I am new to MVC, in my View I have :
#{
MyObjectType myNameObject=getMyNameObject();
}
<p>
Name : #myNameObject.firstName
</p>
Trying to implement desing when line "Name : #myNameObject.firstName" comes from database through Model or ViewBag and still pick up value of #myNameObject.firstName. Is that possible?
Thank you
Your Controller action method should get the data and pass it to the View. Using a ViewModel is usually the way to go, but ViewBag also works for one-off data. Something like this:
// View model.
public class MyViewModel
{
public string Name {get; set;}
}
// Controller method.
public ActionResult MyPage()
{
MyViewModel model = serviceLayer.GetMyData();
return View(model);
}
// MyPage View.
#model MyViewModel
<p>Name: #Model.Name</p>
your Model:
public class MyNameObject
{
public MyNameObject()
{
//getvalues from database
//this.FirstName = yourObjectFromDatabase.FirstName;
}
public string FirstName { get; set; }
}
in your views that you want to show the first name:
#using WebApplication1.Models; //put it at the top of the view
#{ Html.RenderPartial("FirstName", new MyNameObject()); }
your view:
#model WebApplication1.Models.MyNameObject
#{
ViewBag.Title = "FirstName";
}
<h2>Name : #Model.FirstName</h2>
Related
In addition to the model itself, I want to pass the product id in the partial model. How to do this?
#Model.product.id
<partial name="_Score" model="#Model.rating"/>
//Create a class and add two properties example like below
` public class Your_Class_Name{
public int CaseId
{
get;set;
}
public string PatientName
{
get;set;
}
//and call your partial view like
#Html.Partial("PartialPatientHeaderDetails", new YourClassName
{
CaseId= #Model.CaseId,PatientName= #havePatientName })
//finally change your return mode in partial View
#model Your_Class_Name
#{
}
#Model.CaseId
#Model.PatientName
Passing ViewModel to #Html.Partial
Have two ViewModels
public class RegisterVM
{
... some properties
public AddressVM AddressInformation { get; set; } //viewmodel
}
public class AddressVM {
public string Street1 { get; set; }
public string Street2 { get; set; }
public string PostalCode { get; set; }
}
When loading main view using VM:
#model ViewModels.RegisterVM
All field load. But When I add Partial View and pass viewmodel
#Html.Partial("_AddressDetails", Model.AddressInformation)
It fails
Error: Exception Details: System.NullReferenceException: Object reference not set to an instance of an object. Why does it fail?
The partial View _AddressDetails is expecting a
#model ViewModels.AddressVM
Update
Based on changes from Prashant,
When submitting the information The Address information is NULL.
In The controller:
[HttpPost]
public ActionResult Register(RegisterVM vm){
...
//when viewing vm.AddressInformation.Street1 is null. and there is a value
//Is there a different way of retrieving the values from partial view?
}
Thanks for reading.
The error is generated because property AddressInformation is null, and you need to initailize it in a parameterless constructor or in the controller before you pass it to the view, for example
public class RegisterVM
{
public RegisterVM() // default constructor
{
AddressInformation = new AddressVM();
}
public AddressVM AddressInformation { get; set; }
....
}
However you usage means that the controls generated will be
<input name="Street1" .../>
whereas they need to be
<input name="AddressInformation.Street1" .../>
in order to bind to your model. You can either make your partial an EditorTemplate (/Views/Shared/EditorTemplates/AddressVM.cshtml) and use in the main view as
#Html.EditorFor(m => m.AddressInformation)
or pass the prefix to the partial as additional ViewData
#Html.Partial("_AddressDetails", Model.AddressInformation, new ViewDataDictionary { TemplateInfo = new TemplateInfo { HtmlFieldPrefix = "AddressInformation" }})
This is working for me. You just need to instantiate your VM, attach it and send it to the view.
Page Action
public ActionResult Page(){
RegisterVM vm = new RegisterVM();
vm.AddressInformation = new AddressVM();
return View(vm);
}
Page.cshtml
#model Project.Web.Models.RegisterVM
<!-- loading partial view -->
#Html.Partial("_AddressDetails",Model.AddressInformation)
Partial View File
<input type="text" name="name" value=" " />
I am not having more info about code but as per mention details, can you try this
public ActionResult Register(){ return View(register); }
i know you may tried this but try to assigned explict value. as this is basic MVC implementation. if it not work out then you need to provide more code details.
hope this help.
in Register get Method must instatiate your viewModel because in view, call other partial with viewModel members(proprties);
public ActionResult Register(){
RegisterVM vm = new RegisterVM();
return View(vm);
}
I know there are a lot of similar question here but none seem quite the same as mine.
In my View:
#model LocalInformedMotionServer.Models.FeedData
#Html.DropDownList("Premise", Model.LoadUp("key"), new { #style = "width: 218px;height:35px;" })
In my controller:
public class CloudController : Controller
{
public IEnumerable<wsCommon.Premise> Premises { get; set; }
public ActionResult Feed(string key)
{
var feedData = new FeedData();
Premises= feedData.LoadUp(key);
return View(feedData);
}
}
In my Model:
public class FeedData
{
public IEnumerable<wsCommon.Premise> LoadUp(string saltKey)
{
Premises premises = new InformedBiz.Premises();
return premises.GetPremises(saltKey);
}
}
It errors because the variable:
"key"
in this call:
Model.LoadUp("key")
is being read in as'null' in my controller method.
Of course as this is all new to me I could be doing this all wrong..
ADDITIONAL:
In my CloudController Class I have this:
public class CloudController : Controller
{
public ActionResult Feed(string saltKey)
{
var feedData = new FeedData();
feedData.LoadUp(saltKey);
return View(feedData);
}
public ActionResult Index()
{
return View();
}
public ActionResult LogIn()
{
return View();
}
}
I'm not sure what your Premise class looks like, but I usually use an IEnumberable of SelectListItem for drop downs in my views. So you could do something like this:
public IEnumerable<SelectListItem> LoadUp(string saltKey)
{
Premises premises = new InformedBiz.Premises();
return premises.GetPremises(saltKey).Select(
p => new SelectListItem { Text = p.Name, Value = z.PremiseId.ToString() }
);
}
You'll also need to create a Post ActionResult method that accepts the model in your view (FeedData) as well as wrap your DropDownList control in a Html.BeginForm, to post results to the controller. Hope this makes a bit of sense.
You have not posted the properties of your FeedData model but assuming it contains a property which is typeof Premise and you want to be able to select a Premise from a collection, then using a view model that represents what you want to display/edit is the recommended approach (refer View Model Design And Use In Razor Views and What is ViewModel in MVC?)
You view model might look like
public class FeedDataVM
{
.....
[Display(Name = "Premise")]
[Required(ErrorMessage = "Please select a Premise")]
public int? SelectedPremise { get; set; }
....
public SelectList PremiseList { get; set; }
}
and in your controller (not sure what saltKey is for?)
public ActionResult Feed(string saltKey)
{
FeedDataVM model = new FeedDataVM();
IEnumerable<Premise> premises = // get the collection of premise objects from your repository
// assuming you want to display the name property of premise, but post back the key property
model.PremiseList = new SelectList(premises, "key", "name");
return View(model);
}
View
#model FeedDataVM
#using(Html.BeginForm())
{
....
#Html.LabelFor(m => m.SelectedPremise)
#Html.DropDownListFor(m => m.SelectedPremise, Model.PremiseList, "-Please select")
#Html.ValidationMessageFor(m => m.SelectedPremise)
....
<input type="submit" value="Save" />
}
and the POST method
public ActionResult Feed(FeedDataVM model)
{
// model.SelectedPremise contains the value of the selected option as defined by the key property of Premise
}
Side note: Your FeedData model contains a method to retrieve a collection of Premise which appears to be calling another service. You should avoid this type of design which makes it difficult to debug and unit test. Your controller is responsible for initializing/getting you data models and view models and for populating/mapping their properties.
I am developing an application. I have created a view and a controller. The view has a button, on the click of which I am supposed to do database operations. I have put the database operations in the model, I am creating the object of model in the controller. On clicking the button the action is handled by a method in the controller, and the object of the model is created to get the records from the database. I would like to know if there is any way to display this data in the view.Is the approach correct or the view is supposed to interact with model directly to get the data.
Following is the code in controller that gets invoked on the button click
public ActionResult getRecord()
{
DataModel f_DM = new DataModel();
DataTable f_DT = f_DM.getRecord();
return View();
}
DataModel is the model class with simply a method "getRecord".
Any help will be highly appreciated.
I would like to add that i am using vs2010 and mvc4
Regards
you should write the logic of retrieving data in your controller. Store all your data in view model and pass it to the view.
for eg.
Model
namespace Mvc4App.Models
{
public class Product
{
public string Name { get; set; }
}
public class ProductViewModel
{
public Product Product { get; set; }
public string SalesPerson { get; set; }
}
}
Controller
public class ProductController : Controller
{
public ActionResult Info()
{
ProductViewModel ProductViewModel = new ProductViewModel
{
Product = new Product { Name = "Toy" },
SalesPerson = "Homer Simpson"
};
return View(ProductViewModel);
}
}
View
#model Mvc4App.Models.ProductViewModel
#{ ViewBag.Title = "Info"; }
<h2>Product: #Model.Product.Name</h2>
<p>Sold by: #Model.SalesPerson</p>
This is the best known practice to pass data from controller to the view.
you may use other techniques also like,
1. ViewData
2. ViewBag
3. TempData
4. View Model Object
5. Strongly-typed View Model Object
Yes, it's possible, but actually now very logical way to to this.
Lets follow your way. You have some View were you have a button, that will trigger this action.
For ex:
public ActionResult Index()
{
return View();
}
Inside view you can have a Ajax link, that will trigget your getRecord method:
<div id="GetDataDiv"></div>
<div>
#Ajax.ActionLink("Get Record", "getRecord", "ControllerName", null, new AjaxOptions() { HttpMethod = "GET", UpdateTargetId = "GetDataDiv" })
</div>
In the getRecord method you should have:
public ActionResult getRecord()
{
DataModel f_DM = new DataModel();
DataTable f_DT = f_DM.getRecord();
return PartialView(f_DT);
}
And in View it should be:
#model DataTable
#Model.PropertyOne #Model.PropertyTwo
It should works for you.
Actually same exaple here: http://www.dotnetpools.com/Article/ArticleDetiail/?articleId=151
My scenario is much complicated so i simplified it with the example below. The main problem is binding collection properties of a model, specifying the path of the property like Html.TextBox("List[0].Name") and not the Html.TextBoxFor(t => t.List[0].Name). So, for the current view i will only know some of the metadata of the model so i will have to construct it this way. Here is the scenario :
Model
public class ModelTest
{
public int Id {get;set;}
public List<Foo> Collection {get;set;}
}
public class Foo
{
public string Value1 {get;set;}
public string Value2 {get;set;}
}
Controller
public class TestController: Controller
{
[HttpGet]
public ActionResult Test()
{
var model = new ModelTest()
{
Id = 455,
Collection = new List<Foo>()
{
new Foo(){ Value1 = "sagasga", Value2 = "Beul"},
new Foo(){ Value1 = "dgdsgds", Value2 = "fhfhd" }
}
};
return View(model);
}
[HttpPost]
public ActionResult Test( ModelTest model)
{
//....
return View();
}
View:
#using (Html.BeginForm())
{
#Html.TextBox("Id")
#Html.TextBox("Collection[0].Value1")
#Html.TextBox("Collection[0].Value2")
<input type="submit" value="Add" />
}
For the code above i get empty textboxes for the collection values. However, when the page is submited i get the model built correct in the Post method.
Many thanks,
Alex
This is the way to name you input fields when you wanna post a collection to your controller. However, you have to specify the initial value yourself. Your code is currently just creating textbox with the name property set to Collection[0].Value1. You still need to specify the input this way,
#Html.TextBox("Collection[0].Value1", Model.Collection.FirstOrDefault().Value1)
#Html.TextBox("Collection[0].Value2", Model.Collection.FirstOrDefault().Value2)