hi I'm trying to convert this python code to Lua
names=['Deepak','Reema','John','Deepak','Munna','Reema','Deepak','Amit','John','Reema']
d={}
for i in range(len(names)-1):
x=names[i]
c=0
for j in range(i,len(names)):
if names[j]==names[i]:
c=c+1
count=dict({x:c})
if x not in d.keys():
d.update(count)
print (d)
I got all the other parts working from top but I couldn't figure out how to convert this part into Lua
if x not in d.keys():
d.update(count)
would be really great if someone can help me make sense of this conversion
if x not in d.keys():
d.update(count)
x is the name currently indexed in that loop cycle
d is a dictionary that is used to store the count of each name
c is a dictionary with a single entry, the count c of x in names
So that line basically says:
if the current name x has not been counted yet (is not in our dictionary), add its count c to d using the name in x as key.
This code is not very efficient as it counts the names every time, even if that name has already been counted. The order should be changed so you only count if there is no count in d, yet.
There is also no need to iterate over the whole array for each entry. That nested loop is nonsense. You can count that in one go.
You shouldn't learn from whatever resource that is.
In Lua the snippet above would look something like:
if not d[x] then d[x] = c end
or simply
d[x] = d[x] or c
This is how you could implement it in Lua efficiently.
local names= {'Deepak','Reema','John','Deepak','Munna','Reema','Deepak',
'Amit','John','Reema'}
local counts = {}
for _, v in ipairs(names) do
counts[v] = counts[v] and counts[v] + 1 or 1
end
Related
Ive been coding for a mod Im making for a game but I ran into an issue with tables not returning values when the key is entered:
for k, v in pairs(self.math) do
print(self.exce[1])
print(self.exce[k])
print(k)
if self.exce[k] ~= nil then
self.math[k] = nil
end
end
This is the specific part of the script that is breaking. When I run these in the game it returns:
[lua]: true
[lua]: nil
[lua]: 1
Which means is basically saying that 1 is not equal to 1.
The function I used to store my data is
function filterExceptions.server_onException( self, id )
if self.exce[id] == nil then
self.exce[id] = true
self.network:sendToClients( "client_onList", id )
else
self.exce[id] = true
self.network:sendToClients( "client_offList", id )
end
end
In this code the self is a table made by the game you can acces and get game data from or store it in and the id comes from a function I made to get the players id. This id in this case is a 1 (I printed it multiple times).I know that every part of this code is working except for the code in the first block, and escpecialy the part where it tries to do self.exce[k]. Ive tried a lot like going trough every variable in self.exce to see if it was in there and then do stuff, but it still wouldn't work. Its very annoying how lua thinks that k ~= 1 while it definitely is, ive even used similar code in a part that is working.
So what is wrong about this code that its not printing the self.exce[k] while self.exce[1] does work? Dont worry about the creation of the table and stuff, cuz that is already happening whenever it is needed, else it would have given errors about that too.
Putting together a couple different comments and your code here, it looks like the index value of the array in some particular iteration of the "for in pairs" loop (or perhaps all of them, but I'll touch on that in a minute) is a string instead of an integer.
To summarize if you don't want to read the entire thing, "for k, v in pairs" loops will iterate through an entire array, setting k to the index of the value v. It appears your "for in pairs" loop is attempting to iterate through a value of nil where k is a string instead of an integer. You may also want to look into using ipairs instead of pairs in your for loop.
The value of someArray[1]is different than the value of someArray["1"].
The index [1] is a completely different index than the index ["1"] for any given array.
A simple fix would be to use
ind = tonumber(k)
print(self.exce[ind])
This converts the string k to a number type. Be aware this may throw an error if k is a non-numerical string. If the array has any values where the index is a non-numerical string, you may get an error. As the other answer suggests, converting the index k to a string instead of an integer would work as well, and would not throw errors if you used a non-numerical value for your indices.
My guess as to why this is happening would be that the function that you're using to store your data to an array, filterExceptions.server_onException( self, id ), is being passed a string instead of an integer, which would result in the k value being set to a string in that particular iteration of the "for in pairs" loop.
To help better understand this, here's a bit of example code:
a = {true, false, false}
a[1] = true
a["1"] = true
print("Raw for in pairs loop")
for k, v in pairs (a) do
print(type(k)..k)
end
print("For in pairs converting k to a number")
for k, v in pairs (a) do
ind = tonumber(k)
print(type(ind)..ind)
end
print("For in ipairs")
--which I'm not sure I completely understand but
--it seems to skip over any iteration where k is not a number
for k, v in ipairs(a) do
print(type(k)..k)
end
This code produces the following output:
Raw for in pairs loop
number1
number2
number3
string1
For in pairs converting k to a number
number1
number2
number3
number1
For in ipairs
number1
number2
number3
EDIT: Not sure what's going on in the self.math table so I can't comment on that.
EDIT2: I'd also refer you to the following link: lua: iterate through all pairs in table
The top answer there should help understand the difference between pairs and ipairs, if you don't already. You may want to use ipairs to prevent values of k where v == nil from being iterated through with pairs. pairs will iterate through every key/value pair, whereas ipairs will iterate through integer keys starting at 1 and going until it hits a nil value.
EDIT3: I'm sorry this is such a long answer...I just wanted to be thorough.
It apears converting the id to a string fixes this, tough im still confused as to why this same code worked on another block and not this one.
function filterExceptions.server_onException( self, id )
local id2 = tostring(id)
if self.exce[id2] == nil then
self.exce[id2] = true
self.network:sendToClients( "client_onList", id )
else
self.exce[id2] = true
self.network:sendToClients( "client_offList", id )
end
end
I am stuck trying to make the contese of a table (all integers) add together to form one sum. I am working on a project where the end goal is a percentage. I am putting the various quantities and storing them in one table. I want to then add all of those integers in the table together to get a sum. I haven't been able to find anything in the standard Library, so I have been tyring to use this:
function sum(t)
local sum = 0
for k,v in pairs(t) do
sum = sum + v
end
return sum
However, its not giving me anything after return sum.... Any and all help would be greatly appreciated.
A more generic solution to this problem of reducing the contents of a table (in this case by summing the elements) is outlined in this answer (warning: no type checking in code sketch).
If your function is not returning at all, it is probably because you are missing an end statement in the function definition.
If your function is returning zero, it is possible that there is a problem with the table you are passing as an argument. In other words, the parameter t may be nil or an empty table. In that case, the function would return zero, the value to which your local sum is initialized.
If you add print (k,v) in the loop for debugging, you can determine whether the function has anything to add. So I would try:
local function sum ( t ) do
print( "t", t ) -- for debugging: should not be nil
local s = 0
for k,v in pairs( t ) do
print(k,v) --for debugging
s = s + v
end
return s
end
local myTestData = { 1, 2, 4, 9 }
print( sum( myTestData) )
The expected output when running this code is
t table: [some index]
1 1
2 2
3 4
4 9
16
Notice that I've changed the variable name inside the function from sum to s. It's preferable not to use the function name sum as the variable holding the sum in the function definition. The local sum in the function overrides the global one, so for example, you couldn't call sum() recursively (i.e. call sum() in the definition of sum()).
I have simplified my code so you can have a better understanding:
x = {}
x["foo"]=1
a = {}
a[1]=x
x["foo"]=2
a[2]=x
print(a[1]["foo"])
print(a[2]["foo"])
The result is:
2
2
Or I was expecting:
1
2
I understant that a[1] is directing at the adress of the table x["foo"]. Then, when I change the value of this table, the variable a[1] points to the new value.
How can I tell Lua that I want to assign the VALUE and not link to and adress?
And just another thing: if x is a "simple" variable, not an array, the value is passed:
y = {}
x = 1
a = {}
a[1] = x
x = 2
a[2] = x
print(a[1])
print(a[2])
returns
1
2
The Lua manual, last but one paragraph of §2.1, says:
Tables, functions, threads, and (full) userdata values are objects: variables do not actually contain these values, only references to them. Assignment, parameter passing, and function returns always manipulate references to such values; these operations do not imply any kind of copy.
I'm having a problem with lua's table.concat, and suspect it is just my ignorance, but cannot find a verbose answer to why I'm getting this behavior.
> t1 = {"foo", "bar", "nod"}
> t2 = {["foo"]="one", ["bar"]="two", ["nod"]="yes"}
> table.concat(t1)
foobarnod
> table.concat(t2)
The table.concat run on t2 provides no results. I suspect this is because the keys are strings instead of integers (index values), but I'm not sure why that matters.
I'm looking for A) why table.concat doesn't accept string keys, and/or B) a workaround that would allow me to concatenate a variable number of table values in a handful of lines, without specifying the key names.
Because that's what table.concat is documented as doing.
Given an array where all elements are strings or numbers, returns table[i]..sep..table[i+1] ··· sep..table[j]. The default value for sep is the empty string, the default for i is 1, and the default for j is the length of the table. If i is greater than j, returns the empty string.
Non-array tables have no defined order so table.concat wouldn't be all that helpful then anyway.
You can write your own, inefficient, table concat function easily enough.
function pconcat(tab)
local ctab, n = {}, =1
for _, v in pairs(tab) do
ctab[n] = v
n = n + 1
end
return table.concat(ctab)
end
You could also use next manually to do the concat, etc. yourself if you wanted to construct the string yourself (though that's probably less efficient then the above version).
I need a base converter function for Lua. I need to convert from base 10 to base 2,3,4,5,6,7,8,9,10,11...36 how can i to this?
In the string to number direction, the function tonumber() takes an optional second argument that specifies the base to use, which may range from 2 to 36 with the obvious meaning for digits in bases greater than 10.
In the number to string direction, this can be done slightly more efficiently than Nikolaus's answer by something like this:
local floor,insert = math.floor, table.insert
function basen(n,b)
n = floor(n)
if not b or b == 10 then return tostring(n) end
local digits = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"
local t = {}
local sign = ""
if n < 0 then
sign = "-"
n = -n
end
repeat
local d = (n % b) + 1
n = floor(n / b)
insert(t, 1, digits:sub(d,d))
until n == 0
return sign .. table.concat(t,"")
end
This creates fewer garbage strings to collect by using table.concat() instead of repeated calls to the string concatenation operator ... Although it makes little practical difference for strings this small, this idiom should be learned because otherwise building a buffer in a loop with the concatenation operator will actually tend to O(n2) performance while table.concat() has been designed to do substantially better.
There is an unanswered question as to whether it is more efficient to push the digits on a stack in the table t with calls to table.insert(t,1,digit), or to append them to the end with t[#t+1]=digit, followed by a call to string.reverse() to put the digits in the right order. I'll leave the benchmarking to the student. Note that although the code I pasted here does run and appears to get correct answers, there may other opportunities to tune it further.
For example, the common case of base 10 is culled off and handled with the built in tostring() function. But similar culls can be done for bases 8 and 16 which have conversion specifiers for string.format() ("%o" and "%x", respectively).
Also, neither Nikolaus's solution nor mine handle non-integers particularly well. I emphasize that here by forcing the value n to an integer with math.floor() at the beginning.
Correctly converting a general floating point value to any base (even base 10) is fraught with subtleties, which I leave as an exercise to the reader.
you can use a loop to convert an integer into a string containting the required base. for bases below 10 use the following code, if you need a base larger than that you need to add a line that mapps the result of x % base to a character (usign an array for example)
x = 1234
r = ""
base = 8
while x > 0 do
r = "" .. (x % base ) .. r
x = math.floor(x / base)
end
print( r );