How do you convert a DateComponents to a Date Object.
Currently, I have following code
Calendar.date(from: DateComponents(year: 2018, month: 1, day: 15))
but I'm getting an error stating "No 'date' candidates produce the expected contextual result type 'Date'
Sorry for the basic question, but I'm still struggling with how to work with dates in Swift
You cannot call date(from on the type. You have to use an instance of the calendar, either the current calendar
Calendar.current.date(from: DateComponents(year: 2018, month: 1, day: 15))
or a fixed one
let calendar = Calendar(identifier: .gregorian)
calendar.date(from: DateComponents(year: 2018, month: 1, day: 15))
//create an instance of DateComponents to keep your code flexible
var dateComponents = DateComponents()
//create the date components
dateComponents.year = 2018
dateComponents.month = 1
dateComponents.day = 15
//dateComponents.timeZone = TimeZone(abbreviation: "EST")
dateComponents.hour = 4
dateComponents.minute = 12
//make something useful out of it
func makeACalendarObject(){
//create an instance of a Calendar for point of reference ex: myCalendar, and use the dateComponents as the parameter
let targetCalendar = Calendar.current
let newCalendarObject = targetCalendar.date(from: dateComponents)
guard let newCalObject = newCalendarObject else {
return
}
print(newCalObject)
}
//call the object
makeACalendarObject()
Related
May I know, what is reliable way, to calculate day differences without taking time into consideration?
A similar question is asked before. However, the highest voted and accepted answer isn't entirely accurate - https://stackoverflow.com/a/28163560/72437
The code is broken, when dealing with Day light saving case. You can run the following code in Playground
Use startOfDay (Broken)
import UIKit
struct LocalDate: Equatable {
let year: Int
let month: Int
let day: Int
}
struct LocalTime: Equatable, Codable {
let hour: Int
let minute: Int
}
extension Date {
var startOfDay: Date {
return Calendar.current.startOfDay(for: self)
}
static func of(localDate: LocalDate, localTime: LocalTime) -> Date {
var dateComponents = DateComponents()
dateComponents.year = localDate.year
dateComponents.month = localDate.month
dateComponents.day = localDate.day
dateComponents.hour = localTime.hour
dateComponents.minute = localTime.minute
dateComponents.second = 0
return Calendar.current.date(from: dateComponents)!
}
func adding(_ component: Calendar.Component, _ value: Int) -> Date {
return Calendar.current.date(byAdding: component, value: value, to: self)!
}
}
// During 22 March 2021, Tehran will advance by 1 hour from 00:00 AM, to 01:00 AM.
let tehranTimeZone = TimeZone(identifier: "Asia/Tehran")!
let oldDefault = NSTimeZone.default
NSTimeZone.default = tehranTimeZone
defer {
NSTimeZone.default = oldDefault
}
// Just a random local time. We will use 'startOfDay' to perform local time resetting.
let localTime = LocalTime(hour: 2, minute: 59)
let localDate1 = LocalDate(year: 2021, month: 3, day: 22)
let localDate2 = LocalDate(year: 2021, month: 3, day: 23)
let date1 = Date.of(localDate: localDate1, localTime: localTime).startOfDay
let date2 = Date.of(localDate: localDate2, localTime: localTime).startOfDay
let components = Calendar.current.dateComponents([.day], from: date1, to: date2)
/*
date1 Monday, March 22, 2021 at 1:00:00 AM Iran Daylight Time
date2 Tuesday, March 23, 2021 at 12:00:00 AM Iran Daylight Time
diff in day is Optional(0)
*/
print("date1 \(date1.description(with: .current))")
print("date2 \(date2.description(with: .current))")
print("diff in day is \(components.day)")
The different of day should be 1, without taking time into consideration. However, due to day light saving, the computed hour difference is 23 hours instead of 24 hours.
We are then getting 0 day difference.
One of the workaround, is using 12:00 (noon) as local time, with an assumption there is no place in this world, where day light saving occurs during 12:00. I am not sure how solid is this assumption. Such assumption seems to be pretty fragile. What if one day government decides to admen day light saving to be at 12:00?
Use 12:00 (Seems to work. But, how solid it is?)
import UIKit
struct LocalDate: Equatable {
let year: Int
let month: Int
let day: Int
}
struct LocalTime: Equatable, Codable {
let hour: Int
let minute: Int
}
extension Date {
var startOfDay: Date {
return Calendar.current.startOfDay(for: self)
}
static func of(localDate: LocalDate, localTime: LocalTime) -> Date {
var dateComponents = DateComponents()
dateComponents.year = localDate.year
dateComponents.month = localDate.month
dateComponents.day = localDate.day
dateComponents.hour = localTime.hour
dateComponents.minute = localTime.minute
dateComponents.second = 0
return Calendar.current.date(from: dateComponents)!
}
func adding(_ component: Calendar.Component, _ value: Int) -> Date {
return Calendar.current.date(byAdding: component, value: value, to: self)!
}
}
// During 22 March 2021, Tehran will advance by 1 hour from 00:00 AM, to 01:00 AM.
let tehranTimeZone = TimeZone(identifier: "Asia/Tehran")!
let oldDefault = NSTimeZone.default
NSTimeZone.default = tehranTimeZone
defer {
NSTimeZone.default = oldDefault
}
// Use noon
let localTime = LocalTime(hour: 12, minute: 00)
let localDate1 = LocalDate(year: 2021, month: 3, day: 22)
let localDate2 = LocalDate(year: 2021, month: 3, day: 23)
let date1 = Date.of(localDate: localDate1, localTime: localTime)
let date2 = Date.of(localDate: localDate2, localTime: localTime)
let components = Calendar.current.dateComponents([.day], from: date1, to: date2)
/*
date1 Monday, March 22, 2021 at 12:00:00 PM Iran Daylight Time
date2 Tuesday, March 23, 2021 at 12:00:00 PM Iran Daylight Time
diff in day is Optional(1)
*/
print("date1 \(date1.description(with: .current))")
print("date2 \(date2.description(with: .current))")
print("diff in day is \(components.day)")
May I know, what is reliable way, to calculate day differences without taking time into consideration?
Date is a precise point in time, hence expressible as a TimeInterval (aka Double) from an exact moment in time (that'll be reference date aka January 1st 2001 00:00 GMT+0).
Thus that same point in time is differently calculated between TimeZones through Calendar: if the TimeZone has daylight savings, then the calendar take it into account.
Therefore when you operate through a Calendar adopting DateComponents you should keep that in mind.
Depending on what you are trying to do in your application it could be useful to just adopt a private Calendar instance set to adopt TimeZone(secondsFromGMT: 0)! for calculating dates as absolutes values.
As in:
extension Calendar {
static let appCal: Self = {
// I'm used to reason with Gregorian calendar
var cal = Calendar(identifier: .gregorian)
// I just need this calendar for executing absolute time calculations
cal.timeZone = TimeZone(secondsFromGMT: 0)!
return cal
}()
}
When I run this code:
let calendar = Calendar.current
var dateComponents = DateComponents()
dateComponents.weekday = calendar.firstWeekday
dateComponents.weekOfYear = 2
dateComponents.year = 2017
let startOfWeek = calendar.date(from: dateComponents)
let endOfWeek = calendar.date(byAdding: .day, value: 6, to: startOfWeek!)
let formatter = DateFormatter()
formatter.dateStyle = .short
print(formatter.string(from: startOfWeek!))
print(formatter.string(from: endOfWeek!))
It prints this:
1/8/17
1/14/17
When I change the code to this:
dateComponents.weekOfYear = 1
dateComponents.year = 2017
It prints this:
12/31/17
1/6/18
Why is it 12/31/17?
When I use .full style to print the dates, I get Sunday, December 31, 2017 for the first date, but it's obviously wrong because December 31 is a Thursday.
If you want to get the correct date, use yearForWeekOfYear instead of year. Docs:
You can use the yearForWeekOfYear property with the weekOfYear and weekday properties to get the date corresponding to a particular weekday of a given week of a year. For example, the 6th day of the 53rd week of the year 2005 (ISO 2005-W53-6) corresponds to Sat 1 January 2005 on the Gregorian calendar.
Alternative, you can be a little naughty and not listen to the docs and use weekOfYear = 54:
let calendar = Calendar.current
var dateComponents = DateComponents()
dateComponents.weekday = calendar.firstWeekday
dateComponents.weekOfYear = 54
dateComponents.year = 2017
let startOfWeek = calendar.date(from: dateComponents)
let endOfWeek = calendar.date(byAdding: .day, value: 6, to: startOfWeek!)
let formatter = DateFormatter()
formatter.dateStyle = .short
print(formatter.string(from: startOfWeek!))
print(formatter.string(from: endOfWeek!))
This prints:
1/1/17
1/7/17
which is coincidentally, the correct dates.
Im new at swift programming and i havent been able successfully find code to find difference between two dates in terms of years , months and days.
I tried the following code but it didnt work
let form = NSDateComponentsFormatter()
form.maximumUnitCount = 2
form.unitsStyle = .Full
let s = form.stringFromTimeInterval( date2.timeIntervalSinceReferenceDate - date1.timeIntervalSinceReferenceDate)
Input
Date1 = "12/March/2015"
Date2 = "1/June/2015"
Output : x years y months z days
Please advice
We can use this function in Swift 2.0
func yearsBetweenDate(startDate: NSDate, endDate: NSDate) -> Int
{
let calendar = NSCalendar.currentCalendar()
let components = calendar.components([.Year], fromDate: startDate, toDate: endDate, options: [])
return components.year
}
You can return anything like I returned year in this function. This will return number of years between the two dates.
You can just write months,days etc in order to find the difference between the two dates in months and days respectively.
Edit
Swift 3.0 and Above
func yearsBetweenDate(startDate: Date, endDate: Date) -> Int {
let calendar = Calendar.current
let components = calendar.dateComponents([.year], from: startDate, to: endDate)
return components.year!
}
If you need the difference (in years, months, days) numerically then
compute NSDateComponents as in Swift days between two NSDates or Rajan's answer.
If you need the difference as a (localized) string to present it to the user,
then use NSDateComponentsFormatter like this
let form = NSDateComponentsFormatter()
form.maximumUnitCount = 2
form.unitsStyle = .Full
form.allowedUnits = [.Year, .Month, .Day]
let s = form.stringFromDate(date1, toDate: date2)
As already mentioned in the comments, computing the difference
from the pure time interval between the dates cannot give correct
results because most information about the dates is lost.
Update for Swift 3:
let form = DateComponentsFormatter()
form.maximumUnitCount = 2
form.unitsStyle = .full
form.allowedUnits = [.year, .month, .day]
let s = form.string(from: date1, to: date2)
With Swift 5 and iOS 12, you can use one of the 3 solutions below in order to calculate the difference (in years, months, days) between two dates.
#1. Using Calendar's dateComponents(_:from:to:) method
Calendar has a method called dateComponents(_:from:to:). dateComponents(_:from:to:) has the following declaration:
func dateComponents(_ components: Set<Calendar.Component>, from start: DateComponents, to end: DateComponents) -> DateComponents
Returns the difference between two dates specified as DateComponents.
The Playground example below show how to use dateComponents(_:from:to:) in order to compute the difference between two dates:
import Foundation
let calendar = Calendar.current
let startComponents = DateComponents(year: 2010, month: 11, day: 22)
let endComponents = DateComponents(year: 2015, month: 5, day: 1)
let dateComponents = calendar.dateComponents([.year, .month, .day], from: startComponents, to: endComponents)
print(dateComponents) // prints: year: 4 month: 5 day: 9 isLeapMonth: false
#2. Using Calendar's dateComponents(_:from:to:) method
Calendar has a method called dateComponents(_:from:to:). dateComponents(_:from:to:) has the following declaration:
func dateComponents(_ components: Set<Calendar.Component>, from start: Date, to end: Date) -> DateComponents
Returns the difference between two dates.
The Playground example below show how to use dateComponents(_:from:to:) in order to compute the difference between two dates:
import Foundation
let calendar = Calendar.current
let startDate = calendar.date(from: DateComponents(year: 2010, month: 11, day: 22))!
let endDate = calendar.date(from: DateComponents(year: 2015, month: 5, day: 1))!
let dateComponents = calendar.dateComponents([.year, .month, .day], from: startDate, to: endDate)
print(dateComponents) // prints: year: 4 month: 5 day: 9 isLeapMonth: false
#3. Using DateComponentsFormatter's string(from:to:) method
DateComponentsFormatter has a method called string(from:to:). string(from:to:) has the following declaration:
func string(from startDate: Date, to endDate: Date) -> String?
Returns a formatted string based on the time difference between two dates.
The Playground example below show how to use string(from:to:) in order to compute the difference between two dates:
import Foundation
let calendar = Calendar.current
let startDate = calendar.date(from: DateComponents(year: 2010, month: 11, day: 22))!
let endDate = calendar.date(from: DateComponents(year: 2015, month: 5, day: 1))!
let formatter = DateComponentsFormatter()
formatter.unitsStyle = .full
formatter.allowedUnits = [.year, .month, .day]
let string = formatter.string(from: startDate, to: endDate)!
print(string) // prints: 4 years, 5 months, 9 days
Try this one
func calculateDiffInTwoDate (date1: NSDate, date2: NSDate) -> NSInteger {
//var userAge : NSInteger = 0
let calendar : NSCalendar = NSCalendar.currentCalendar()
let unitFlags : NSCalendarUnit = [ .Year , .Month, .Day]
let dateComponentNow : NSDateComponents = calendar.components(unitFlags, fromDate: date2)
let dateComponentBirth : NSDateComponents = calendar.components(unitFlags, fromDate: date1)
if ( (dateComponentNow.month < dateComponentBirth.month) ||
((dateComponentNow.month == dateComponentBirth.month) && (dateComponentNow.day < dateComponentBirth.day))
)
{
return dateComponentNow.year - dateComponentBirth.year - 1
}
else {
return dateComponentNow.year - dateComponentBirth.year
}
}
By This you can get diff between two dates in Years
Why don't you use the inbuild method to find the difference between 2 dates in seconds, and then write a method to convert seconds in terms of years, months and days.
let diff = date1.timeIntervalSinceDate(date2)
//Assigning Dates
let StartDate = datePicker.date
let currentDate = Date()
//Finding Difference of Dates
let components = Set<Calendar.Component>([.day, .month, .year])
let differenceOfDate = Calendar.current.dateComponents(components, from:
StartDate, to: currentDate)
Print(differenceOfDate)
We can get day of year for date using below line.
let day = cal.ordinalityOfUnit(.Day, inUnit: .Year, forDate: date)
But how can we get the date from day of year?
If you know the year you can get DateComponents date property as follow:
extension Calendar {
static let iso8601 = Calendar(identifier: .iso8601)
}
let now = Date()
let day = Calendar.iso8601.ordinality(of: .day, in: .year, for: now)! // 121
let year = Calendar.iso8601.component(.year, from: now) // 2017
let date = DateComponents(calendar: .iso8601, year: year, day: day).date // "May 1, 2017, 12:00 AM"
or using DateFormatter
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyyy D"
if let date = dateFormatter.date(from: "\(year) \(day)") {
dateFormatter.dateStyle = .medium
dateFormatter.timeStyle = .short
dateFormatter.string(from: date) // "May 1, 2017, 12:00 AM"
}
You cannot go the other way. Going from a date to a day of the year discards all other information, you are left with only the day of the year (you no longer know what year). To go back to a full date you would have to make assumptions about the year the day was in.
The answer that #LeoDabus gave is more succinct than this, so it is perhaps the better choice. Having said that, this is the code that I would have used:
let dateComponents = NSDateComponents();
dateComponents.year = 2015
dateComponents.day = day
let calendar = NSCalendar.currentCalendar()
let date = calendar.dateFromComponents(dateComponents)
Updated for Swift 4:
let dateComponents = NSDateComponents();
dateComponents.year = 2018
dateComponents.day = someDay
let calendar = NSCalendar.current
let date = calendar.date(from: dateComponents as DateComponents)
How might the day number of the year be found with swift? Is there a simple way that I'm not seeing, or do I have to find the number of seconds from Jan 1 to the current date and divide by the number of seconds in a day?
This is a translation of the answer to How do you calculate the day of the year for a specific date in Objective-C? to Swift.
Swift 2:
let date = NSDate() // now
let cal = NSCalendar.currentCalendar()
let day = cal.ordinalityOfUnit(.Day, inUnit: .Year, forDate: date)
print(day)
Swift 3:
let date = Date() // now
let cal = Calendar.current
let day = cal.ordinality(of: .day, in: .year, for: date)
print(day)
This gives 1 for the first day in the year, and 56 = 31 + 25 for today (Feb 25).
... or do I have to find the number of seconds from Jan 1 to the current date
and divide by the number of seconds in a day
This would be a wrong approach, because a day does not have a fixed
number of seconds (transition from or to Daylight Saving Time).
Swift 3
extension Date {
var dayOfYear: Int {
return Calendar.current.ordinality(of: .day, in: .year, for: self)!
}
}
use like
Date().dayOfYear
Not at all !!! All you have to do is to use NSCalendar to help you do your calendar calculations as follow:
let firstDayOfTheYear = NSCalendar.currentCalendar().dateWithEra(1, year: NSCalendar.currentCalendar().component(.CalendarUnitYear, fromDate: NSDate()), month: 1, day: 1, hour: 0, minute: 0, second: 0, nanosecond: 0)! // "Jan 1, 2015, 12:00 AM"
let daysFromJanFirst = NSCalendar.currentCalendar().components(.CalendarUnitDay, fromDate: firstDayOfTheYear, toDate: NSDate(), options: nil).day // 55
let secondsFromJanFirst = NSCalendar.currentCalendar().components(.CalendarUnitSecond, fromDate: firstDayOfTheYear, toDate: NSDate(), options: nil).second // 4,770,357
You can find the number of days since your date like this:
let date = NSDate() // your date
let days = cal.ordinalityOfUnit(.CalendarUnitDay, inUnit: .CalendarUnitYear, forDate: date)
println(days)