How to slice a ByteBuffer - dart

Dart's ByteBuffer and ByteData are pretty direct copies of Javascript's ArrayBuffer and DataView respectively (but with even more confusing names!)
However there doesn't seem to be an equivalent to ArrayBuffer.slice(), that creates a copy of of part of an ArrayBuffer. Did I miss it? Is this deliberate or just an omission?

You can copy part of a ByteBuffer, although the process might be a bit convoluted:
You can use Uint8List.view to create a Uint8List view (i.e., not a copy) of a ByteBuffer. From there you can use its sublist method to copy a portion of it to a new Uint8List, and then access its buffer property to get back a ByteBuffer.
In other words:
ByteBuffer slice = Uint8List.view(byteBuffer).sublist(start, end).buffer;
Another way to get a Uint8List view from a ByteBuffer and then creating a copy:
ByteBuffer slice = Uint8List.fromList(byteBuffer.asUint8List(start, end)).buffer;
In practice, I think this usually isn't quite as bad as it might seem since typically you'd start off from a Uint8List anyway.

Related

What's the most efficient way to make a single-item Iterable in Dart?

In Dart, single-item iterables can be created in various ways.
['item']; // A single-item list
Iterable.generate(1, (_) => 'item'); // A single-item generated Iterable
How do these methods compare in terms of speed and memory usage, during both creation and iteration?
The list is probably the cheapest.
At least if you use a List.filled(1, 'item') to make it a fixed-length list, those are cheaper than growable lists.
You need to store the one element somehow. Storing it directly in the list takes a single reference. Then the list might spend one more cell on the length (of 1).
On top of that, compilers know platform lists and can be extra efficient if they can recognize that that's what they're dealing with.
They probably can't here, since you need an iterable to pass to something expecting an arbitrary iterable, because otherwise a single element iterable isn't useful.
It's a little worrying that the list is mutable. If you know the element at compile time, a const ['item'] is even better.
Otherwise Iterable.generate(1, constantFunction) is not a bad choice, if you know the value at compile time and can write a String constantFunction() => 'item'; static or top-level function that you can tear off efficiently.
That said, none of the things here really matter for performance, unless you're going to do it a lot of times in a singe run of your program.
The difference in timing is going to be minimal. The difference in memory usage is likely less than the size of the Iterable being created by either method.
You'll save much more by not using a for (var e in iterable) on an iterable, and, say, use for (var i = 0; i < list.length; i++) { var e = list[i]; ... } instead, if you can ensure that the iterable is always a list.

How to process big files in dart asyncronously in a performant way

By using File.openRead() Dart allows to read big files asyncronously in chunks of 64k Bytes. But as the chunks are of Type List<int> I doubt that this is a performant method.
There is a datatype ByteBuffer() which would probably be a perfect match for that requirement, as the data could be transferred directly from disk to memory.
But by returning a List<int> The file has to be read byte by byte and for every byte a 64bit integer object has to be created, that has to be appended to the list. So my question:
Is there an internal optimization to List to make it performant?
Or are there different methods for more efficiency?
It seems there is an internal optimization to do this. They use Uint8List so there isn't wasted memory like you said.
Source: file_impl.dart

OCaml Marshal very large data structure

I would like to send a very large (~8GB) datastructure through the network, so I use the Marshal module to transform it into Bytes.
My problem is that the memory doubles, because we need to store both representations (initial data and Marshaled data).
Is there a simple way to Marshal into a Stream instead ? This would avoid to have the full Marshalled representation of the initial datastructure.
I thought of Marshaling to an out_channel in which I opened a pipe with a second thread and reading from the pipe in the main thread into s Stream, but I guess there might be a simpler solution.
Thanks !
Edit: Answer to a comment:
In the toplevel :
let a = Array.make (1024*1024*1024) 0. ;; (* Takes 8GB of RAM *)
let data = Marshal.to_bytes a [Marshal.Closures] ;; (* Takes an extra 8GB *)
It's not possible. You would have to modify the Marshal module to stream the data as it marshals something and to reconstruct the data in place without buffering it all first.
In the short run it might be simpler to implement your own specialized marshal function specific to your data. For an 8GiB array you might want to switch to using BigArray so you can send/recv the data without having to copy it.
Note: A 8GiB array will use 16GiB if the GC ever copies it, at least temporary.
From what I understand, MPI only allows to send data packets with a known size, not a stream of data. You could implement a custom stream type that split an incoming flow of data to packets of constant, small size (on close, you flush whatever remains in the buffer).
Also, you only can marshall arbitrary long data to a channel, because otherwise you take up too many space.
And then, you need to have a way to connect the channel to the stream, which AFAIK is not easily possible. Maybe you could start antoer ocaml process: the process would convert the flow of bytes (you can wrap a custom stream over Stream.of_channel) and send it through MPI. The main process would marshall data to the process's input channel.

Accessing field on original C struct in Go

I'm trying to use OpenCV from Go. OpenCV defines a struct CvMat that has a data field:
typedef struct CvMat
{
...
union
{
uchar* ptr;
short* s;
} data;
}
I'm using the go bindings for opencv found here. This has a type alias for CvMat:
type Mat C.CvMat
Now I have a Mat object and I want to access the data field on it. How can I do this? If I try to access _data, it doesn't work. I printed out the fields on the Mat object with the reflect package and got this:
...
{data github.com/lazywei/go-opencv/opencv [8]uint8 24 [5] false}
...
So there is a data field on it, but it's not even the same type. It's an array of 8 uint8s! I'm looking for a uchar* that is much longer than 8 characters. How do I get to this uchar?
The short answer is that you can't do this without modifying go-opencv. There are a few impediments here:
When you import a package, you can only use identifiers that have been exported. In this case, data does not start with an upper case letter, so is not exported.
Even if it was an exported identifier, you would have trouble because Go does not support unions. So instead the field has been represented by a byte array that matches the size of the underlying C union (8 bytes in this case, which matches the size of a 64-bit pointer).
Lastly, it is strongly recommended not to expose cgo types from packages. So even in cases like this where it may be possible to directly access the underlying C structure, I would recommend against it.
Ideally go-opencv would provide an accessor for the information you are after (presumably one that could check which branch of the union is in use, rather than silently returning bad data. I would suggest you either file a bug report on the package (possibly with a patch), or create a private copy with the required modifications if you need the feature right away.

Can immutable be a memory hog?

Let's say we have a memory-intensive class like an Image, with chainable methods like Resize() and ConvertTo().
If this class is immutable, won't it take a huge amount of memory when I start doing things like i.Resize(500, 800).Rotate(90).ConvertTo(Gif), compared to a mutable one which modifies itself? How to handle a situation like this in a functional language?
If this class is immutable, won't it take a huge amount of memory?
Typically your memory requirements for that single object might double, because you might have an "old copy" and a "new copy" live at once. So you can view this phenomenon, over the lifetime of the program, as having one more large object allocated than you might in a typical imperative program. (Objects that aren't being "worked on" just sit there, with the same memory requirements as in any other language.)
How to handle a situation like this in a functional language?
Do absolutely nothing. Or more accurately, allocate new objects in good health.
If you are using an implementation designed for functional programming, the allocator and garbage collector are almost certainly tuned for high allocation rates, and everything will be fine. If you have the misfortune to try to run functional code on the JVM, well, performance won't be quite as good as with a bespoke implementation, but for most programs it will still be fine.
Can you provide more detail?
Sure. I'm going to take an exceptionally simple example: 1000x1000 greyscale image with 8 bits per pixel, rotated 180 degrees. Here's what we know:
To represent the image in memory requires 1MB.
If the image is mutable, it's possible to rotate 180 degrees by doing an update in place. The amount of temporary space needed is enough to hold one pixel. You write a doubly nested loop that amounts to
for (i in columns) do
for (j in first half of rows) do {
pixel temp := a[i, j];
a[i, j] := a[width-i, height-j];
a[width-i, height-j] := tmp
}
If the image is immutable, it's required to create an entire new image, and temporarily you have to hang onto the old image. The code is something like this:
new_a = Image.tabulate (width, height) (\ x y -> a[width-x, height-y])
The tabulate function allocates an entire, immutable 2D array and initializes its contents. During this operation, the old image is temporarily occupying memory. But when tabulate completes, the old image a should no longer be used, and its memory is now free (which is to say, eligible for recycling by the garbage collector). The amount of temporary space required, then, is enough to hold one image.
While the rotation is going on, there's no need to have copies of objects of other classes; the temporary space is needed only for the image being rotated.
N.B. For other operations such as rescaling or rotating a (non-square) image by 90 degrees, it is quite likely that even when images are mutable, a temporary copy of the entire image is going to be necessary, because the dimensions change. On the other hand, colorspace transformations and other computations which are done pixel by pixel can be done using mutation with a very small temporary space.
Yes. Immutability is a component of the eternal time-space tradeoff in computing: you sacrifice memory in exchange for the increased processing speed you gain in parallelism by foregoing locks and other concurrent access control measures.
Functional languages typically handle operations of this nature by chunking them into very fine grains. Your Image class doesn't actually hold the logical data bits of the image; rather, it uses pointers or references to much smaller immutable data segments which contain the image data. When operations need to be performed on the image data, the smaller segments are cloned and mutated, and a new copy of the Image is returned with updated references -- most of which point to data which has not been copied or changed and has remained intact.
This is one reason why functional design requires a different fundamental thought process from imperative design. Not only are algorithms themselves laid out very differently, but data storage and structures need to be laid out differently as well to account for the memory overhead of copying.
In some cases, immutability forces you to clone the object and needs to allocate more memory. It doesn't necessary occupy the memory, because older copies can be discarded. For example, the CLR garbage collector deals with this situation quite well, so this isn't (usually) a big deal.
However, chaining of operations doesn't actually mean cloning the object. This is certainly the case for functional lists. When you use them in the typical way, you only need to allocate a memory cell for a single element (when appending elements to the front of the list).
Your example with image processing can be also implemented in a more efficient way. I'll use C# syntax to keep the code easy to understand without knowing any FP (but it would look better in a usual functional language). Instead of actually cloning the image, you could just store the operations that you want to do with the image. For example something like this:
class Image {
Bitmap source;
FileFormat format;
float newWidth, newHeight;
float rotation;
// Public constructor to load the image from a file
public Image(string sourceFile) {
this.source = Bitmap.FromFile(sourceFile);
this.newWidth = this.source.Width;
this.newHeight = this.source.Height;
}
// Private constructor used by the 'cloning' methods
private Image(Bitmap s, float w, float h, float r, FileFormat fmt) {
source = s; newWidth = w; newHeight = h;
rotation = r; format = fmt;
}
// Methods that can be used for creating modified clones of
// the 'Image' value using method chaining - these methods only
// store operations that we need to do later
public Image Rotate(float r) {
return new Image(source, newWidth, newHeight, rotation + r, format);
}
public Image Resize(float w, float h) {
return new Image(source, w, h, rotation, format);
}
public Image ConvertTo(FileFormat fmt) {
return new Image(source, newWidth, newHeight, rotation, fmt);
}
public void SaveFile(string f) {
// process all the operations here and save the image
}
}
The class doesn't actually create a clone of the entire bitmap each time you invoke a method. It only keeps track of what needs to be done later, when you'll finally try to save the image. In the following example, the underlying Bitmap would be created only once:
var i = new Image("file.jpg");
i.Resize(500, 800).Rotate(90).ConvertTo(Gif).SaveFile("fileNew.gif");
In summary, the code looks like you're cloning the object and you're actually creating a new copy of the Image class each time you call some operation. However, that doesn't mean that the operation is memory expensive - this can be hidden in the functional library, which can be implemented in all sorts of ways (but still preserv the important referential transparency).
It depends on the type of data structures used, their application in a given program. In general, immutability does not have to be overly expensive on memory.
You may have noticed that the persistent data structures used in functional programs tend to eschew arrays. This is because persistent data structures typically reuse most of their components when they are "modified". (They are not really modified, of course. A new data structure is returned, but the old one is just the same as it was.) See this picture to get an idea of how the structure sharing can work. In general, tree structures are favoured, because a new immutable tree can be created out of an old immutable tree only rewriting the path from the root to the node in question. Everything else can be reused, making the process efficient in both time and memory.
In regards to your example, there are several ways to solve the problem other than copying a whole massive array. (That actually would be horribly inefficient.) My preferred solution would be to use a tree of array chunks to represent the image, allowing for relatively little copying on updates. Note an additional advantage: we can at relatively small cost store multiple versions of our data.
I don't mean to argue that immutability is always and everywhere the answer -- the truth and righteousness of functional programming should be tempered with pragmatism, after all.
Yes one of the disadvantage of using immutable objects is that they tend to hog memory, One thing that comes to my mind is something similar to lazy evaluation, which is when a new copy is requested provide a reference and when the user does some changes then initialize the new copy of the object.
Short, tangential answer: in FP language I'm familiar with (scala, erlang, clojure, F#), and for the usual data structures: arrays, lists, vectors, tuples, you need to understand shallow/deep copies and how implemented:
e.g.
Scala, clone() object vs. copy constructor
Does Scala AnyRef.clone perform a shallow or deep copy?
Erlang: message passing a shallow-copied data structure can blow up a process:
http://groups.google.com/group/erlang-programming/msg/bb39d1a147f72800

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