How can I redirect to a particular view based on url in grails - grails

Question

I am using grails 2.5.5 version, Suppose I am entering url as www.localhost:8080/app-name then it should open the MyHome.gsp, suppose if I give other url ex: demo1.localhost.com:8080/app-name then it should redirect to some login page like login.jsp. How can I do that?

Answer 1

Let me break it up for you :
Suppose I have www.localhost:8080/app-name
suppose if I give other url ex: demo1.localhost.com:8080/app-name
Your app starts here:
Case 1 :/app-name
case 2 :/app-name
The rest of that url is actually DNS and configurating binding tomcat specific or wild card urls to a given application.
So in short you need to filter entire url in the application parse url and redirect in your app accordingly.
You need to then intercept every url with grails 2 there is SecurityFilters which so far as i know works with apache-shiro may also work with spring security.
and within it you need to overall check for something like
URL url = new URL(request.getRequestURL().toString())
String subdomain=url.host
if (subdomain.contains('.')) {
subdomain= subdomain.split('.')[0]
}
that then returns your `demo1` you then redirect it another url if it matches your specific rule.
But as I said you are talking about superficial stuff here as I expressed what the address is or how somone gets to the app has nothing to do with the actual application. This is why IT is big business. Big business not because everyone tries to narrow everything down into one box doing all of this but because when situations likes this happen bigger thinking is needed i.e. do i need a load balancer something like F5 that will split traffic according to a given url and send to another app container that asks for authorisation.
subdomain= subdomain.split('.')[1] in that case then but this leaves room for errors since user could put in demo1.somedomain.com and if that resolves well it is either split by subdomain= subdomain.split('.')[0]
I would do this then
String subdomain=url.host
if (subdomain.contains('.')) {
def splitter= subdomain.split('.')
subdomain= splitter[0]
if (subdomain=='www' && splitter.size()>1) {
subdomain= splitter[1]
}
}