Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed last year.
Improve this question
Hiii, I need help
Getting parser error here in the line
require(msg.value > o.1 ether);
// SPDX-License-Identifier: MIT
pragma solidity ^0.8.0;
contract Lottery{
address public manager;
address[] public players;
constructor(){
manager=msg.sender;
}
function enter() public payable{
require(msg.value > o.1 ether); //getting error here
players.push(msg.sender);
}
}
You have a typo, using the letter o instead of the number 0.
Corrected line:
require(msg.value > 0.1 ether);
Related
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 3 months ago.
Improve this question
My Code:
%{
#include<stdio.h>
%}
%%
"int"|"char"|"double"|"void"|"main" {printf("\n%s is a keyword",yytext);}
^[a - z A - Z _][a - z A - Z 0 - 9 _] * {printf("\n%s is an identifier",yytext);}
^[-+]?[0-9]* {printf(}\n%s is an integer",yytext);}
^[-+]?[0-9]*[.][0-9]+$ {printf("\n%s is a floating number",yytext);}
"+"|"-"|"*"|"/"|"%"|"//" {printf("\n%s is an arithmetic operator",yytext);}
">"|"<"|">="|"<="|"="|"=="|"<>" {printf("\n%s is a relational operator",yytext);}
.;
%%
int yywrap()
{
return 1;
}
main()
{
printf("Enter a String:\n");
yylex();
}
This is the Code I've written. I'm getting an error while compiling it and I'm not sure what it is. Can you please take a look at it and say how to fix it. Thank you.
Your code doesn't compile because there is a missing " in line ^[-+]?[0-9]* {printf(}\n%s is an integer",yytext);} (at the beginning of the printf's argument).
Flex says it found an EOF which means "End Of File". It found an "opening" " and it was looking for a matching closing " but it encountered end of the file first.
You should also pay attention to whitespaces in lex patterns.
Those two are not two are not equivalent:
^[a - z A - Z _][a - z A - Z 0 - 9 _] *
^[a-zA-Z_][a-zA-Z0-9_]*
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 2 years ago.
Improve this question
I am trying to say if the desired location in the field is 1 return true otherwise return false. Why is this code not working?
fireShot :: Coordinate -> Field -> Bool
fireShot coord Shipfield
| nth ( fst(coord)((nth snd(coord)) ShipField) == 1 = True
| otherwise = False
The brackets in the guard are not balanced, you open five brackets, and you close four brackets. Furthermore variables start with a lowercase, so it should (probably) be shipfield, not Shipfield.
I think it might be better to use pattern matching to obtain the first and second coordinate, since this will make the code more clean. You furthermore do not need guards to return True and False. You can replace the function with:
fireShot :: Coordinate -> Field -> Bool
fireShot (x,y) shipfield = nth x (nth y shipfield) == 1
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 3 years ago.
Improve this question
if !isEditing {
collectionView.indexPathsForSelectedItems?.compactMap({ $0 }).forEach {_ in
collectionView.deselectItem(at: 0, animated: true)
// Cannot convert value of type 'Int' to expected argument type 'IndexPath'
just use forEach loop
collectionView.indexPathsForSelectedItems?.forEach({
collectionView.deselectItem(at:$0, animated: true)
})
Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 7 years ago.
Improve this question
I working on a Swift program and now I have a problem:
How do you compare a Int64 with a Int64?
if(msgCount.value != msg.longLongValue){
Error:
Binary operator '!=' cannot be applied to operands of type 'Int64' and 'Int64'
You can directly compare for equality
Try this, it will help you:
let msgCount : Int64=100
let msg : Int64=101
if(msgCount != msg ){
// perform your logic here.
}
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Closed 8 years ago.
Improve this question
I have php code, where occur sort, like this:
j=0;
while(...){
...
$cancel_alarm_trusee[$j]['created'] = alarm['created'];
...
j++;
}
function Compare($a, $b) {
return $a['created'] < $b['created'];
}
usort($cancel_alarm_trusee, 'Compare');
How to do it in Ruby?
Ruby Has Enumerable#sort and Enumerable#sort_by also.Look those methods.
Example:
%w{apple pear fig}.sort_by { |word| word.length}
#=> ["fig", "pear", "apple"]
%w(rhea kea flea).sort
#=> ["flea", "kea", "rhea"]