JQUERY CODE:
$('#selector button').click(function() {
$(this).addClass('active').siblings().removeClass('active');
$('#gaga').toggle
})
PUG CODE FOR #gaga element:
p#gaga
| This is `${Value}`
PUG CODE FOR #gaga element:
How can I use three buttons to toggle the #gaga element on when button is active and off when you click outside the specific button and pass a different Value for ${Value} depending on the clicked button. Plus have only one instance of #gaga element running at a time. Meaning if I click the first button then click the second button only the ${Value} will change but the p#gaga element remains only one. I know I have left out the buttons pug code, I don't think it is necessary in solving the problem. But if needed will provide it.
I tried doing it using switch statements but I have failed. Hopefully someone can help.
UPDATE & EDIT as requested by https://stackoverflow.com/users/463319/twisty in the comments.
Here is the code: https://jsfiddle.net/YulePale/mdvnf0qt/4/
After doing some research I have made some progress... but I am still stuck.
I am trying to make it in such a way that when I click anywhere outside the gender buttons the input disappears and when I click another button it changes appropriately. Also instead of an input I want to show and hide the template in the html code.
Also, if you don't mind is .data() use to assign or get a value.
PS: Got this code from this answer : Fixing toggle with two buttons
and modified it a bit, but I am still not able to achieve my desired result.
If you review the API for Menu, they have a nice _closeOnDocumentClick(). You can simply use this in your code in a similar way.
Example: https://jsfiddle.net/Twisty/0x43bf8q/
JavaScript
$(function() {
$("input[type='button']").on('click', toggleOptions)
.first()
.trigger('click');
$(document).on("click", function(e) {
if (emptyOnDocumentClick(e)) {
$('[name=gender]').val("");
}
});
function toggleOptions() {
var $this = $(this),
onClass = 'button-toggle-on';
$this.toggleClass(onClass)
.siblings('input[type=button]')
.removeClass(onClass);
var gender = $this.filter('.' + onClass).data('gender');
$('[name=gender]').val(gender);
}
function emptyOnDocumentClick(event) {
return !$(event.target).closest("input[type='button']").length;
}
});
Hope that helps.
Related
How can I adjust the position of Select2 container so that the search box is position right over the original select element like in this website
http://www.jobnisit.com/en
It look cleaner in terms of UI in my opinion.
Ps. sorry, I can't post the image now.
There is 2 ways to do this.
1) With css:
.select2-dropdown--below {
top: -2.8rem; /*your input height*/
}
This will not affect a container (.select2-container), but will move dropdown and search field, so you will have a desired effect.
2) With js:
$('select').select2().on('select2:open', function() {
var container = .$('.select2-container').last();
/*Add some css-class to container or reposition it*/
});
This code attaches a handler to 'select2:open' event, which will be fired every time when user opens a dropdown. This method is better if you have more than one select on page.
Tested with select2 4.0.0
The proper way of positioning the dropdown is using the core feature provided by select2 plugin.
It provides us with 'dropdownParent' property to place to dropdown inside the particular element
select field: #edit-field-job-skillsets-tid
parent item: div.form-item-field-job-skillsets-tid
jQuery("#edit-field-job-skillsets-tid").select2(
{dropdownParent: jQuery('div.form-item-field-job-skillsets-tid')}
);
I'm trying to fire an event programmatically. My problem is that I have two SVG on two DIVs and I want to be able to change the border of the DIV I have clicked. To do that I thought to pass the DIV inside my classes and then trigger a click on it once I click on anything. (if there is a better way, please tell me)
I have the following code:
div = querySelector(divName);
svgElement = new svg.SvgSvgElement();
div.append(svgElement);
div.onClick.listen(_setBorders(1));
later I pass the svgElement to another class
ell.show(svgElement);
where show is
show(svg.SvgElement element) {
if (element.parent is DivElement){
_parentDiv= element.parent as DivElement;
element.children.add(_group);
}
}
_parentDiv is of course a DivElement, which I use for an internal onClick()
_onClick(MouseEvent e) {
window.console.info("onClick Ell");
_parentDiv.click();
}
I'm expecting to see the _setBorders(1); I defined with the main div, but it doesn't work. The weird thing is that when I check with the debugger set to the _parentDiv.click() I see that _parentDiv has the event correctly set.
I suppose click() doesn't work as I expected. Any Idea?
If you want that _setBorders(1) is called on click events you have to use :
div.onClick.listen((_) => _setBorders(1));
I am trying to use the ShowHide effect that comes with Kevin Moore's widget package here:
http://dart-lang.github.io/widget.dart/#showhide
Not sure how to use this. Anyone got an example I can look at ?
Basically all I want is for a dropdown to show with one of those effects if a certain event happens.
Your tips appreciated.
Thanks.
You need to add a listener for an event to an element in the DOM, and then use ShowHide.toggle(element, effect) to trigger an effect. Here is an example which listens for a click on a button, and toggles FadeEffect on an image each time it is pressed:
var button = query("#fadeButton")
..onClick.listen((event) {
ShowHide.toggle(query("#fadeImage"), effect: new FadeEffect());
});
If you wanted to fade in/out a dropdown when you click on a menu bar, then substitute "fadeButton" for the menu which listens for clicks, and "fadeImage" with the dropdown element.
Also, any other effect can be substituted for FadeEffect, such as DoorEffect, ScaleEffect, ShrinkEffect, etc.
I have a jQuery mobile button hooked up to an ajax POST. If the POST fails, the jQuery mobile button stays pressed instead of ``popping up". Any ideas?
It can be done easily.
Here a jsFiddle example made for one of my previous answers: http://jsfiddle.net/3PhKZ/7/
If you take a look there's this line of code:
$.mobile.activePage.find('.ui-btn-active').removeClass('ui-btn-active ui-focus');
It will try to find pressed button on a current active page, if it succeed it will remove 2 classes responsible for a button pressed state. Unfortunately pure CSS solution is impossible here. You can test this example, just comment top line and see what will happen.
One last thing selector $.mobile.activePage can only be used during the pagebeforeshow, pageshow, pagebeforechange, pagechange, pagebeforehide and pagehide page event so takes this into account.
In case you cant use this selector just replace it with a page id, like this:
$('#pageID').find('.ui-btn-active').removeClass('ui-btn-active ui-focus');
So your final code would look like this:
$.ajax( "example.php" )
.success(function() { doStuff(); })
.error(function() {
$('#pageID').find('.ui-btn-active').removeClass('ui-btn-active ui-focus');
})
Add an error clause to your AJAX handling which pops the button back.
$.ajax( "example.php" )
.success(function() { doStuff(); })
.error(function() { /*code to unpress button here*/ })
For those folks out there using "input" and not "anchors" as buttons. When using for instance "submit" and "reset" buttons and pressing them they remain as active, which is sometimes undesired depending on the actions performed when the buttons is clicked.
I am not sure if it is the expected behaviour, I have read that is a jQuery mobile bug, but the behavior is still present at least in jQM 1.3.2
An yes the trick is to remove the active class as stated however those get tricky because the class is not added to the input tag, i*t is added to a parent DIV* that is created by all of the ugly stuff around the "input" to style the button, that is why removing the active class when selecting the input doesn´t work.
By analyzing the HTML produced by jquery mobile a workaround is to:
remove the active class on the input parent instead of the actual input element.
$('.mybutton_class_or_ID').parent().removeClass('ui-btn-active');
I prefer this approach instead of clearing all the active classes across the whole page in case you want to be more selective with the class removal.
I need add the functionality to show and hide the Search Filter bar
I tried use (example):
setTimeout(showFilter,5000);
function showFilter(){
alert('showFilter');
$.mobile.listview.prototype.options.filter = true;
$('#workList').listview('refresh');
setTimeout(hideFilter,1500);
}
function hideFilter(){
alert('hideFilter');
$.mobile.listview.prototype.options.filter = false;
$('#workList').listview('refresh');
}
But not working, can you help me ? Thanks
You can hide it with a simple .hide() on the searchfilter's container div. The following code will hide every searchfilter textbox on the page, so if you want to hide a certain subset, you'll have to narrow it down to particular parts of your DOM.
$(".ui-input-search").hide();
Use .show() to bring it back up. Alternately, use .toggle() to switch back and forth between hidden and visible.
(Note: Any text that has been typed into the search box will still apply, even if the search box is hidden.)