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I working on a Swift program and now I have a problem:
How do you compare a Int64 with a Int64?
if(msgCount.value != msg.longLongValue){
Error:
Binary operator '!=' cannot be applied to operands of type 'Int64' and 'Int64'
You can directly compare for equality
Try this, it will help you:
let msgCount : Int64=100
let msg : Int64=101
if(msgCount != msg ){
// perform your logic here.
}
Related
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Hiii, I need help
Getting parser error here in the line
require(msg.value > o.1 ether);
// SPDX-License-Identifier: MIT
pragma solidity ^0.8.0;
contract Lottery{
address public manager;
address[] public players;
constructor(){
manager=msg.sender;
}
function enter() public payable{
require(msg.value > o.1 ether); //getting error here
players.push(msg.sender);
}
}
You have a typo, using the letter o instead of the number 0.
Corrected line:
require(msg.value > 0.1 ether);
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I am trying to say if the desired location in the field is 1 return true otherwise return false. Why is this code not working?
fireShot :: Coordinate -> Field -> Bool
fireShot coord Shipfield
| nth ( fst(coord)((nth snd(coord)) ShipField) == 1 = True
| otherwise = False
The brackets in the guard are not balanced, you open five brackets, and you close four brackets. Furthermore variables start with a lowercase, so it should (probably) be shipfield, not Shipfield.
I think it might be better to use pattern matching to obtain the first and second coordinate, since this will make the code more clean. You furthermore do not need guards to return True and False. You can replace the function with:
fireShot :: Coordinate -> Field -> Bool
fireShot (x,y) shipfield = nth x (nth y shipfield) == 1
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I am trying to calculate body fat related calculation but it will give me error binary operator can not be applied on operands.
it is gives me error like this
error: :3:22: error: binary operator '/' cannot be applied to
operands of type 'Optional' and 'Int' print((lbs * Int(Fat /
100)))
Here is my expression. how I can solve this.
let bodyFatPounds = (lbs * Int(Fat / 100))
let LBM = Double(lbs - bodyFatPounds)
Fat value in your code is optional and that's why it showing this error. Use to convert like this
let bodyFatPounds = (lbs * Int((Fat ?? 0) / 100))
let LBM = Double(lbs - bodyFatPounds)
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I am getting a lot of reports that a function that is called by applicationWillTerminate, not exclusively by that but I have a feeling that the root of the issue might have something to do with that. I am getting these reports from Fabric.io Crashlytics. Anyways the reported line causing the crash is the following:
return Int(NSDate().timeIntervalSince1970 * 1000)
This code has also been working in most cases but has risen up the list of crashes. Can anyone give me any hint as to why this might be crashing.
My guess is that your crashes are coming from 32-bit devices, where Int(NSDate().timeIntervalSince1970 * 1000) is impossible because NSDate().timeIntervalSince1970 * 1000 is bigger than Int.max.
Here's a little playground code to show that that is true:
let i = Int32.max // max size of Int on 32-bit
i // 2147483647
let j = NSDate().timeIntervalSince1970 * 1000
j // 1486250171084.633
And we can proceed to test it like this:
// let's try to simulate the crash
Int32(j)
// yup, crash:
// "Double value cannot be converted to Int32 because the result would be greater than Int32.max"
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I haven't been doing Erlang for a while so I am practicing but I don't get it anymore :(
-module(conversion).
-export([convert/1, convertMeteoCelcius/1]).
convert({celcius, Degres}) -> {farenheit, (Degres * 1.8) + 32};
convert({celcius, Degres}) -> {celcius, Degres};
convert({farenheit, Degres}) -> {celcius, (Degres - 32)/1.8};
convert({farenheit, Degres}) -> {farenheit, Degres}.
convertMeteoCelcius([], [Result])
-> [Result];
convertMeteoCelcius([{City, {Unit, Temp}}|Rest], [Result])
-> convertMeteoCelcius([Rest], [{City, convert({celcius, Temp})}, Result]).
convertMeteoCelcius([Raw]) -> formatMeteoCelcius([Raw], []).
There is one compiler error: undefined formatMeteoCelcius/2 in the last line. I suppose that you meant convertMeteoCelcius. Changing that, your code compiles.
On the other hand, you then get three warning messages. The third one is about the unused Unit variable, and I suppose you can safely ignore it. The other two, however, show two potential problems in your code:
conversion.erl:5: Warning: this clause cannot match
because a previous clause at line 4 always matches
conversion.erl:7: Warning: this clause cannot match
because a previous clause at line 6 always matches
The first warning basically says that you will have to decide what you want the result of convert({celcius, 0}) to be. It cannot be both {farenheit, 32} and {celcius, 0}.
You may have been mislead by the apparent similarity between Erlang and Prolog. Erlang is not a logic programming language; it is functional. For every function defined using pattern matching, one pattern will be used deterministically every time you call it.