Convert Reactive Cocoa Code to RxSwift? - ios

For this code
fileprivate let nameChangedProperty = MutableProperty("")
public func nameChanged(_ name: String) {
self.nameChangedProperty.value = name
}
What I did
fileprivate let nameChangedProperty = BehaviorRelay<String>(value: "")
public func nameChanged(_ name: String) {
self.nameChangedProperty.accept(name)
}
But confused about
public init() {
let initialText = self.viewDidLoadProperty.signal.mapConst("")
let name = Signal.merge(
self.nameChangedProperty.signal,
initialText
)
}
here, for first line, I did
let initialToken = self.viewDidLoadProperty.asObservable().map { _ in "" }
but no idea abut merge signal ....
If some theory concepts are given, is appreciated.

Observable has static method merge method. You could make the following changes to your code to create name observable.
let initialText = rx.sentMessage(#selector(MyViewController.viewDidLoad)).map { _ in "" }
let name = Observable.merge(initialText, nameChangedProperty.asObservable())

Related

Write Generic Swift Method to load data from property list

I have a method that loads an array of dictionaries from a propertylist. Then I change those arrays of dictionaries to array of a defined custom type;
I want to write that method in generic form so I call that method with the type I expect, then the method loads it and returns an array of my custom type rather than dictionaries
func loadPropertyList(fileName: String) -> [[String:AnyObject]]?
{
if let path = NSBundle.mainBundle().pathForResource(fileName, ofType: "plist")
{
if let plistXML = NSFileManager.defaultManager().contentsAtPath(path)
{
do {
if let temp = try NSPropertyListSerialization.propertyListWithData(plistXML, options: .Immutable, format: nil) as? [[String:AnyObject]]
{
return temp
}
}catch{}
}
}
return nil
}
//
func loadList<T>(fileName: String) -> [T]?{//**Here the answer I am expecting**}
I am assuming your function to read from a Plist works and that you don't want to subclass NSObject.
Since Swift reflecting does not support setting values this is not possible without some implementation for each Type you want this to work for.
It can however be done in a pretty elegant way.
struct PlistUtils { // encapsulate everything
static func loadPropertyList(fileName: String) -> [[String:AnyObject]]? {
if let path = NSBundle.mainBundle().pathForResource(fileName, ofType: "plist") {
if let plistXML = NSFileManager.defaultManager().contentsAtPath(path) {
do {
if let temp = try NSPropertyListSerialization.propertyListWithData(plistXML, options: .Immutable, format: nil) as? [[String:AnyObject]] {
return temp
}
} catch {
return nil
}
}
}
return nil
}
}
This protocol will be used in a generic fashion to get the Type name and read the corresponding Plist.
protocol PListConstructible {
static func read() -> [Self]
}
This protocol will be used to implement Key Value setters.
protocol KeyValueSettable {
static func set(fromKeyValueStore values:[String:AnyObject]) -> Self
}
This is the combination of both to generate an array of objects. This does require that the Plist is named after the Type.
extension PListConstructible where Self : KeyValueSettable {
static func read() -> [Self] {
let name = String(reflecting: self)
var instances : [Self] = []
if let data = PlistUtils.loadPropertyList(name) {
for entry in data {
instances.append(Self.set(fromKeyValueStore: entry))
}
}
return instances
}
}
This is some Type.
struct Some : PListConstructible {
var alpha : Int = 0
var beta : String = ""
}
All you have to do is implement the Key Value setter and it will now be able to be read from a Plist.
extension Some : KeyValueSettable {
static func set(fromKeyValueStore values: [String : AnyObject]) -> Some {
var some = Some()
some.alpha = (values["alpha"] as? Int) ?? some.alpha
some.beta = (values["beta"] as? String) ?? some.beta
return some
}
}
This is how you use it.
Some.read()

Is there any way of sharing getter and setter through properties in Swift?

I'm building a helper to enable typed access to NSUserDefaults properties. Something like this:
struct UserDefaults {
private static var standardUserDefaults: NSUserDefaults = {
return NSUserDefaults.standardUserDefaults()
}()
private static let propKey = "PROP"
static var prop: Bool {
get {
return standardUserDefaults.boolForKey(propKey)
}
set {
standardUserDefaults.setBool(newValue, forKey: propKey)
standardUserDefaults.synchronize()
}
}
}
This way I can have a nice syntax for reading and writing to NSUserDefaults:
UserDefaults.prop // read
UserDefaults.prop = false // write
The problem is that there's a lot of boilerplate code for this, I need 10 lines for each aditional property.
Is there any way of reducing the amount of lines needed for each new property? Reusing getter and setter? Any kind of run time generator?
You can try wrapping the actual value in a class that handles all the dirty work for you:
class WrappedUserDefault<T> {
let key : String
let defaultValue : T
var value : T {
get {
if let value = UserDefaults.standardUserDefaults.objectForKey(key) as? T {
return value
} else {
return defaultValue
}
}
set {
if let value = newValue as? AnyObject {
UserDefaults.standardUserDefaults.setValue(value, forKey: key)
} else {
UserDefaults.standardUserDefaults.removeObjectForKey(key)
}
UserDefaults.standardUserDefaults.synchronize()
}
}
init(key:String, defaultValue:T) {
self.key = key
self.defaultValue = defaultValue
}
}
struct UserDefaults {
static let standardUserDefaults = NSUserDefaults.standardUserDefaults()
static let ready = WrappedUserDefault<Bool>(key:"ready", defaultValue: true)
static let count = WrappedUserDefault<Int>(key: "count", defaultValue: 0)
}
Then with just a little bit more code you wind up with:
UserDefaults.count.value++
UserDefaults.ready.value = true
UserDefaults.ready.value
If the verbosity of ready.value bothers you, you can somewhat hide that, although then you're back to you're back to having a fair amount of copy/paste code:
struct UserDefaults {
static let standardUserDefaults = NSUserDefaults.standardUserDefaults()
private static let readyWrapper = WrappedUserDefault<Bool>(key:"ready", defaultValue: true)
static var ready : Bool {
get { return readyWrapper.value }
set { readyWrapper.value = newValue }
}
}
At least in this case though, the copy/paste code is fairly trivial, so unlikely to need to be altered in the future.
I like David's answer much better, but here's another option. Drops your 10 lines per variable down to 5 (mainly because of new line removal...)
struct UserDefaults {
private static var standardUserDefaults: NSUserDefaults = {
return NSUserDefaults.standardUserDefaults()
}()
//Repeate these 5 lines for all new variables,
//changing the as? to the proper variable type
//Adding in a default value for the return in
//case the as? cast fails for any reason
private static let propKey = "PROP"
static var prop: Bool {
get { return (getVar(propKey) as? Bool) ?? false }
set { setVar(newValue, key:propKey) }
}
//The generic set/get
private static func getVar(key : String) -> AnyObject?
{
return standardUserDefaults.objectForKey(key)
}
private static func setVar(newValue : AnyObject, key : String)
{
if(newValue is Bool)
{
standardUserDefaults.setBool((newValue as? Bool)!, forKey: key)
}
//... More cases here
else if(newValue == nil)
{
standardUserDefaults.removeObjectForKey(key)
}
else
{
standardUserDefaults.setObject(newValue, forKey: key)
}
standardUserDefaults.synchronize()
}
}

Swift - how do I pass the type through a method call?

A Realm object:
class Dog: Object {
dynamic var name = ""
dynamic var age = 0
}
Calling results:
let results = realm.objects(Dog)
Or doing it this way:
let type = Dog.self
let results = realm.objects(type)
I want to be able to do it by passing into a method like this:
class SomeClass {
func callRealm(type: AnyObject) {
let results = realm.objects(type)
}
}
let someClass = SomeClass()
let type = Dog.self
someClass.callRealm(type)
How would I do this? I've had no luck with generics, although I think this might be the way to go.
Your function callRealm should take input as AnyClass instead of AnyObject.
func callRealm(type: AnyClass) {
let results = realm.objects(type)
}

What is the best way to connect Realm and SwiftBond

I love Realm and I love Bond. Both of them makes app creation a joy. So I was wondering what is the best way to connect Realm and Bond? In Realm we can store basic types such as Int, String, e.g. But in Bond we work with Dynamics and Bonds. The only way that I found to connect Realm and Bond is following:
class TestObject: RLMObject {
dynamic var rlmTitle: String = ""
dynamic var rlmSubtitle: String = ""
var title: Dynamic<String>
var subtitle: Dynamic<String>
private let titleBond: Bond<String>!
private let subtitleBond: Bond<String>!
init(title: String, subtitle: String) {
self.title = Dynamic<String>(title)
self.subtitle = Dynamic<String>(subtitle)
super.init()
self.titleBond = Bond<String>() { [unowned self] title in self.rlmTitle = title }
self.subtitleBond = Bond<String>() { [unowned self] subtitle in self.rlmSubtitle = subtitle }
self.title ->> titleBond
self.subtitle ->> subtitleBond
}
}
But it surely lacks simplicity and elegance and produces a lot of boiler code. Is there any way to do this better?
With Realm supporting KVO and Bond 4, you can extend Realm objects to provide Observable variants. There is some boilerplate to it, but it's clean and without hacks.
class Dog: Object {
dynamic var name = ""
dynamic var birthdate = NSDate(timeIntervalSince1970: 1)
}
extension Dog {
class ObservableDog {
let name: Observable<String>
let birthdate: Observable<NSDate>
init(dog: Dog) {
name = Observable(object: dog, keyPath: "name")
birthdate = Observable(object: dog, keyPath: "birthdate")
}
}
func observableVariant() -> Dog.ObservableDog {
return ObservableDog(dog: self)
}
}
Than you'll be able to do:
let myDog = Dog().observableVariant()
myDog.name.observe { newName in
print(newName)
}
myDog.name.bindTo(nameLabel.bnd_text)
realm.write {
myDog.name.value = "Jim"
}
You could likely simplify the pattern you're using somewhat if you used
default property values:
class TestObject: RLMObject {
dynamic var rlmTitle = ""
dynamic var rlmSubtitle = ""
var title: Dynamic<String>
var subtitle: Dynamic<String>
private let titleBond = Bond<String>() { [unowned self] title in self.rlmTitle = title }
private let subtitleBond = Bond<String>() { [unowned self] subtitle in self.rlmSubtitle = subtitle }
init(title: String, subtitle: String) {
self.title = Dynamic<String>(title)
self.subtitle = Dynamic<String>(subtitle)
self.title ->> titleBond
self.subtitle ->> subtitleBond
super.init()
}
}
You could remove another two lines of code if Bond's ->> operator returned the
left value so you could do self.title = Dynamic<String>(title) ->> titleBond.
But ultimately, until Swift has native language support for KVO or an equivalent observation mechanism, you're sadly going to have to write some amount of boilerplate.
I've been thinking about this for three days and came up with nearly perfect solution, which does not employ any boilerplate code. First of all I have created a super class for a realm model's wrapper:
class BondRealmBaseClass {
private var realmModel: RLMObject!
private let realm = RLMRealm.defaultRealm()
private var bonds = NSMutableArray()
init(){
realmModel = createRealmModel()
realm.beginWriteTransaction()
realm.addObject(realmModel)
realm.commitWriteTransaction()
createBonds()
}
init(realmModel: RLMObject){
self.realmModel = realmModel
createBonds()
}
func createBondFrom<T>(from: Dynamic<T>, toModelKeyPath keyPath: String){
from.value = realmModel.valueForKeyPath(keyPath) as T
let bond = Bond<T>() { [unowned self] value in
self.realm.beginWriteTransaction()
self.realmModel.setValue(value as NSObject, forKey: keyPath)
self.realm.commitWriteTransaction()
}
from ->| bond
bonds.addObject(bond)
}
//MARK: - Should be overriden by super classes
func createBonds(){ fatalError("should be implemented in supreclass") }
func createRealmModel() -> RLMObject{ fatalError("should be implemented in supreclass") }
}
After that for each realm model I create two classes, first is the actual realm model, which stores all properties:
class RealmTodoModel: RLMObject {
dynamic var title = ""
dynamic var date = NSDate()
}
and a second one is the wrapper around realm model:
class TodoModel : BondRealmBaseClass{
let title = Dynamic("")
let date = Dynamic(NSDate())
override func createBonds(){
createBondFrom(title, toModelKeyPath: "title")
createBondFrom(date, toModelKeyPath: "date")
}
override func createRealmModel() -> RLMObject { return RealmTodoModel() }
}
And this two classes is actually all is needed to link Realm and Bond: creating new TodoModel will actually add to Realm new RealmTodoModel and all changes made with TodoModel's title and date will be automatically saved to corresponding Realm model!
EDIT
I added some functionality and posted this as a framework on GitHub. Here is the link.

Swift language NSClassFromString

How to achieve reflection in Swift Language?
How can I instantiate a class
[[NSClassFromString(#"Foo") alloc] init];
You must put #objc(SwiftClassName) above your swift class.
Like:
#objc(SubClass)
class SubClass: SuperClass {...}
This is the way I init derived UIViewController by class name
var className = "YourAppName.TestViewController"
let aClass = NSClassFromString(className) as! UIViewController.Type
let viewController = aClass()
More information is here
In iOS 9
var className = "YourAppName.TestViewController"
let aClass = NSClassFromString(className) as! UIViewController.Type
let viewController = aClass.init()
Less hacky solution here: https://stackoverflow.com/a/32265287/308315
Note that Swift classes are namespaced now so instead of "MyViewController" it'd be "AppName.MyViewController"
Deprecated since XCode6-beta 6/7
Solution developed using XCode6-beta 3
Thanks to the answer of Edwin Vermeer I was able to build something to instantiate Swift classes into an Obj-C class by doing this:
// swift file
// extend the NSObject class
extension NSObject {
// create a static method to get a swift class for a string name
class func swiftClassFromString(className: String) -> AnyClass! {
// get the project name
if var appName: String? = NSBundle.mainBundle().objectForInfoDictionaryKey("CFBundleName") as String? {
// generate the full name of your class (take a look into your "YourProject-swift.h" file)
let classStringName = "_TtC\(appName!.utf16count)\(appName)\(countElements(className))\(className)"
// return the class!
return NSClassFromString(classStringName)
}
return nil;
}
}
// obj-c file
#import "YourProject-Swift.h"
- (void)aMethod {
Class class = NSClassFromString(key);
if (!class)
class = [NSObject swiftClassFromString:(key)];
// do something with the class
}
EDIT
You can also do it in pure obj-c:
- (Class)swiftClassFromString:(NSString *)className {
NSString *appName = [[NSBundle mainBundle] objectForInfoDictionaryKey:#"CFBundleName"];
NSString *classStringName = [NSString stringWithFormat:#"_TtC%d%#%d%#", appName.length, appName, className.length, className];
return NSClassFromString(classStringName);
}
I hope this will help somebody !
UPDATE: Starting with beta 6 NSStringFromClass will return your bundle name plus class name separated by a dot. So it will be something like MyApp.MyClass
Swift classes will have a constructed internal name that is build up of the following parts:
It will start with _TtC,
followed by a number that is the length of your application name,
followed by your application name,
folowed by a number that is the length of your class name,
followed by your class name.
So your class name will be something like _TtC5MyApp7MyClass
You can get this name as a string by executing:
var classString = NSStringFromClass(self.dynamicType)
Update In Swift 3 this has changed to:
var classString = NSStringFromClass(type(of: self))
Using that string, you can create an instance of your Swift class by executing:
var anyobjectype : AnyObject.Type = NSClassFromString(classString)
var nsobjectype : NSObject.Type = anyobjectype as NSObject.Type
var rec: AnyObject = nsobjectype()
It's almost the same
func NSClassFromString(_ aClassName: String!) -> AnyClass!
Check this doc:
https://developer.apple.com/library/prerelease/ios/documentation/Cocoa/Reference/Foundation/Miscellaneous/Foundation_Functions/#//apple_ref/c/func/NSClassFromString
I was able to instantiate an object dynamically
var clazz: NSObject.Type = TestObject.self
var instance : NSObject = clazz()
if let testObject = instance as? TestObject {
println("yes!")
}
I haven't found a way to create AnyClass from a String (without using Obj-C). I think they don't want you to do that because it basically breaks the type system.
For swift2, I created a very simple extension to do this more quickly
https://github.com/damienromito/NSObject-FromClassName
extension NSObject {
class func fromClassName(className : String) -> NSObject {
let className = NSBundle.mainBundle().infoDictionary!["CFBundleName"] as! String + "." + className
let aClass = NSClassFromString(className) as! UIViewController.Type
return aClass.init()
}
}
In my case, i do this to load the ViewController I want:
override func viewDidLoad() {
super.viewDidLoad()
let controllers = ["SettingsViewController", "ProfileViewController", "PlayerViewController"]
self.presentController(controllers.firstObject as! String)
}
func presentController(controllerName : String){
let nav = UINavigationController(rootViewController: NSObject.fromClassName(controllerName) as! UIViewController )
nav.navigationBar.translucent = false
self.navigationController?.presentViewController(nav, animated: true, completion: nil)
}
This will get you the name of the class that you want to instantiate. Then you can use Edwins answer to instantiate a new object of your class.
As of beta 6 _stdlib_getTypeName gets the mangled type name of a variable. Paste this into an empty playground:
import Foundation
class PureSwiftClass {
}
var myvar0 = NSString() // Objective-C class
var myvar1 = PureSwiftClass()
var myvar2 = 42
var myvar3 = "Hans"
println( "TypeName0 = \(_stdlib_getTypeName(myvar0))")
println( "TypeName1 = \(_stdlib_getTypeName(myvar1))")
println( "TypeName2 = \(_stdlib_getTypeName(myvar2))")
println( "TypeName3 = \(_stdlib_getTypeName(myvar3))")
The output is:
TypeName0 = NSString
TypeName1 = _TtC13__lldb_expr_014PureSwiftClass
TypeName2 = _TtSi
TypeName3 = _TtSS
Ewan Swick's blog entry helps to decipher these strings: http://www.eswick.com/2014/06/inside-swift/
e.g. _TtSi stands for Swift's internal Int type.
In Swift 2.0 (tested in the Xcode 7.01) _20150930
let vcName = "HomeTableViewController"
let ns = NSBundle.mainBundle().infoDictionary!["CFBundleExecutable"] as! String
// Convert string to class
let anyobjecType: AnyObject.Type = NSClassFromString(ns + "." + vcName)!
if anyobjecType is UIViewController.Type {
// vc is instance
let vc = (anyobjecType as! UIViewController.Type).init()
print(vc)
}
xcode 7 beta 5:
class MyClass {
required init() { print("Hi!") }
}
if let classObject = NSClassFromString("YOURAPPNAME.MyClass") as? MyClass.Type {
let object = classObject.init()
}
string from class
let classString = NSStringFromClass(TestViewController.self)
or
let classString = NSStringFromClass(TestViewController.classForCoder())
init a UIViewController class from string:
let vcClass = NSClassFromString(classString) as! UIViewController.Type
let viewController = vcClass.init()
I am using this category for Swift 3:
//
// String+AnyClass.swift
// Adminer
//
// Created by Ondrej Rafaj on 14/07/2017.
// Copyright © 2017 manGoweb UK Ltd. All rights reserved.
//
import Foundation
extension String {
func convertToClass<T>() -> T.Type? {
return StringClassConverter<T>.convert(string: self)
}
}
class StringClassConverter<T> {
static func convert(string className: String) -> T.Type? {
guard let nameSpace = Bundle.main.infoDictionary?["CFBundleExecutable"] as? String else {
return nil
}
guard let aClass: T.Type = NSClassFromString("\(nameSpace).\(className)") as? T.Type else {
return nil
}
return aClass
}
}
The use would be:
func getViewController(fromString: String) -> UIViewController? {
guard let viewController: UIViewController.Type = "MyViewController".converToClass() else {
return nil
}
return viewController.init()
}
I think I'm right in saying that you can't, at least not with the current beta (2). Hopefully this is something that will change in future versions.
You can use NSClassFromString to get a variable of type AnyClass but there appears to be no way in Swift to instantiate it. You can use a bridge to Objective C and do it there or -- if it works in your case -- fall back to using a switch statement.
Apparently, it is not possible (anymore) to instantiate an object in Swift when the name of the class is only known at runtime. An Objective-C wrapper is possible for subclasses of NSObject.
At least you can instantiate an object of the same class as another object given at runtime without an Objective-C wrapper (using xCode Version 6.2 - 6C107a):
class Test : NSObject {}
var test1 = Test()
var test2 = test1.dynamicType.alloc()
In Swift 2.0 (tested in the beta2 of Xcode 7) it works like this:
protocol Init {
init()
}
var type = NSClassFromString(className) as? Init.Type
let obj = type!.init()
For sure the type coming from NSClassFromString have to implement this init protocol.
I expect it is clear, className is a String containing the Obj-C runtime name of the class which is by default NOT just "Foo", but this discussion is IMHO not the major topic of your question.
You need this protocol because be default all Swift classes don't implement an init method.
Looks like the correct incantation would be...
func newForName<T:NSObject>(p:String) -> T? {
var result:T? = nil
if let k:AnyClass = NSClassFromString(p) {
result = (k as! T).dynamicType.init()
}
return result
}
...where "p" stands for "packaged" – a distinct issue.
But the critical cast from AnyClass to T currently causes a compiler crash, so in the meantime one must bust initialization of k into a separate closure, which compiles fine.
I use different targets, and in this case the swift class is not found. You should replace CFBundleName with CFBundleExecutable. I also fixed the warnings:
- (Class)swiftClassFromString:(NSString *)className {
NSString *appName = [[NSBundle mainBundle] objectForInfoDictionaryKey:#"CFBundleExecutable"];
NSString *classStringName = [NSString stringWithFormat:#"_TtC%lu%#%lu%#", (unsigned long)appName.length, appName, (unsigned long)className.length, className];
return NSClassFromString(classStringName);
}
Isn't the solution as simple as this?
// Given the app/framework/module named 'MyApp'
let className = String(reflecting: MyClass.self)
// className = "MyApp.MyClass"
Also in Swift 2.0 (possibly before?) You can access the type directly with the dynamicType property
i.e.
class User {
required init() { // class must have an explicit required init()
}
var name: String = ""
}
let aUser = User()
aUser.name = "Tom"
print(aUser)
let bUser = aUser.dynamicType.init()
print(bUser)
Output
aUser: User = {
name = "Tom"
}
bUser: User = {
name = ""
}
Works for my use case
Try this.
let className: String = String(ControllerName.classForCoder())
print(className)
I have implemented like this,
if let ImplementationClass: NSObject.Type = NSClassFromString(className) as? NSObject.Type{
ImplementationClass.init()
}
Swift 5, easy to use, thanks to #Ondrej Rafaj's
Source code:
extension String {
fileprivate
func convertToClass<T>() -> T.Type? {
return StringClassConverter<T>.convert(string: self)
}
var controller: UIViewController?{
guard let viewController: UIViewController.Type = convertToClass() else {
return nil
}
return viewController.init()
}
}
class StringClassConverter<T> {
fileprivate
static func convert(string className: String) -> T.Type? {
guard let nameSpace = Bundle.main.infoDictionary?["CFBundleExecutable"] as? String, let aClass = NSClassFromString("\(nameSpace).\(className)") as? T.Type else {
return nil
}
return aClass
}
}
Call like this:
guard let ctrl = "ViewCtrl".controller else {
return
}
// ctrl do sth
A page jump example shown here, the hope can help you!
let vc:UIViewController = (NSClassFromString("SwiftAutoCellHeight."+type) as! UIViewController.Type).init()
self.navigationController?.pushViewController(vc, animated: true)
// Click the Table response
tableView.deselectRow(at: indexPath, animated: true)
let sectionModel = models[(indexPath as NSIndexPath).section]
var className = sectionModel.rowsTargetControlerNames[(indexPath as NSIndexPath).row]
className = "GTMRefreshDemo.\(className)"
if let cls = NSClassFromString(className) as? UIViewController.Type {
let dvc = cls.init()
self.navigationController?.pushViewController(dvc, animated: true)
}
Swift3+
extension String {
var `class`: AnyClass? {
guard
let dict = Bundle.main.infoDictionary,
var appName = dict["CFBundleName"] as? String
else { return nil }
appName.replacingOccurrences(of: " ", with: "_")
let className = appName + "." + self
return NSClassFromString(className)
}
}
Here is a good example:
class EPRocks {
#require init() { }
}
class EPAwesome : EPRocks {
func awesome() -> String { return "Yes"; }
}
var epawesome = EPAwesome.self();
print(epawesome.awesome);

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