Below code works fine on iOS devices and watchOS simulator.
static func getEventDateTime(startDateTime: Date?) -> String {
if let startDateTime = startDateTime {
let startTimeInMillis = Int(startDateTime.timeIntervalSince1970 * 1000)
let fiveMinutesInMillis = 300000
let eventStartDateTime = Date(timeIntervalSince1970: TimeInterval((startTimeInMillis-fiveMinutesInMillis)/1000))
return convertDateToString(eventStartDateTime)
}
return ""
}
However when I run it on Apple Watch Series 3, I get the following error: double value cannot be converted to int because the result would be greater than int.max on line let startTimeInMillis = Int(startDateTime.timeIntervalSince1970 * 1000).
So I changed
let startTimeInMillis = Int(startDateTime.timeIntervalSince1970 * 1000) to let startTimeInMillis = Int64(startDateTime.timeIntervalSince1970 * 1000)
and
let eventStartDateTime = Date(timeIntervalSince1970: TimeInterval((startTimeInMillis-fiveMinutesInMillis)/1000)) to let eventStartDateTime = Date(timeIntervalSince1970: TimeInterval((Int(startTimeInMillis)-fiveMinutesInMillis)/1000)).
Now I am getting following error: Not enough bits to represent the passed value on line let eventStartDateTime = Date(timeIntervalSince1970: TimeInterval((Int(startTimeInMillis)-fiveMinutesInMillis)/1000))
How do I change the function to make it work on Apple Watch Series 3 or watchOS 7?
Updated function code:
static func getEventDateTime(startDateTime: Date?) -> String {
if let startDateTime = startDateTime {
let startTimeInMillis = Int64(startDateTime.timeIntervalSince1970 * 1000)
let fiveMinutesInMillis = 300000
let eventStartDateTime = Date(timeIntervalSince1970: TimeInterval((Int(startTimeInMillis)-fiveMinutesInMillis)/1000))
return convertDateToString(eventStartDateTime)
}
return ""
}
Use the Calendar API to add/subtract time units (doesn't support milliseconds, but does support nanoseconds, which can be converted from): https://developer.apple.com/documentation/foundation/calendar.
func getEventDateTimeCal(startDateTime: Date?) -> String {
if let startDateTime = startDateTime,
let date = Calendar.current.date(byAdding: .minute, value: -5, to: startDateTime) {
return convertDateToString(date, startDateTime)
}
return ""
}
But also, if you don't need millisecond precision, subtract seconds from TimeInterval. Note that TimeInterval is typealias TimeInterval = Double and always represents seconds.
func getEventDateTime(startDateTime: Date?) -> String {
if let startDateTime = startDateTime {
let fiveMinutesInSeconds = 5.0 * 60
let eventStartDateTime = Date(timeIntervalSince1970: startDateTime.timeIntervalSince1970 - fiveMinutesInSeconds)
return convertDateToString(startDateTime, eventStartDateTime)
}
return ""
}
I've a string with minutes and seconds in format "minutes:seconds". For example, "5:36". I want to convert it to Int value. For example "5:36" string should be 336 Int value. How this can be done?
let timeString = "5:36"
let timeStringArray = timeString.split(separator: ":")
let minutesInt = Int(timeStringArray[0]) ?? 0
let secondsInt = Int(timeStringArray[1]) ?? 0
let resultInt = minutesInt * 60 + secondsInt
print(resultInt)
Here's a simple extension you can use which will validate the format of your input string too:
import Foundation
extension String {
func toSeconds() -> Int? {
let elements = components(separatedBy: ":")
guard elements.count == 2 else {
print("Provided string doesn't have two sides separated by a ':'")
return nil
}
guard let minutes = Int(elements[0]),
let seconds = Int(elements[1]) else {
print("Either the minute value or the seconds value cannot be converted to an Int")
return nil
}
return (minutes*60) + seconds
}
}
Usage:
let testString1 = "5:36"
let testString2 = "35:36"
print(testString1.toSeconds()) // prints: "Optional(336)"
print(testString2.toSeconds()) // prints: "Optional(2136)"
I tried out your example on the playground here's the code:
import Foundation
let time1String = "0:00"
let time2String = "5:36"
let timeformatter = DateFormatter()
timeformatter.dateFormat = "m:ss"
let time1 = timeformatter.date(from: time1String)
let time2 = timeformatter.date(from: time2String)
if let time1 = time1 {
print(time2?.timeIntervalSince(time1)) // prints: Optional(336.0)
}
I read the similar questions here and Write this method in my app
let formatter = NumberFormatter()
func convertEngNumToPersianNum(num: String)->String{
let number = NSNumber(value: Int(num)!)
let format = NumberFormatter()
format.locale = Locale(identifier: "fa_IR")
let faNumber = format.string(from: number)
return faNumber!
}
I didn't get Error But I didn't get the result too!
my Number code is this :
let checkNumber = Home2ViewController().customtitle.count
personalCustom.text = ("\(checkNumber)")
I used another Number in another View Controller that works But I want to show this Number in persian or arabic number format not in English format
Try this :
func convertEngNumToPersianNum(num: String)->String{
//let number = NSNumber(value: Int(num)!)
let format = NumberFormatter()
format.locale = Locale(identifier: "fa_IR")
let number = format.number(from: num)
let faNumber = format.string(from: number!)
return faNumber!
}
OR repalce with your line
let number = format.number(from: num)
let faNumber = format.string(from: number!)
You can do something like,
let formatter = NumberFormatter()
formatter.locale = NSLocale.current // you can specify locale that you want
formatter.numberStyle = .decimal
formatter.usesGroupingSeparator = true
let number = formatter.number(from: "١٠.٠٠")
print(number ?? "")
To convert to Arabic while keeping the leading zeros
func convertToArDigits(_ digits: String) -> String {
// We need a CFMutableString and a CFRange:
let cfstr = NSMutableString(string: digits) as CFMutableString
var range = CFRange(location: 0, length: CFStringGetLength(cfstr))
// Do the transliteration (this mutates `cfstr`):
CFStringTransform(cfstr, &range, kCFStringTransformLatinArabic, false)
// Convert result back to a Swift string:
return (cfstr as String)
}
extension String {
public var faToEnDigits : String {
let farsiNumbers = ["٠": "0","١": "1","٢": "2","٣": "3","٤": "4","٥": "5","٦": "6","٧": "7","٨": "8","٩": "9"]
var txt = self
farsiNumbers.map { txt = txt.replacingOccurrences(of: $0, with: $1)}
return txt
}
public var enToFaDigits : String {
let englishNumbers = ["0": "۰","1": "۱","2": "۲","3": "۳","4": "۴","5": "۵","6": "۶","7": "۷","8": "۸","9": "۹"]
var txt = self
englishNumbers.map { txt = txt.replacingOccurrences(of: $0, with: $1)}
return txt
}
}
I have a double:
let value = 0.99720317490866084
And a Double extention function:
extension Double {
func stringWithFixedFractionDigits(min: Int, max: Int) -> String {
let formatter = NumberFormatter()
formatter.minimumFractionDigits = min
formatter.maximumFractionDigits = max
formatter.minimumIntegerDigits = 1
let numberObject = NSNumber(value: self)
return formatter.string(from: numberObject) ?? "\(self)"
}
}
If I use:
value.stringWithFixedFractionDigits(min: 2, max: 2)
I get 1.00 but I would like to get 0.99
What can I change?
You just need to set your NumberFormatter rounding mode property to .down:
formatter.roundingMode = .down
Note that you don't need to create a new NSNumber object, you can safely cast from Double to NSNumber or use string(for: Any) method instead. As an alternative you can extend the protocol FloatingPoint to make it available to all Float types :
extension Formatter {
static let number = NumberFormatter()
}
extension FloatingPoint {
func formattedWithFractionDigits(minimum: Int = 2, maximum: Int = 2, minimumIntegerDigits: Int = 1, roundingMode: NumberFormatter.RoundingMode = .halfEven) -> String {
Formatter.number.roundingMode = roundingMode
Formatter.number.minimumFractionDigits = minimum
Formatter.number.maximumFractionDigits = maximum
Formatter.number.minimumIntegerDigits = minimumIntegerDigits
return Formatter.number.string(for: self) ?? ""
}
}
0.9972031749.formattedWithFractionDigits() // 1.00
0.9972031749.formattedWithFractionDigits(roundingMode: .down) // "0.99"
0.9972031749.formattedWithFractionDigits(minimumIntegerDigits: 0, roundingMode: .down) // ".99"
I'm new to Swift programming and I've been creating a simple tip calculator app in Xcode 8.2, I have my calculations set up within my IBAction below. But when I actually run my app and input an amount to calculate (such as 23.45), it comes up with more than 2 decimal places. How do I format it to .currency in this case?
#IBAction func calculateButtonTapped(_ sender: Any) {
var tipPercentage: Double {
if tipAmountSegmentedControl.selectedSegmentIndex == 0 {
return 0.05
} else if tipAmountSegmentedControl.selectedSegmentIndex == 1 {
return 0.10
} else {
return 0.2
}
}
let billAmount: Double? = Double(userInputTextField.text!)
if let billAmount = billAmount {
let tipAmount = billAmount * tipPercentage
let totalBillAmount = billAmount + tipAmount
tipAmountLabel.text = "Tip Amount: $\(tipAmount)"
totalBillAmountLabel.text = "Total Bill Amount: $\(totalBillAmount)"
}
}
You can use this string initializer if you want to force the currency to $:
String(format: "Tip Amount: $%.02f", tipAmount)
If you want it to be fully dependent on the locale settings of the device, you should use a NumberFormatter. This will take into account the number of decimal places for the currency as well as positioning the currency symbol correctly. E.g. the double value 2.4 will return "2,40 €" for the es_ES locale and "¥ 2" for the jp_JP locale.
let formatter = NumberFormatter()
formatter.locale = Locale.current // Change this to another locale if you want to force a specific locale, otherwise this is redundant as the current locale is the default already
formatter.numberStyle = .currency
if let formattedTipAmount = formatter.string(from: tipAmount as NSNumber) {
tipAmountLabel.text = "Tip Amount: \(formattedTipAmount)"
}
How to do it in Swift 4:
let myDouble = 9999.99
let currencyFormatter = NumberFormatter()
currencyFormatter.usesGroupingSeparator = true
currencyFormatter.numberStyle = .currency
// localize to your grouping and decimal separator
currencyFormatter.locale = Locale.current
// We'll force unwrap with the !, if you've got defined data you may need more error checking
let priceString = currencyFormatter.string(from: NSNumber(value: myDouble))!
print(priceString) // Displays $9,999.99 in the US locale
You can to convert like that: this func convert keep for you maximumFractionDigits whenever you want to do
static func df2so(_ price: Double) -> String{
let numberFormatter = NumberFormatter()
numberFormatter.groupingSeparator = ","
numberFormatter.groupingSize = 3
numberFormatter.usesGroupingSeparator = true
numberFormatter.decimalSeparator = "."
numberFormatter.numberStyle = .decimal
numberFormatter.maximumFractionDigits = 2
return numberFormatter.string(from: price as NSNumber)!
}
i create it in class Model
then when you call , you can accecpt it another class , like this
print("InitData: result convert string " + Model.df2so(1008977.72))
//InitData: result convert string "1,008,977.72"
you can create an Extension for either string or Int, I would show an example with String
extension String{
func toCurrencyFormat() -> String {
if let intValue = Int(self){
let numberFormatter = NumberFormatter()
numberFormatter.locale = Locale(identifier: "ig_NG")/* Using Nigeria's Naira here or you can use Locale.current to get current locale, please change to your locale, link below to get all locale identifier.*/
numberFormatter.numberStyle = NumberFormatter.Style.currency
return numberFormatter.string(from: NSNumber(value: intValue)) ?? ""
}
return ""
}
}
link to get all locale identifier
The best way to do this is to create an NSNumberFormatter. (NumberFormatter in Swift 3.) You can request currency and it will set up the string to follow the user's localization settings, which is useful.
As an alternative to using a NumberFormatter, If you want to force a US-formatted dollars and cents string you can format it this way:
let amount: Double = 123.45
let amountString = String(format: "$%.02f", amount)
As of Swift 5.5, you can do this with the help of .formatted:
import Foundation
let amount = 12345678.9
print(amount.formatted(.currency(code: "USD")))
// prints: $12,345,678.90
This should support most common currency code, such as "EUR", "GBP", or "CNY".
Similarly, you can append locale to .currency:
print(amount.formatted(
.currency(code:"EUR").locale(Locale(identifier: "fr-FR"))
))
// prints: 12 345 678,90 €
In addition to the NumberFormatter or String(format:) discussed by others, you might want to consider using Decimal or NSDecimalNumber and control the rounding yourself, thereby avoid floating point issues. If you're doing a simple tip calculator, that probably isn't necessary. But if you're doing something like adding up the tips at the end of the day, if you don't round the numbers and/or do your math using decimal numbers, you can introduce errors.
So, go ahead and configure your formatter:
let formatter: NumberFormatter = {
let _formatter = NumberFormatter()
_formatter.numberStyle = .decimal
_formatter.minimumFractionDigits = 2
_formatter.maximumFractionDigits = 2
_formatter.generatesDecimalNumbers = true
return _formatter
}()
and then, use decimal numbers:
let string = "2.03"
let tipRate = Decimal(sign: .plus, exponent: -3, significand: 125) // 12.5%
guard let billAmount = formatter.number(from: string) as? Decimal else { return }
let tip = (billAmount * tipRate).rounded(2)
guard let output = formatter.string(from: tip as NSDecimalNumber) else { return }
print("\(output)")
Where
extension Decimal {
/// Round `Decimal` number to certain number of decimal places.
///
/// - Parameters:
/// - scale: How many decimal places.
/// - roundingMode: How should number be rounded. Defaults to `.plain`.
/// - Returns: The new rounded number.
func rounded(_ scale: Int, roundingMode: RoundingMode = .plain) -> Decimal {
var value = self
var result: Decimal = 0
NSDecimalRound(&result, &value, scale, roundingMode)
return result
}
}
Obviously, you can replace all the above "2 decimal place" references with whatever number is appropriate for the currency you are using (or possibly use a variable for the number of decimal places).
extension String{
func convertDoubleToCurrency() -> String{
let amount1 = Double(self)
let numberFormatter = NumberFormatter()
numberFormatter.numberStyle = .currency
numberFormatter.locale = Locale(identifier: "en_US")
return numberFormatter.string(from: NSNumber(value: amount1!))!
}
}
In 2022 using Swift 5.5, I created extensions that convert Float or Double into a currency using your device's locale or the locale you pass as an argument. You can check it out here https://github.com/ahenqs/SwiftExtensions/blob/main/Currency.playground/Contents.swift
import UIKit
extension NSNumber {
/// Converts an NSNumber into a formatted currency string, device's current Locale.
var currency: String {
return self.currency(for: Locale.current)
}
/// Converts an NSNumber into a formatted currency string, using Locale as a parameter.
func currency(for locale: Locale) -> String {
let numberFormatter = NumberFormatter()
numberFormatter.usesGroupingSeparator = locale.groupingSeparator != nil
numberFormatter.numberStyle = .currency
numberFormatter.locale = locale
return numberFormatter.string(from: self)!
}
}
extension Double {
/// Converts a Double into a formatted currency string, device's current Locale.
var currency: String {
return NSNumber(value: self).currency(for: Locale.current)
}
/// Converts a Double into a formatted currency string, using Locale as a parameter.
func currency(for locale: Locale) -> String {
return NSNumber(value: self).currency(for: locale)
}
}
extension Float {
/// Converts a Float into a formatted currency string, device's current Locale.
var currency: String {
return NSNumber(value: self).currency(for: Locale.current)
}
/// Converts a Float into a formatted currency string, using Locale as a parameter.
func currency(for locale: Locale) -> String {
return NSNumber(value: self).currency(for: locale)
}
}
let amount = 3927.75 // Can be either Double or Float, since we have both extensions.
let usLocale = Locale(identifier: "en-US") // US
let brLocale = Locale(identifier: "pt-BR") // Brazil
let frLocale = Locale(identifier: "fr-FR") // France
print("\(Locale.current.identifier) -> " + amount.currency) // default current device's Locale.
print("\(usLocale.identifier) -> " + amount.currency(for: usLocale))
print("\(brLocale.identifier) -> " + amount.currency(for: brLocale))
print("\(frLocale.identifier) -> " + amount.currency(for: frLocale))
// will print something like this:
// en_US -> $3,927.75
// en-US -> $3,927.75
// pt-BR -> R$ 3.927,75
// fr-FR -> 3 927,75 €
I hope it helps, happy coding!
extension Float {
var localeCurrency: String {
let formatter = NumberFormatter()
formatter.numberStyle = .currency
formatter.locale = .current
return formatter.string(from: self as NSNumber)!
}
}
amount = 200.02
print("Amount Saved Value ",String(format:"%.2f", amountSaving. localeCurrency))
For me Its return 0.00!
Looks to me Extenstion Perfect when accessing it return 0.00! Why?
Here's an easy way I've been going about it.
extension String {
func toCurrency(Amount: NSNumber) -> String {
var currencyFormatter = NumberFormatter()
currencyFormatter.usesGroupingSeparator = true
currencyFormatter.numberStyle = .currency
currencyFormatter.locale = Locale.current
return currencyFormatter.string(from: Amount)!
}
}
Being used as follows
let amountToCurrency = NSNumber(99.99)
String().toCurrency(Amount: amountToCurrency)
Here's how:
let currentLocale = Locale.current
let currencySymbol = currentLocale.currencySymbol
let outputString = "\(currencySymbol)\(String(format: "%.2f", totalBillAmount))"
1st line: You're getting the current locale
2nd line: You're getting the currencySymbol for that locale. ($, £, etc)
3rd line: Using the format initializer to truncate your Double to 2 decimal places.