How do I do a countdown until matching digits in coral? What I'm trying to do is write a program that takes the input number (as long as it's between 20 and 98) and it counts down by 1 until the digits are the same. For example if the input number is 93, the output will be 93 92 91 90 89 88. Once the count gets to 88 (the two digits are the same) the program stops. Or if the input is 77 then the output will only be 77.
I'm not sure how this is related to google-coral, but here is a suggestion. You can start by writing a compare_digit function that takes in a number, convert it to a string and compare the 2 characters in that string. Then in the main loop, just print out the number, call compare_digit on that number and then minus one from that number. Here is some pseudo code for you:
def compare_digits(num):
string num_str = to_string(num)
return num_str[0] == num_str[1]
def main():
input_num = input("Enter number")
while(True):
if compare_digits(input_num):
stop_program()
print(input_num)
input_num--
Related
I have a problem. We have coded item names which has certain values that I need to do calculations with.
I.E. ASG-120U9624M I need to extract only 120, 96, 24, as they are parameters required for calculations. Also 96 could be 220(2-3 digits). 24 could be only 12 or 24. I know that you can get values after certain symbols i.e (-, u) but can you detect that value ends before 12/24. If 96 value could be only 2 digits it would be easy but now it's out of my knowledge to do so. Need some help.
B1:
=ARRAYFORMULA(IFNA(REGEXEXTRACT(A1:A, "-(\d+)U")))
C1:
=ARRAYFORMULA(IFNA(REGEXEXTRACT(A1:A, "U(\d+)..M")))
D1:
=ARRAYFORMULA(IFNA(REGEXEXTRACT(A1:A, ".+(\d{2})M")))
Try this:
=ARRAYFORMULA(IFNA(IF(IFERROR(LEN(REGEXEXTRACT(A1:A, ".*U(\d{4})M")), 5) = 4, REGEXEXTRACT(A1:A, "^ASG-(\d{3})U(\d{2})(\d{2})M$"), REGEXEXTRACT(A1:A, "^ASG-(\d{3})U(\d{3})(\d{2})M$"))))
LEN(REGEXEXTRACT(A1:A, ".*U(\d{4})M")), 5) = 4 - Determine the number of digits from U-M
REGEXEXTRACT(A1:A, "^ASG-(\d{3})U(\d{2})(\d{2})M$") - use this regex if number of digits is 4.
REGEXEXTRACT(A1:A, "^ASG-(\d{3})U(\d{3})(\d{2})M$") - use this regex if number of digits is 5.
Sample Sheet:
Let's say your raw data runs A2:A. Place the following in B2:
=ArrayFormula(IF(A2:A="",,REGEXEXTRACT(A2:A,"(\d+)\D(\d+)(12|24)")))
This one formula will extract all three columns of numbers.
The regex captures three groups, each contained in parentheses. It reads: "Any number of digits followed by one non-digit followed by any number of digits up to a 12 or 24."
I have a 4 byte hexadecimal value that I have a script to print out, But I want to now take that value then subtract the value C8 from it 37 times and save them as different variables each time, But the problem is I don't know how to do hexadecimal calculations in lua, If anyone can link me to any documentation on how to do this then that would be much appreciated.
You can make a hexadecimal literal in Lua by prefixing it with 0x, as stated in the reference manual. I found this by googling "lua hex"; such searches usually get good results.
"Hexadecimal numbers" aren't anything special, hexadecimal is just a way to represent numbers, same as decimal or binary. You can do 1000-0xC8 and you'll get the decimal number 800.
Code to convert:
function convertHex()
local decValue = readInteger(0x123456);
hexValue = decValue
end
function hexSubtract()
for i = 1,37 do
local value = 0xC8
hexValue = hexValue - 0xC8
result = hexValue
if i == 37 then
print(result) --Prints dec value
print(string.format('%X',result)); --Prints hex value
end
end
end
Replace 0x123456 with your address, use those functions like this convertHex(),hexSubtract()
A string '321#322#323#324#325'.
here number of digits in each number is 3 but it's not limited to 3 it could be any number.
here are 5 numbers in a string but this number could be anything.
task is to get 321,322,323,324,325 and store in a table so that any operation could be performed over them.
I have tried several string functions like c = c:gsub('%W','') to eliminate those non-alphanumeric characters, but nothing helped.
function encrypter()--FUNCTION 14
c=' '
print('Please enter your message!')
local message=io.read()
lengthOfString=string.len(message)--Inbuit function to get length of a string.
newLine()
print('Please enter your key. Remember this key, otherwise your message wont be decrypted')
newLine()
key=io.read()
key=tonumber(key)
largeSpace()
print("Encrypted message is")
for s=1,lengthOfString do
--print(encryptionFormula(string.byte(message,s),key))
--inbuilt function for converting character of a string to it's respective ASCII value. First place gets character or variable having string whereas second place gets position of that character in the given string.
b=encryptionFormula(string.byte(message,s),key)
c=c..tostring(b)..'#'
--print(c)
b=0
end
print(c)
largeSpace()
print("Now share this message along with the key to the receiver. Don't share your key with anyone, if you don't want your message to be read.")
end
What you're looking for is string.gmatch().
local input = "123#546514#13#548#2315"
local numbers = {}
for number in string.gmatch(input, '%d+') do
table.insert(numbers, number)
end
-- Output the numbers
for index, number in ipairs(numbers) do
print(index, number)
-- This prints:
-- 1 123
-- 2 546514
-- 3 13
-- 4 548
-- 5 2315
end
If you don't know how Lua patterns work, you can read about them in the reference manual or you can have a look at Programming in Lua (the first edition is available for free on their website)
I have a variable named A in SPSS database.
A
--
102102
23453212
142378
2367890654
2345
45
I want to split this variable by 2 lengths and create multiple variables as follows.
A_1 A_2 A_3 A_4 A_5
--- --- --- --- ---
10 21 02
23 45 32 12
14 23 78
23 67 89 06 54
23 45
45
Can anyone write SPSS macro to compute this operation?
Using STRING manipulations (after converting the NUMERIC field to STRING, if necessary), specifically SUBSTR you can extract out pairs of digits as you wish.
/* Simulate data */.
data list list / x (f8.0).
begin data.
102102
23453212
142378
2367890654
2345
45
end data.
dataset name dsSim.
If you have a known maximum value, in your example a value of 10 digits long then you'll need 5 variables to store the pairs of digits, which the follow does:
preserve.
set mxwarns 0 /* temporarily supress warning messages */ .
string #xstr (a10).
compute #xstr=ltrim(string(x,f18.0)).
compute A_1=number(substr(#xstr,1,2), f8.0).
compute A_2=number(substr(#xstr,3,2), f8.0).
compute A_3=number(substr(#xstr,5,2), f8.0).
compute A_4=number(substr(#xstr,7,2), f8.0).
compute A_5=number(substr(#xstr,9,2), f8.0).
exe.
restore.
However, you may prefer to code something like this more dynamically (using python) where the code itself would read the maximum value in the data and create as many variables as needed.
begin program.
import spssdata, math
spss.Submit("set mprint on.")
# get maximum value
spss.Submit("""
dataset declare dsAgg.
aggregate outfile=dsAgg /MaxX=max(x).
dataset activate dsAgg.
""")
maxvalue = spssdata.Spssdata().fetchone()[0]
ndigits=math.floor(math.log(maxvalue,10))+1
cmd="""
dataset close dsAgg.
dataset activate dsSim.
preserve.
set mxwarns 0.
string #xstr (a10).
compute #xstr=ltrim(string(x,f18.0)).
"""
for i in range(1,int(math.ceil(ndigits/2))+1):
j=(i-1)*2+1
cmd+="\ncompute B_%(i)s=number(substr(#xstr,%(j)s,2), f8.0)." % locals()
cmd+="\nexe.\nrestore."
spss.Submit(cmd)
spss.Submit("set mprint off.")
end program.
You would need to weigh up the pros on cons of each method to asses which suits you best, for how you anticipate your data to arrive and how you then go onto work with in later. I haven't attempted to wrap either of these up in a macro but that could just as easily be done.
I'm fairly confused about how the s>d and d>s functions work in Forth.
From what I've read, typing 16.0 will put 160 0 on the stack (since it takes up two cells) and d. will show 160.
Now, if I enter 16 s>d I would expect the stack to be 160 0 and d. to show 160 like in the previous example. However, the stack is 16 0 and d. is 16.
Am I entering doubles incorrectly? Is s>d not as simple as "convert a single celled value into a double celled value? Is there any reason for this irregularity? Any clues would be much appreciated.
Gforth interpets all of these the same: 1.60, 16.0, and 160., i.e. 160 converted to a double number. Whereas 16 s>d converts 16 to a double number.
ANS Forth only mandates that when the text interpreter processes a number that is immediately followed by a decimal point and is not found as a definition name, the text interpreter shall convert it to a double-cell number. But Gforth goes beoynd that: http://www.complang.tuwien.ac.at/forth/gforth/Docs-html/Number-Conversion.html#Number-Conversion