I have a Google sheet with a column of dates and numbers. What I want to be able to do is say: If the date is earlier than 9/1/2021, take the number and multiply by 1, otherwise multiply by 2, then sum all the products. The date and number columns keep getting new information as time goes on.
Now I know that I could create a kind of "scratch-work" column where I have a cell containing =IF(DATEVALUE(A1)<DATEVALUE("2021-9-1"),1,2) * B1 and then apply this formula to the column, and then sum the column somewhere else. However, this is not ideal because every time a new date and number come in I have to reapply the formula to the new scratch-work column's cell.
What I was hoping for was some kind of vectorized operator that would eliminate the need for the scratch work column in the first place. Something like being able to multiply whole columns like =B1:B * 2 or what is more appropriate for my current task, =IF(DATEVALUE(A1:A)<DATEVALUE("2021-9-1"),1,2) * B1:B.
I know you can do this kind of thing in R but haven't seen any vectorized operations in Google Sheets. I'm guessing it's not possible but wanted to ask just in case.
=arrayformula(if(A1:A="","",IF(DATEVALUE(A1:A)<DATEVALUE("2021-9-1"),1,2) * B1:B))
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So I'm creating a Google Sheets doc that contains my hours and overtime for an hourly position I have, and how much overtime I'll need to make the amount of money I need to make to survive.
In addition to this I am also trying to track my hours so I can track the actual amount of money I'm making.
So I have a projected clock out time in Column B that uses a formula to tell me what time I need to ideally clock out at based on how many hours I need and what time I clocked in at. When I clock out, I enter the actual time I clocked out at.
In Column C I have the total amount of hours I worked that day, formatted in duration based on the difference between the value in Column A and Column B. If I haven't entered in a value in Column B, it shows me the ideal amount of hours I need that day.
I want to calculate my actual hours worked per week as I'm working that week, so I need to ONLY sum the values in Column C if the adjacent value in Column B is NOT a formula. So I need it to sum the values in column C if I've entered the actual time that I clocked out at in column B.
I've looked up this question and tried multiple solutions I've found here, even tried troubleshooting with ChatGPT, but most are just trying to sum the range that contains the values/formula, and not summing a different column based on if another column has formulas or not.
There seems to be a lot of posts that come super close but don't seem to work for how I need this to work.
Edit: Here is the example sheet.
So F3:F6 are values that have been manually entered, while F:7 has been calculated by a formula.
I need H9 to sum the values of H3:H7, but only the values adjacent to the times in the F column that have been manually entered. In this example, I need it to sum H3:H6 and ignore H7 until I enter a time and remove the formula in F7.
try:
=SUMPRODUCT(MAP(F3:F7,LAMBDA(z,IFNA(FORMULATEXT(z),1))),H3:H7)
You may filter and check if there is a formula with FORMULATEXT. If there isn't it will throw a #N/A error. Then with ISNA it will keep the values in which its adjacents did'nt have a formula:
=SUM(FILTER(C:C,BYROW(B:B,LAMBDA(b,ISNA(FORMULATEXT(o))))))
I'm on google sheets trying to find the percentage of values where the difference between two columns in another sheet, is less than the value in a third column of the sheet. I've tried a bunch of things but all come up with err0rs or parse error. Any help is appreciated.
This is what I came up with.
=COUNTIF((sum(Data!($E$2:$E$229):Data!($F$2:$F$229)),"<Data!$C$2:$C$229"))/count(Data!$C$2:$C$229)
then I make it a percentage value
Thanks for your help!
If possible, the simplest strategy would probably be something like this:
In the sheet with the two columns, calculate another column that is the difference of the first two. E.g.:
=A1-B1.
Then, write an if statement that checks whether that difference is less than the value in the third column. If it is, return 1, if it isn't return 0. E.g.:
=IF(C1<D1, 1, 0)
Finally, calculate the percentage of values that are less with a formula like this:
=SUM(if_column) / COUNTA(if_column) * 100
SUM returns the count of all cells whose difference is less than the third column and COUNTA returns the total number of non-blank cells.
I'm creating a Google Sheet documenting how many times a certain item appears in a video game with the formula in the D column (formatted to a percent):
=IFERROR(C2/SUM(C2:C51))
I want the "C2" cell to apply down the column (C3, then C4, you get the idea), but I want the "C2:C51" array to stay constant while the C2 part gets applied down the down the column. How could I modify the formula to do this? (I could manually edit the formulas all the way down, I only have 50 rows, but I think it would be helpful to learn for the future)
Try this:
=iferror(C2 / sum(C$2:C$51))
See absolute and relative references.
Alternatively, try this array formula that fills a whole column in one go:
=arrayformula(iferror(C2:C51 / sum(C2:C51)))
I'm wondering how I would go about adding to a cell based on two other cells.
For example, I'm creating a Google Sheets document to track profit & loss on certain things in an online game I play.
I'll try to explain this as best as possible.
If cell B71 is equal to the string in cell B7, increase the value in cell D71 equal to the number in cell D7.
However, the values will need to be compared to various other things depending on the item required.
For example, the string in cell B7 might change depending on what specific type of item is needed for that day as it does change daily.
I have cells near the bottom of the sheet which list the different type of item which will show the total amount of items used in that month.
I've tried to explain this a little better as requested below
I'm trying to make a spreadsheet that keeps track of the quantity of a specific item I use in a game for a daily task. This task can be done daily, and to keep track of profit & loss, I have created a spreadsheet to keep track of this.
So, each day, there are three different types of items (runes) that can be used in the machine to create an item called 'Vis Wax'. As Runes are cheap, creating the vis wax can generate a good profit. (I love working with data, hense the spreadsheet.
The image above shows what a daily section looks like. I input each type of rune (has to be 3), input the quantity used and the amount each rune is worth to create the total cost under Total.
Further down below, this table has been created
This will keep track of each rune and the amount used during that month.
So with that said, I'm looking for a solution so that if Air rune is entered in ANY of them slots with the QUANTITY used, it'll update that table accordinly (as well as the other runes that are used too). I've tried nested IF statements, but don't seem to have any luck. With the amount of checks that seem to be happening, I can't seem to find a working solution. As Air Rune might be in slot 1 one day, then slot 3 the next day. So it seems each cell in the Quantity Table will need to compare EACH cell in the daily section, to each rune type that can be used.
Hopefully that has explained it a little better.
Spreadsheet Link
https://docs.google.com/spreadsheets/d/1sYLpZJ46IpNk52gxMoJOIZsOCWToLkC4FF83RBncCf0/edit?usp=sharing
I would suggest you to use a different structure and take all the data from one day in one column, something like this:
In this way you will be able to extend the days keeping the formulas in a really simple way. Below, I will explain some useful formulas that you can use to lighten your work:
Day: =text(DAY(B2),"dddd")
Rune type: Check Data validation to create a drop-down list of your rune types
For counting how many runes have you used you can use SUMIFS function. It returns the sum of a range depending on multiple criteria. In your case, you need apply it three time per rune, as you can have the same rune in three different places. You see it with the following image:
The formula is: =SUMIFS($B$8:$H$8,$B$7:$H$7,A25) + SUMIFS($B$12:$H$12,$B$11:$H$11,A25) + SUMIFS($B$16:$H$16,$B$15:$H$15,A25). In this way you only need to write it once and you can fill the rest of the runes just dragging the mouse. If you need more days just change the column H with the last column that you want to take.
I assume that with all this information you can also keep track of your monthly statics easily. I suggest you to create a different sheet for each month.
I hope that my answer was useful, let me know if you have any doubt.
George, I agree with #fullfine, your data structure does not seem ideal for data analysis. And it doesn't seem that efficient for data entry either, with the sideways scrolling (at least on my screen).
But I recognise that you might not want to change it, perhaps having specific reasons for that layout, and having invested time in it. So I offer this formula as an alternative, which basically pulls the needed cells from your existing sheet, and comes up with the totals you'll need.
=QUERY(QUERY({B7:D9;G7:I9;L7:N9;Q7:S9;V7:X9;AA7:AC9;AF7:AH9;
B20:D22;G20:I22;L20:N22;Q20:S22;V20:X22;AA20:AC22;AF20:AH22;
B33:D35;G33:I35;L33:N35;Q33:S35;V33:X35;AA33:AC35;AF33:AH35;
B46:D48;G46:I48;L46:N48;Q46:S48;V46:X48;AA46:AC48;AF46:AH48;
B59:D61;G59:I61;L59:N61},
"select Col1, Col2, Col3*Col2 where Col1 <>'' order by Col1 label Col3*Col2 '' ",0),
"select Col1, sum(Col2), sum(Col3) group by Col1 label sum(Col2) '', sum(Col3) '' ",0)
The same formula can be used for each month, since it always totals all 31 days, even if the month has fewer days.
For your Rune table in the Statistics sheet, you only need the firsts two columns, so you could delete the "sum(Col3)" from the last select statement.
For your smaller financial table, you would take the sum of the Col3 produced by the above formula, ie. the total value of all the runes used. A similar formula would be used to collect the count of the wax produced, its value, and the profit/loss for each day. This would let you complete the financial table.
If you do decide to go with this approach, and want any help with completing the tables, or the formulas, please share your sheet so "anyone can edit it", to make it easier for me to assist you.
I'm making a spreadsheet that includes a long list of values, with a column that contains a total of values, and after that an average of the values in the row. I need the averaged column to always be 1/6 of the value in the summed column, but I can't figure out a way to make it automatically calculate it for me for each new row.
So far, I have been doing it all manually (type out all the values, manually add them together for the total, then divide by 6 myself for the average) but I'd really like to automate the math parts. I have not found a single way to properly do this - using "=DIVIDE(K2,6)" as a modified version of a suggestion on this other question (modified to use the column I'm actually putting the numbers in) does literally nothing, and I'd have to manually change and paste it into each row, which is actually harder and more tedious than continuing to do the math myself.
Here's an example image of what my columns look like. All the math is correct so far, I just want to automate it so I can type fewer numbers:
EDIT: Combined answers from Scott and Player0 is what worked! thanks for being patient with me! I was able to also use that to make the Sum column function automatically as well, so both columns are fully automated now! :D
You don't have to enter the formula manually on every line.
Enter =K2/6 in cell L2; then select cell L2
and drag/fill it down to L12.
(That means click on the dot in the lower right corner of the cell
and drag it down.)
Or however far your sheet actually goes.
That will automatically fill in L3 with =K3/6,
L4 with =K4/6, and so on.
use on row 2:
=INDEX(IFERROR(K2:K/6; 0)
also see: ArrayFormula of Average on Infinite Truly Dynamic Range in Google Sheets