Sequelize.s include where ancestor column - join

Question

Sorry for my bad English, but I do not know how to better formulate the title.
Anyway I have the following 3 models
const ModelAlpha = sequelize.define('tbl_A', {
id: {
type: Sequelize.INTEGER.UNSIGNED,
field: 'a_id',
autoIncrement: true,
primaryKey: true,
}
});
const ModelBeta = sequelize.define('tbl_B', {
id: {
type: Sequelize.INTEGER.UNSIGNED,
field: 'b_id',
autoIncrement: true,
primaryKey: true,
},
attributeB: {
type: Sequelize.TINYINT.UNSIGNED,
field: 'b_attribute'
}
});
const ModelCharlie = sequelize.define('tbl_C', {
id: {
type: Sequelize.INTEGER.UNSIGNED,
field: 'c_id',
autoIncrement: true,
primaryKey: true,
},
attributeC: {
type: Sequelize.TINYINT.UNSIGNED,
field: 'c_attribute'
}
});
One ModelAlpha has one ModelBeta.
ModelAlpha has a foreign key column referencing the primary key of ModelBeta.
ModelAlpha can have many ModelCharlie
I am to trying to achieve the following
SELECT C.* FROM tbl_C
JOIN tbl_A ON tbl_A.a_id = C.fkey_a_id
JOIN tbl_B ON tbl_B.b_id = tbl_A.fkey_b_id
WHERE C.c_attribute = B.b_attribute
AND tbl_A.a_id = 123
So, in other words, all Charlies of the Alpha whose id is 123
and whose c_attribute is equal to b_attribute of the Beta
So far I have written something like the following,
but I am stuck as to what I am supposed to add to the where
clause.
ModelAlpha.belongsTo(ModelBeta, {foreignKey: 'fkey_b_id', as: 'beta'});
ModelAlpha.hasMany(ModelCharlie,{foreignKey: 'fkey_a_id', as : 'charlies'});
ModelAlpha.find({
where: {id: '123'},
include: [
{
model: ModelBeta,
as: 'beta',
attributes: [],
},
{
model: ModelCharlie,
as: 'charlies',
attributes:[],
where: {
attributeC: ......
}
}
],
limit: 1
}).then(result => {
//...
});
Has anyone come up with this situation before?
Thank you.