Create a JSON String in Swift - ios

Question

I send the text from a TextView to my Backend. To include linebreaks, i try to serialize the textView.text to JSON.
let jsonObject: NSMutableDictionary = NSMutableDictionary()
jsonObject.setValue(textView.text, forKey: "text")
let jsonData: NSData
do {
jsonData = try JSONSerialization.data(withJSONObject: jsonObject, options: JSONSerialization.WritingOptions()) as NSData
let jsonString = NSString(data: jsonData as Data, encoding: String.Encoding.utf8.rawValue) as! String
print(jsonString)
} catch _ {
print ("JSON Failure")
}
}
But since this is a Dictionary, the resulting text looks like this:
{"text":"test\nstack\n\noverflow"}
i actually just need: test\nstack\n\noverflow
Is there a pretty way to transform a multiline String in swift to have these "\n" for linebreaks without any extra characters?
Edit:
I expect to type into my textView something like this:
and as a result get the string "hello\n\n"
The source looks like this:
let text = textView.text
let components = text?.components(separatedBy: CharacterSet.newlines).filter({!$0.isEmpty})
let textWithLineFeeds = components?.joined(separator:"\n")
print(textWithLineFeeds!)
print(textView.text)
the first print gives:
test
hello
linebreak above
the second print statement:
test
hello
linebreak above
i wish i could see:
test\nhello\n\nlinebreak above

Answer 1

To convert text with arbitrary new line characters (CR, LF, CRLF etc.) to distinct - only LF - line breaks use:
let text = "test\r\nstack\n\noverflow\rfoo"
let components = text.components(separatedBy: CharacterSet.newlines).filter({!$0.isEmpty})
let textWithLineFeeds = components.joined(separator:"\n")
If the server accepts only CR, change \n to \r.