Pulling several keys from a table with lowest integer values - lua

I've made a table like this
TableAlpha = {
Alpha = 3648,
Beta = 6593,
Charlie = 2358,
Delta = 6483,
Echo = 4736
}
Im wondering how can i pull out 3 keys with lowest values inside the table?

local TableAlpha = {
Alpha = 3648,
Beta = 6593,
Charlie = 2358,
Delta = 6483,
Echo = 4736
}
--- Returns the keys of tab sorted numerically by their values
local function ascending(tab)
local list = {}
for key, integer in pairs(tab) do
table.insert(list, {integer, key})
end
table.sort(list, function(left, right) return left[1] < right[1] end)
for i, tuple in ipairs(list) do
list[i] = tuple[2]
end
return list
end
local unpack = unpack or table.unpack or error("Could not find an unpack function!")
print(unpack(ascending(TableAlpha), 1, 3))

Related

Full path to the required value

How do I get the full path to the required value in the table? I want to track changes in another table through a proxy table.
I understand that I need to use metatables and __index in it. But I haven't been able to come up with a tracker yet.
Sample table structure:
Objects = {
Panel = { layer = 1, x = 600, y = 328, w = 331, h = 491;
objects = {
label = { layer = 1, x = 0, y = 0, text = 'header' };
Window = { layer = 2, x = 400, y = 100, w = 100, h = 100;
objects = {
label = { layer = 1, x = 0, y = 0, text = 'lorem ipsum dorem' };
};
};
};
};
};
Path: Objects.Panel.objects.Window.objects.label.text
I tried to create a metatable for each of the tables and collect the result of each call to __index into a table in order to roughly understand which key and value were retrieved or changed in order to synchronize these values ​​with other tables.
This will prove itself to be horrendously slow and memory inefficient. Anyway, you were right on the track: proxy and handle __index and __newindex metamethods to your liking. This being said you also need to track the state of the proxy somehow.
You can try to hide it with some closures and upvalues but the easy way is to store the information directly in the proxy tables:
function make_tracker (o, name)
local mt = {}
mt.__index = function (proxy, key)
local path = {unpack(rawget(proxy, "__path"))} -- Stupid shallow copy
local object = rawget(proxy, "__to")
table.insert(path, key)
if type(object[key]) == "table" then
return setmetatable({__to = object[key], __path = path}, mt)
else
return table.concat(path, ".") .. " = " .. tostring(object[key])
end
end
return setmetatable({__to = o, __path = {name}}, mt)
end
__to fields indicates what proxy should point to and __path is there to cover fields we have trespassed so far. It does a shallow copy, so that one can use subproxies with local variables. name parameter is there to initialize the name of the first table, as you just simply can't know that. You use it like this:
local tObjects = make_tracker(Objects, "Objects")
local subproxy = tObjects.Panel.objects.Window
print(subproxy.objects.label.text)
print(tObjects.Panel.objects.label.text)
print(subproxy.x)
-- prints:
-- Objects.Panel.objects.Window.objects.label.text = lorem ipsum dorem
-- Objects.Panel.objects.label.text = header
-- Objects.Panel.objects.Window.x = 400
Of course, I doubt that appending the path to the original value is what you want. Modify insides of else block:
return table.concat(path, ".") .. " = " .. tostring(object[key])
according to your needs, e.g:
register_tracked_path(table.concat(path, "."))
return object[key]
If you want to handle modification of values you need to extend the metatable with similar __newindex.

Insert Additional data into Lua table at index

I have a table called "inventory", initialized like so:
inventory = {}
inventory[1] = { qty = 0 }
I want to add more data to this table, at the index 1, eg:
val = { id = "example" }
inventory[1] = inventory[1], val
Is there a way I can do this while preserving the data that is already in this table at this index?
The final result should be something like:
inventory[1] = { qty = 0, id = "example" }
But if I try to print the id after trying this code I get:
print(inventory[1].id) == Nil
inventory[1].id = "example"
or
inventory[1]["id"] = "example"
or
this other SO answer with first_table being inventory[1] and second_table being val.
FWIW, you'd need 2 variables on the left side of the expression for inventory[1] = inventory[1], val to work: a, b = x, y.
You need to take the first key in the table and use it:
local inventory = {}
inventory[1] = { qty = 0 }
local val = { id = "example" }
--
local KeyName = next(val)
inventory[1][KeyName] = val[KeyName]
print(inventory[1][KeyName])
-- or
print(inventory[1].id)

Update Elements in table without changing table order Lua

I'd like to maintain the order of a table when updating table values in Lua.
Example
tbl = {
messageId = 0,
timestamp = currentTime,
responseStatus = {
status = "FAILED",
errorCode = "599",
errorMessage = "problem"
}
}
meaning tbl.messageId = 12345 leaves the elements ordered
Like #moteus said, your premise is incorrect: non-numeric entries in Lua tables are not sorted. The order, in which they are defined won't, in general, be the same order as that in which they will be read (e.g., pairs will iterate over those entries in an arbitrary order). Assigning a new value will not affect this in any way.
I suppose you can use table.sort, there is a simple example:
local tbl = {
messageId = 0,
timestamp = currentTime,
responseStatus = {
status = "FAILED",
errorCode = "599",
errorMessage = "problem"
}
}
function fnCompare (e1, e2)
-- you should promise e1 and e2 is tbl struct
-- you can check e1 and e2 first by yourself
return e1.messageId < e2.messageId;
end
-- test
local tbAll = {}
tbl.messageId = 3;
table.insert(tbAll, tbl);
-- add a another
table.insert(tbAll, {messageId = 1});
table.sort(tbAll, fnCompare);
for k, v in ipairs(tbAll) do
print(v.messageId); -- result: 1 3
end

Lua - iterating through nested list

I'm going to simplify the situation as much as I can. I have the following code:
windows = { "window1", "window2" }
window1 = {
x = 100
y = 100
properties = { active = false, width = 200, height = 200 }
}
window2 = {
x = 0
y = 0
properties = { active = false, width = 200, height = 200 }
}
If I do the following, I get the correct output:
print (window1.x)
OUTPUT: 0
print (window1.properties.active)
OUTPUT: false
HOWEVER, if I iterate through the list, I get "nil" values for "l.x" and "l.properties.active":
for _,l in ipairs(windows) do
print (l)
print (l.x)
print (l.properties.active)
end
Is there a different way I need to iterate through the variables in the lists, so I can get the values?
That is not a nested table, but just a table containing strings. And, as you just saw, a string doesn't contain a value for the key "x".
You have to put the tables in a sequence:
local window1 = {...} -- first table
local window2 = {...} -- second table
local windows = {window1, window2}
for _,l in ipairs(windows) do
-- do stuff with l
end
Or, if you want to keep the list of strings and iterate over the strings, put the windows in a second table using these strings as a key.
local windowNames = { "window1", "window2" }
local windows = {}
windows.window1 = {...} -- first table
windows.window2 = {...} -- second table
for _,l in ipairs(windowNames) do
local ourWindow = windows[l]
-- do stuff with ourWindow
end

Randomly select a key from a table in Lua

I want to randomly populate a grid in Lua using a list of possible items, which is defined as follows:
-- Items
items = {}
items.glass = {}
items.glass.color = colors.blue
items.brick = {}
items.brick.color = colors.red
items.grass = {}
items.grass.color = colors.green
So the keys of the table are "glass", "brick" and "grass".
How do I randomly select one of these keys if they are not addressable by a numeric index?
Well, I kind of got a workaround, but I would be open to any better suggestions.
The first solution consists of having a secondary table which serves as an index to the first table:
item_index = {"grass", "brick", "glass"}
Then I can randomly store a key of this table (board is a matrix that stores the value of the random entry in item_index):
local index = math.random(1,3)
board[i][j] = item_index[index]
After which I can get details of the original list as follows:
items[board[y][x]].color
The second solution, which I have decided on, involves adding the defined elements as array elements to the original table:
-- Items
items = {}
items.glass = {}
items.glass.color = colors.blue
table.insert(items, items.glass) --- Add item as array item
items.brick = {}
items.brick.color = colors.red
table.insert(items, items.brick) --- Add item as array item
items.grass = {}
items.grass.color = colors.green
table.insert(items, items.grass) --- Add item as array item
Then, I can address the elements directly using an index:
local index = math.random(1,3)
board[i][j] = items[index]
And they can be retrieved directly without the need for an additional lookup:
board[y][x].color
Although your second method gives concise syntax, I think the first is easier to maintain. I can't test here, but I think you can get the best of both, won't this work:
local items = {
glass = {
color = colors.blue,
},
brick = {
color = colors.red,
},
grass = {
color = colors.green,
},
}
local item_index = {"grass", "brick", "glass"}
local index = math.random(1,3)
board[i][j] = items[item_index[index]]
print('color:', board[i][j].color)
If you're table is not too big and you can just break off at a random point. This method assumes that you know the number of entries in the table (which is not equal to #table value, if the table has non-number keys).
So find the length of the table, then break at random(1, length(table)), like so:
local items = {} ....
items.grass.color = colors.green
local numitems = 0 -- find the size of the table
for k,v in pairs(items) do
numitems = numitems + 1
end
local randval = math.random(1, numitems) -- get a random point
local randentry
local count = 0
for k,v in pairs(items) do
count = count + 1
if(count == randentry) then
randentry = {key = k, val = v}
break
end
end
The goods: You don't have to keep track of the keys. It can be any table, you don't need to maintain it.
The bad and ugly: It is O(n) - two linear passes.So, it is not at all ideal if you have big table.
The above answers assume you know what all of the keys are, which isn't something I was able to do earlier today. My solution:
function table.randFrom( t )
local choice = "F"
local n = 0
for i, o in pairs(t) do
n = n + 1
if math.random() < (1/n) then
choice = o
end
end
return choice
end
Explanation: we can't use table.getn( t ) to get the size of the table, so we track it as we go. The first item will have a 1/1=1 chance of being picked; the second 1/2 = 0.5, and so on...
If you expand for N items, the Nth item will have a 1/N chance of being chosen. The first item will have a 1 - (1/2) - (1/3) - (1/4) - ... - (1/N) chance of not being replaced (remember, it is always chosen at first). This series converges to 1 - (N-1)/N = 1/N, which is equal to the chance of the last item being chosen.
Thus, each item in the array has an equal likelihood of being chosen; it is uniformly random. This also runs in O(n) time, which isn't great but it's the best you can do if you don't know your index names.

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