What should I do if I have seven segment pins in different ports? - mplab

Question

In my circuit, 7 segment pins is in different port like:Seg A to SegD (in RA0 to RA4) SegE(in RF1) SegF (RG4) SegG(RG3). I can count 0 to 9 with setting bits one by one. I need to count 0-9999 but ı can't store values. How can ı do that for my specs?
#include "mcc_generated_files/mcc.h"
#define DISP1 RD7
#define DISP2 RD6
#define DISP3 RD5
#define DISP4 RD4
#define SEGA RA0
#define SEGB RA1
#define SEGC RA2
#define SEGD RA3
#define SEGE RF1
#define SEGF RG4
#define SEGG RG3
void main(void)
{
// initialize the device
SYSTEM_Initialize();
TRISD = 0x00; // Set All Pins To Be Output Pins
PORTD = 0x00; // Initially Clear All The 8-Pins
while(1)
{
SEGA=1;SEGB=1;SEGC=1;SEGD=1;SEGE=1;SEGF=1;SEGG=0;DISP4=1;//0
__delay_ms(500);
SEGA=0;SEGB=1;SEGC=1;SEGD=0;SEGE=0;SEGF=0;SEGG=0;DISP4=1;//1
__delay_ms(500);
SEGA=1;SEGB=1;SEGC=0;SEGD=1;SEGE=1;SEGF=0;SEGG=1;DISP4=1;//2
__delay_ms(500);
SEGA=1;SEGB=1;SEGC=1;SEGD=1;SEGE=0;SEGF=0;SEGG=1;DISP4=1;//3
__delay_ms(500);
SEGA=0;SEGB=1;SEGC=1;SEGD=0;SEGE=0;SEGF=1;SEGG=1;DISP4=1;//4
__delay_ms(500);
SEGA=1;SEGB=0;SEGC=1;SEGD=1;SEGE=0;SEGF=1;SEGG=1;DISP4=1;//5
__delay_ms(500);
SEGA=1;SEGB=0;SEGC=1;SEGD=1;SEGE=1;SEGF=1;SEGG=1;DISP4=1;//6
__delay_ms(500);
SEGA=1;SEGB=1;SEGC=1;SEGD=0;SEGE=0;SEGF=0;SEGG=0;DISP4=1;//7
__delay_ms(500);
SEGA=1;SEGB=1;SEGC=1;SEGD=1;SEGE=1;SEGF=1;SEGG=1;DISP4=1;//8
__delay_ms(500);
SEGA=1;SEGB=1;SEGC=1;SEGD=1;SEGE=0;SEGF=1;SEGG=1;DISP4=1;//9
__delay_ms(500);
}

Answer 1

Some hints:
If you want 4 digits, you had to multiplex your display.
Write a table where you define each number:
const uint8_t LEDTable[10] = {0b00111111, //led drive for 0
0b00000110, //led drive for 1
....
0b01101101}; //led drive for 9
Do the multiplexing in an interrupt routine.
In the interrupt you had to do the output for each digit:
ones
tens
hunderts...
The output for each digit could look like:
SEGA = (value & 0x01) ? 1:0;
SEGB = (value & 0x02) ? 1:0;
SEGC = (value & 0x04) ? 1:0;
SEGD = ...