Converting Base64 to data returning nil - ios

Question

I am trying to convert base64 string to image, I checked the json response, base64 string is not empty, but Data returns nil in between.
let base64String = image.Image_bytes_1
var data = Data(base64Encoded: base64String!, options: .ignoreUnknownCharacters)
let image = UIImage(data: data! as Data)
imageView.image = image
at line#4 getting this below error
Thread 3: Fatal error: Unexpectedly found nil while unwrapping an
Optional value

Answer 1

The Data initializer you are using, init(base64Encoded:options:) is declared as init?(base64Encoded base64Data: Data, options: Data.Base64DecodingOptions = [])
That's known as a "failable initializer", which means it can return nil. (note the question mark after init in the declaration.)
If the base64 data is not well-formed, it may fail and return nil.
Stop using force-unwrapping. Rewrite using optional binding:
if let base64String = image.Image_bytes_1,
let data = Data(base64Encoded: base64String, options: .ignoreUnknownCharacters),
let image = UIImage(data: data) {
imageView.image = image
} else {
print("Unable to load base64 data and convert to image")
}
Edit:
As workingdog pointed out in their comment, your code does not make sense:
let base64String = image.Image_bytes_1 // line 1
var data = Data(base64Encoded: base64String!, options: .ignoreUnknownCharacters) // line 2
let image = UIImage(data: data! as Data) // line 3
imageView.image = image // line 4
Line 1 references something called image. You don't show the code that declares it, so we don't know what it is.
Then in line 3, you declare a new local constant also named image. If the original image is an instance variable of your class, and the code you posted is inside a function, you are creating a new local variable that overrides the other variable called image. I strongly advise against using the same variable name in different levels of scope. That is confusing at best, and causes errors at worst.