I made a timer in Swift using the following code:
import UIKit
class ViewController: UIViewController {
// #IBOutlet var ProgressBar: UIProgressView!
#IBOutlet var label: UILabel!
var hours: Int = 0
var mins: Int = 0
var secs: Int = 0
override func viewDidLoad() {
super.viewDidLoad()
//ProgressBar.progress = 0.0
}
#IBAction func didTapAddButton() {
// var progress: Float = 0.0
//ProgressBar.progress = progress
let vc = storyboard?.instantiateViewController(identifier:"date_picker") as! DateViewController
vc.title = "New Event"
vc.completionHandler = { [weak self] name, date in
DispatchQueue.main.async {
self?.didCreateEvent(name: name, targetDate: date)
}
}
navigationController?.pushViewController(vc, animated: true)
}
private func didCreateEvent(name: String, targetDate: Date){
self.title = name
let difference = floor(targetDate.timeIntervalSince(Date()))
if difference > 0.0 {
let computedHours: Int = Int(difference) / 3600
let remainder: Int = Int(difference) - (computedHours * 3600)
let minutes: Int = remainder / 60
let seconds: Int = Int(difference) - (computedHours * 3600) - (minutes * 60)
print("\(computedHours) \(minutes) \(seconds)")
hours = computedHours
mins = minutes
secs = seconds
updateLabel()
startTimer()
}
else{
print("negative interval")
}
}
private func startTimer() {
Timer.scheduledTimer(withTimeInterval: 1.0, repeats: true, block: { _ in
if self.secs > 0 {
self.secs = self.secs - 1
}
else if self.mins > 0 && self.secs == 0 {
self.mins = self.mins - 1
self.secs = 59
}
else if self.hours > 0 && self.mins == 0 && self.secs == 0 {
self.hours = self.hours - 1
self.mins = 59
self.secs = 59
}
self.updateLabel()
})
}
private func updateLabel() {
label.text = "\(hours):\(mins):\(secs)"
}
}
I am trying to make a progress bar somewhat show how much time is left. I want the bar to be full when there is no time left. How should I do this?
I tried searching how to do this but Google wasn't helpful.
So the first thing you want to do is bring all your values for hour, minutes, and seconds into a singular combined value, represented as something like totalSeconds or whatever you want.
var hours: Int = XXX
var minutes: Int = XXX
var seconds: Int = XXX
var totalSeconds: Int = 0
totalSeconds = getTotalSecondsFrom(hours, minutes, seconds)
func getTotalSecondsFrom(hours: Int, minutes: Int, seconds: Int) -> Int {
let hoursToSec = (hours * 60) * 60
let minutesToSec = minutes * 60
return hoursToSec + minutesToSec + seconds
}
Once you have all of your values brought down into a singular value now you have a representation for calculating a progress bar's maximum limit. Remember that a progress bar can only have values betweeen 0.0 and 1.0 which is perfect for a percentage calculation. In the interest of explaining in a way that will make sense for learning, let's look at this from a different perspective. How can we get a percentage from a total maximum, then map it to a value in the range of 0.0 -> 1.0?
func getCompletedPercent(currentSeconds: Int, totalSeconds: Int) -> Float {
return Float(currentSeconds) / Float(totalSeconds)
}
Why does this work? Well, let's assume our total seconds are 5000 and current is 500. Doing the math, 500 / 5000 = 0.1 which is 1/10th or 10% of 5000, which is exactly what we're looking for. With this knowledge in hand all you need to do at this point is set your progress bars maximum to 1.0 and then every second, in your timer, update it's current progress using the functional examples getTotalSecondsFrom(...) and getCompletedPercent(...). Of course your version may vary slightly, but the concepts are the same.
I have a (somewhat?) basic question regarding time conversions in Swift.
I have an integer that I would like converted into Hours / Minutes / Seconds.
Example: Int = 27005 would give me:
7 Hours 30 Minutes 5 Seconds
I know how to do this in PHP, but alas, swift isn't PHP.
Define
func secondsToHoursMinutesSeconds(_ seconds: Int) -> (Int, Int, Int) {
return (seconds / 3600, (seconds % 3600) / 60, (seconds % 3600) % 60)
}
Use
> secondsToHoursMinutesSeconds(27005)
(7,30,5)
or
let (h,m,s) = secondsToHoursMinutesSeconds(27005)
The above function makes use of Swift tuples to return three values at once. You destructure the tuple using the let (var, ...) syntax or can access individual tuple members, if need be.
If you actually need to print it out with the words Hours etc then use something like this:
func printSecondsToHoursMinutesSeconds(_ seconds: Int) {
let (h, m, s) = secondsToHoursMinutesSeconds(seconds)
print ("\(h) Hours, \(m) Minutes, \(s) Seconds")
}
Note that the above implementation of secondsToHoursMinutesSeconds() works for Int arguments. If you want a Double version you'll need to decide what the return values are - could be (Int, Int, Double) or could be (Double, Double, Double). You could try something like:
func secondsToHoursMinutesSeconds(seconds: Double) -> (Double, Double, Double) {
let (hr, minf) = modf(seconds / 3600)
let (min, secf) = modf(60 * minf)
return (hr, min, 60 * secf)
}
In macOS 10.10+ / iOS 8.0+ (NS)DateComponentsFormatter has been introduced to create a readable string.
It considers the user's locale und language.
let interval = 27005
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.hour, .minute, .second]
formatter.unitsStyle = .full
let formattedString = formatter.string(from: TimeInterval(interval))!
print(formattedString)
The available unit styles are positional, abbreviated, short, full, spellOut and brief.
For more information please read the documenation.
Building upon Vadian's answer, I wrote an extension that takes a Double (of which TimeInterval is a type alias) and spits out a string formatted as time.
extension Double {
func asString(style: DateComponentsFormatter.UnitsStyle) -> String {
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.hour, .minute, .second, .nanosecond]
formatter.unitsStyle = style
return formatter.string(from: self) ?? ""
}
}
Here are what the various DateComponentsFormatter.UnitsStyle options look like:
10000.asString(style: .positional) // 2:46:40
10000.asString(style: .abbreviated) // 2h 46m 40s
10000.asString(style: .short) // 2 hr, 46 min, 40 sec
10000.asString(style: .full) // 2 hours, 46 minutes, 40 seconds
10000.asString(style: .spellOut) // two hours, forty-six minutes, forty seconds
10000.asString(style: .brief) // 2hr 46min 40sec
In Swift 5:
var i = 9897
func timeString(time: TimeInterval) -> String {
let hour = Int(time) / 3600
let minute = Int(time) / 60 % 60
let second = Int(time) % 60
// return formated string
return String(format: "%02i:%02i:%02i", hour, minute, second)
}
To call function
timeString(time: TimeInterval(i))
Will return 02:44:57
I have built a mashup of existing answers to simplify everything and reduce the amount of code needed for Swift 3.
func hmsFrom(seconds: Int, completion: #escaping (_ hours: Int, _ minutes: Int, _ seconds: Int)->()) {
completion(seconds / 3600, (seconds % 3600) / 60, (seconds % 3600) % 60)
}
func getStringFrom(seconds: Int) -> String {
return seconds < 10 ? "0\(seconds)" : "\(seconds)"
}
Usage:
var seconds: Int = 100
hmsFrom(seconds: seconds) { hours, minutes, seconds in
let hours = getStringFrom(seconds: hours)
let minutes = getStringFrom(seconds: minutes)
let seconds = getStringFrom(seconds: seconds)
print("\(hours):\(minutes):\(seconds)")
}
Prints:
00:01:40
Here is a more structured/flexible approach: (Swift 3)
struct StopWatch {
var totalSeconds: Int
var years: Int {
return totalSeconds / 31536000
}
var days: Int {
return (totalSeconds % 31536000) / 86400
}
var hours: Int {
return (totalSeconds % 86400) / 3600
}
var minutes: Int {
return (totalSeconds % 3600) / 60
}
var seconds: Int {
return totalSeconds % 60
}
//simplified to what OP wanted
var hoursMinutesAndSeconds: (hours: Int, minutes: Int, seconds: Int) {
return (hours, minutes, seconds)
}
}
let watch = StopWatch(totalSeconds: 27005 + 31536000 + 86400)
print(watch.years) // Prints 1
print(watch.days) // Prints 1
print(watch.hours) // Prints 7
print(watch.minutes) // Prints 30
print(watch.seconds) // Prints 5
print(watch.hoursMinutesAndSeconds) // Prints (7, 30, 5)
Having an approach like this allows the adding of convenience parsing like this:
extension StopWatch {
var simpleTimeString: String {
let hoursText = timeText(from: hours)
let minutesText = timeText(from: minutes)
let secondsText = timeText(from: seconds)
return "\(hoursText):\(minutesText):\(secondsText)"
}
private func timeText(from number: Int) -> String {
return number < 10 ? "0\(number)" : "\(number)"
}
}
print(watch.simpleTimeString) // Prints 07:30:05
It should be noted that purely Integer based approaches don't take leap day/seconds into account. If the use case is dealing with real dates/times Date and Calendar should be used.
Swift 5:
extension Int {
func secondsToTime() -> String {
let (h,m,s) = (self / 3600, (self % 3600) / 60, (self % 3600) % 60)
let h_string = h < 10 ? "0\(h)" : "\(h)"
let m_string = m < 10 ? "0\(m)" : "\(m)"
let s_string = s < 10 ? "0\(s)" : "\(s)"
return "\(h_string):\(m_string):\(s_string)"
}
}
Usage:
let seconds : Int = 119
print(seconds.secondsToTime()) // Result = "00:01:59"
Swift 4
func formatSecondsToString(_ seconds: TimeInterval) -> String {
if seconds.isNaN {
return "00:00"
}
let Min = Int(seconds / 60)
let Sec = Int(seconds.truncatingRemainder(dividingBy: 60))
return String(format: "%02d:%02d", Min, Sec)
}
SWIFT 3.0 solution based roughly on the one above using extensions.
extension CMTime {
var durationText:String {
let totalSeconds = CMTimeGetSeconds(self)
let hours:Int = Int(totalSeconds.truncatingRemainder(dividingBy: 86400) / 3600)
let minutes:Int = Int(totalSeconds.truncatingRemainder(dividingBy: 3600) / 60)
let seconds:Int = Int(totalSeconds.truncatingRemainder(dividingBy: 60))
if hours > 0 {
return String(format: "%i:%02i:%02i", hours, minutes, seconds)
} else {
return String(format: "%02i:%02i", minutes, seconds)
}
}
}
Use it with AVPlayer calling it like this?
let dTotalSeconds = self.player.currentTime()
playingCurrentTime = dTotalSeconds.durationText
Here is another simple implementation in Swift3.
func seconds2Timestamp(intSeconds:Int)->String {
let mins:Int = intSeconds/60
let hours:Int = mins/60
let secs:Int = intSeconds%60
let strTimestamp:String = ((hours<10) ? "0" : "") + String(hours) + ":" + ((mins<10) ? "0" : "") + String(mins) + ":" + ((secs<10) ? "0" : "") + String(secs)
return strTimestamp
}
Xcode 12.1. Swift 5
DateComponentsFormatter: A formatter that creates string representations,
by using unitsStyle u can get a string as you want and mention allowedUnits.
e.g: output for unitsStyle:: for 10000 secods
full = "2 hours, 46 minutes, 49 seconds"
positional = "2:46:40"
abbreviated = "2h 46m 40s"
spellOut = "two hours, forty-six minutes, forty seconds”
short = "2hr,46 min,40 sec"
brief = "2hr 46min 40sec"
Easy to use:
let time = convertSecondsToHrMinuteSec(seconds: 10000)
func convertSecondsToHrMinuteSec(seconds:Int) -> String{
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.hour, .minute, .second]
formatter.unitsStyle = .full
let formattedString = formatter.string(from:TimeInterval(seconds))!
print(formattedString)
return formattedString
}
I had answered to the similar question, however you don't need to display milliseconds in the result. Hence my solution requires iOS 10.0, tvOS 10.0, watchOS 3.0 or macOS 10.12.
You should call func convertDurationUnitValueToOtherUnits(durationValue:durationUnit:smallestUnitDuration:) from the answer that I already mentioned here:
let secondsToConvert = 27005
let result: [Int] = convertDurationUnitValueToOtherUnits(
durationValue: Double(secondsToConvert),
durationUnit: .seconds,
smallestUnitDuration: .seconds
)
print("\(result[0]) hours, \(result[1]) minutes, \(result[2]) seconds") // 7 hours, 30 minutes, 5 seconds
Answer of #r3dm4n was great. However, I needed also hour in it. Just in case someone else needed too here it is:
func formatSecondsToString(_ seconds: TimeInterval) -> String {
if seconds.isNaN {
return "00:00:00"
}
let sec = Int(seconds.truncatingRemainder(dividingBy: 60))
let min = Int(seconds.truncatingRemainder(dividingBy: 3600) / 60)
let hour = Int(seconds / 3600)
return String(format: "%02d:%02d:%02d", hour, min, sec)
}
Swift 5 & String Response, In presentable format
public static func secondsToHoursMinutesSecondsStr (seconds : Int) -> String {
let (hours, minutes, seconds) = secondsToHoursMinutesSeconds(seconds: seconds);
var str = hours > 0 ? "\(hours) h" : ""
str = minutes > 0 ? str + " \(minutes) min" : str
str = seconds > 0 ? str + " \(seconds) sec" : str
return str
}
public static func secondsToHoursMinutesSeconds (seconds : Int) -> (Int, Int, Int) {
return (seconds / 3600, (seconds % 3600) / 60, (seconds % 3600) % 60)
}
Usage:
print(secondsToHoursMinutesSecondsStr(seconds: 20000)) // Result = "5 h 33 min 20 sec"
According to GoZoner answer I have wrote an Extension to get the time formatted according to the hours, minute, and seconds:
extension Double {
func secondsToHoursMinutesSeconds () -> (Int?, Int?, Int?) {
let hrs = self / 3600
let mins = (self.truncatingRemainder(dividingBy: 3600)) / 60
let seconds = (self.truncatingRemainder(dividingBy:3600)).truncatingRemainder(dividingBy:60)
return (Int(hrs) > 0 ? Int(hrs) : nil , Int(mins) > 0 ? Int(mins) : nil, Int(seconds) > 0 ? Int(seconds) : nil)
}
func printSecondsToHoursMinutesSeconds () -> String {
let time = self.secondsToHoursMinutesSeconds()
switch time {
case (nil, let x? , let y?):
return "\(x) min \(y) sec"
case (nil, let x?, nil):
return "\(x) min"
case (let x?, nil, nil):
return "\(x) hr"
case (nil, nil, let x?):
return "\(x) sec"
case (let x?, nil, let z?):
return "\(x) hr \(z) sec"
case (let x?, let y?, nil):
return "\(x) hr \(y) min"
case (let x?, let y?, let z?):
return "\(x) hr \(y) min \(z) sec"
default:
return "n/a"
}
}
}
let tmp = 3213123.printSecondsToHoursMinutesSeconds() // "892 hr 32 min 3 sec"
Here is what I use for my Music Player in Swift 4+. I am converting seconds Int to readable String format
extension Int {
var toAudioString: String {
let h = self / 3600
let m = (self % 3600) / 60
let s = (self % 3600) % 60
return h > 0 ? String(format: "%1d:%02d:%02d", h, m, s) : String(format: "%1d:%02d", m, s)
}
}
Use like this:
print(7903.toAudioString)
Output: 2:11:43
Latest Code: XCode 10.4 Swift 5
extension Int {
func timeDisplay() -> String {
return "\(self / 3600):\((self % 3600) / 60):\((self % 3600) % 60)"
}
}
From #Gamec answer
typealias CallDuration = Int
extension CallDuration {
func formatedString() -> String? {
let hours = self / 3600
let minutes = (self / 60) % 60
let seconds = self % 60
if hours > 0 { return String(format: "%0.2d:%0.2d:%0.2d", hours, minutes, seconds) }
return String(format: "%0.2d:%0.2d", minutes, seconds)
}
}
Usage:
let duration: CallDuration = 3000
duration.formatedString() // 50 minute
The simplest way imho:
let hours = time / 3600
let minutes = (time / 60) % 60
let seconds = time % 60
return String(format: "%0.2d:%0.2d:%0.2d", hours, minutes, seconds)
NSTimeInterval is Double do do it with extension. Example:
extension Double {
var formattedTime: String {
var formattedTime = "0:00"
if self > 0 {
let hours = Int(self / 3600)
let minutes = Int(truncatingRemainder(dividingBy: 3600) / 60)
formattedTime = String(hours) + ":" + (minutes < 10 ? "0" + String(minutes) : String(minutes))
}
return formattedTime
}
}
convert a number into time as a string
func convertToHMS(number: Int) -> String {
let hour = number / 3600;
let minute = (number % 3600) / 60;
let second = (number % 3600) % 60 ;
var h = String(hour);
var m = String(minute);
var s = String(second);
if h.count == 1{
h = "0\(hour)";
}
if m.count == 1{
m = "0\(minute)";
}
if s.count == 1{
s = "0\(second)";
}
return "\(h):\(m):\(s)"
}
print(convertToHMS(number:3900))
I went ahead and created a closure for this (in Swift 3).
let (m, s) = { (secs: Int) -> (Int, Int) in
return ((secs % 3600) / 60, (secs % 3600) % 60) }(299)
This will give m = 4 and s = 59. So you can format that as you wish. You may of course want to add hours as well, if not more information.
Swift 4 I'm using this extension
extension Double {
func stringFromInterval() -> String {
let timeInterval = Int(self)
let millisecondsInt = Int((self.truncatingRemainder(dividingBy: 1)) * 1000)
let secondsInt = timeInterval % 60
let minutesInt = (timeInterval / 60) % 60
let hoursInt = (timeInterval / 3600) % 24
let daysInt = timeInterval / 86400
let milliseconds = "\(millisecondsInt)ms"
let seconds = "\(secondsInt)s" + " " + milliseconds
let minutes = "\(minutesInt)m" + " " + seconds
let hours = "\(hoursInt)h" + " " + minutes
let days = "\(daysInt)d" + " " + hours
if daysInt > 0 { return days }
if hoursInt > 0 { return hours }
if minutesInt > 0 { return minutes }
if secondsInt > 0 { return seconds }
if millisecondsInt > 0 { return milliseconds }
return ""
}
}
useage
// assume myTimeInterval = 96460.397
myTimeInteval.stringFromInterval() // 1d 2h 47m 40s 397ms
neek's answer isn't correct.
here's the correct version
func seconds2Timestamp(intSeconds:Int)->String {
let mins:Int = (intSeconds/60)%60
let hours:Int = intSeconds/3600
let secs:Int = intSeconds%60
let strTimestamp:String = ((hours<10) ? "0" : "") + String(hours) + ":" + ((mins<10) ? "0" : "") + String(mins) + ":" + ((secs<10) ? "0" : "") + String(secs)
return strTimestamp
}
Another way would be convert seconds to date and take the components i.e seconds, minutes and hour from date itself.
This solution has limitation only till 23:59:59
Is it possible get playing time and total play time in AVPlayer? If yes, how can I do this?
You can access currently played item by using currentItem property:
AVPlayerItem *currentItem = yourAVPlayer.currentItem;
Then you can easily get the requested time values
CMTime duration = currentItem.duration; //total time
CMTime currentTime = currentItem.currentTime; //playing time
Swift 5:
if let currentItem = player.currentItem {
let duration = CMTimeGetSeconds(currentItem.duration)
let currentTime = CMTimeGetSeconds(currentItem.currentTime())
print("Duration: \(duration) s")
print("Current time: \(currentTime) s")
}
_audioPlayer = [self playerWithAudio:_audio];
_observer =
[_audioPlayer addPeriodicTimeObserverForInterval:CMTimeMake(1, 2)
queue:dispatch_get_main_queue()
usingBlock:^(CMTime time)
{
_progress = CMTimeGetSeconds(time);
}];
Swift 3
let currentTime:Double = player.currentItem.currentTime().seconds
You can get the seconds of your current time by accessing the seconds property of the currentTime(). This will return a Double that represents the seconds in time. Then you can use this value to construct a readable time to present to your user.
First, include a method to return the time variables for H:mm:ss that you will display to the user:
func getHoursMinutesSecondsFrom(seconds: Double) -> (hours: Int, minutes: Int, seconds: Int) {
let secs = Int(seconds)
let hours = secs / 3600
let minutes = (secs % 3600) / 60
let seconds = (secs % 3600) % 60
return (hours, minutes, seconds)
}
Next, a method that will convert the values you retrieved above into a readable string:
func formatTimeFor(seconds: Double) -> String {
let result = getHoursMinutesSecondsFrom(seconds: seconds)
let hoursString = "\(result.hours)"
var minutesString = "\(result.minutes)"
if minutesString.characters.count == 1 {
minutesString = "0\(result.minutes)"
}
var secondsString = "\(result.seconds)"
if secondsString.characters.count == 1 {
secondsString = "0\(result.seconds)"
}
var time = "\(hoursString):"
if result.hours >= 1 {
time.append("\(minutesString):\(secondsString)")
}
else {
time = "\(minutesString):\(secondsString)"
}
return time
}
Now, update the UI with the previous calculations:
func updateTime() {
// Access current item
if let currentItem = player.currentItem {
// Get the current time in seconds
let playhead = currentItem.currentTime().seconds
let duration = currentItem.duration.seconds
// Format seconds for human readable string
playheadLabel.text = formatTimeFor(seconds: playhead)
durationLabel.text = formatTimeFor(seconds: duration)
}
}
With Swift 4.2, use this;
let currentPlayer = AVPlayer()
if let currentItem = currentPlayer.currentItem {
let duration = currentItem.asset.duration
}
let currentTime = currentPlayer.currentTime()
Swift 4
self.playerItem = AVPlayerItem(url: videoUrl!)
self.player = AVPlayer(playerItem: self.playerItem)
self.player?.addPeriodicTimeObserver(forInterval: CMTimeMakeWithSeconds(1, 1), queue: DispatchQueue.main, using: { (time) in
if self.player!.currentItem?.status == .readyToPlay {
let currentTime = CMTimeGetSeconds(self.player!.currentTime())
let secs = Int(currentTime)
self.timeLabel.text = NSString(format: "%02d:%02d", secs/60, secs%60) as String//"\(secs/60):\(secs%60)"
})
}
AVPlayerItem *currentItem = player.currentItem;
NSTimeInterval currentTime = CMTimeGetSeconds(currentItem.currentTime);
NSLog(#" Capturing Time :%f ",currentTime);
Swift:
let currentItem = yourAVPlayer.currentItem
let duration = currentItem.asset.duration
var currentTime = currentItem.asset.currentTime
Swift 5:
Timer.scheduledTimer seems better than addPeriodicTimeObserver if you want to have a smooth progress bar
static public var currenTime = 0.0
static public var currenTimeString = "00:00"
Timer.scheduledTimer(withTimeInterval: 1/60, repeats: true) { timer in
if self.player!.currentItem?.status == .readyToPlay {
let timeElapsed = CMTimeGetSeconds(self.player!.currentTime())
let secs = Int(timeElapsed)
self.currenTime = timeElapsed
self.currenTimeString = NSString(format: "%02d:%02d", secs/60, secs%60) as String
print("AudioPlayer TIME UPDATE: \(self.currenTime) \(self.currenTimeString)")
}
}
Swift 4.2:
let currentItem = yourAVPlayer.currentItem
let duration = currentItem.asset.duration
let currentTime = currentItem.currentTime()
in swift 5+
You can query the player directly to find the current time of the actively playing AVPlayerItem.
The time is stored in a CMTime Struct for ease of conversion to various scales such as 10th of sec, 100th of a sec etc
In most cases we need to represent times in seconds so the following will show you what you want
let currentTimeInSecs = CMTimeGetSeconds(player.currentTime())