i would like to run the docker image gcr.io/google-containers/echoserver:1.8. i tried this command docker run -d gcr.io/google-containers/echoserver:1.8 -p 8081:80 but it seems not to work. there is the error message:
and when i insert the docker ps command, no process is running. i don't know if parameters are placed badly or it is not the right command to run this image
All the strings after the image name is considered as a command to run in the container:
you may use:
docker run -d -p 8081:80 gcr.io/google-containers/echoserver:1.8
then the container will run the Entrypoint/CMD wich is configured in the image
Related
I was following this guide on customizing MySQL databases in Docker, and ran this command multiple times after making tweaks to the mounted sql files:
docker run -d -p 3306:3306 --name my-mysql -v /Users/pneedham/dev/docker-testing/sql-scripts:/docker-entrypoint-initdb.d/ -e MYSQL_ROOT_PASSWORD=supersecret -e MYSQL_DATABASE=company mysql
On all subsequent executions of that command, I would see an error like this:
docker: Error response from daemon: Conflict. The container name "/my-mysql" is already in use by container "9dc103de93b7ad0166bb359645c12d49e0aa4a3f2330b5980e455cec24843663". You have to remove (or rename) that container to be able to reuse that name.
See 'docker run --help'.
What I'd like to know is whether that docker run command can be modified to auto-kill the previous container (if it exists)? Or if there is a different command that has the same desired result.
If I were to create a shell script to do that for me, I'd first run docker ps -aqf "name=mysql" and if there is any output, use that resulting container ID by running docker rm -f $containerID. And then run the original command.
docker run command has a --rm arguments that deletes the container after the run is completed. see the docs . So, just change your command to
docker run --rm -d -p 3306:3306 --name my-mysql -v /Users/pneedham/dev/docker-testing/sql-scripts:/docker-entrypoint-initdb.d/ -e MYSQL_ROOT_PASSWORD=supersecret -e MYSQL_DATABASE=company mysql
I'm trying to create a new docker container using the following command:
docker run -d -it --name compsci -v /c/Users/garre/Documents/CPSC_Courses:/homechapmanfse/computing-resources:cs_base
However, it gives me this error message:
"docker run" requires at least 1 argument.
See 'docker run --help'.
Usage: docker run [OPTIONS] IMAGE [COMMAND] [ARG...]
Run a command in a new container
How would I fix this?
You have to provide the name of the image that you want to run. This is currently missing in your command.
For example, if I were to run mysql, I would execute this:
docker run --name some-mysql -e MYSQL_ROOT_PASSWORD=my-secret-pw -d mysql
See the last argument, mysql? That is the name of the image.
Think that you it has build image in your machine. You must inform name of image run.
docker run image-name
This command --name is necessary only you specific name for your container. And the -it command must be entered only when entering the executed container.
docker run -d -it -v
/c/Users/garre/Documents/CPSC_Courses:/homechapmanfse/computing-resources:cs_base
--name 'the name you want to give' 'official name of the image'
I have created a docker image that includes some python code and a shell script that can execute it. It is going to process a bunch of images from the host system.
This command should create a new contaier and run it.
sudo docker run -v /host/folder:/container/folder opencv:latest bash /extract-embeddings.sh
At the end, the container exits. If I type the same command, then another container is created and exited at completion. But how is the correct usage of containers? Should I use restart, start or run (and then clean up exited containers after)? It just seems unnessary to create a new container each time.
I basically just want a docker image containing some code and 3-4 different commands I can execute whenever needed.
And the docker start command doesn't seem to accept "bash /extract-embeddings.sh" as parameters, instead things bash and extract-embeddings.sh are containers. So maybe I am misunderstanding the lifecycle of containers or the usage.
edit:
Got it to work with:
docker run -t -d --name opencv -v /host/folder:/container/folder
docker exec -it opencv bash /extract-embeddings.sh
You can write the Dockerfile to create your docker image and keep the scripts into it-
Dockerfile:
FROM opencv:latest
COPY ./your-script /some_folder
Create image:
docker build -t my_image .
Run your container:
docker run -d --name my_container
Run the script inside the container:
docker exec -it <container_id_or_name> bash /some_folder/your-script
Build your own docker image that starts with opencv:latest and give the command you run as the entrypoint. Dockerfile could be like
FROM opencv:latest
CMD ["/bin/bash", "/extract-embeddings.sh"]
Use docker create to create a named container.
sudo docker create --name=processmyimage -v /host/folder:/container/folder myopencv:latest
Then use docker start each time you want to run it.
sudo docker start processmyimage
This works well if there is only one command you want to run. If there is more than one command, I would take the approach of building an image that runs unrelated command forever (like a tail -f < /dev/null). Then you can use
sudo docker exec -d /bin/bash < cmd-to-run >
for each command
How can do something like:
docker exec -it 06a0076fb4c0 install-smt
But use the name of the container instead
docker exec -it container/container install-smt
I am running a build on CI server so I can not manually input the container ID.
How can I achieve this?
Yes, you can do this by naming the container with --name. Note that your command with container/container is likely referencing an image name and not the container.
➜ ~ docker run --name my_nginx -p 80:80 -d nginx
d122acc37d5bc2a5e03bdb836ca7b9c69670de79063db995bfd6f66b9addfcac
➜ ~ docker exec my_nginx hostname
d122acc37d5b
Although it won't save any typing, you can do something like this if you want to use the image name instead of giving the container a name:
docker run debian
docker exec -it `docker ps -q --filter ancestor=debian` bash
This will only work if you're only running one instance of the debian image.
It does help if you're constantly amending the image when working on a new Dockerfile, and wanting to repeatedly run the same command in each new container to check your changes worked as expected.
I was able to fix this by setting a container name in the docker-compose file, and rundocker exec -it with the name form the file.
#Héctor (tnx)
These steps worked for me:
This will start the container named mytapir and spawn a shell into the docker container:
docker run -d --name mytapir -it wsmoses/tapir-built:latest bash
Upon docker ps to ensure the docker container is running:
docker exec -it mytapir /bin/bash
Will spawned a shell into an existing container named mytapir.
And you can stop the container as usual docker stop mytapir.
And starting it via docker start mytapir, if it is not running.
(check via docker ps -a)
I try to start container with following command
sudo docker run ubuntu
after that I checked with
sudo docker ps -a
found the container exited already
why does it exit?
How could I keep it running in backgroud without specifying -it and attach to it on demanding?
Solved by myself, a elegant way to keep the container running and waiting for further "attach" or "exec" is the following (to keep the STDIN open by -i option)
docker run -i -d ubuntu
You need to start an application with the docker run command that won't exit.
Example:
docker run -d --entrypoint '/bin/bash cat' ubuntu
You can add the tail command while running the container.
docker run -d ubuntu tail -f /dev/null
the correct syntax is
(from docker run --help)
docker run [OPTIONS] IMAGE [COMMAND] [ARG...]
you have forgotten to specify a command.
You should have a look at the docker hub
https://registry.hub.docker.com/
For example for nginx, if you look at
https://hub.docker.com/_/nginx/
you will find
docker run --name some-nginx -v /some/nginx.conf:/etc/nginx/nginx.conf:ro -d nginx
If you look at
https://github.com/nginxinc/docker-nginx/blob/7f3ef0927ec619d20181e677c97f991df0d7d446/Dockerfile
you will notice that the last line of the Dockerfile is
CMD ["nginx", "-g", "daemon off;"]
This means that when you launch the docker image nginx, the implicit action is to start nginx.
If you want the container to not exist, you have to use the -d argument
So it look like this:
docker run -d ubuntu