I have send the value as "00:15" in database.But its in string.So I converted into time but i'm getting error while doing so.
I used
("00:15".to_time) / 1.hours
but its giving error as
"NoMethodError: undefined method `/' for 2017-02-16 00:15:00 +0530:Time"
So i need to convert minutes into hours and update it into database so i get value as 15mins = 0.25 hrs
According to Stefan's comment I would suggest the following method:
time = "02:15" #or whatever time you want
time.to_time.hour + time.to_time.min / 60.00 #results in 2.25
The hour methods returns the hour part of a given time object, the min methods returns only the minute part of a time object.
The right part of the addition in the second line converts the minute part into the decimal part of an hour.
You can't do division on a string, you need to convert it to an integer before doing the calculation. Dividing by a float automatically converts it to a float so you get the decimal places; if you divided by 60 you would get 0
("00:15".to_time.strftime('%M').to_i / 60.00)
Related
I am currently working on a plugin for grandMA2 lighting control using Lua. I need the current time. The only way to get the current time is the following function:
gma.show.getvar('TIME')
which always returns the current system time, which I then store in a variable. An example return value is "12h54m47.517s".
How can I separate the hours, minutes and seconds into 3 variables?
If os.date is available (and matches gma.show.getvar('TIME')), this is trivial:
If format starts with '!', then the date is formatted in Coordinated Universal Time. After this optional character, if format is the string "*t", then date returns a table with the following fields: year, month (1–12), day (1–31), hour (0–23), min (0–59), sec (0–61, due to leap seconds), wday (weekday, 1–7, Sunday is 1), yday (day of the year, 1–366), and isdst (daylight saving flag, a boolean). This last field may be absent if the information is not available.
local time = os.date('*t')
local hour, min, sec = time.hour, time.min, time.sec
This does not provide you with a sub-second precision though.
Otherwise, parsing the time string is a typical task for tostring and string.match:
local hour, min, sec = gma.show.getvar('TIME'):match('^(%d+)h(%d+)m(%d*%.?%d*)s$')
-- This is usually not needed as Lua will just coerce strings to numbers
-- as soon as you start doing arithmetic on them;
-- it still is good practice to convert the variables to the proper type though
-- (and starts being relevant when you compare them, use them as table keys or call strict functions that check their argument types on them)
hour, min, sec = tonumber(hour), tonumber(min), tonumber(sec)
Pattern explanation:
^ and $ pattern anchors: Match the full string (and not just part of it), making the match fail if the string does not have the right format.
(%d)+h: Capture hours: One or more digits followed by a literal h
(%d)+m: Capture minutes: One or more digits followed by a literal m
(%d*%.?%d*)s: Capture seconds: Zero or more digits followed by an optional dot followed by again zero or more digits, finally ending with a literal s. I do not know the specifics of the format and whether something like .1s, 1.s or 1s is occasionally emitted, but Lua's tonumber supports all of these so there should be no issue. Note that this is slightly overly permissive: It will also match . (just a dot) and an s without any leading digits. You might want (%d+%.?%d+)s instead to force digits appearing before & after the dot.
Lets do it with string method gsub()
local ts = gma.show.getvar('TIME')
local hours = ts:gsub('h.*', '')
local mins = ts:gsub('.*%f[^h]', ''):gsub('%f[m].*', '')
local secs = ts:gsub('.*%f[^m]', ''):gsub('%f[s].*', '')
To make a Timestring i suggest string method format()
-- secs as float
timestring = ('[%s:%s:%.3f]'):format(hours, mins, secs)
-- secs not as float
timestring = ('[%s:%s:%.f]'):format(hours, mins, secs)
I am trying to learn F# and was wondering if i have a json object which has time in microseconds as int. I want to get the day, date and time out of this and was wondering how to do it.
I actually happen to have needed to do this recently. You'll almost certainly want to use the .NET time objects (DateTime, DateTimeOffset, TimeSpan) in some capacity. Here's what I went with:
let TicksPerMicrosecond =
TimeSpan.TicksPerMillisecond / 1000L
let FromUnixTimeMicroseconds (us: int64) =
DateTimeOffset.FromUnixTimeMilliseconds 0L + TimeSpan.FromTicks(us * TicksPerMicrosecond)
From TimeSpan.TicksPerMillisecond we can calculate how many are in a microsecond (if I remember correctly it's 10, but this way it doesn't seem as "magic"). Then I can convert the microseconds value into ticks and add it to the epoch date.
To get the day of the week (assuming the time zone is UTC), you'd just use DateTimeOffset.DayOfWeek.
I’m using Rails 4.2.4. I have the below method for converting a time (duration) to milliseconds …
Time.parse(convert_to_hrs(duration)).seconds_since_midnight * 1000
in which the method “convert_to_hrs” is defined as
def convert_to_hrs(string)
case string.count(':')
when 0
'00:00:' + string.rjust(2, '0')
when 1
'00:' + string
else
string
end
end
However, if the duration is something really big (e.g. “34:13:00” -- read: 34 hours, 13 minutes, and zero seconds), the above fails with the error
Error during processing: argument out of range
/Users/mikea/.rvm/rubies/ruby-2.3.0/lib/ruby/2.3.0/time.rb:302:in `local'
/Users/mikea/.rvm/rubies/ruby-2.3.0/lib/ruby/2.3.0/time.rb:302:in `make_time'
/Users/mikea/.rvm/rubies/ruby-2.3.0/lib/ruby/2.3.0/time.rb:366:in `parse'
/Users/mikea/Documents/workspace/myproject/app/services/my_service.rb:25:in `block in process_page_data'
/Users/mikea/Documents/workspace/myproject/app/services/my_service.rb:22:in `each'
/Users/mikea/Documents/workspace/myproject/app/services/my_service.rb:22:in `process_page_data'
How do I rewrite my first line to accurately convert duration into milliseconds?
If you know you're always going to be using a hours:minutes:seconds format, but the number in each field isn't guaranteed to be inside the 'normal' range (e.g. 0-23 for hours, 0-59 for minutes, etc), then you're probably best off doing it 'manually' using something like this:
def duration_in_milliseconds(input)
h, m, s = input.split(':').map(&:to_i)
(h.hours + m.minutes + s.seconds) * 1000
end
puts duration_in_milliseconds('34:13:00') #=> 123180000
Note that this only works with ActiveSupport, but you have that, since you've specified Rails. Also, this assumes you're always getting all three terms (e.g. 5 seconds is 00:00:05). The full setup that accepts shorter strings as well would want to also use your convert_to_hrs method.
Note also that this works even if formatting isn't strictly 'time-like', as long as you have consistent colons as seperators:
puts duration_in_milliseconds('1:1:5') #=> 3665000
The Numeric#hours, Numeric#minutes and Numeric#seconds methods are provided by ActiveSupport, as part of active_support/core-ext/time.rb. They aren't particularly documented, but they return ActiveSupport::Duration objects, which have fancy methods for interacting with Time and Date issues like 5.days.ago, but when treated as an integer are effectively a number of seconds.
Time.parse is throwing error, becuase values you passing in duration variable is out of range.
For Ex:
Time.parse(convert_to_hrs('59:59')) as per your written code, it's return 2016-07-27 00:59:59 +0530
Here the value 59:59 consider as minutes:seconds, so if you pass the value 60:60 then it will raise the error argument out of range
Here is the official documentation for parse method of Time
Hope this will help you.
I have a string of the following format:
"136:16:11.862504"
(hours:minutes:seconds:milliseconds)
Whenever I try to use Ruby's strptime to parse this string, it throws an ArgumentError: invalid strptime format - '%H:%M:%S'
I've actually searched quite extensively and cannot figure out an elegant way to parse this (besides the rather clunky solution of splitting the string by its colons and periods, and doing it all manually). Is there a way of doing this that I'm overlooking?
EDIT: I'm not looking to get a timestamp out of this, I'm looking to get a time duration.
What is your expected output? '136' is not a valid hour, and since you don't have a date portion, we can't simply turn those 'extra' hours into days. If you don't care about the date portion, this solution may work for you:
time = "136:16:11.862504"
hours, minutes, seconds = time.split(":").map(&:to_f)
hours %= 24
minutes %= 60
seconds %= 60
Time.new(0, 1, 1, hours, minutes, seconds, 0)
=> 0000-01-01 16:16:11 +0000
In case if nothing blocks you from using Regexp, you could use something based on this answer, for example:
/^(\d+):([0-5][0-9]):([0-5][0-9])\.\d+$/ =~ "136:16:11.862504"
puts "#{$1} : #{$2} : #{$3}"
136 : 16 : 11
I'm working on a project that stores data on audio tracks and requires the use of timecodes for the start and end points of the track on the audio. I also need to calculate and display the duration of the track. Eg. a track starts at 0:01:30 and finishes at 0:04:12. So its duration is a total of 2 mins and 42 secs.
The trick is that everything needs to be displayed and handled as timecodes, so in the above example the duration needs to be displayed as 0:02:42.
So my question is how you would store the values? The easiest option would be to store the start and end times as Time in the database. Its very easy to calculate the duration and you can utilise the Rails time helpers in the forms. The only painful part is turning the duration back into a time value for display (since if I supply just the number of seconds to strptime it keeps using the current time to fill in the other fields)
The other option that I considered is storing them as numeric values (as the number of seconds). But then I have to write a lot of code to convert them to and from some type of timecode format and I can't use the Rails time helpers.
Is there another idea that I haven't considered? Is there an easy way to calculate and display the duration as a timecode format?
I would store them as seconds or milliseconds. I've been working on a music library manager/audio player in Ruby, and I actually had to write the two methods you would need. It's not that much code:
# Helper method to format a number of milliseconds as a string like
# "1:03:56.555". The only option is :include_milliseconds, true by default. If
# false, milliseconds won't be included in the formatted string.
def format_time(milliseconds, options = {})
ms = milliseconds % 1000
seconds = (milliseconds / 1000) % 60
minutes = (milliseconds / 60000) % 60
hours = milliseconds / 3600000
if ms.zero? || options[:include_milliseconds] == false
ms_string = ""
else
ms_string = ".%03d" % [ms]
end
if hours > 0
"%d:%02d:%02d%s" % [hours, minutes, seconds, ms_string]
else
"%d:%02d%s" % [minutes, seconds, ms_string]
end
end
# Helper method to parse a string like "1:03:56.555" and return the number of
# milliseconds that time length represents.
def parse_time(string)
parts = string.split(":").map(&:to_f)
parts = [0] + parts if parts.length == 2
hours, minutes, seconds = parts
seconds = hours * 3600 + minutes * 60 + seconds
milliseconds = seconds * 1000
milliseconds.to_i
end
It's written for milliseconds, and would be a lot simpler if it was changed to work with seconds.