I have an http url defined in my x.yml file. In run time it gives me error like below:
http://user:password%40localhost:7001/wls-exporter/metrics: invalid URL escape "%40
This is how it is configured in yml file:
http://user:password#localhost:7001/wls-exporter/metrics
I tried double code for "#" and also double quotes for entire url, but it still does not work.
Looking for some guidance, help please.
Related
I was having the url which on converting to punycode has suffix as xn---- which all the regex present in ruby libraries fails to match.
Currently I am using validates_url_format_of ruby library.
Example Url: "https://www.θεραπευτικη-κανναβη.com.gr"
Punycode url: "https://www.xn----ylbbafnbqebomc7ba3bp1ds.com.gr"
So can you please suggest that is there any issue in the regex in the library or the issue lies in the conversion to punycode.
As per the punycode conversion rules the suffix always is xn--. So can anyone suggest what extra two -- means here
"https://www.xn----ylbbafnbqebomc7ba3bp1ds.com.gr".match(/https?:\/\/w*\.xn----.*/)
=> #<MatchData "https://www.xn----ylbbafnbqebomc7ba3bp1ds.com.gr">
Note the url matcher is not perfect
When you have a - inside the URL, the algorithm gets it duplicated and moves it to the beginning of the puny code.
For example:
áéíóú.com -> xn--1caqmy9a.com
á-é-í-ó-ú.com -> xn-------4na3c3a3cwd.com
I guess it has to do with the xn-- encoding restrictions.
This one should work for you:
(xn--)(--)*[a-z0-9]+.com.gr
The beginning of the code: (xn--)
An even number (or 0) of --: (--)*
The domain chars/numbers :([a-z0-9]+)
The TLD of the domain : .com.gr
You can add http/https if you wish
Update:
After adding numbers to the URL I found that the regex needs a fix:
(xn--)(-[-0-9]{1})*[a-z0-9]+.com.gr
á-1é-2í-3ó-4ú.gr.com -> xn---1-2-3-4-7ya6f1b6dve.gr.com
I am trying to detect the urls from a text and replace them by wrapping in quotes like below:
original text: Hey, it is a url here www.example.com
required text: Hey, it is a url here "www.example.com"
original text show my input value and required text represents the required output. I searched a lot on web but could not find any possible solution. I already have tried URL.extract feature but that doesn't seem to detect URLs without http or https. Below are the examples of some of urls I want to deal with. Kindly let me know if you know the solution.
ANQUETIL-DUPERRON Abraham-Hyacinthe, KIEFFER Jean-Luc, www.hominides.net/html/actualites/outils-preuve-presence-hominides-asie-0422.php,Les Belles lettres, 2001.
https://www.ancient-code.com/indian-archeologists-stumbleacross-ruins-great-forgotten-civilization-mizoram/
www.jstor.org/stable/24084454
www.biorespire.com/2016/03/22/une-nouvelle-villeantique-d%C3%A9couverte-en-inde/
insu.cnrs.fr/terre-solide/terre-et-vie/de-nouvellesdatations-repoussent-l-age-de-l-apparition-d-outils-surle-so
www.cerege.fr/spip.php?page=pageperso&id_user=94
Find words who look like urls:
str = "ANQUETIL-DUPERRON Abraham-Hyacinthe, KIEFFER Jean-Luc, www.hominides.net/html/actualites/outils-preuve-presence-hominides-asie-0422.php,Les Belles lettres, 2001.\n\nhttps://www.ancient-code.com/indian-archeologists-stumbleacross-ruins-great-forgotten-civilization-mizoram/\n\nwww.jstor.org/stable/24084454\n\nwww.biorespire.com/2016/03/22/une-nouvelle-villeantique-d%C3%A9couverte-en-inde/\n\ninsu.cnrs.fr/terre-solide/terre-et-vie/de-nouvellesdatations-repoussent-l-age-de-l-apparition-d-outils-surle-so\n\nwww.cerege.fr/spip.php?page=pageperso&id_user=94"
str.split.select{|w| w[/(\b+\.\w+)/]}
This will give you an array of words which have no spaces and include a one or more . characters which MIGHT work for your use case.
puts str.split.select{|w| w[/(\b+\.\w+)/]}
www.hominides.net/html/actualites/outils-preuve-presence-hominides-asie-0422.php,
https://www.ancient-code.com/indian-archeologists-stumbleacross-ruins-great-forgotten-civilization-mizoram/
www.jstor.org/stable/24084454
www.biorespire.com/2016/03/22/une-nouvelle-villeantique-d%C3%A9couverte-en-inde/
insu.cnrs.fr/terre-solide/terre-et-vie/de-nouvellesdatations-repoussent-l-age-de-l-apparition-d-outils-surle-so
www.cerege.fr/spip.php?page=pageperso&id_user=94
Updated
Complete solution to modify your string:
str_with_quote = str.clone # make a clone for the `gsub!`
str.split.select{|w| w[/(\b+\.\w+)/]}
.each{|url| str_with_quote.gsub!(url, '"' + url + '"')}
Now your cloned object wraps urls inside double quotes
puts str_with_quote
Will give you this output
ANQUETIL-DUPERRON Abraham-Hyacinthe, KIEFFER Jean-Luc, "www.hominides.net/html/actualites/outils-preuve-presence-hominides-asie-0422.php,Les" Belles lettres, 2001.
"https://www.ancient-code.com/indian-archeologists-stumbleacross-ruins-great-forgotten-civilization-mizoram/"
"www.jstor.org/stable/24084454"
"www.biorespire.com/2016/03/22/une-nouvelle-villeantique-d%C3%A9couverte-en-inde/"
"insu.cnrs.fr/terre-solide/terre-et-vie/de-nouvellesdatations-repoussent-l-age-de-l-apparition-d-outils-surle-so"
"www.cerege.fr/spip.php?page=pageperso&id_user=94"
currently i'm have a bit problem to parse URL using URI
i've tried to use this code :
uri = URI::parse(Model.first.media)
#<URI::HTTPS https://my-bucket.s3.amazonaws.com/model/media/41/cdbb21cc-1c59-4aa3-92ec-917e7237a850.mp4>
uri.path
"/model/media/41/cdbb21cc-1c59-4aa3-92ec-917e7237a850.mp4"
File.basename(Model.first.media, '.mp4')
"cdbb21cc-1c59-4aa3-92ec-917e7237a850.mp4"
but i'm still confused to get path without / as first char in example model/media/41/cdbb21cc-1c59-4aa3-92ec-917e7237a850.mp4 and get only the path without domain and the file in example model/media/41
do i must using regex to get above output ? or URI can handle this ?
note:
i've found how to get url extension without first char based on this question Ruby regexp: capture the path of url
URI class helps break apart URLs into components and gives you methods like
[:scheme, :userinfo, :host, :port, :path, :query, :fragment]
If you simply need to get rid of the first slash it's simple as this with no regex.
uri.path[1..-1] #gives all string characters except the 0 index.
But you could probably even get away with:
Model.first.media.split('.com/').last # don't even need URI parse.
For last part of your question you can do:
File.dirname(uri.path) # will return => "/model/media/41"
File.dirname(uri.path)[1..-1] # if you want to remove leading /
I am facing problem when passing value for url through data field.
I am passing value in goto url like this
="javascript:void(window.open('file:" &Fields!url.Value &"','_blank'))"
url value = /servername/foldername/FormuláriodeCalibração.xls
After report deployed and opened in internet explorer and clicked on the url. It is changing the url like this
/servername/foldername/FormuláriodeCalibração.xls
because of which I am unable to open the file.
Please help me in this.
Finally we come up with a solution of replacing non ASCII characters of Portuguese with HTML ASCII Codes.
For e.g. this is the actual file name of the attachment
TE-5180FormuláriodeCalibração(modelo)1271440308393(2)1338379011084.xls
We replaced the Portuguese characters with HTML ASCII Codes.
TE-5180FormuláriodeCalibração(modelo)1271440308393(2)1338379011084.xls
After these changes the above modified URL is passed in the place of actual URL and when it hits the server it was decoded properly and worked as expected.
The message box crops up could not find part of the path of the file"file path" when i try to open a file that has space in its file path. I have used LocalPath instead of AbsolutePath and it works fine for me, but its only limited to WinApps, i needed a more generic solution. Some thing like Uri unescaped data path. I am not sure about the syntax.
In Java: URI uri = new File("spaces in file name").toURI();
If the file can be fetched depends on your implementation of the software. Try to replace the spaces with %20
What kind of development are we talking about here? JAVA GUI or WebApps? C/C++?
You should try enclosing your URI with quotes
new Uri("\"C:\some path\some file\"");