I have written a jenkins script where i want build no and previous build no.For that i am performing a subtraction operation.
i want to perform a subtraction between two variables in jenkins DSL script.
But i am not able to subtract.Ex i want to perform a=b-1 ....
the result what i am getting is always value of b.it does not perform subtraction.
It just assigns value of b to a.
Below is want i want :
build_num = "3"
pre_build_num = build_num-"1"
and result what i want should be pre_build_num = "2".
But i am getting pre_build_num = "3".
any help?
The problem is that your build_num variable is a string and the minus operator for strings removes a part of a string. It doesn't subtract numbers.
Some examples:
"three" - "th" = "ree"
"three" - "ree" = "th"`
To subtract your build_num variable you have to convert it to an integer first:
pre_build_num = (build_num as int) - 1
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I just started working on lua scripting since a week. I have a lua file where in the logic needs to be written for a certain condition.
The condition when gets triggered
it does an iteration on one of the fields to change value from
(ABC123-XYZ) to this value
(ABC123#1-XYZ) and it keeps increasing whenever iterations happens (ABC123#2-XYZ)
I need to run a function that removes the # followed by number to change it back to (ABC123-XYZ). Looking for any advice!
Edit 1:
Below is the updated code that is written Thanks to #Piglet
I have another scenario if therr are two hashes in the variable.
local x = 'BUS144611111-PNB_00#80901#1555-122TRNHUBUS'
local b = x:gsub("#%d+","")
function remove_char(a) a=a:gsub("#%d+","")
return a;
end if string.match(x,"#")
then print('function')
print(remove_char(x));
else print(x);
end
Expected output should be
x = 'BUS144611111-PNB_00#80901-122TRNHUBUS' for the aforesaid variable
local a = "ABC123#1-XYZ"
local b = a:gsub("#%d+", "")
this will remove any # followed by or one more digits from your string.
I am pretty new to this, so I hope you can give me a hand.
I am programming lights, and what I like to do is take a variable from my lighting desk (a text string called "4 Mythos Stage") and split is into different variables.
to get the variables from the desk I use:
return function ()
local Layer1 = gma.user.getvar("Layer1") -- I placed "4 Mythos Stage" variable in Layer1
gma.feedback(Layer1) -- gives feedback 4 Mythos Stage
end
Now I would like to split the string into 3 new local variables named:
local number -- should produce 4
local fixturetype -- should produce Mythos
local location -- should produce Stage
i tried the following:
local number = string.match('Layer1', '%d+')
local fixturetype = string.match('Layer1', '%a+')
local location = string.match('Layer1', '%a+')
this didn't work, so can somebody please help me in the right direction. I would be really greatful.
with kind regards,
Martijn
You can assign all three variables at the same time, because Lua has multiple returns and multiple assignment. Put parentheses around each of your patterns in order to return them as captures, and combine them into a single pattern with spaces between them:
local number, fixturetype, location = string.match(Layer1, '(%d+) (%a+) (%a+)')
In case you will be using multiple spaces or tabs between the items, this pattern would be better:
local number, fixturetype, location = string.match(Layer1, '(%d+)[ \t]+(%a+)[ \t]+(%a+)')
The reason why your attempt didn't work is because string.match('Layer1', '%d+') is searching inside 'Layer1' (a string) instead of Layer1 (a variable).
But even if you corrected that, you would get 'Mythos' every time you called string.match(Layer1, '%a+') (where Layer1 == '4 Mythos Stage'). string.match always starts from the beginning of the string, unless you supply an index in the third parameter: string.match(Layer1, '%a+', 9) --> 'Stage'.
A robust solution for this task is to split the string into three "words", a word being a sequence of non-whitespace characters:
local number, fixturetype, location = string.match(Layer1, '(%S+)%s+(%S+)%s+(%S+)')
I want to intersect multiple sets (2 or more). The number of sets to be intersected are passed as ARGV from command line. As number of sets are being passed from command-line. So the number of arguments in redis.call() function are uncertain.
How can I do so using redis.call() function in Lua script.
However, I have written a script which has algo like:
Accepting the number of sets to be intersected in the KEYS[1].
Intersecting the first two sets by using setIntersected = redis.call(ARGV[1], ARGV[2]).
Running a loop and using setIntersected = redis.call("sinter", tostring(setIntersected), set[i])
Then finally I should get the intersected set.
The code for the above algorithm is :
local noOfArgs = KEYS[1] -- storing the number of arguments that will get passed from cli
--[[
run a loop noOfArgs time and initialize table elements, since we don't know the number of sets to be intersected so we will use Table (arrays)
--]]
local setsTable = {}
for i = 1, noOfArgs, 1 do
setsTable[i] = tostring(ARGV[i])
end
-- now find intersection
local intersectedVal = redis.call("sinter", setsTable[1], setsTable[2]) -- finding first intersection because atleast we will have two sets
local new_updated_set = ""
for i = 3, noOfArgs, 1 do
new_updated_set = tostring(intersectedVal)
intersectedVal = redis.call("sinter", new_updated_set, setsTable[i])
end
return intersectedVal
This script works fine when I pass two sets using command-line.
EG:
redic-cli --eval scriptfile.lua 2 , points:Above20 points:Above30
output:-
1) "playerid:1"
2) "playerid:2"
3) "playerid:7"
Where points:Above20 and points:Above30 are sets. This time it doesn't go through the for loop which starts from i = 3.
But when I pass 3 sets then I always get the output as:
(empty list or set)
So there is some problem with the loop I have written to find intersection of sets.
Where am I going wrong? Is there any optimized way using which I can find the intersection of multiple sets directly?
What you're probably looking for is the elusive unpack() Lua command, which is equivalent to what is known as the "Splat" operator in other languages.
In your code, use the following:
local intersectedVal = redis.call("sinter", unpack(setsTable))
That said, SINTER is variadic and can accept multiple keys as arguments. Unless your script does something in addition to just intesects, you'd be better use that instead.
I have an SPSS variable containing lines like:
|2|3|4|5|6|7|8|10|11|12|13|14|15|16|18|20|21|22|23|24|25|26|27|28|29|
Every line starts with pipe, and ends with one. I need to refactor it into boolean variables as the following:
var var1 var2 var3 var4 var5
|2|4|5| 0 1 0 1 1
I have tried to do it with a loop like:
loop # = 1 to 72.
compute var# = SUBSTR(var,2#,1).
end loop.
exe.
My code won't work with 2 or more digits long numbers and also it won't place the values into their respective variables, so I've tried nest the char.substr(var,char.rindex(var,'|') + 1) into another loop with no luck because it still won't allow me to recognize the variable number.
How can I do it?
This looks like a nice job for the DO REPEAT command. However the type conversion is somewhat tricky:
DO REPEAT var#i=var1 TO var72
/i=1 TO 72.
COMPUTE var#i = CHAR.INDEX(var,CONCAT("|",LTRIM(STRING(i,F2.0)),"|"))>0).
END REPEAT.
Explanation: Let's go from the inside to the outside:
STRING(value,F2.0) converts the numeric values into a string of two digits (with a leading white space where the number consist of just one digit), e.g. 2 -> " 2".
LTRIM() removes the leading whitespaces, e.g. " 2" -> "2".
CONCAT() concatenates strings. In the above code it adds the "|" before and after the number, e.g. "2" -> "|2|"
CHAR.INDEX(stringvar,searchstring) returns the position at which the searchstring was found. It returns 0 if the searchstring wasn't found.
CHAR.INDEX(stringvar,searchstring)>0 returns a boolean value indicating if the searchstring was found or not.
It's easier to do the manipulations in Python than native SPSS syntax.
You can use SPSSINC TRANS extension for this purpose.
/* Example data*/.
data list free / TextStr (a99).
begin data.
"|2|3|4|5|6|7|8|10|11|12|13|14|15|16|18|20|21|22|23|24|25|26|27|28|29|"
end data.
/* defining function to achieve task */.
begin program.
def runTask(x):
numbers=map(int,filter(None,[i.strip() for i in x.lstrip('|').split("|")]))
answer=[1 if i in numbers else 0 for i in xrange(1,max(numbers)+1)]
return answer
end program.
/* Run job*/.
spssinc trans result = V1 to V30 type=0 /formula "runTask(TextStr)".
exe.
Suppose I have a factor variable with labels "a" "b" and "c" and want to see which observations have a label of "b". Stata refuses to parse
gen isb = myfactor == "b"
Sure, there is literally a "type mismatch", since my factor is encoded as an integer and so cannot be compared to the string "b". However, it wouldn't kill Stata to (i) perform the obvious parse or (ii) provide a translator function so I can write the comparison as label(myfactor) == "b". Using decode to (re)create a string variable defeats the purpose of encoding, which is to save space and make computations more efficient, right?
I hadn't really expected the comparison above to work, but I at least figured there would be a one- or two-line approach. Here is what I have found so far. There is a nice macro ("extended") function that maps the other way (from an integer to a label, seen below as local labi: label ...). Here's the solution using it:
// sample data
clear
input str5 mystr int mynum
a 5
b 5
b 6
c 4
end
encode mystr, gen(myfactor)
// first, how many groups are there?
by myfactor, sort: gen ng = _n == 1
replace ng = sum(ng)
scalar ng = ng[_N]
drop ng
// now, which code corresponds to "b"?
forvalues i = 1/`=ng'{
local labi: label myfactor `i'
if "b" == "`labi'" {
scalar bcode = `i'
break
}
}
di bcode
The second step is what irks me, but I'm sure there's a also faster, more idiomatic way of performing the first step. Can I grab the length of the label vector, for example?
An example:
clear all
set more off
sysuse auto
gen isdom = 1 if foreign == "Domestic":`:value label foreign'
list foreign isdom in 1/60
This creates a variable called isdom and it will equal 1 if foreigns's value label is equal to "Domestic". It uses an extended macro function.
From [U] 18.3.8 Macro expressions:
Also, typing
command that makes reference to `:extended macro function'
is equivalent to
local macroname : extended macro function
command that makes reference to `macroname'
This explains one of the two : in the offered syntax. The other can be explained by
... to specify value labels directly in an expression, rather than through
the underlying numeric value ... You specify the label in double quotes
(""), followed by a colon (:), followed by the name of the value
label.
The quote is from Stata tip 14: Using value labels in expressions, by Kenneth Higbee, The Stata Journal (2004). Freely available at http://www.stata-journal.com/sjpdf.html?articlenum=dm0009
Edit
On computing the number of distinct observations, another way is:
by myfactor, sort: gen ng = _n == 1
count if ng
scalar sc_ng = r(N)
display sc_ng
But yours is fine. In fact, it is documented here: http://www.stata.com/support/faqs/data-management/number-of-distinct-observations/, along with more methods and comments.