I'm using a custom circular animation in my VC to segue to a new VC and it works fine and this is the code
override func prepare(for segue: UIStoryboardSegue, sender: Any?)
{
let secondVC = segue.destination as! SecondViewController
secondVC.transitioningDelegate = self
secondVC.modalPresentationStyle = .custom
}
But when I use another button on the same VC to segue to some another VC, I get an error saying Could not cast value of type 'I_Need.ReminderTableViewController' (0x1020e6e98) to 'I_Need.SecondViewController (0x1020e6a08).
You need to do if let instead of let, because your other VC is not of type SecondViewController:
if let secondVC = segue.destination as? SecondViewController{
secondVC.transitioningDelegate = self
secondVC.modalPresentationStyle = .custom
}
Related
I want to pass photo data from one Viewcontroller(cameraVC) in a Tabbarcontroller to another Viewcontroller(mainVC) in the same Tabbarcontroller without losing the tabbar after I perform the segue.
Setup:
*Tabbarcontroller
-Navbarcontroller
--mainVC (Tabbar Item)
--cameraVC (Tabbar Item)
I must be able to use prepareForSegue and performSegue in cameraVC (This is how I am passing the data over to mainVC).
What I have tried W/O success:
Keeping tab bar on View after segue?,
Why TabBar hides after the segue?
current implementation:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
let destinationNavigationController = segue.destination as! UINavigationController
let targetController = destinationNavigationController.topViewController as! HomeVC
// if let homeVC = segue.destination as? HomeVC {
if let imageDict = sender as? Dictionary<String, Any> {
let imageData = imageDict["snapshotData"]
targetController.imageData = imageData as? Data
// }
}
}
#IBAction func sendBtnPressed(_ sender: Any) {
performSegue(withIdentifier: "goFeed", sender: ["snapshotData": photoData.removeValue(forKey: "photoData")])
imageTaken.image = nil
self.view.insertSubview(previewView, aboveSubview: imageView)
}
You are using the sender argument of the performSegue(_:, sender:) method incorrectly. It should be the view controller initiating the segue. It looks like your photoData property belongs to the view controller initiating the segue, so just access it directly in the prepareForSegue method. So it would look like this:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
let destinationNavigationController = segue.destination as! UINavigationController
let targetController = destinationNavigationController.topViewController as! HomeVC
if let imageData: Data = self.photoData["photoData"] as? Data {
targetController.imageData = imageData
}
}
#IBAction func sendBtnPressed(_ sender: Any) {
performSegue(withIdentifier: "goFeed", sender: self)
imageTaken.image = nil
self.view.insertSubview(previewView, aboveSubview: imageView)
}
The way I solved the problem was by creating a variable in my TabbarController which is globally recognized and used to pass the image data to the mainVC. This was the most viable solution for me to avoid creating duplicate views.
I have been following a firebase tutorial to create my own chat application, I am trying to access a chatviewcontroller from the uiviewcontroller containing a table view. The Viewcontroller is embedded in a navigation controller. How can I bring up the chatviewcontroller when a cell is selected?
Here is my code:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
super.prepare(for: segue, sender: sender)
//retrieve the destination view controller
let navVc = segue.destination as! UINavigationController
let channelVc = navVc.viewControllers.chatViewController as! ViewController
// set the senderDisplayName in Viewcontroller to the email provided in the email field by the user
channelVc.senderDisplayName = userEmailTextField?.text
}
Here is the error msg
Assuming your ChatViewController is the root view controller of your navigation controller you should change your code to this:
let channelVc = navVc.viewControllers.first as! ChatViewController
navVC.viewControllers is an array of the UIViewControllers managed by that UINavigationController, so that array would not have a property called chatViewController unless you implemented something custom.
EDIT: To put it all together, and also to demonstrate how to safely unwrap these optionals, your prepareForSegue should look like this:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
super.prepare(for: segue, sender: sender)
if let navVc = segue.destination as? UINavigationController, let channelVc = navVc.viewControllers.first as? ChatViewController {
//Now you have a reference to your ChatVC, and you can set the DisplayName
channelVc.senderDisplayName = userEmailTextField?.text
}
}
You have to get the first view controller from the UINavigationController:
let channelVc = navVc.viewControllers.first as! ChatViewController
I'm using a circular animation custom segue in my ViewController and it works fine but when I add a new button in by ViewController and link it to another ViewController through simple segue it gives me SIGABRT error. The line in which I get the error is :
"let secondVC = segue.destination as! SecondViewController"
of code
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
let secondVC = segue.destination as! SecondViewController
secondVC.transitioningDelegate = self
secondVC.modalPresentationStyle = .custom
}
I have this button in my first view controller, when you press it, it
triggers 2 action:
a function iterateItems
a segue which animates to ResultViewController
I need to set dataSource of ResultViewController to bestComposition in order to complete its view, and the value of this property can only be obtained after iterateItems is finished, I put this code in iterateItems:
print(bestComposition.count)
let resultVC = ResultViewController()
resultVC.dataSource = bestComposition
However, in the viewDidAppear method of ResultViewController, value of dataSource is not changed, here's the ResultViewController:
var dataSource = [WeaponItems]()
override func viewDidAppear(_ animated: Bool) {
print(dataSource.count)
...
}
The value of dataSource is 3 in ViewController, but is always 0 in ResultViewController, why doesn't it change?
Edit (Code for prepare for segue):
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
let secondVC = segue.destination as! ResultViewController
secondVC.transitioningDelegate = self
secondVC.modalPresentationStyle = .custom
}
resultVC is AN instance of ResultViewController, newly created by this line:
let resultVC = ResultViewController()
It's not THE instance that is created automatically as part of the segue. resultVC is never displayed, so it's viewDidAppear never runs, and so the print statement is never executed. Meanwhile, the instance created by the segue is presented, so it's viewDidAppear does run - but the value for its dataSource is unchanged. Try:
let resultVC = segue.destinationViewController as! ResultViewController
Try this:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
let secondVC = segue.destination as! ResultViewController
secondVC.transitioningDelegate = self
secondVC.modalPresentationStyle = .custom
secondVC.dataSource = bestComposition
}
I am developing an iOS application in Swift.
I want to send data from a view to an other one, using the prepareForSegue function.
However, my target view is preceded by a navigation controller, so it doesn't work. How can I set data on the VC contained within the navigation controller?
In prepareForSegue access the target navigation controller, and then its top:
let destinationNavigationController = segue.destination as! UINavigationController
let targetController = destinationNavigationController.topViewController
From the target controller you can access its view and pass data.
In old - now obsolete - versions of Swift and UIKit the code was slightly different:
let destinationNavigationController = segue.destinationViewController as UINavigationController
let targetController = destinationNavigationController.topViewController
Prepare the segue in the SendViewController
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "segueShowNavigation" {
if let destVC = segue.destination as? UINavigationController,
let targetController = destVC.topViewController as? ReceiveViewController {
targetController.data = "hello from ReceiveVC !"
}
}
}
Edit the identifier segue to "showNavigationController"
In your ReceiveViewController add
this
var data : String = ""
override func viewDidLoad() {
super.viewDidLoad()
print("data from ReceiveViewController is \(data)")
}
Of course you can send any other type of data (int, Bool, JSON ...)
Complete answer using optional binding and Swift 3 & 4:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if let navigationVC = segue.destination as? UINavigationController, let myViewController = navigationVC.topViewController as? MyViewControllerClass {
myViewController.yourProperty = myProperty
}
}
Here is the answer for Swift 3:
let svc = segue.destination as? UINavigationController
let controller: MyController = svc?.topViewController as! MyController
controller.myProperty = "Hi there"
A one liner in Swift 3:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if let vc = segue.destination.childViewControllers[0] as? FooController {
vc.variable = localvariable
}
}
In Swift 5
If you must not only segue from a SourceViewController to a DestinationViewController embedded in a UINavigationController, but also to a new Storyboard also, then do the following...
Place a "Storyboard Reference" object from your Object Library next to your source ViewController in Interface Builder, and then drag a segue to it (from a button on the SourceViewController view, for instance). Name the segue identifier "ToOtherStoryboard", for example.
Go to NavigationViewController and give it a Storyboard ID using the Identity Inspector. "DestinationNavVC" would do.
Click the Storyboard Reference icon you created in step 1, and in its attribute inspector's 'Referenced ID' field, enter the Storyboard ID you wrote for the UINavigationController in step 2. This creates the segue from source to the DestinationViewController no matter what you write in source file of the source ViewController. This is because seguing to a NaviationController will automatically show the root ViewController (the first one) of the UINavigationController.
(OPTIONAL) If you need to attach data along with your segue and send it to properties within the DestinationViewController, you would write the following code inside a Prepare-For-Segue method in your SourceViewController file:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "ToOtherStoryboard" {
let destinationNavVC = segue.destination as! UINavigationController
let destinationVC = destinationNavVC.topController as! DestinationViewController
destinationVC.name = nameTextField.text // for example
destinationVC.occupation = occupationTextField.text
}
}
You do not NEED to have a PrepareForSegue if you're simply trying to move from one ViewController to another, the methods above will work (w/o step 3)
In your IBAction Outlet method for your button you used to initiate the segue, you would write:
performSegue(withIdentifer: "ToOtherStoryboard", sender: self)
Set the identifier name in the segue arrow property in order to use in the the performeSegue.
Like this:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if let vc: ProfileViewController = segue.destination as? ProfileViewController {
//do any setting to the next screen
}
}
and then:
performSegue(withIdentifier: "yourIdentifierOfViewProfile", sender: indexPath.row)
I hope it helps.
It's a good idea to skip the check for UINavigationController as there may be multiple segues that use a navigationController and so will go into that check for every segue that uses a navigationController. A better way is to check the first viewController of the children and cast it as the viewController you are looking for.
if let destVC = segue.destination.children.first as? MyViewController {
destVC.hideBottomBar = true
}