{
DataModel f_DM = new DataModel();
DataTable f_DT = f_DM.getRecord();
return PartialView(f_DT);
}
And in View it should be:
#model DataTable
#Model.PropertyOne #Model.PropertyTwo
It should works for you.
Actually same exaple here: http://www.dotnetpools.com/Article/ArticleDetiail/?articleId=151
My scenario is much complicated so i simplified it with the example below. The main problem is binding collection properties of a model, specifying the path of the property like Html.TextBox("List[0].Name") and not the Html.TextBoxFor(t => t.List[0].Name). So, for the current view i will only know some of the metadata of the model so i will have to construct it this way. Here is the scenario :
Model
public class ModelTest
{
public int Id {get;set;}
public List<Foo> Collection {get;set;}
}
public class Foo
{
public string Value1 {get;set;}
public string Value2 {get;set;}
}
Controller
public class TestController: Controller
{
[HttpGet]
public ActionResult Test()
{
var model = new ModelTest()
{
Id = 455,
Collection = new List<Foo>()
{
new Foo(){ Value1 = "sagasga", Value2 = "Beul"},
new Foo(){ Value1 = "dgdsgds", Value2 = "fhfhd" }
}
};
return View(model);
}
[HttpPost]
public ActionResult Test( ModelTest model)
{
//....
return View();
}
View:
#using (Html.BeginForm())
{
#Html.TextBox("Id")
#Html.TextBox("Collection[0].Value1")
#Html.TextBox("Collection[0].Value2")
<input type="submit" value="Add" />
}
For the code above i get empty textboxes for the collection values. However, when the page is submited i get the model built correct in the Post method.
Many thanks,
Alex
This is the way to name you input fields when you wanna post a collection to your controller. However, you have to specify the initial value yourself. Your code is currently just creating textbox with the name property set to Collection[0].Value1. You still need to specify the input this way,
#Html.TextBox("Collection[0].Value1", Model.Collection.FirstOrDefault().Value1)
#Html.TextBox("Collection[0].Value2", Model.Collection.FirstOrDefault().Value2)
I need to create a view that displays Order Header information and I need to add a patial view that displays a grid of Line Items. The partial view will be strongly typed from a viewmodel. I understand that I should use the html helper #Html.Partial("Path/view"). I have only used controllers up til now to open a view, populating the viewmodel before sending it to the view. Since the partial view is being called form the html helper, I would like to know is what would be the best way to populate the parital view with the model data.
Option 1: Inherit from parent page
By default, any partial view rendered by calling #Html.Partial("PartialViewName") will get the view model passed to the parent view.
So if you have:
View Model
namespace MyNamesapce
{
public OrderInfoViewModel
{
public string OrderTitle { get; set; }
public IEnumerable<OrderItem> OrderItems { get; set; }
}
}
OrderInfo.cshtml
#model MyNamespace.OrderInfoViewModel
<h1>#Model.OrderTitle</h1>
#Html.Partial("OrderLineItems")
The OrderLineItems page should get a MyNamespace.OrderViewModel passed to it... so your partial view should look like this:
OrderLineItems.cshtml
#model MyNamespace.OrderInfoViewModel
foreach (var orderItem in Model.OrderItems)
{
//Do stuff
}
Option 2: Specify model
You can use the second parameter to specify the view model to be passed. I.e.
OrderInfo.cshtml
#model MyNamespace.OrderInfoViewModel
<h1>#Model.OrderTitle</h1>
#Html.Partial("OrderLineItems", Model.OrderItems)
OrderLineItems.cshtml
#model IEnumerable<OrderItem>
foreach (var orderItem in Model)
{
//Do stuff
}
Option 3: Use partial actions
If you need to reuse a partial view over multiple pages, it could be a good idea to use a partial view to eliminate having to populate different view models with the same info just because the page is going to be using the same partial.
E.g.
View Model
namespace MyNamesapce
{
public OrderInfoViewModel
{
public string OrderTitle { get; set; }
}
}
Controller
public class OrderController : Controller
{
public ActionResult OrderInfo(int orderId)
{
OrderInfoViewModel viewModel = GetViewModel(orderId);
return View(viewModel);
}
public PartialViewResult OrderLineItems(int orderId)
{
IEnumerable<OrderItem> orderItems = GetOrderItems(orderId);
return Partial(orderItems);
}
}
OrderInfo.cshtml
#model MyNamespace.OrderInfoViewModel
<h1>#Model.OrderTitle</h1>
#Html.Action("OrderLineItems")
OrderLineItems.cshtml
#model IEnumerable<OrderItem>
foreach (var orderItem in Model.OrderItems)
{
//Do stuff
}
With a partial view, you are just sending in a Model just like you would with a normal View. For example, if your Model has a property of LineItem objects named 'LineItems' you simply would do this:
#Html.Partial("_PartialName", Model.LineItems)
Now if your Model does not have that property, you can either add it, or pass it another way, like ViewBag (I prefer a strongly typed method, but that is my opnion:
#Html.Partial("_PartialName", (List<LineItem>)ViewBag.LineItems)
These are not the only ways, but they are my preferred methods.