So I have a table using Lua and within it is a variable, but I can't figure out how to reach it because of its name. I was able to use json.prettify( _id ) in order to view whats in the table. All I want is the id within this table but because of how it's named I can't seem to get what's inside of _id, I tried both
_id[1] but that == nil
_id.$oid but that gave me a runtime error
printed response: _id = {
"$oid":"597015b757203b04d6941d45"
}
interesting note is that #_id == 0
Use
tableName[ 'variableName' ]
or
tableName.variableName
Note: Sometimes you can not use both form for example:
tableName[ 'name with spaces' ] -- ok
tableNames.name with spaces -- error
I think operator # can not be used with non-indexed tables.
You need decode json string to Lua table and get value in any way:
local json = require("json")
local str = [[ { "$oid":"597015b757203b04d6941d45" } ]]
local t_res= json.decode(str)
-- access
print( t_res["$oid"] )
-- or
local k,v = next(t_res)
print( v )
-- or
for k, v in pairs(t_res) do
print(v)
break
end
PS: Lua operator # only for a regular array, with non-nil values.
In order to overcome the fact that the name of the variable included the '$' symbol the correct way to get the variable within the table was to use:
_id['$oid'], this worked.
_id.$oid gave a runtime error.
Related
Alright I'll get straight to the point. I am currently working on a script for the RedM and I have run into a bit of trouble. I have a table I need to call but I need to be able to call it with a string and despite trying to figure this out for days I have had no luck. Here's a quick example of what I am trying to do.
Table = {
"Value 1",
"Value 2",
"Value 3"
}
local _Table = "Table"
for key, value in pairs(_Table) do
print(value)
end
What I am wanting that to do is print out everything in that table however when you try to use a string you get the following error
$lua main.lua
lua: main.lua:9: bad argument #1 to 'for iterator' (table expected, got string)
stack traceback:
[C]: in function 'next'
main.lua:9: in main chunk
[C]: in ?
And obviously the script works when you don't use a string however that won't work for me. To be totally honest I'm not even sure what I'm trying to do is even possible, but if it is and anyone has a solution it would be VERY appreciated lol.
If I understand correctly, you want to get a table by its variable name. This is only possible at all if the variable is global, which it shouldn't (Always make your variables local, children) and even then it wouldn't be the most elegant solution.
A better alternative might be: put your tables in another table:
local Tables = {
Table_1 = { 1, 2, 3, }
Table_2 = { 2, 3, 4, }
}
print(Tables["Table_1"])
This keeps the global scope clean and allows you to pass the whole set of tables around as a single value.
you cannot call a table unless its metatable implements __call. I assume you're confusing some basic terminology here.
your code doesn't make sense
-- this line assigns the string "Table" to _Table
local _Table = "Table"
-- now you put into pairs which may only take a table as input
for key, value in pairs(_Table) do
print(value)
end
If Table is a global variable as in your example you can access it through the global environment table _G.
for key, value in pairs(_G.Table) do print(value) end
or
local _Table = "Table"
for key, value in pairs(_G[_Table]) do print(value) end
I have a lua script with code block as below:
local call_data = cjson.decode(ARGV[1])
local other_data = cjson.decode(ARGV[2])
local data = {}
local next = next
local populate_data = function(source)
if next(source) == nil then
return
end
for property,value in pairs(source) do
redis.call('HSET', KEYS[2], property, value)
end
end
populate_data(call_data)
populate_data(other_data)
When I try to run the script with the following command KEYS and ARGV as:-
redis-cli --eval dialed.lua "inflight_stats:18" "calls:AC443d7a8111a96ba8074f54a71f0521ce:CA1ec49703eee1959471c71506f43bb42e:dialed" , "{\"from\":\"+18035224181\",\"to\":\"+919943413333\",\"sid\":\"CA1ec49703eee1959471c71506f43bb42e\",\"status\":\"queued\",\"direction\":\"outbound-api\",\"date_created\":null,\"account_sid\":\"AC443d8a8111a96ba8074f54a71f0521ce\"}" "{\"phone\":\"919943413333\",\"campaign_id\":18,\"caller_session_sid\":\"CA828b163153bf5cc301ef5285e38925f9\"}" 0
Error :-
(error) ERR Error running script (call to f_08dcc69ee8baa0200e0cf552948ab4bc338c9978): #user_script:11: #user_script: 11: Lua redis() command arguments must be strings or integers
TL;DR for values returned by cjson.decode(), use cjson.null to compare to JSON's null value.
Explanation: Lua uses nil in tables to mark deleted entries. If JSONinc nulls were converted to Lunatic nils, the decoded objects would be corrupt. Therefore, the cjson lib uses a lightweight userdata type to represent null/nil.
Your 'call_data' has a 'date_created' field that is null - that causes the error.
The funny thing is that Redis, like Lua, will not store a nil/null value, so you'll have to either ignore null values or use a special value in Redis to flag them.
Assuming you'll be ignoring them, here's one way around it:
local call_data = cjson.decode(ARGV[1])
local other_data = cjson.decode(ARGV[2])
local data = {}
local next = next
local null = cjson.null
local populate_data = function(source)
if next(source) == nil then
return
end
for property,value in pairs(source) do
if value ~= null then
redis.call('HSET', KEYS[2], property, value)
end
end
end
populate_data(call_data)
populate_data(other_data)
Also, a small optimization would be to batch the updates, like so:
local payload = {}
for property,value in pairs(source) do
if value ~= null then
table.insert(payload, property)
table.insert(payload, value)
end
end
redis.call('HSET', KEYS[2], unpack(payload))
P.S. if you want, look at ReJSON that I wrote - it is designed to help with what it appears that you're trying to do.
I'm using this (old) Lua module to save and access tables from local files (if there is a better way, please shout I'm not invested) -- https://github.com/gideros/table.save/blob/master/table.save-0.94.lua
It's been working great, but now I'm trying to save key value pairs I'm getting the error:
attempt to call global exportstring (a nil value)
I'm new to Lua. The error is on line 108 on that file I linked to. Any ideas?
I've tried creating blank tables, or basic tables without key value pairs, this works fine. It's when I come to insert strings the issues arise.
This will work:
local myTable = {}
myTable[0] = 2
inputOutputTable.save(myTable, "testytesty")
local testy = inputOutputTable.load("testytesty")
print("Testing 123... " .. testy[0])
However this wont:
local myTable = {}
myTable["welcome"] = "1"
I get : attempt to call global 'exportstring' (a nil value)
Expected results - it saves the table.
What happens - it throws the error.
When call a lua function like
PrintMe(MyVariableName)
I would like to be able to actually print "MyVariableName" and not it's value(well, for demo purposes).
Obviously I could just pass the string but that requires extra quotes and I also would like to print it's value.
e.g.,
MyVariable = 4
PrintVariable(MyVariable)
Would print "MyVariable is 4" or whatever
I do not want to have to duplicate the name and variable like
PrintVariable(MyVariable, "MyVariable")
as this is unnecessary duplication.
Can lua handle it?
What I'm doing now is passing the variable name in quotes and using loadstring to get the value but I would like to just pass the variable directly without the extra unnecessary quotes(which I thought debug.getlocal did but it ends up returning the value instead of the name).
Here is mock example
function printme1(var, val)
print(var.." = "..val)
end
function printme2(v)
local r
loadstring("r = "..v)() -- equivalent to r = a but must be used since v is a string representing a and not the object a
print(v.." = "..tostring(r))
end
function printme3(v)
-- unknown
end
a = 3
printme1("a", a)
printme2("a")
printme3(a)
In this case all 3 should print the same thing. printme3 obviously is the most convenient.
You can't say PrintVariable(MyVariable), because Lua gives you no way of determining which variable (if any; a constant could have been used) was used to pass an argument to your function. However, you can say PrintVariable('MyVariable') then used the debug API to look for a local variable in the caller's scope which has that name:
function PrintVariable(name)
-- default to showing the global with that name, if any
local value = _G[name]
-- see if we can find a local in the caller's scope with that name
for i=1,math.huge do
local localname, localvalue = debug.getlocal(2,i,1)
if not localname then
break -- no more locals to check
elseif localname == name then
value = localvalue
end
end
if value then
print(string.format("%s = %s", name, tostring(value)))
else
print(string.format("No variable named '%s' found.", name))
end
end
Now you can say:
PrintVariable('MyVariable')
While in this case will print "MyVariable = 4".
Not, if you really want to do this without the quotes, you could check the caller's locals for variables that have a supplied value, but that's occasionally going to give you the wrong variable name if there is more than one variable in the caller's scope with a given value. With that said, here's how you'd do that:
function PrintVariable(value)
local name
-- see if we can find a local in the caller's scope with the given value
for i=1,math.huge do
local localname, localvalue = debug.getlocal(2,i,1)
if not localname then
break
elseif localvalue == value then
name = localname
end
end
-- if we couldn't find a local, check globals
if not name then
for globalname, globalvalue in pairs(_G) do
if globalvalue == value then
name = globalname
end
end
end
if name then
print(string.format("%s = %s", name, tostring(value)))
else
print(string.format("No variable found for the value '%s'.", tostring(value)))
end
end
Now you can say PrintVariable(MyVariable), but if there happened to be another variable in the caller's scope with the value 4, and it occurred before MyVariable, it's that variable name that will be printed.
you can do stuff like this with the debug library... something like this does what you seem to be looking for:
function a_func(arg1, asdf)
-- if this function doesn't use an argument... it shows up as (*temporary) in
-- calls to debug.getlocal() because they aren't used...
if arg1 == "10" then end
if asdf == 99 then end
-- does stuff with arg1 and asdf?
end
-- just a function to dump variables in a user-readable format
function myUnpack(tbl)
if type(tbl) ~= "table" then
return ""
end
local ret = ""
for k,v in pairs(tbl) do
if tostring(v) ~= "" then
ret = ret.. tostring(k).. "=".. tostring(v).. ", "
end
end
return string.gsub(ret, ", $", "")
end
function hook()
-- passing 2 to to debug.getinfo means 'give me info on the function that spawned
-- this call to this function'. level 1 is the C function that called the hook.
local info = debug.getinfo(2)
if info ~= nil and info.what == "Lua" then
local i, variables = 1, {""}
-- now run through all the local variables at this level of the lua stack
while true do
local name, value = debug.getlocal(2, i)
if name == nil then
break
end
-- this just skips unused variables
if name ~= "(*temporary)" then
variables[tostring(name)] = value
end
i = i + 1
end
-- this is what dumps info about a function thats been called
print((info.name or "unknown").. "(".. myUnpack(variables).. ")")
end
end
-- tell the debug library to call lua function 'hook 'every time a function call
-- is made...
debug.sethook(hook, "c")
-- call a function to try it out...
a_func("some string", 2012)
this results in the output:
a_func(asdf=2012, arg1=some string)
you can do fancier stuff to pretty this up, but this basically covers how to do what you're asking.
I have bad news, my friend. You can access function parameter names as they appear at the top of the function, but the data to access exactly what they were named in the calling function does not exist. See the following:
function PrintVariable(VariableToPrint)
--we can use debug.getinfo() to determine the name 'VariableToPrint'
--we cannot determine the name 'MyVariable' without some really convoluted stuff (see comment by VBRonPaulFan on his own answer)
print(VariableToPrint);
end
MyVariable = 4
PrintVariable(MyVariable)
To illustrate this, imagine if we had done:
x = 4
MyVariable = x
MyOtherVariable = x
x = nil
PrintVariable(MyVariable)
Now if you were Lua, what name would you attach in the metadata to the variable that ends up getting passed to the function? Yes, you could walk up the stack with debug.getint() looking for the variable that was passed in, but you may find several references.
Also consider:
PrintVariable("StringLiteral")
What would you call that variable? It has a value but no name.
You could just use this form:
local parms = { "MyVariable" }
local function PrintVariable(vars)
print(parms[1]..": "..vars[1])
end
local MyVariable = "bar"
PrintVariable{MyVariable}
Which gives:
MyVariable: bar
It isn't generic, but it is simple. You avoid the debug library and loadstring by doing it this way. If your editor is any good, you could write a macro to do it.
Another possible solution is add this facility your self.
The Lua C API and source is pretty simple and extendable.
I/we don't know the context of your project/work but if you ARE making/embedding your own Lua build you could extend the debug library with something to do this.
Lua passes it's values by reference, but unknown offhand if these contain a string name in them and if so if easily accessible.
In your example the value declaration is the same as:
_G["MyVariable"] = 4
Since it's global. If it were declared local then like others stated here you can enumerate those via debug.getlocal(). But again in the C context of the actual reference context it might not matter.
Implement a debug.getargumentinfo(...) that extends the argument table with name key, value pairs.
This is quite an old topic and I apologize for bringing it back to life.
In my experience with lua, the closest I know to what the OP asked for is something like this:
PrintVariable = {}
setmetatable(PrintVariable, {__index = function (self, k, v) return string.format('%s = %s', k, _G[k]) end})
VAR = 0
VAR2 = "Hello World"
print(PrintVariable.VAR, PrintVariable.VAR2)
-- Result: VAR = 0 VAR2 = Hello World
I do not give more explanation, because the code is quite readable, however:
What happens here is simple, you only set a metatable to the PrintVariable variable and add the __index metamethod that is called when the table is forced to search for a value in its index, thanks to this functionality you can achieve what you see in the example.
Reference: https://www.lua.org/manual/5.1/manual.html
I hope that future and new visitors will find this helpful.
For example, I have a table
table.insert( t, 1, function()
print ("rock");
end );
Is there any way to get function name from this table. I know that I can store name like a key, but what if I want to keep numeric index and also I want to know function name?
Is there any way to do it?
Thanks, on advance.
Say you have this code:
t = {}
x = 5
table.insert(t, 1, x)
t would then be {[1] = 5}. "5" is just a number - it has no name, and isn't associated with the variable "x"; it's a value.
In Lua, functions are treated exactly the same way, as values:
t = {}
x = function() print("test! :D") end
table.insert(t, 1, x)
The value of x is not associated with x in any way, shape, or form. If you want to manually name a function, you can do it by wrapping the function in a table, for example:
t = {}
x = function() print("test! :D") end
table.insert(t, 1, {
name = "MyFunctionName",
func = x
})
That is how you would do it!
...unless..
..you break the rules!
When Lua was developed, the developers realised that the anonymous nature of functions would make productive error messages difficult to produce, if not impossible.
The best thing you'd see would be:
stdin: some error!
stdin: in function 'unknown'
stdin: in function 'unknown'
So, they made it so that when Lua code was parsed, it would record some debug information, to make life easier. To access this information from Lua itself, the debug library is provided.
Be very careful with functions in this library.
You should exert care when using this library. The functions provided here should be used exclusively for debugging and similar tasks, such as profiling. Please resist the temptation to use them as a usual programming tool: they can be very slow. Moreover, several of these functions violate some assumptions about Lua code (e.g., that variables local to a function cannot be accessed from outside or that userdata metatables cannot be changed by Lua code) and therefore can compromise otherwise secure code.
To achieve your desired effect, you must use the debug.getinfo function; an example:
x = function()
print("test!")
print(debug.getinfo(1, "n").name)
end
x() -- prints "test!" followed by "x"
Unfortunately, the form of debug.getinfo that operates directly on a function doesn't fill the name argument (debug.getinfo(x, "n").name == nil) and the version above requires you to run the function.
It seems hopeless!
...unless..
..you really break the rules.
The debug.sethook function allows you to interrupt running Lua code at certain events, and even change things while it's all happening. This, combined with coroutines, allows you to do some interestingly hacky stuff.
Here is an implementation of debug.getfuncname:
function debug.getfuncname(f)
--[[If name found, returns
name source line
If name not found, returns
nil source line
If error, returns
nil nil error
]]
if type(f) == "function" then
local info = debug.getinfo(f, "S")
if not info or not info.what then
return nil, nil, "Invalid function"
elseif info.what == "C" then
-- cannot be called on C functions, as they would execute!
return nil, nil, "C function"
end
--[[Deep magic, look away!]]
local co = coroutine.create(f)
local name, source, linedefined
debug.sethook(co, function(event, line)
local info = debug.getinfo(2, "Sn")
name = info.namewhat ~= "" and info.name or nil
source, linedefined = info.short_src, info.linedefined
coroutine.yield() -- prevent function from executing code
end, "c")
coroutine.resume(co)
return name, source, linedefined
end
return nil, nil, "Not a function"
end
Example usage:
function test()
print("If this prints, stuff went really wrong!")
end
print("Name = ", debug.getfuncname(test))
This function isn't very reliable - it works sometimes, and doesn't others. The debug library is very touchy, so it's to be expected.
Note that you should never use this for actual release code! Only for debugging!
The most extreme case that is still acceptable is logging errors on piece of released software, to help the developer fix issues. No vital code should depend on functions from the debug library.
Good luck!
The function hasn't got any name. If you want you can assign it to a named variable:
theFunction = t[1]
-- Call it:
theFunction()
If what you want is storing a named function to the table, define it beforehand and use its name to store it:
theFunction = function()
print ("rock");
end
table.insert(t, 1, theFunction)
If this is not what you meant, give more details; for example how you would like to access the function. You're question is a bit misty.
The thing is table.insert considers the table as a sequence, only with numeric keys.
If you want to be able to call the function as t.fun() you'll have to use the table as an associative array and hence use a string as key. (BTW any type except nil or NaN are allowed as key)
t={}
t['MyFun']=function print'foo' end
t.myFun() -- uses syntactic sugar for string keys that are valid identifiers.
You might also notice that functions are passed by reference. So all functions are actually anonymous, and are just stored as a value to a certain key or variable.
You can store the names in a separate table.
functions = {}
functionNames = {}
function addFunction(f, name)
table.insert(functions, f)
functionNames[name] = f
end
To get the function, you can use the index. Once you have the function, you can get its name from function_names:
f = functions[3]
name = functionNames[f]
Good luck!