converting string to map in dart - dart

Question

I wanted to convert a string to map.
String value = "{first_name : fname,last_name : lname,gender : male, location : { state : state, country : country, place : place} }"
into
Map = {
first_name : fname,
last_name : lname,
gender : male,
location = {
state : state,
country : country,
place : place
}
}
How do I convert the string into a map<String, dynamic> where the value consists of string, int, object, and boolean?
I wanted to save the string to a file and obtain the data from the file.

Answer 1

That's not possible.
If you can change the string to valid JSON, you can use
import 'dart:convert';
...
Map valueMap = json.decode(value);
// or
Map valueMap = jsonDecode(value);
The string would need to look like
{"first_name" : "fname","last_name" : "lname","gender" : "male", "location" : { "state" : "state", "country" : "country", "place" : "place"} }

Answer 2

You would have to change the way you create the string.
I'm guessing you are creating the string using the yourMap.toString() method. You should rather use json.encode(yourMap), which converts your map to valid JSON, which you can the parse with json.decode(yourString).

Answer 3

create two objects
class User {
final String firstName;
final String lastName;
final String gender;
final location;
User({
this.firstName,
this.lastName,
this.gender,
this.location,
});
User.fromJson(Map json)
: firstName = json['firstName'],
lastName = json['lastName'],
gender = json['gender'],
location = Location.fromJson(json['location']);
}
class Location {
final String state;
final String country;
final String place;
Location({
this.state,
this.country,
this.place,
});
Location.fromJson(Map json)
: state = json['state'],
country = json['country'],
place = json['place'];
}
then use it like this
var user = User.fromJson(value);
print(user.firstName);
or convert it to list like this
var user = User.fromJson(value).toList();

Answer 4

you can do like this ->
import 'dart:convert';
...
if your data like this **
{'bus1':'100Tk','bus2':'150TK','bus3':'200TK'}
**;
then you can do like this ->
Map valueMap = json.decode(value);
// or
Map valueMap = jsonDecode(value);
or if like this ->var data = {'1':'100TK','2':'200TK','3':'300TK'};
var dataSp = data.split(',');
Map<String,String> mapData = Map();
dataSp.forEach((element) => mapData[element.split(':')[0]] = element.split(':')[1]);
Note: Map first value was Int that's why I did that.

Answer 5

Make a wrapper class for the location where you define the methods fromMap, toMap

Answer 6

Yeah, that's not possible.
But i have workaround to fix that.
Remove space in ur invalid json
Fix ur invalid string json to valid string json
Convert valid string json to map
Here's the full code for above process:
import 'dart:convert';
void main() {
String value = "{first_name : fname,last_name : lname,gender : male, location : { state : state, country : country, place : place} }";
String jsonString = _convertToJsonStringQuotes(raw: value);
print("Test 1: $jsonString");
final Map<dynamic, dynamic> result = json.decode(jsonString);
print('Test 2: $result');
}
String _convertToJsonStringQuotes({required String raw}) {
/// remove space
String jsonString = raw.replaceAll(" ", "");
/// add quotes to json string
jsonString = jsonString.replaceAll('{', '{"');
jsonString = jsonString.replaceAll(':', '": "');
jsonString = jsonString.replaceAll(',', '", "');
jsonString = jsonString.replaceAll('}', '"}');
/// remove quotes on object json string
jsonString = jsonString.replaceAll('"{"', '{"');
jsonString = jsonString.replaceAll('"}"', '"}');
/// remove quotes on array json string
jsonString = jsonString.replaceAll('"[{', '[{');
jsonString = jsonString.replaceAll('}]"', '}]');
return jsonString;
}

Answer 7

To convert a string into a map<String, dynamic>, you can use the
following code:
String value = "{first_name : fname,last_name : lname,gender : male, location : { state : state, country : country, place : place} }";
String result = value
.replaceAll("{","{\"")
.replaceAll("}","\"}")
.replaceAll(":","\":\"")
.replaceAll(",","\",\"");
print(result);
Here, we first replace the opening and closing curly braces with double quotes, and then replace the colons and commas with quotes to create a valid JSON string. Then, we use the jsonDecode method to convert the JSON string into a map.

Answer 8

I found a way to cast that string
Ok, lets use a complex model to cast:
final testMap = {
'userName': 'Igor',
'age': 22,
'totalCash': 138.57,
'isMale:': true,
'userStatus': {
'isUserActive': true,
'isAPremiumUser': false,
},
'userTags': ['Flutter Developer', 'Proactive', 'Clean code'],
'userCourses': [
{
'title': 'How to use TDD in flutter',
'finished': false,
'coursePercentage': 47.4,
'buyDate': '1969-07-20T20:18:04.000Z',
'courseTag': ['New', 'Popular'],
'courseDetails': null,
},
{
'title': 'Clean arquiteture in flutter',
'finished': false,
'coursePercentage': 20.8,
'buyDate': '1969-07-20T20:18:04.000Z',
'courseTag': ['New'],
'courseDetails': {
'teacherName': 'Tayler Mostoult',
'totalSubscribers': 5402,
},
},
{
'title': 'Micro-frontends in flutter',
'finished': true,
'coursePercentage': 100.0,
'buyDate': '1969-07-20T20:18:04.000Z',
'courseTag': [],
'courseDetails': {},
},
]
};
Know, cast it to string:
final testMapInStringFormat = testMap.toString();
To convert this String to map, we can use:
final String response = _getJsonFromString(testMap.toString());
final Map jsonConvertido = jsonDecode(response); // Decoded, back to map format
The function that will effectively do the casting:
String _getJsonFromString(String rawText) {
// Will find, for exemple, the text: "{isUserActive:"
final regexMapKeyWithOpenBracket = RegExp('(?<={)(.*?):+');
// Will find, for exemple, the text: ", userCourses:"
final regexMapKeyWithCommaAndSpace = RegExp(r'(?<=, )([^\]]*?):');
final regexOnlyKeyInLine = RegExp(r'^.+:$');
final splitedSentences = rawText
.replaceAllMapped(regexMapKeyWithCommaAndSpace,
(Match match) => '\n${match.text.trim()}\n')
.replaceAllMapped(regexMapKeyWithOpenBracket,
(Match match) => '\n${match.text.trim()}\n')
.replaceAll(RegExp(r'}(?=,|]|}|$|\s+)'), '\n}\n')
.replaceAll(RegExp(r'(?<=(,|:|^|\[)\s?){'), '\n{\n')
.replaceAll(RegExp('\\[\\s?\\]'), '\n[\n]\n')
.replaceAll(RegExp('\\{\\s?\\}'), '\n{\n}\n')
.split('\n')
..removeWhere((element) => element.replaceAll(' ', '').isEmpty);
final List<String> correctLines = [];
for (String line in splitedSentences) {
final isMapKey = regexOnlyKeyInLine.hasMatch(line);
if (isMapKey) {
final lineWithoutFinalTwoDots = line.substring(0, line.length - 1);
final lineWithQuaot = _putQuotationMarks(lineWithoutFinalTwoDots);
correctLines.add('$lineWithQuaot:');
} else {
String l = line.trim();
// If it falls in this else, it is a value of a key or a map structure
final isNumber = double.tryParse(l) != null || int.tryParse(l) != null;
final isBolean = l == 'false' || l == 'true';
final isStructureCaracter = ['{', '}', '[', ']', ','].any((e) => e == l);
final isNull = l == 'null';
if (isStructureCaracter || isNumber || isBolean || isNull) {
correctLines.add(l);
continue;
}
final hasCommaInFinal = l.endsWith(',');
if (hasCommaInFinal) {
l = l.substring(0, l.length - 1);
}
// If you got to this point, i'm sure it's a value string, so lets add a double quote
final lineWithQuaot = _putQuotationMarks(l);
if (hasCommaInFinal) {
correctLines.add('$lineWithQuaot,');
} else {
correctLines.add(lineWithQuaot);
}
}
}
return correctLines.join('');
}
extension MatchExtension on Match {
String get text => input.substring(start, end);
}
String _putQuotationMarks(String findedText) {
if (!findedText.startsWith('\'') && !findedText.startsWith('"')) {
findedText = findedText[0] + findedText.substring(1);
}
if (!findedText.endsWith('\'')) {
final lastIndex = findedText.length - 1;
findedText = findedText.substring(0, lastIndex) + findedText[lastIndex];
}
return '"$findedText"';
}

Answer 9

Use below method
just pass String json data it will give Map data
jsonStringToMap(String data){
List<String> str = data.replaceAll("{","").replaceAll("}","").replaceAll("\"","").replaceAll("'","").split(",");
Map<String,dynamic> result = {};
for(int i=0;i<str.length;i++){
List<String> s = str[i].split(":");
result.putIfAbsent(s[0].trim(), () => s[1].trim());
}
return result;
}