When I try to compile a bazel project that uses gRPC reflection, I get the following error.
fatal error: external/com_github_grpc_grpc/src/proto/grpc/reflection/v1alpha/reflection.grpc.pb.h: No such file or directory
In my WORKSPACE, I have the following bindings:
def _com_github_grpc_grpc():
external_http_archive("com_github_grpc_grpc")
external_http_archive("build_bazel_rules_apple")
# Rebind some stuff to match what the gRPC Bazel is expecting.
native.bind(
name = "protobuf_headers",
actual = "#com_google_protobuf//:protobuf_headers",
)
native.bind(
name = "libssl",
actual = "//external:ssl",
)
native.bind(
name = "cares",
actual = "//external:ares",
)
native.bind(
name = "grpc",
actual = "#com_github_grpc_grpc//:grpc++",
)
In my BUILD file, I have the following deps:
deps = [
"//external:protobuf_headers",
"//external:grpc",
],
What additional incantations do I need for the include at the top of the question?
After a spelunking through issues, I figured out that I need the following WORKSPACE
workspace(name = "xxx")
load("#bazel_tools//tools/build_defs/repo:http.bzl", "http_archive")
http_archive(
name = "com_github_grpc_grpc",
strip_prefix = "grpc-master",
urls = ["https://github.com/grpc/grpc/archive/master.tar.gz"],
)
load("#com_github_grpc_grpc//bazel:grpc_deps.bzl", "grpc_deps")
grpc_deps()
load("#com_github_grpc_grpc//bazel:grpc_extra_deps.bzl", "grpc_extra_deps")
grpc_extra_deps()
and the following BUILD:
cc_binary(
name = "ReflectionPlay",
copts = ["-std=c++17"],
srcs = ["reflection_play.cc"],
deps = [
"#com_github_grpc_grpc//:grpc++",
"#com_github_grpc_grpc//:grpc++_reflection",
"#com_github_grpc_grpc//:grpcpp_admin",
],
)
Related
I am trying to consume some Python code + C extensions that are produced by CMake.
I'm using rules_foreign_cc to build the code, and it puts the code into an output directory, but I'm stumped as to how I can turn that into a py_library. I tried the below:
Depend on the cmake rule as srcs
Set imports to try to point to the directory containing the Python packages
But it doesn't work. When I run the py_test, the constructed PYTHONPATH doesn't point to the directory containing the python package from the cmake rule.
Thanks for any help!
Here's what I've got in my third_party/BUILD.bazel:
load("#rules_foreign_cc//foreign_cc:defs.bzl", "cmake")
load("#rules_python//python:defs.bzl", "py_library", "py_test")
filegroup(
name = "torch_mlir_src",
srcs = glob(["torch-mlir/**"]),
)
make(
name = "torch_mlir",
...
install = False,
lib_source = ":torch_mlir_src",
out_data_dirs = ["python_packages"],
postfix_script = " && ".join([
"cp -r --dereference tools/torch-mlir/python_packages/torch_mlir $$INSTALLDIR$$/python_packages",
]),
targets = ["tools/torch-mlir/all"],
working_directory = "external/llvm-project/llvm",
)
# This doesn't seem to work.
py_library(
name = "torch_mlir_py",
srcs = [":torch_mlir"],
imports = ["$(BINDIR)/third_party/torch_mlir/python_packages"],
srcs_version = "PY3",
)
py_test(
name = "torch_mlir_annotations_sugar_test",
srcs = ["torch-mlir/python/test/annotations-sugar.py"],
main = "torch-mlir/python/test/annotations-sugar.py",
srcs_version = "PY3",
deps = [":torch_mlir_py"],
)
I'm experimenting with using libhttpserver and, by extension, libmicrohttpd from inside a Bazel build. The build process for these libraries seems to go:
./bootstrap
mkdir build
cd build
../configure
make
which is a slight variation, that I haven't seen before, on the more classic configure && make workflow.
Has anyone managed to make such a library work under Bazel?
Does anyone have a public example I can crib from?
The closest thing I've found to supporting this is #rules_foreign_cc//tools/build_defs:configure.bzl#configure_make but that seems to have no concept of the bootstrap step. Even hacking it doesn't seem to work as the bootstrap script ends up failing with:
mkdir: cannot create directory 'tmpwrk23': Read-only file system
autopoint: *** cannot create directory tmpwrk23
autopoint: *** Stop.
autoreconf: autopoint failed with exit status: 1
I'm about ready to just reach for a genrule() but that seems very error prone...
I went down the same path as you and was able to get libhttpserver compiling with bazel using the rules_foreign_cc project after coming across the 6/23/20 update on this blog post. I added code below, but in general rules_foreign_cc has a make rule, which you can set override make_commands and call ./bootstrap.
WORKSPACE:
...
http_archive(
name = "rules_foreign_cc",
strip_prefix = "rules_foreign_cc-master",
url = "https://github.com/bazelbuild/rules_foreign_cc/archive/master.zip",
)
load("#rules_foreign_cc//:workspace_definitions.bzl", "rules_foreign_cc_dependencies")
rules_foreign_cc_dependencies(register_default_tools = True)
all_content = """filegroup(name = "all", srcs = glob(["**"]), visibility = ["//visibility:public"])"""
http_archive(
name = "rules_cc",
urls = ["https://github.com/bazelbuild/rules_cc/archive/262ebec3c2296296526740db4aefce68c80de7fa.zip"],
strip_prefix = "rules_cc-262ebec3c2296296526740db4aefce68c80de7fa",
)
http_archive(
name = "libgnutls",
build_file_content = all_content,
strip_prefix = "gnutls-3.6.15",
urls = ["https://www.gnupg.org/ftp/gcrypt/gnutls/v3.6/gnutls-3.6.15.tar.xz"],
)
http_archive(
name = "libhttpserver",
build_file_content = all_content,
strip_prefix = "libhttpserver-master",
urls = ["https://github.com/etr/libhttpserver/archive/master.zip"],
)
http_archive(
name = "libmicrohttpd",
build_file_content = all_content,
strip_prefix = "libmicrohttpd-0.9.71",
urls = ["https://ftp.gnu.org/gnu/libmicrohttpd/libmicrohttpd-0.9.71.tar.gz"],
)
BUILD:
load("#rules_foreign_cc//tools/build_defs:configure.bzl", "configure_make")
load("#rules_foreign_cc//tools/build_defs:make.bzl", "make")
load("#rules_cc//cc:defs.bzl", "cc_binary", "cc_library")
package(default_visibility = ["//visibility:public"])
configure_make(
name = "libgnutls",
lib_source = "#libgnutls//:all",
configure_options = ["--with-included-unistring"],
out_include_dir = "include/gnutls",
shared_libraries = ["libgnutls.so"],
)
configure_make(
name = "libmicrohttpd",
lib_source = "#libmicrohttpd//:all",
deps = [":libgnutls"],
)
make(
name = "libhttpserver",
lib_source = "#libhttpserver//:all",
make_commands = [
"./bootstrap",
"mkdir build_dir",
"cd build_dir",
"../configure --prefix=${INSTALLDIR}",
"make",
"make install",
],
deps = [":libmicrohttpd", ":libgnutls"],
)
cc_binary(
name = "hello-world",
srcs = ["hello_world.cc"],
deps = [
":libhttpserver"
],
)
hello_world.cc (example on libhttpserver github page, run "curl -XGET -v http://localhost:8080/hello" to test)
#include <iostream>
#include <httpserver.hpp>
using namespace std;
using namespace httpserver;
class hello_world_resource : public http_resource {
public:
const std::shared_ptr<http_response> render(const http_request&) {
return std::shared_ptr<http_response>(new string_response("Hello, World!"));
}
};
int main(int argc, char** argv) {
cout << "hello!" << std::endl;
webserver web_server = create_webserver(8080);
hello_world_resource resource;
web_server.register_resource("/hello", &resource);
web_server.start(true);
return 0;
}
I'm trying to build a rule for bazel which emulates the CMake *.in template system.
This has two challenges, the first is generate the template output. The second is make the output available to both genrules, filegroups and cc_* rules. The third is to get that dependency to transitively be passed to further downstream rules.
I have it generating the output file version.hpp in genfiles (or bazel-bin), and I can get the initial library rule to include it, but I can't seem to figure out how to make my cc_binary rule, which depends on the cc_library and transitively the header_template rule to find the header file.
I have the following .bzl rule:
def _header_template_impl(ctx):
# this generates the output from the template
ctx.actions.expand_template(
template = ctx.file.template,
output = ctx.outputs.out,
substitutions = ctx.attr.vars,
)
return [
# create a provider which says that this
# out file should be made available as a header
CcInfo(compilation_context=cc_common.create_compilation_context(
headers=depset([ctx.outputs.out])
)),
# Also create a provider referencing this header ???
DefaultInfo(files=depset(
[ctx.outputs.out]
))
]
header_template = rule(
implementation = _header_template_impl,
attrs = {
"vars": attr.string_dict(
mandatory = True
),
"extension": attr.string(default=".hpp"),
"template": attr.label(
mandatory = True,
allow_single_file = True,
),
},
outputs = {
"out": "%{name}%{extension}",
},
output_to_genfiles = True,
)
elsewhere I have a cc_library rule:
load("//:tools/header_template.bzl", "header_template")
# version control
BONSAI_MAJOR_VERSION = '2'
BONSAI_MINOR_VERSION = '0'
BONSAI_PATCH_VERSION = '9'
BONSAI_VERSION = \
BONSAI_MAJOR_VERSION + '.' + \
BONSAI_MINOR_VERSION + '.' + \
BONSAI_PATCH_VERSION
header_template(
name = "bonsai_version",
extension = ".hpp",
template = "version.hpp.in",
vars = {
"#BONSAI_MAJOR_VERSION#": BONSAI_MAJOR_VERSION,
"#BONSAI_MINOR_VERSION#": BONSAI_MINOR_VERSION,
"#BONSAI_PATCH_VERSION#": BONSAI_PATCH_VERSION,
"#BONSAI_VERSION#": BONSAI_VERSION,
},
)
# ...
private = glob([
"src/**/*.hpp",
"src/**/*.cpp",
"proto/**/*.hpp",
])
public = glob([
"include/*.hpp",
":bonsai_version",
])
cc_library(
# target name matches directory name so you can call:
# bazel build .
name = "bonsai",
srcs = private,
hdrs = public,
# public headers
includes = [
"include",
],
# ...
deps = [
":bonsai_version",
# ...
],
# ...
)
When I build, my source files need to be able to:
#include "bonsai_version.hpp"
I think the answer involves CcInfo but I'm grasping in the dark as to how it should be constructed.
I've already tried add "-I$(GENDIR)/" + package_name() to the copts, to no avail. The generated header still isn't available.
My expectation is that I should be able to return some kind of Info object that would allow me to add the dependency in srcs. Maybe it should be a DefaultInfo.
I've dug through the bazel rules examples and the source, but I'm missing something fundamental, and I can't find documentation that discuss this particular.
I'd like to be able to do the following:
header_template(
name = "some_header",
extension = ".hpp",
template = "some_header.hpp.in",
vars = {
"#SOMEVAR#": "value",
"{ANOTHERVAR}": "another_value",
},
)
cc_library(
name = "foo",
srcs = ["foo.src", ":some_header"],
...
)
cc_binary(
name = "bar",
srcs = ["bar.cpp"],
deps = [":foo"],
)
and include the generated header like so:
#include "some_header.hpp"
void bar(){
}
The answer looks like it is:
def _header_template_impl(ctx):
# this generates the output from the template
ctx.actions.expand_template(
template = ctx.file.template,
output = ctx.outputs.out,
substitutions = ctx.attr.vars,
)
return [
# create a provider which says that this
# out file should be made available as a header
CcInfo(compilation_context=cc_common.create_compilation_context(
# pass out the include path for finding this header
includes=depset([ctx.outputs.out.dirname]),
# and the actual header here.
headers=depset([ctx.outputs.out])
))
]
elsewhere:
header_template(
name = "some_header",
extension = ".hpp",
template = "some_header.hpp.in",
vars = {
"#SOMEVAR#": "value",
"{ANOTHERVAR}": "another_value",
},
)
cc_library(
name = "foo",
srcs = ["foo.cpp"],
deps = [":some_header"],
...
)
cc_binary(
name = "bar",
srcs = ["bar.cpp"],
deps = [":foo"],
)
If your header has a generic name (eg config.h) and you want it to be private (ie srcs instead of hdrs), you might need a different approach. I've seen this problem for gflags, which "leaked" config.h and affected libraries that depended on it (issue).
Of course, in both cases, the easiest solution is to generate and commit header files for the platforms you target.
Alternatively, you can set copts for the cc_library rule that uses the generated private header:
cc_library(
name = "foo",
srcs = ["foo.cpp", "some_header.hpp"],
copts = ["-I$(GENDIR)/my/package/name"],
...
)
If you want this to work when your repository is included as an external repository, you have a bit more work cut out for you due to bazel issue #4463.
PS. You might want to see if cc_fix_config from https://github.com/antonovvk/bazel_rules works for you. It's just a wrapper around perl but I found it useful.
In my Java-based Bazel project I use a code generator written in Java. The generator is part of the root project, and used in sub-projects as well.
What I want to achieve is to include the output of the root project (a .jar file) as a dependency for the code generation in sub-projects to grant the code generator access to all compiled files of the root project (through the classpath). Is that possible in Bazel?
What I see is that the classpath for key generation in the child project only includes the dependencies of the code generator binary (//parent:SettingsGenerator in the script below).
In my custom rule I invoke the code generator basically like this:
def _generate_settings(ctx):
...
ctx.actions.run(
inputs = [ctx.file._src] + [ctx.files.deps],
outputs = [keys, settings, loader],
mnemonic = "GenKeysAndSettings",
arguments = [args],
executable = ctx.executable._tool,
)
return [DefaultInfo(
files=depset([keys, settings, loader]),
runfiles=ctx.runfiles(files=ctx.files.deps)
)]
gen_settings = rule(
implementation = _generate_settings,
attrs = {
"lang": attr.string(),
"deps": attr.label_list(
allow_files = True
),
"_tool": attr.label(
cfg = "host",
executable = True,
default = Label("//parent:SettingsGenerator"),
),
"_src": attr.label(
single_file = True,
default = Label("//parent:Name")
),
}
)
The parent project BUILD:
load("//parent:settings.bzl", "gen_settings")
gen_settings(
name = "GenerateSettings",
lang = ""
)
java_library(
name = "parent",
srcs = glob(["src/main/java/**/*.java"]) + [
":GenerateSettings",
],
...
)
java_binary(
name = "SettingsGenerator",
srcs = glob(["src/main/java/**/SettingsGenerator.java"]),
main_class = "my.company.SettingsGenerator",
...
)
The child project BUILD:
gen_settings(
name = "GenerateSettings",
lang = "Java",
deps = ["//parent"]
)
...
My workaround is to include the .jar file as input and use a custom classloader in the generator. But it would be nice if I could control the classpath directly from Bazel.
Any help would be appreciated. Thank you.
In the Bazel official documentation there is an example explaining how to create a Java library built from regular java files and files generated by a :gen_java_srcs rule. I rewrite this code here for ease of reading:
java_library(
name = "mylib",
srcs = glob(["*.java"]) + [":gen_java_srcs"],
deps = "...",
)
genrule(
name = "gen_java_srcs",
outs = [
"Foo.java",
"Bar.java",
],
...
)
Now in a C++ perspective, I am in a scenario where the genrule generates two kind of files: .hpp and .cpp:
genrule(
name = "gen_cpp_srcs",
outs = [
"myFile_1.hpp","myFile_2.hpp",...,"myFile_N.hpp",
"myFile.cpp","myFile_2.cpp",...,"myFile_N.cpp",
],
...
)
where N is some tens.
My problem/question is: how to write the cc_library rule, with an automatic dispatching of the hpp and cpp files into hdrs and srcs field?
I want something like:
cc_library(
name = "mylib",
srcs = glob(["*.cpp"]) + (howto: .cpp files of [":gen_cpp_srcs"]),
hdrs = glob(["*.hpp"]) + (howto: .hpp files of [":gen_cpp_srcs"]),
...
)
Some magic like:
output_filter(":gen_cpp_srcs","*.cpp")
would be perfect, but I do not know enough of Bazel to make it real.
Globs only get expanded when they're passed into rules, so you'll need to write a simple rule. I would package it like this (in a file named filter.bzl):
# The actual rule which does the filtering.
def _do_filter_impl(ctx):
return struct(
files = set([f for f in ctx.files.srcs if f.path.endswith(ctx.attr.suffix)]),
)
_do_filter = rule(
implementation = _do_filter_impl,
attrs = {
"srcs": attr.label_list(
mandatory = True,
allow_files = True,
),
"suffix": attr.string(
mandatory = True,
),
},
)
# A convenient macro to wrap the custom rule and cc_library.
def filtered_cc_library(name, srcs, hdrs, **kwargs):
_do_filter(
name = "%s_hdrs" % name,
visibility = ["//visibility:private"],
srcs = hdrs,
suffix = ".hpp",
)
_do_filter(
name = "%s_srcs" % name,
visibility = ["//visibility:private"],
srcs = srcs,
suffix = ".cpp",
)
native.cc_library(
name = name,
srcs = [ ":%s_srcs" % name ],
hdrs = [ ":%s_hdrs" % name ],
**kwargs
)
This is what my demo BUILD file looks like (I changed the globs so they both include *.cpp and *.hpp files; using the label of a genrule will work the same way):
load("//:filter.bzl", "filtered_cc_library")
filtered_cc_library(
name = "mylib",
srcs = glob(["*.*pp"]),
hdrs = glob(["*.*pp"]),
)
This is easy to extend to more sophisticated filtering by changing _do_filter_impl. In particular, changing suffix to an attr.string_list so you can accept multiple C/C++ source/header extensions seems like a good idea.
Depending on the genrule by name (:gen_cpp_srcs) will give you all of the outputs of the genrule, as you have noted. Instead, you can depend on the individual outputs of the genrule (e.g. hdrs = [:myFile.hpp] and srcs = [:myFile.cpp]).
See also the answer to Bazel & automatically generated cpp / hpp files.
Looks like you know the total number of files that should be generated. Can you put those in their own variables and then reuse them in both targets. Something like this in your BUILD file:
output_cpp_files = [
"myFile_1.cpp",
"myFile_2.cpp",
"myFile_3.cpp"
]
output_hpp_files = [
"myFile_1.hpp",
"myFile_2.hpp",
"myFile_3.hpp"
]
genrule(
name = "gen_cpp_srcs",
outs = output_cpp_files + output_hpp_files,
cmd = """
touch $(OUTS)
"""
)
cc_library(
name = "mylib",
srcs = output_cpp_files,
hdrs = output_hpp_files
)