I have a formula to only show values if it isn't zero, -100%, or an error:
=IF(IFERROR((AA92 - AA91) / AA91; ); IF((AA92 - AA91) / AA91 = -100%; ; (AA92 - AA91) / AA91); )
What it does is basically
if (output == error) {
display("")
} else if (output == "-100%") {
display("")
} else {
display(output)
}
Is it possible to make some sort of reference to (AA92-AA91) / AA91 so I don't have to continuously repeat that part, without using a named range? As you might guess, I use this formula on several hundreds of rows
This sheet has been specially made for this question. This formula in cell B1 (and only cell B1) might be what you're looking for but didn't know was possible(?)
={"% Dif";ARRAYFORMULA(IF(A2:A="",,IFERROR(ARRAY_CONSTRAIN(A2:A/A1:A-1,ROWS(A2:A),1))))}
try:
=ARRAYFORMULA(IF(IFERROR((AA92:AA1000 - AA91:AA999) / AA91:AA999; );
IF((AA92:AA1000 - AA91:AA999) / AA91:AA999 = -100%; ;
(AA92:AA1000 - AA91:AA999) / AA91:AA999); ))
Related
I'm currently using this formula to highlight duplicates in my spreadsheet.
=ARRAYFORMULA(COUNTIF(A$2:$A2,$A2)>1)
Quite simple, it allows me to skip the first occurrence and only highlight 2nd, 3rd, ... occurrences.
I would like the formula to go a bit further and highlight near duplicates as well.
Meaning if there is only one character difference between 2 cells, then it should be considered as a duplicate.
For instance: "Marketing", "Marketng", "Marketingg" and "Market ing" would all be considered the same.
I've made a sample sheet in case my requirement is not straightforward to understand.
Thanks in advance.
Answer
Unfortunately, it is not possible to do this only through Formulas. Apps Scripts are need as well. The process for achieving your desired results is described below.
In Google Sheets, go to Extensions > Apps Script, paste the following code1 and save.
function TypoFinder(range, word) { // created by https://stackoverflow.com/users/19361936
if (!Array.isArray(range) || word == "") {
return false;
}
distances = range.map(row => row.map(cell => Levenshtein(cell, word))) // Iterate over range and check Levenshtein distance.
var accumulator = 0;
for (var i = 0; i < distances.length; i++) {
if (distances[i] < 2) {
accumulator++
} // Keep track of how many times there's a Levenshtein distance of 0 or 1.
}
return accumulator > 1;
}
function Levenshtein(a, b) { // created by https://stackoverflow.com/users/4269081
if (a.length == 0) return b.length;
if (b.length == 0) return a.length;
// swap to save some memory O(min(a,b)) instead of O(a)
if (a.length > b.length) {
var tmp = a;
a = b;
b = tmp;
}
var row = [];
// init the row
for (var i = 0; i <= a.length; i++) {
row[i] = i;
}
// fill in the rest
for (var i = 0; i < b.length; i++) {
var prev = i;
for (var j = 0; j < a.length; j++) {
var val;
if (b.charAt(i) == a.charAt(j)) {
val = row[j]; // match
} else {
val = Math.min(row[j] + 1, // substitution
prev + 1, // insertion
row[j + 1] + 1); // deletion
}
row[j] = prev;
prev = val;
}
row[a.length] = prev;
}
return row[a.length];
}
In cell B1, enter =TypoFinder($A$2:$A2,$A2). Autofill that formula down the column by draggin.
Create a conditional formatting rule for column A. Using Format Rules > Custom Formula, enter =B2:B.
At this point, you might wish to hide column B. To do so, right click on the column and press Hide Column.
The above explanation assumes the column you wish to highlight is Column A and the helper column is column B. Adjust appropriately.
Note that I have assumed you do not wish to highlight repeated blank columns as duplicate. If I am incorrect, remove || word == "" from line 2 of the provided snippet.
Explanation
The concept you have described is called Levenshtein Distance, which is a measure of how close together two strings are. There is no built-in way for Google Sheets to process this, so the Levenshtein() portion of the snippet above implements a custom function to do so instead. Then the TypoFinder() function is built on top of it, providing a method for evaluating a range of data against a specified "correct" word (looking for typos anywhere in the range).
Next, a helper column is used because Sheets has difficulties parsing custom formulas as part of a conditional formatting rule. Finally, the rule itself is implemented to check the helper column's determination of whether the row should be highlighted or not. Altogether, this highlights near-duplicate results in a specified column.
1 Adapted from duality's answer to a related question.
I'm studying recursion and I wrote this method to calculate the NĀ° number of the Fibonacci series:
fibonacci(int n, Map memo) {
if (memo.containsKey(n)) return memo[n]; // Memo check
if (n <= 2) return 1; // base case
// calculation
memo[n] = fibonacci(n - 1, memo) + fibonacci((n - 2), memo);
return memo[n];
}
I think it doesn't need to be explained, my problem is just how to call this function from the main, avoiding providing an empty Map.
this is how I call the function now:
fibonacci(n, {});
But I would rather prefer to call it just like this:
fibonacci(n);
The canonical approach is to make memo optional, and use a fresh map if the memo argument is omitted. Because you want to change and update the map, you can't use a default value for the parameter, because default values must be constant, and constant maps are not mutable.
So, written very concisely:
int fibonacci(int n, [Map<int, int>? memo]) {
if (n <= 2) return 1;
return (memo ??= {})[n] ??= fibonacci(n - 1, memo) + fibonacci(n - 2, memo);
}
The ??= operator assigns to the right-hand side if the value is null.
It's used both to initialize memo to a new map if the argument was omitted,
and to update the map if a cached value wasn't present.
I'd actually reconsider using a map. We know that the Fibonacci computation will compute a value for every prior number down to 1, so I'd just use a list instead:
int fibonacci(int n, [List<int?>? memo]) {
if (n <= 2) return 1;
return (memo ??= List<int?>.filled(n - 2))[n - 3] ??=
fibonacci(n - 1, memo) + fibonacci(n - 2, memo);
}
That should work just like the map.
(I subtract 3 from n when doing the lookup because no value below 3 needs the list - it's handled by the prior if).
There are multiple ways to do it. This is my personal favorite, because it also limits the function that is only used for internal means and it doesn't have the need to check every recursion, as you already know there is a map provided:
int fibonacci(int n) {
return _fibonacci(n, {});
}
int _fibonacci(int n, Map<int, int> memo) {
if (n <= 2) return 1; // base case
final previouslyCalculated = memo[n]; // Memo check
if(previouslyCalculated != null) {
return previouslyCalculated;
}
// calculation
final next = _fibonacci(n - 1, memo) + _fibonacci((n - 2), memo);
memo[n] = next;
return next;
}
void main() {
print(fibonacci(4));
}
As Dart does not support overloading, if you actually need both versions to be publicly available (or want both private) you would have to pick different names.
Please note that I added proper types to your methods and cleaned them up a bit for everything that would not compile once proper types are used. Make sure you always use proper types and don't rely on dynamic to somehow works it's magic. The compiler can only help you, if you are explicit about what you want to do. Otherwise they can only nod and let you run into any mistake you may have made. Be smart, let your compiler help, it will catch a lot of errors for you at compile time that you would otherwise have to spent countless hours on debugging.
This is the solution I've found so far but looks very verbose and inelegant:
fibonacci(int n, [Map<int, int>? memo]) {
memo == null ? memo = {} : null; // null check
if (memo.containsKey(n)) return memo[n];
if (n <= 2) return 1;
memo[n] = fibonacci(n - 1, memo) + fibonacci((n - 2), memo);
return memo[n];
}
In this way I can call just:
fibonacci(n);
Maybe I'm missing a keyword in my searches for a solution, but I didn't find what I'm looking for.
In Google Sheets I want to take a set of numbers and reorder it randomly. For example, start with the set [1,2,3,4] and get back [4,2,1,3].
Any ideas which function or a combination of functions may achieve this goal?
The entire process that I want to achieve is something like this:
I have a set of 4 fields. Their sum is fixed. I want to assign them randomized values.
So, I was thinking to iterate through this process:
Create a random integer between 0 and the max possible value (in the first iteration it's the fixed sum)
The new max value is the last max value minus the new random number.
Check if the new max is zero.
If not:
Return to the 1st step and repeat - This goes on until there are four values
If needed the 4th value shall be increased so the total will match the fixed sum.
Else, continue.
Randomize the order of the 4 values.
Assign the values to the 4 fields.
try:
=INDEX(SORT({{1; 2; 3; 4}, RANDARRAY(4, 1)}, 2, ),, 1)
or:
=INDEX(SORT({ROW(1:4), RANDARRAY(4, 1)}, 2, ),, 1)
Here are a couple of app script examples as well
function DiceRolls(nNumRolls) {
var anRolls = [];
nNumRolls = DefaultTo(nNumRolls, 1000)
for (var i = 1;i <= nNumRolls; i++) {
anRolls.push(parseInt((Math.random() * 6))+1);
}
return anRolls;
}
function CoinFlips(nNumFlips) {
var anFlips = [];
nNumFlips = DefaultTo(nNumFlips, 1000)
for (var i = 1;i <= nNumFlips; i++) {
anFlips.push(getRndInteger(1,2));
}
return anFlips;
}
function getRndInteger(min, max) {
return Math.floor(Math.random() * (max - min + 1) ) + min;
}
I have a set of data. What i am looking forwards is to add 2 blank rows after each set of 3 values like this
Hope to get help in getting this solved.
you can find the sample google sheet here : https://docs.google.com/spreadsheets/d/11nMvUWn3xcTfxlk4v30KruPr03HSheMk1jrxZPpJ_p4/edit?usp=sharing
Thanks
Shijilal
Solution:
IF it's the third row, Add 3 bunnies separated by a space, else keep the values as it is
JOIN them all and SPLIT by a bunny and TRANSPOSE
Sample:
=ARRAYFORMULA(TRANSPOSE(SPLIT(TEXTJOIN("š",1,IF(MOD(ROW(A2:A16),3)=1,A2:A16&REPT("š ",3),A2:A16)),"š")))
Some time ago, I created this custom function that may help you. I changed it slightly to meet your requirement and added it to the script editor.
function rowsBetween(range, s, rowsWithData, text) {
var n = [],
a = [],
i = 0;
while (i < s) {
a.push(text
)
i++;
}
range.forEach(function(r, i) {
n.push(r);
if((i + 2) % rowsWithData == 1) {
a.forEach(function(x) {
n.push(x);
});
}
});
return n;
}
This script will allow you to enter in the spreadsheet this (custom) formula (see also cell E2)
=rowsBetween(A2:A16, 2, 12,)
See if that works for you?
I have 30 columns and 1000 rows, I would like to compare column1 with another column. IF the value dont match then I would like to colour it red. Below is a small dataset in my spreadsheet:
A B C D E F ...
1 name sName email
2
3
.
n
Because I have a large dataset and I want to storing my columns in a array, the first row is heading. This is what I have done, however when testing I get empty result, can someone correct me what I am doing wrong?
var index = [];
var sheet = SpreadsheetApp.getActiveSheet();
function col(){
var data = sheet.getDataRange().getValues();
for (var i = 1; i <= data.length; i++) {
te = index[i] = data[1];
Logger.log(columnIndex[i])
if (data[3] != data[7]){
// column_id.setFontColor('red'); <--- I can set the background like this
}
}
}
From the code you can see I am scanning whole spreadsheet data[1] get the heading and in if loop (data[3] != data[7]) compare two columns. I do have to work on my colour variable but that can be done once I get the data that I need.
Try to check this tutorial if it can help you with your problem. This tutorial use a Google AppsScript to compare the two columns. If differences are found, the script should point these out. If no differences are found at all, the script should put out the text "[id]". Just customize this code for your own function.
Here is the code used to achieve this kind of comparison
function stringComparison(s1, s2) {
// lets test both variables are the same object type if not throw an error
if (Object.prototype.toString.call(s1) !== Object.prototype.toString.call(s2)){
throw("Both values need to be an array of cells or individual cells")
}
// if we are looking at two arrays of cells make sure the sizes match and only one column wide
if( Object.prototype.toString.call(s1) === '[object Array]' ) {
if (s1.length != s2.length || s1[0].length > 1 || s2[0].length > 1){
throw("Arrays of cells need to be same size and 1 column wide");
}
// since we are working with an array intialise the return
var out = [];
for (r in s1){ // loop over the rows and find differences using diff sub function
out.push([diff(s1[r][0], s2[r][0])]);
}
return out; // return response
} else { // we are working with two cells so return diff
return diff(s1, s2)
}
}
function diff (s1, s2){
var out = "[ ";
var notid = false;
// loop to match each character
for (var n = 0; n < s1.length; n++){
if (s1.charAt(n) == s2.charAt(n)){
out += "ā";
} else {
out += s2.charAt(n);
notid = true;
}
out += " ";
}
out += " ]"
return (notid) ? out : "[ id. ]"; // if notid(entical) return output or [id.]
}
For more information, just check the tutorial link above and this SO question on how to compare two Spreadsheets.