iOS: call mobile phone screen with phone number like on Android - ios

Question

Is it possible to make same action like on Android, when we press Phone icon in application?
On Android we will see Phone Call screen with entered phone number.
On iOS it will call to a phone number immediately.
Example:
Android: Some app call button click -> Native Android Phone Call screen with pre-entered number -> Manual click call button
iOS: Same app call button click -> Immediately call action to phone number
I need to know, is it possible to add 2nd step into iOS like on Android.

Answer 1

yes it is possible by using openUrl as follows, i wrote in swift u can try same in objc
// swift
func makePhoneCall(_ phoneNumber: String?) {
if phoneNumber != nil && phoneNumber?.length ?? 0 > 0 {
let charSet: CharacterSet = CharacterSet(charactersIn: "0123456789-+()").inverted
let cleanedString: String? = (phoneNumber!.components(separatedBy: charSet) as NSArray).componentsJoined(by:"")
let escapedPhoneNumber: NSString? = cleanedString?.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed) as NSString?
let phoneURLString: String = String(format:"telprompt:%#", escapedPhoneNumber!)
let phoneURL: URL? = URL(string: phoneURLString)
if phoneURL != nil {
if UIApplication.shared.canOpenURL(phoneURL!) == true {
UIApplication.shared.openURL(phoneURL!)
} else {
// show alert or something
}
}
}
}
// objc
-(void) makePhoneCall:(NSString *)phoneNumber {
if(phoneNumber.length > 0) {
NSCharacterSet *charSet = [[NSCharacterSet characterSetWithCharactersInString:#"0123456789-+()"] invertedSet];
NSString *cleanedString = [[phoneNumber componentsSeparatedByCharactersInSet:charSet] componentsJoinedByString:#""];
NSString *escapedPhoneNumber = [cleanedString stringByAddingPercentEncodingWithAllowedCharacters: [NSCharacterSet URLQueryAllowedCharacterSet]];
NSString *phoneURLString = [NSString stringWithFormat:#"telprompt:%#", escapedPhoneNumber];
NSURL *url = [NSURL URLWithString:phoneURLString];
if([[UIApplication sharedApplication] canOpenURL:url]) {
[[UIApplication sharedApplication] openURL:url];
} else {
// show alert // or something
}
}
}