I am using ZPL for the first time to generate shipping labels. I am using a ruby-on-rails gem https://github.com/rjocoleman/labelary to ultimately turn the ZPL sting into a pdf. I want to create multiple pages, incrementing a variable for each page using a loop until enough pages have been created. Say the ZPL looks like this:
^XA
^FX Top section with company logo, name and address.
^CF0,60
^FO50,50^GB100,100,100^FS
^FO75,75^FR^GB100,100,100^FS
^FO88,88^GB50,50,50^FS
^FO220,50^FDInternational Shipping, Inc.^FS
^CF0,40
^FO220,100^FD1000 Shipping Lane^FS
^FO220,135^FDShelbyville TN 38102^FS
^FO220,170^FDUnited States (USA)^FS
^FO50,250^GB700,1,3^FS
^FX Second section with recipient address and permit information.
^CFA,30
^FO50,300^FDJohn Doe^FS
^FO50,340^FD100 Main Street^FS
^FO50,380^FDSpringfield TN 39021^FS
^FO50,420^FDUnited States (USA)^FS
^CFA,15
^FO600,300^GB150,150,3^FS
^FO638,340^FDPermit^FS
^FO638,390^FD123456^FS
^FO50,500^GB700,1,3^FS
^FX Third section with barcode.
^BY5,2,270
^FO175,550^BC^FD1234567890^FS
^FX Fourth section (the two boxes on the bottom).
^FO50,900^GB700,250,3^FS
^FO400,900^GB1,250,3^FS
^CF0,40
^FO100,960^FDShipping Ctr. X34B-1^FS
^FO100,1010^FDREF1 F00B47^FS
^FO100,1060^FDREF2 BL4H8^FS
^CF0,190
^FO485,965^FDCA^FS
^XZ
How can I add a page break to the end of the ZPL string, so the loop can create a new identical page after the first one (all in a single zpl string)?
Thanks in advance
If your pages are truly identical, you could just use the ^PQ command to set the number of copies you want to print (e.g. ^PQ3 to print three copies). This command must appear before the ^XZ command.
However if your pages aren't identical (maybe you have a sequence number or something), just start a new format by using a new ^XA command after your first page is done.
Related
I am trying to print to a GT800 Zebra printer thru serial port.
I am using ZPL. I want to control the width which is fine in auto mode. To address that in the >^BC> command I am using Auto mode as no other size setting under ^BY works
Following is the code
^XA
^MMT
^PW831
^LL400
^LS0
^BY2,,76^FT225,141^BCN,76,Y,Y,N,A
^FD:RNIP29200082034^FS
^FO225,157^A#N,18,10,E:CAL002.FNT^FD26030-0892R^FS
^FO383,157^A#N,18,10,E:CAL002.FNT^FD08.01.20 12:00PM^FS
^FO225,187^A#N,18,10,E:CAL002.FNT^FDLAMP-DR RH^FS
^FO453,187^A#N,18,10,E:CAL002.FNT^FDXBA3^FS
^PQ1,0,0,Y
^XZ
There is a funny problem. If the ^BC mode = A then if three zeros come together gives issues for eg ABCD29200082034 it prints ABCD29200 and does not complete the barcode. But the other lines are getting printed. But if the data is ABCD29200182034 , there are no issues.
If BC mode = U then even if the code is ABCD29200182034 it prints 292001820347. Note 7 is added in the end.
I am clueless as to what is this issue. I remember facing this same issue in Honeywell printer too once.
Thanks
NOTE : I replaced the 000 with 111 and the problem persists.
ZPL Manual says the following
A= Automatic Mode :This analyzes the data sent and automatically determines the best packing method. The full ASCII character set can be used in the ^FD
statement — the printer determines when to shift subsets. A string of
four or more numeric digits causes an automatic shift to Subset C.
Note , it says a string of four or more numeric digits causes an automatic shift to subset C, but when the same string is 290010 it has no issues. I am really lost
I need to be able to print Hebrew characters on my Epson TM-T20ii. I am trying to get my printer to switch to character code page 36(PC862) using
ESC t36
for some reason the printer is switching to code page 3 and then printing the number 6.
Is there a way to let the printer know that the 6 is part of my command?
If you know of a different workaround please comment below.
Thanks
You are making a mistake, you aren't meant to replace n with an actual number.
The proper syntax in your case would be ←t$
Explanation: the manual says "ESC t n", n referring to the page sheet, however you don't replace n with a number rather with the ASCII character n, so in your example 36 = $ because $ is the 36th character on the ASCII table.
I want to copy a table from iPython notebook into a Word doc. I'm using Word for Mac 2011. The table is a standard pandas output and looks like this:
If I use Apple+C to copy the table, and then paste it into a Word doc, I get this:
Surely there must be an easier way?
Creating a table with the same number of rows/columns in Word and then trying to paste the cells there doesn't work either.
I guess I could screenshot the table, but I'd like to include the raw data in the document if possible.
The problem in this case (from the Word perspective) is not the table layout - it's the paragraph layout. Each paragraph has a substantial indent on right and left, and more space before/after than you would normally want.
I don't think any of the Paste options (e.g. Paste Special) in Word is going to help, unless you paste as unformatted text, then select the text, convert to a table, then proceed from there.
But, even a simple Word VBA macro such as this one will leave you with something a bit more manageable. (Select a table you copied in, then run the macro). A little bit more work on the code would probably allow you to get most of the formatting you want, most of the time.
Sub fixupSelectedTable()
With Selection.Tables(1).Range.ParagraphFormat
.LeftIndent = 0
.RightIndent = 0
.SpaceBefore = 0
.SpaceAfter = 0
.LineSpacingRule = wdLineSpaceSingle
End With
End Sub
If you are more familiar with Applescript, the equivalent looks something like this:
-- you may need to fix up the application name
-- (I use this to ensure that the script uses the Open Word 2011 doc
-- and does not try to start Word for Mac 15 (2016))
tell application "/Applications/Microsoft Office 2011/Microsoft Word.app"
tell the paragraph format of the text object of table 1 of the text object of the selection
set paragraph format left indent to 0
set paragraph format right indent to 0
set space before to 0
set space after to 0
set line spacing rule to line space single
end tell
end tell
Here is a simple lists where I like to change the numbers: the entries are as below and it got over 300 entries like it
tom112
smith113
harry114
linda115
cindy106
samantha147
It need to be changed to
tom212
smith213
harry214
...and so on.
Please assist using notepad++ regular expression.
Thanks.
Assuming it's just a matter of replacing a name followed by a number starting with 1 with the same number but starting with 2 instead:
Ctrl + H for search & replace.
Check Regular expression under Search Mode.
Next to Find what type or copy in ([a-zA-Z]+)1([0-9]+).
Next to Replace with type or copy in \12\2.
Click Replace All and that should do it.
Add any other characters that might appear in the name before the number inside the first set of brackets with a-zA-Z.
I have followig task:
I am generating sequence of consecutive barcodes eg: 117-1, 117-2, 117-3, 117-4...
I have to print labels with those barcodes: first label with first code, second label with second code and so on.
Currently I am printig labels one-by-one. Is it possible in ZPL to combine multiple labels to one command for printer? Something like:
^header
print first one
take next label
print second one
take next label
...
^footer
I am generating ZPL so there is no need to introduce variables in ZPL.
My current code for printing single label
string zpl = string.Format(
#"^XA
^LH5,5
^CF0,129
^FO20,10
^FB800,4,,C
^FD{0}
^FS
^FO160,150
^FB800,1,,C
^BY3
^BCN,150,N,N,N
^FD{0}
^FS
^XZ
", code.ToString());
You can concatenate ZPL files to merge several labels into one.
Untested code would be something like this, if I understand your requirements:
String template = "^XA^LH5,5^CF0,129^FO20,10^FB800,4,,C^FD{0}^FS^FO160,150^FB800,1,,C^BY3^BCN,150,N,N,N^FD{0}^FS^XZ";
String zpl = String.format(template, code.toString());
zpl += String.format(template, code2.toString());
...and so one, or use a loop