I am using ActionCable to provide Browser Notification which is easy to implement. The problem is coming when a user has open the multiple tabs in the browser and I need to send the data to only one tab i.e to only one WebSocket in user room. How can this be done?
Isolating a single pub/sub client isn't directly possible with the pub/sub approach, because the whole idea is that publishers have no knowledge of subscribers.
However, there are two common ways to solve this:
to use a different named channel per connection, saving the named channel in the database and forwarding all messages to that specific named channel (i.e. saving the channel user-ID-TIMESTAMP in the database and using it as the target connection).
another, somewhat more reliable approach (though more complex) is to send the message to all clients but create a race condition that allows only a single client to receive the actual message. This would look something like this:
server sends "you have a message" to all clients.
client polls "undelivered" messages from the server.
server locks the message pool or uses a database transaction in order to retrieve undelivered messages and mark the messages as delivered. The server sends the undelivered messages to the client (optionally setting an ACK timeout).
a single client connection receives the undelivered messages the rest get an empty array of messages (since they were all delivered to the other client) or receive a "delivered" flag so the data is updated but no notification is raised.
(optional) the client sends and ACK.
(optional) the server marks the message delivery as complete. If no ACK was received before "timeout", server unmarks delivery and resends the "you have a message" message.
Good luck!
Every time a new connection is made we will create a new room. So for example when the user is making a new connection we can give the room name as users:user_id:some_unique_random_string which may be equal to users:user_id:123j123b1h2b1j23bh12b3 and when the same user makes another connection by opening another tab we will also do the same and create a separate room.
Now one thing the ActionCable provides is that we can find all the room name followed by any prefix.
Lets the user has made three connections and their rooms are users:128:123n1jh123ko9876, users:128:asdas23412cs1234, users:128:asni9202h5i3jens then we can obtain these room name using ActionCable also.
user_id = 128
pubsub = ActionCable.server.pubsub
channel_with_prefix = pubsub.send(:channel_with_prefix, RoomChannel.channel_name)
channels = pubsub.send(:redis_connection).pubsub('channels', "#{channel_with_prefix}:users:#{user_id}:*")
Now the channels is an array consisting of the rooms name.
So puts channels
["chatapp_production:users:128:123n1jh123ko9876", "chatapp_production:users:128:asdas23412cs1234", "users:128:asni9202h5i3jens"]
This is how we can find all the rooms related to a single user without using any external database and API calls.
Related
I have been trying to work with paho mqtt client to publish and receive messages with mosquitto as the broker and works fine. My use case although involves the sender publishing a message to the broker and disconnects, at this point, the receiver whether connected or disconnected should consume this message and delete it immediately. I have played with all the properties e.g QOS, retained messages, clean sessions, etc but none is yielding the result I want. Please help.
Assuming a Publish and Subscription at QOS2 the message will only ever be delivered to the subscriber once, there is nothing to delete from anywhere.
If you are trying to ensure that the message is only ever consumed by one specific client then I think you have a misunderstanding about what MQTT is.
MQTT is a PUB/SUB protocol, and as such is designed to totally decouple the subscriber from the publisher. The publisher doesn't know how many subscribers there are, just that it has published a message to a given topic.
0 to N (where N can be any number) of clients can subscribe to the topic. Using QOS, persistent subscriptions and the clean session flag, a client can indicate to the broker that it would like to receive any messages published since was last connected, but this will not influence any other clients that may have also subscribed to that topic.
Starting at MQTT protocol v5 (most brokers and clients currently still only support v3 as of Sept 2018) includes something called Shared Subscriptions* that can be used to round-robin deliver messages on a give topic to a group of clients so only 1 of the set will receive this message, but this does not prevent clients not part of the group from also receiving the message.
The last message with the retained flag set published to a topic will be delivered to all clients at the point they subscribe to the topic. This message can be cleared by publishing a new message with a null payload and the retained flag set. A client could publish a message like this as soon as it receives the retained message but there would still be a timing window where other clients may subscribe and receive the retained message.
*some v3 brokers have implemented propriety versions of this.
I'm using mosquitto as broker and paho(python) as client. I'm trying to make subscriber to receive offline messages.
For that I made following changes:
Fixed client ID
qos level 2
but, still the subscriber is not able to receive messages.
any help?
Thanks,
Rahul
In order to have your client as a durable client and receive messages that were sent to topics when it was offline, you need to meet the following criteria:
Fixed client ID (as you've done)
Always connect with clean_session=False
Subscriptions must be made with QoS>0
Messages published must have QoS>0
The mistake that I make most frequently is to forget either one of points 3 and 4, so I'm publishing with QoS=0 or subscribing with QoS=0, either of which would cause messages not to be stored.
You could also look at the queue_qos0_messages option to tell the broker to store QoS=0 messages as well. Note that this is an implementation detail that may be specific to mosquitto.
Check if you have set the retain flag to true when publishing message to topic, with retain=true, new connected client which subscribes the topic will receive the retained message.
I am facing an issue with the presence status, following the documentation and XMPPframework example code. I have written a chat application.
Problem : When the user 1 & 2 are online I get the status successfully and they can chat with each other. However when the user 2 goes physically offline via (Wifi OFF / 3G Off) User 1 is not getting the offline status from XMPP and hence what ever messages are sent from that instant of time are lost when the user 2 comes online.
It seems since the user 2 is not notified or stored as offline in XMPP and hence its not storing the offline messages to push back to user 2 when it comes online.
I have tried to resolve this by explicitly writing a [goOffline] call to XMPP, however the call is shown in 'SEND log' for 'user 2' but not received in 'RECV log' in user 1 from XMPP, due to which the message are lost in between.
Also tried with other sources replies.
Set status for presence available and send XMPP
priority changed with values non-negative
XMPPArchiving work but this is not what I wanted.
Server side Mod_zero push enables but get only first message push notification sometimes.
Setting limit on ejabberd.cfg file for users and offline message limit.
request for offline message pull.
Can anyone help me with this?
This is very typical situation where client losses network but server can't detect that it is offline.
To detect status of each client, server need to send PING packets to every client and wait for response.
If client responds then fine otherwise server will mark that client as offline and every other online client will be informed automatically.
Here is PING Module implementation for ejabberd XMPP Server (hope you are using ejabberd server):
mod_ping:
send_pings: true
ping_interval: 10
timeout_action: kill
ping_ack_timeout: 10
This has to be written in ejabberd.yml configuration file.
At client side also we need to enable ping module to respond to server pings as:
private var xmppPing: XMPPPing?
xmppPing = XMPPPing()
xmppPing!.activate(xmppStream!)
This code has to be written while we setupStream() for iOS.
For detailed info, please go through mod_ping documentations.
Sounds like your problem is at server level. The server thinks that the user is online so it sends the message but nobody gets it. This does not really have a simple solution.
1.
The best solution would be delivery receipts. Where basically when the message is sent to your client, your client returns a confirmation of delivery receipt. If the server does not get that receipt it would resend the message every n time. Depending on your XMPP server you might find a already made solution, of not you would have to roll out your own.
2.
A possible hack would be to have your server always store and deliver last 10 messages and then at client side you discard repeated... This also depends on your server implementation. XMPP MUC and PubSub have resources along these lines.
For a long term scalable solution, you'll need to deal with this both at server and client level.
I am trying to set up a MQTT server which will persist the messages sent by clients into a local DB. Each message has a "successfully received" flag that I want to flip when receiving clients return a puback for each message (QOS = 1) received.
The question is:
When I publish a message, the server receives the puback back from the receiving client correctly. However, the messageId is not the same as the one from publishing client's packet. I know this is intended. But then I will not be able to find the right message in DB to flip the flag. What if client A sends 2 messages with QOS = 1 to client B back to back? How does the server distinguish between the 2 pubacks coming back?
Maybe MQTT client is doing something magical to map the messageIds that I am missing?
I am using mqttjs and paho mqttv3 btw.
MQTT PUBLISH messages with QoS 1 or 2 require a message id as part of the packet. The message id is used to identify which message a PUBACK (or PUBREC/PUBREL/PUBCOMP for QoS 2) is referring to. This is an important feature because you may have multiple messages "in flight" at once.
An important point that you may be missing is that clients are completely separate from one another. This means that message ids are unique to a client (and direction of message flow, broker to client or client to broker). The broker generates message ids for messages originating from the broker and the client generates message ids for messages originating from the client; the message ids are independent for each direction so that there is no need for the broker and the client to keep track of what the other is doing.
If you want to keep track of which incoming messages have been sent to all subscribing clients, you will need to keep track of what outgoing messages relate to the incoming message and only trigger your DB once all of the PUBACKs have been received for those outgoing messages. That will tell you which messages have successfully been sent to all clients that were subscribed at the time of the message being received.
If you just want a log of all messages that have been sent to the broker and can assume that the sending works ok, then life is a lot easier. Simply create a client on the broker host that listens to the "#" topic, or whatever you are interested in, then use the client on_message() callback (or however your library manages it) to process the message and store it in the DB.
The company I am working for has evaluated MQTT and decided to use it as a core messaging platform for a large scale system. The main reason is how compact the protocol is and how easy it can actually be implemented. I have a single issue with MQTT though and I'm seeking for an answer to the following question:
QoS1 and QoS2 messages require confirmation from the client. The only thing I know about the message (identifying it) when receiving PUBACK, PUBREC, PUBREL and PUBCOMP is messageId and the clientId. Message id is an unsigned int16 so the max value is 65535. It doesn't seem to be large enough for long running clients, say a year, sending 15 QoS2 messages an hour.
I am not quite sure if there's any other way to identify the message? I would like to be as compliant with the standard as possible.
Probably the first point to make clear is that message IDs are handled on a per client and per direction basis. That is to say that the broker will create a message ID for each outgoing message with QoS>0 for each client that is connected and these message IDs will be completely independent of any other message IDs used for the same message published to other clients. Likewise, each client generates its own message IDs for messages that it sends.
The message ID doesn't have to be unique, so your client sending 15 messages per hour with QoS level 2 would simply overflow at some point. The real limitation is that there can only be a maximum of 65535 messages per direction "in flight" at once (i.e. part way through the message handshake). Once a message with a given ID has been fully processed then that message ID can be reused.
Another way of looking at it is to consider how it would work if your client only ever had one message in flight at once, whether because of the rate the messages are being transmitted or by design in the way you handle the messages. In this case, you could keep message ID set to 1 for every single message because there is never a chance that there will be a duplicate.
If you wish to support having multiple messages in flight at once it would be relatively straightforward to check there are no message ID duplicates before you assign a new one.
Because the message ID is per client, if you send a single message to >65535 clients there will be no chance of message ID collisions. If you send >65535 messages to each client at once and the message flows aren't complete then there will be problems.
Answering the comment "I have noticed that every MQTT broker tends to deliver only the last QoS1/2 message":
The broker will only send messages to clients it knows about. If you connect for the first time there is no way to get messages from the past, with one exception: retained messages. If a message is set to retained then it is a "last known good" value. When a new client subscribes it will be sent the retained message immediately which makes it useful for things that are updated infrequently. I suspect this is what you are referring to. If you want a client to have messages queued when it is not connected then you must connect with the "clean session" option disabled to make the client persistent. You must also use QoS>0 subscriptions and QoS>0 publications. When your client reconnects (with clean session still set to disabled), the queued messages will be delivered. You can normally configure the number of messages to queue in this way in the broker, where any further messages will be discarded. An important point is that queueing messages for a client that has not previously connected is not supported by design.
For delivering more messages at QOS1 or QOS2, you should use concept of persistant memory. In this when ever a subscriber is not available the message get stored in persistant memory and deliver once subscriber is connected. You can do this at QOS0 also after configuring mosquitto.conf file.