How to get the address from the coordinate - ios

Question

I want to get the address from the coordinate. I have attached my code below..
func locationManager(_ manager: CLLocationManager, didUpdateLocations locations: [CLLocation]) {
let lastLocation = locations.last!
let latvalue = lastLocation.coordinate.latitude
let lngvalue = lastLocation.coordinate.longitude
self.db_latvalue = latvalue
self.db_lngvalue = lngvalue
let location = CLLocation(latitude: latvalue, longitude:lngvalue)
let address = CLGeocoder.init()
address.reverseGeocodeLocation(CLLocation.init(latitude: latvalue, longitude:lngvalue)) { (places, error) in
if error == nil{
if let place = places{
print("addressshowingssq \(place)")
self.db_address = "\(place)"
}
}
}
Output:
[L-30 2nd A Main Road, L-30 2nd A Main Road, HSR Layout, Bengaluru,
Karnataka 560102, India # <+12.91597974,+77.62879254> +/- 100.00m,
region CLCircularRegion (identifier:'<+12.91597974,+77.62879254>
radius 70.94', center:<+12.91597974,+77.62879254>, radius:70.94m)]
I want only the address as i mention below
L-30 2nd A Main Road, L-30 2nd A Main Road, HSR Layout, Bengaluru,
Karnataka 560102
I researched google i got different solution so i got confused.

Answer 1

Update
I have done a few modification to iVarun's solution. This is simpler. and working.
First, add this function:
func geocode(latitude: Double, longitude: Double, completion: #escaping (CLPlacemark?, Error?) -> ()) {
CLGeocoder().reverseGeocodeLocation(CLLocation(latitude: latitude, longitude: longitude)) { completion($0?.first, $1) }
}
After that,
get the address:
geocode(latitude: latvalue, longitude: lngvalue) { placemark, error in
guard let placemark = placemark, error == nil else { return }
// you should always update your UI in the main thread
DispatchQueue.main.async {
// update UI here
print("address1:", placemark.thoroughfare ?? "")
print("address2:", placemark.subThoroughfare ?? "")
print("city:", placemark.locality ?? "")
print("state:", placemark.administrativeArea ?? "")
print("zip code:", placemark.postalCode ?? "")
print("country:", placemark.country ?? "")
}
}
Result:
address1: Rua Casuarina
address2: 443
city: Rio de Janeiro
state: RJ
zip code: 20975
country: Brazil
As #iOSer indicated, CLPlacemark is capable of giving you this part of the string, However.
You could split the string:
let output:String = "[L-30 2nd A Main Road, L-30 2nd A Main Road, HSR Layout, Bengaluru, Karnataka 560102, India # <+12.91597974,+77.62879254> +/- 100.00m, region CLCircularRegion (identifier:'<+12.91597974,+77.62879254> radius 70.94', center:<+12.91597974,+77.62879254>, radius:70.94m)]"
let items = output.components(separatedBy: "#")
print(items[0])
Becuse the # will be always included, you could skip the rest.
Result:

Answer 2

Hope this will help you:
address.reverseGeocodeLocation(CLLocation.init(latitude: latvalue, longitude:lngvalue)) { (places, error) in
if error == nil{
let placeMark = places! as [CLPlacemark]
if placeMark.count > 0 {
let placeMark = places![0]
var addressString : String = ""
if placeMark.subThoroughfare != nil {
addressString = addressString + placeMark.subThoroughfare! + ", "
}
if placeMark.thoroughfare != nil {
addressString = addressString + placeMark.thoroughfare! + ", "
}
if placeMark.subLocality != nil {
addressString = addressString + placeMark.subLocality! + ", "
}
if placeMark.locality != nil {
addressString = addressString + placeMark.locality! + ", "
}
if placeMark.administrativeArea != nil {
addressString = addressString + placeMark.administrativeArea! + ", "
}
if placeMark.country != nil {
addressString = addressString + placeMark.country! + ", "
}
if placeMark.postalCode != nil {
addressString = addressString + placeMark.postalCode! + " "
}
print(addressString)
}
}
}
Output:
L-30, 2nd A Main Road, HSR Layout, Bengaluru, Karnataka, India, 560102

Answer 3

Swift 3
func locationManager(_ manager: CLLocationManager, didUpdateLocations locations: [CLLocation]) {
let locValue:CLLocationCoordinate2D = manager.location!.coordinate
let objLocation = CLLocation(latitude: locValue.latitude, longitude: locValue.longitude)
CLGeocoder().reverseGeocodeLocation(objLocation) { (placemarksArray, error) in
if error != nil {
print("Reverse geocoder failed with error" + (error?.localizedDescription)!)
return
}
if (placemarksArray?.count)! > 0 {
let objPlacemark = placemarksArray?[0]
self.generateAddress(objPlacemark: objPlacemark!)
self.locationManager?.stopUpdatingLocation()
self.locationManager = nil
}
else {
print("Problem with the data received from geocoder")
}
}
}
Function Parsing placemark to string...
func generateAddress(objPlacemark : CLPlacemark) -> String {
print("objPlacemark : \(objPlacemark.description)")
var completeAddress = ""
if objPlacemark.name != nil {
completeAddress = String(describing: objPlacemark.name!)
}
if objPlacemark.thoroughfare != nil && (objPlacemark.name != objPlacemark.thoroughfare) {
completeAddress = completeAddress + ", " + String(describing: objPlacemark.thoroughfare!)
}
if objPlacemark.subThoroughfare != nil {
completeAddress = completeAddress + ", " + String(describing: objPlacemark.subThoroughfare!)
}
if objPlacemark.subLocality != nil {
completeAddress = completeAddress + "," + String(describing: objPlacemark.subLocality!)
}
if objPlacemark.locality != nil {
completeAddress = String(describing: objPlacemark.locality!)
}
if objPlacemark.postalCode != nil {
completeAddress = completeAddress + "," + String(describing: objPlacemark.postalCode!)
}
if objPlacemark.administrativeArea != nil {
completeAddress = completeAddress + "," + String(describing: objPlacemark.administrativeArea!)
}
if objPlacemark.isoCountryCode != nil {
completeAddress = completeAddress + "," + String(describing: objPlacemark.isoCountryCode!)
}
print("completeAddress : \(completeAddress)")
return completeAddress
}

Answer 4

CLGeocodeCompletionHandler contains an array of CLPlacemark. You can access its properties such as name, locality, isoCountryCode etc to form a complete address!!