Edit: i know, always call the first element on list, it isnt the point. i want to call numbers[0] func. and it regenerate new int.actually codes are not same which mine, i have a custom class which based on functions with random int and i need to use list of my custom class , so if i use func in list it will be awesome, how can i make new numbers list each time. when app start list regenerated, but i want when i call the list, it will regenerated
i want to print new int for each print but it prints same int , i tried so many thing and i cant figure out
void main{
int ramdomint(){
final _random = new Random();
int _num = _random.nextInt(100);
return _num;
}
List<int> numbers=[ramdomint(),ramdomint(),ramdomint()];
void printNums(){
for(var i=0;i<3;i++){
List<int> newNumbers =new List.from(numbers); //what can i use for this?
print(newNumbers[0]); //edit:i dont want [i], iwant to use ewNumbers[0] for new int for each time
}
}
printNums();
// expected new int for each but same one
}
solution from a friend:
import 'dart:math';
int get ramdomint => Random().nextInt(100);
List<int> get numbers => [ramdomint, ramdomint, ramdomint];
void main() {
for (var i = 0; i < 3; i++) {
print(numbers[0]);
}
}
Do not nest functions. Move ramdomint and printNums outside main function.
Add an empty list of arguments to the main function.
printNums: pass list of numbers as an argument.
printNums: you don't need to copy the list to the newNumbers if you want only to display the content of the list.
printNums: the problem is, you access only first element of the list (with 0 index).
import 'dart:math';
void main() {
List<int> numbers = [ramdomint(), ramdomint(), ramdomint()];
printNums(numbers);
}
int ramdomint() => Random().nextInt(100);
void printNums(List<int> numbers) {
// Easier way:
for (int item in numbers) {
print(item);
}
// Your way:
for (int i = 0; i < numbers.length; i++) {
print(numbers[i]);
}
}
EDIT:
According to #jamesdlin's comment, you can extend list class to randomize unique values in the list:
import 'dart:math';
void main() {
var numbers = <int>[]..randomize();
printNums(numbers);
}
void printNums(List<int> numbers) {
// Easier way:
for (int item in numbers) {
print(item);
}
// Your way:
for (int i = 0; i < numbers.length; i++) {
print(numbers[i]);
}
}
extension on List<int> {
void randomize({
int length = 3,
int maxValue = 100,
}) {
final generator = Random();
for (var i = 0; i < length; i++) {
add(generator.nextInt(maxValue));
}
}
}
The Problem here is that you are creating a list from the numbers list and accessing only the first element.
So it always prints the first element.
import 'dart:math';
void main() {
int ramdomint(){
final _random = new Random();
int _num = _random.nextInt(100);
return _num;
}
List<int> numbers=[ramdomint(),ramdomint(),ramdomint()];
void printNums(){
for(var i=0;i<3;i++){
print(numbers[i]);
}
}
printNums();
}
Don't want newNumbers, because it is already in List.
and the usage of List.from() - Documentation
Hope that works!
Related
here is my code
import 'dart:io';
import 'dart:math';
void main() {
bool flag = false;
for (int i = 0; i < 100; i++) {
gameCode();
if (userNumber == computerNumber) {
flag = true;
break;
}
}
}
int randomNumber(number) {
Random randNumber = Random();
int random = randNumber.nextInt(number);
return random;
}
gameCode() {
int computerNumber = randomNumber(9);
print("start guessing the number : ");
int userNumber = int.parse(stdin.readLineSync()!);
if (userNumber == computerNumber) {
print("You got it");
}
}
in this code you can see gameCode function. in that function there is two value that i need to use in main function.so how do i return those two keyword from that function ?
//userNumber // computerNumber
this is the variable that i want to return from that code
Dart not support return multiple values in function, you can return it with array, map, or you can use third lib tuple
Dart does not support returning multiple values in the current latest version. I would in your case recommend creating a class for the specific purpose of define the result from gameCode(). So something like this:
class GameCodeResult {
int userNumber;
int computerNumber;
GameCodeResult({
required this.userNumber,
required this.computerNumber,
});
}
Which we can then use like this in your program:
import 'dart:io';
import 'dart:math';
void main() {
bool flag = false;
for (int i = 0; i < 100; i++) {
GameCodeResult result = gameCode();
if (result.userNumber == result.computerNumber) {
flag = true;
break;
}
}
}
final _random = Random();
int randomNumber(int maxNumber) => _random.nextInt(maxNumber);
GameCodeResult gameCode() {
int computerNumber = randomNumber(9);
print("start guessing the number : ");
int userNumber = int.parse(stdin.readLineSync()!);
if (userNumber == computerNumber) {
print("You got it");
}
return GameCodeResult(userNumber: userNumber, computerNumber: computerNumber);
}
Note, I also fixed your randomNumber() method since it is not recommended to generate a new Random() object for each new random number you want. We should instead reuse an instance of Random in our program.
Please refer to below code
import 'dart:io';
import 'dart:math';
void main() {
bool flag = false;
for (int i = 0; i < 100; i++) {
Map<String, dynamic> res = gameCode();
print(res);
if (res['user_number'] == res['computer_number']) {
flag = true;
break;
}
}
}
int randomNumber(number) {
Random randNumber = Random();
int random = randNumber.nextInt(number);
return random;
}
Map<String, dynamic> gameCode() {
int computerNumber = randomNumber(9);
print("start guessing the number : ");
int userNumber =
int.parse(stdin.readLineSync()!);
if (userNumber == computerNumber) {
print("You got it");
}
return {
"computer_number": computerNumber,
"user_number": userNumber,
};
}
I want to have a new random number every time to print it, but it prints the same on. I tried so many thing, but I can't figure out what's wrong. Help me, please!
import 'dart:math';
int next_int() { return new Random().nextInt(100); }
void main()
{
List<int> list = [next_int(), next_int(), next_int()];
// expected new int each time but got the same one
for (var i = 0; i < 3; i++)
{
List<int> cur_list = new List.from(list);
print(cur_list[0]);
}
}
This code will work as you expect:
import 'dart:math';
int next_int() { return new Random().nextInt(100); }
void main()
{
List<int> list = [next_int(), next_int(), next_int()];
// expected new int each time but got the same one
for (var i = 0; i < 3; i++)
{
List<int> cur_list = new List.from(list);
print(cur_list[i]); // <= Use the index value stored in "i" instead of 0
}
}
I'm not sure if I'm not understanding this correctly, but here's my code. I'm trying to get the StreamTransformer to act on the stream, but the values still come out the other end untouched.
Note: I added the .map() function, which does nothing, just to make sure it wasn't a missing map function that was my issue. I'm leaving it here just in case.
import 'dart:async';
void main() {
int count = 0;
var counterController = new StreamController();
counterController.stream.listen((value) => print(value));
void increment() {
counterController.add(count++);
}
final transformToString =
new StreamTransformer.fromHandlers(handleData: (number, sink) {
if (number.runtimeType == int) {
sink.add("The counter is at $number!");
} else {
sink.addError("$number is not an int!");
}
});
counterController.stream.map((input) => input).transform(transformToString);
for(int i=0; i < 10; i++){
increment();
}
}
Link to the code in DartPad
As was mentioned by my instructor, the transform function creates out a new stream. So I have to attach a listener to the transformed stream, I can't expect transformed values to come out of the old stream. So the modified code below works.
import 'dart:async';
void main() {
...
counterController.stream.map((input) => input)
.transform(transformToString).listen(print);
for(int i=0; i < 10; i++){
increment();
}
}
I have a question regarding this code, you can see in some methods that there are comments with a return, that is because I think I have to use a return method instead of a void method. My teacher told me to transform them to a void class, but isn't a method which modifies field variables suposed to return something? I'm in doubt because sometimes my teacher seems to not know so much about programming or has some doubts so, thank for your help beforehand.
public class ArraysClass {
private int[] array;
private int arrayLength;
public ArraysClass() {
setArrayLength();
array = new int[arrayLength];
}
public int setArrayLength() {
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a number to set the length of the array:");
arrayLength = scanner.nextInt();
System.out.println();
return arrayLength;
}
public void fillArray() {
Scanner scanner = new Scanner(System.in);
for (int i = 0; i < arrayLength; i++) {
System.out.println("Type a number to fill position " + i);
array[i] = scanner.nextInt();
}
// return array;
System.out.println();
}
public void findNumber() {
Scanner scanner = new Scanner(System.in);
int tofind, position;
System.out.println("Enter a number to search it in the array:");
tofind = scanner.nextInt();
position = Arrays.binarySearch(array, tofind);
if (position < 0) {
System.out.println("We did not find your number.");
} else {
System.out.println("The number you typed is in the next position: " + position);
}
System.out.println();
}
public void fillMethod() {
Scanner scanner = new Scanner(System.in);
int tofill;
System.out.println("Enter a number to fill the entire array with:");
tofill = scanner.nextInt();
Arrays.fill(array, tofill);
System.out.println();
//return array;
}
public void Sortmethod() {
Arrays.sort(array);
//return array;
}
private void showArray() {
System.out.println("Showing the array...");
for (int i = 0; i < arrayLength; i++) {
System.out.println(array[i]);
}
System.out.println();
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
ArraysClass arrayobj = new ArraysClass();
int choose;
do {
do {
System.out.println("1-Fill the array");
System.out.println("2-Find a number in the array");
System.out.println("3-Fill the entire array with a number");
System.out.println("4-Sort the array");
System.out.println("5-Show the array");
System.out.println("6-Exit");
System.out.println("Which one do you want to use?:");
choose = scanner.nextInt();
} while (choose < 1 && choose > 6);
switch (choose) {
case 1:
arrayobj.fillArray();
break;
case 2:
arrayobj.findNumber();
break;
case 3:
arrayobj.fillMethod();
break;
case 4:
arrayobj.Sortmethod();
break;
case 5:
arrayobj.showArray();
break;
case 6:
break;
}
} while (choose != 6);
}
}
In general, a method should return something if you need value from it. It is an approach used by some programmers to return a boolean even for do-only methods for success or failure or an int, for a status code. I do not follow these approaches. When I implement a method, I always ask myself how would I like to use that method. If I need a value from it, then it will have its type. Otherwise, it will be void. Let us see your methods:
setArrayLength: In general, from this name I would expect that you pass an int to it, representing the length and the method to be void. This is very common for setters, but here you are reading the actual value inside the method which is clearly inferior compared to having an int parameter, as your method will be useless if one wants to set the array length using a value not read from the console.
fillArray: I would expect this to be void, so I agree with its declaration, but again, the reading part should not be here.
findNumber: Should get the number to be found as a parameter and return an int, which represents its index, -1 if not found.
fillMethod: Should be void and should have an int parameter, which represents the value to be used to fill the array.
sortMethod: ok, maybe return the resulting array, but depends on your needs.
showArray: I would expect a PrintStream there, you will not necessarily output to System.out
General mistake: You mix methods with in/out operations to the console, the code is not general enough this way.
I can conveniently change opsCount variable directly from inside the function,
because there is only one of that type of variable.
int opsCount = 0;
int jobXCount = 0;
int jobYCount = 0;
int jobZCount = 0;
void doStats(var jobCount) {
opsCount++;
jobCount++;
}
main() {
doStats(jobXCount);
}
But there are many jobCount variables, so how can I change effectively that variable, which is used in parameter, when function is called?
I think I know what you are asking. Unfortunately, the answer is "you can't do this unless you are willing to wrap your integers". Numbers are immutable objects, you can't change their value. Even though Dart's numbers are objects, and they are passed by reference, their intrinsic value can't be changed.
See also Is there a way to pass a primitive parameter by reference in Dart?
You can wrap the variables, then you can pass them as reference:
class IntRef {
IntRef(this.val);
int val;
#override
String toString() => val.toString();
}
IntRef opsCount = new IntRef(0);
IntRef jobXCount = new IntRef(0);
IntRef jobYCount = new IntRef(0);
IntRef jobZCount = new IntRef(0);
void doStats(var jobCount) {
opsCount.val++;
jobCount.val++;
}
main() {
doStats(jobXCount);
print('opsCount: $opsCount; jobXCount: $jobXCount; jobYCount: $jobYCount; jobZCount: $jobZCount');
}
EDIT
According to Roberts comment ..
With a custom operator this would look like:
class IntRef {
IntRef(this.val);
int val;
#override
String toString() => val.toString();
operator +(int other) {
val += other;
return this;
}
}
void doStats(var jobCount) {
opsCount++;
jobCount++;
}