I think the tile explains it self how do I access these files and read and write them?
this is what my code looks like
local openFile = assert(io.open(wasd_ ,"r")) -- wasd_ is the .txt file I want to open
local t = openFile:read("r") -- read the file
I'm not sure if in the 1st line of code if I shut replace "wasd_" with "wasd_.txt" or the file path (i.e replace wasd_ with something like this --> C:/users/stuff/blah/thing/wasd_)
ant help is greatly appreciated
According to the documentation:
local Filename = "wasd_.txt"
local File = io.open(Filename, "r")
local FileContent = File:read("*all")
File:close()
The file will be open according to the current directory %CD%. If your current directory is C:\test\, then the open file will be C:\test\wasd_.txt. If you want to find another file, you could specify the full path C:\users\stuff\blah\thing\wasd_.txt
you can do it all-at-once if you want; Lua allows that, but you have more control over editing when you do it line-at-a-time; in case you need to use certain edits on certain lines. It's also much safer to write to a new file, so you still have your original, to compare and try again, if need be.
line by line, keeping original, writing to new text
local path = 'C:/users/stuff/blah/thing/wasd_.txt' -- wasd_ is the .txt file I want to open
local newpath = path :sub( 1, -5 ) ..'new.txt' -- C:/users/stuff/blah/thing/wasd_new.txt
local iput = assert( io.input( path ) )
local oput = assert( io.output( newpath ) )
local linenum = 0 -- used as a counter
while true do
linenum = linenum +1
local line = iput :read()
if line == nil then break end -- break out of loop if there's nothing else to read
local newline, _ = line :gsub( 'this', 'that' ) -- do your changes here
if linenum == 1 then newline = 'HEADER: ' ..newline end -- example of specific line edit
oput :write( linenum ..' ' ..newline ..'\n' ) -- read() line strips newline char, so add it back
end
iput :close()
oput :close()
You can take out all instances of linenum if it's not needed, but I would strongly recommend that you use two separate read & write files, at least until you're comfortable it's doing exactly what you want, and has no errors.
Related
I typed up my code not expecting it to work first try, and of course it didn't. I kept tweaking it for hours on end, but I kept getting the same result until I made as simple as possible.
local file = io.open("File_Name", "r")
io.output(file)
local test = io.read('*all')
io.close(file)
print(test)
After getting (no return) from this, I've decided to take a break and let someone else answer my question.
The problem with your code is that you're trying to read from whatever is defined as your input file. You only opened a file, but you didn't tell Lua to use it as the input file, so io.read won't read from the opened file, yet.
local file = io.open(filename, "r")
local test = file:read("a")
io.close(file)
print(test)
Alternatively:
local file = io.open(filename, "r")
io.input(file)
local test = io.read("a")
io.close(file)
print(test)
or
local file = io.open(filename, "r")
local test = io.input(file):read("a")
io.close(file)
print(test)
Of course you should check wether opening the file succeeded befor using the file handle.
Depending on your Lua version the read format is either *a or a. I cannot remember if both is ok in all versions. At least that's what the manual says.
I am learning the Lua IO library. I'm having trouble with io.write(). In Programming Design in Lua, there is a piece of code that iterates through the file line by line and precedes each line with a serial number.
This is the file I`m working on:
test file: "iotest.txt"
This is my code
io.input("iotest.txt")
-- io.output("iotest.txt")
local count = 0
for line in io.lines() do
count=count+1
io.write(string.format("%6d ",count), line, "\n")
end
This is the result of the terminal display, but this result cannot be written to the file, whether I add IO. Output (" iotest.txt ") or not.
the results in terminal
This is the result of file, we can see there is no change
The result after code running
Just add io.flush() after your write operations to save the data to the file.
io.input("iotest.txt")
io.output("iotestout.txt")
local count = 0
for line in io.lines() do
count=count+1
io.write(string.format("%6d ",count), line, "\n")
end
io.flush()
io.close()
Refer to Lua 5.4 Reference Manual : 6.8 - Input and Output Facilities
io.flush() will save any written data to the output file which you set with io.output
See koyaanisqatsi's answer for the optional use of file handles. This becomes especially useful if you're working on multiple files at a time and gives you more control on how to interact with the file.
That said you should also have different files for input and output. You'll agree that it doesn't make sense to read and write from and to the same file alternatingly.
For writing to a file you need a file handle.
This handle comes from: io.open()
See: https://www.lua.org/manual/5.4/manual.html#6.8
A file handle has methods that acts on self.
Thats the function after the : at file handle.
So io.write() puts out on stdout and file:write() in a file.
Example function that can dump a defined function to a file...
fdump=function(func,path)
assert(type(func)=="function")
assert(type(path)=="string")
-- Get the file handle (file)
local file,err = io.open(path, "wb")
assert(file, err)
local chunk = string.dump(func,true)
file:write(chunk)
file:flush()
file:close()
return 'DONE'
end
Here are the methods, taken from io.stdin
close = function: 0x566032b0
seek = function: 0x566045f0
flush = function: 0x56603d10
setvbuf = function: 0x56604240
write = function: 0x56603e70
lines = function: 0x566040c0
read = function: 0x56603c90
This makes it able to use it directly like...
( Lua console: lua -i )
> do io.stdout:write('Input: ') local result=io.stdin:read() return result end
Input: d
d
You are trying to open the same file for reading and writing at the same time. You cannot do that.
There are two possible solutions:
Read from file X, iterate through it and write the result to another file Y.
Read the complete file X into memory, close file X, then delete file X, open the same filename for writing and write to it while iterating through the original file (in memory).
Otherwise, your approach is correct although file operations in Lua are more often done using io.open() and file handles instead of io.write() and io.read().
I need to load configuration variables from .conf file in lua script, and use those variables to connect to a database. I have tried using:
require "host.conf"
loadfile("host.conf") - error with unexpected token '#'
os.execute("pathToConfFile/host.lua") - and I have created a lua host file with variables in bash shell
io.popen("host.conf") etc..
None of these solutions are valid.
Is there a way to use the existing host.conf file in lua, and avoid the unexpected token error?
Thank you for your suggestions.
local original = io .open('host.conf')
local hostconf = {} -- copy contents into Lua table
for line in original :lines() do
table .insert( hostconf, line )
end ; io .close( original )
print( hostconf[1] ) -- prints line 1
You haven't specified what format your host.conf comes in, but you'll likely want to parse it better than just throwing contents in a list. Perhaps splitting each line into head / tail, based upon a delimiter ( comma, space, whatever you have between variable & value )
Thank you to everyone who helped out. My question wasn't precise and I had more to learn before I have asked and sorry about that. This is what I used to solve the problem.
local open = io.open
local function read_file(path)
local file = open(path, "r")
if not file then return nil end
local content = file:read "*a" -- *a or *all reads the whole file
local lines = {}
for line in io.lines(path) do
--print(line);
if(line:find(var)~=nil)then
local varStart=string.len(var)+2
local varEnd=string.len(line)
var=string.sub(line,varStart,varEnd)
print(var);
end
--repeat for every line
end
file:close()
return lines;
end
local fileContent = read_file("path");
I'm trying to make a Discord bot with lua and its going well so far, but I'm having a couple problems with the IO portion of lua.
I'm trying to read a large list.txt file in lua and inserting each line into a table, but so far all of my attempts didn't work.
Any advice?
Attempt #1 spits out nil:
local open = io.open
local function read_file(path)
local file = open(path, "r") -- r read mode and b binary mode
if not file then return nil end
local content = file:read "*a" -- *a or *all reads the whole file
file:close()
return content
end
local fileContent = read_file("list.txt")
local vga_files = {}
table.insert(vga_files, fileContent)
I was not able to replicate your error running your code. Your code is valid, and is likely doing what you asked it to do.
here you tell the read_file function to return nil:
if not file then return nil end
So if the file is not found you will get nil. A good step in debugging would be to add a print in the body of this if statement and see if it is getting entered.
When you call read_file:
local fileContent = read_file("list.txt")
you pass in only a file name, this means lua will look for that where ever the code is being executed, and this location maybe different from what you expect.
I validated your code works by pointing the read at itself, and printing the result.
local open = io.open
local function read_file(path)
local file = open(path, "r") -- r read mode and b binary mode
if not file then return nil end
local content = file:read "*a" -- *a or *all reads the whole file
file:close()
return content
end
print(read_file("so_io_read_test.lua"))
Additionally to get the lines you should really used io.lines which creates an iterator that you can use in a for loop.
local vga_files = {}
for line in io.lines("list.txt") do
table.insert(vga_files, line)
end
Or alternatively you can read the file and then split the lines using gmatch.
local contents = read_file("so_io_read_test.lua")
for line in contents:gmatch("([^\n]+)") do
table.insert(vga_files, line)
end
I am trying to copy only latest file from a directory using lua file.
Latest file means : depends on modified time/created time.
How can i do this?
Referring to this question: How can I get last modified timestamp in Lua
You might be able to leverage the io.popen function to execute a shell command to get the name of the file. It seems like there's no builtin function that exposes filesystem metadata or stats. Something like this might work:
local name_handle = io.popen("ls -t1 | head -n 1")
local filename = name_handle:read()
I'm not familiar with Lua, but perhaps this helps. I imagine that once you have the name of the newest file you can use the other IO functions to do the copying.
local function get_last_file_name(directory)
local command = 'dir /a-d /o-d /tw /b "'..directory..'" 2>nul:'
-- /tw for last modified file
-- /tc for last created file
local pipe = io.popen(command)
local file_name = pipe:read()
pipe:close()
return file_name
end
local directory = [[C:\path\to\your\directory\]]
local file_name = get_last_file_name(directory)
if file_name then
print(file_name)
-- read the last file
local file = io.open(directory..file_name)
local content = file:read"*a"
file:close()
-- print content of the last file
print(content)
else
print"Directory is empty"
end