Aspose.Words delete line(row) containing a Bookmark - aspose.words

I have a very basic helper method that sets Bookmark's text.
public static Bookmark SetBookmark(this Document doc, string bookmarkName, string value)
{
var bm = doc.Range.Bookmarks[bookmarkName];
if(bm == null)
throw new NullReferenceException(string.Format("Bookmark {0} Not Found!", bookmarkName));
bm.Text = value ?? string.Empty;
return bm;
}
What I need is to remove a bookmark and delete line of text that contains it when a certain condition is met, e.g. when value == null. Any suggestions?
Sample document looks like:
Hello
[Bookmark]
Goodbye
Resulted document after removal:
Hello
Goodbye

Please set the value of Bookmark.Text property to empty string to remove its content and use Bookmark.Remove method to remove the bookmark from the document. Bookmark.Remove method does not remove text inside the bookmark.
I work with Aspose as Developer evangelist.

Please set the value of Bookmark.Text property to empty string to remove its content as shown in following code example. I already shared this in my previous answer.
Document doc = new Document(MyDir + "Bookmark.doc");
// Use the indexer of the Bookmarks collection to obtain the desired bookmark.
Bookmark bookmark = doc.Range.Bookmarks["MyBookmark"];
// Remove the contents of bookmark.
bookmark.Text = "";
doc.Save(MyDir + #"Out.docx");
I work with Aspose as Developer evangelist.

Related

How to find requirements by keywords using DOORS DXL

I have identified 3-5 keywords for every requirement in module-A. Each keyword is separated by a comma. Now I want to search every requirement in module-B to see which of them have words that match each of the key words.
Not sure exactly what you're looking for. You might have to specify if none of these solutions I'm about to propose are exactly what you're looking for.
If you're trying to create a filter which displays only objects with those keywords in your current view, you can create an advanced filter by first going to filter (Tools > Filter > Define) and then select the Advanced button on the bottom left of the filter menu that appears.
At this point you can create custom rules for the filter. I would just create an individual rule for each word with the following definition:
Attribute: Object Text
Condition: contains
Value: <insert word here>
Match Case: uncheck
Regular Expression: uncheck
Then select the Add button to add the rule to the list of available rules in the Advanced Options.
At this point you can select multiple rules in the list of available rules and you can AND/OR these rules together to create a custom filter for the view that you want.
So that's for if you're trying to create a custom view with just objects containing specific words.
If you're talking about writing DXL code to automatically spit out requirements that have a particular word in it. You can use the something that looks like this:
Object o
String s
int offset, len
for o in entire (current Module) do
{
if (isDeleted(o)) continue
s = o."Object Text"""
if findPlainText(s, "<insert word here>", offset, len, false)
{
print identifier(o) // or replace this line with however you want to display object
}
}
Hope this is helpful. Cheers!
Edit:
To perform actions on a comma separated list, one at a time, you can use a while loop with some sort of search function that cuts off words one at a time.
void processWord (string someWord, Module mTarget, Object oSource)
{
Object oTarget
string objID = identifier(oSource)
for oTarget in mTarget do
{
if (<someWord in oTarget Object Text>) // edit function as necessary to do this
{
if (oTarget."Exists""" == "")
oTarget."Exists" = objID
else
oTarget."Exists" = oTarget."Exists" "," objID
}
}
}
int offset, len
string searchCriteria
Module mSource = read("<path of source module>", true)
Module mTarget = edit("<path of target module>", true)
Object oSource
for oSource in mSource do // can use "for object in entire(m)" for all objects
{
if (oSource != rqmt) continue // create conditions specific to your module here
searchCriteria = oSource."Search Criteria"""
while (findPlainText(searchCriteria, ",", offset, len, false))
{
processWord(searchCriteria[0:offset-1], mTarget, oSource)
searchCriteria = searchCriteria[offset+1:]
}
}
processWord(searchCriteria, mTarget, oSource) // for last value in comma separated list

How to extract the "href" attribute of <a> and paste it in a Google sheet?

I would like to extract an HTML anchor's ( < a href="" >Link here< /a > ) "href" attribute from the following page:
https://tvm.liga.nu/cgi-bin/WebObjects/nuLigaTENDE.woa/wa/teamPortrait?team=2368692&championship=K%C3%B6ln-Leverkusen+Winter+2019%2F2020&group=18
and put it in my google sheet.
I tried several xpath expressions for this page but it is everytime "N/A".
Still the simple xpath doesn't work, e.g.
importxml("https://tvm.liga.nu/cgi-bin/WebObjects/nuLigaTENDE.woa/wa/teamPortrait?team=2368692&championship=K%C3%B6ln-Leverkusen+Winter+2019%2F2020&group=18";"//tr")
What am I doing wrong?
Thanks Tanaike for all of your efforts.
I changed the script a little bit, because the result is based on pure html and needs to be changed so that the link could be clicked.
function getWebsite(url, searchText, baseURL)
{
var html = UrlFetchApp.fetch(url);
var text = html.getContentText();
var re = new RegExp('(?<=<a href=")(.*)(?=">.*' + searchText +')',"g");
var link = text.match(re)[0];
if (link !== null)
{
var link = text.match(re);
link = link.replace(/&/g,"&");
link = link.replace(/"/g,"\"");
return baseURL + link;
}
else { return "not found"; }
}
It depends which information you're looking for, but for example...
A1: https://tvm.liga.nu/cgi-bin/WebObjects/nuLigaTENDE.woa/wa/teamPortrait?team=2368692&championship=K%C3%B6ln-Leverkusen+Winter+2019%2F2020&group=18
A2: //table[2]/tbody/tr/td[6]/a/#href
A3: =IMPORTXML(A1,A2,1)
To find A2 - in Chrome - right-click a link of interest and "Inspect." Right-click on the href of interest to you, and "Copy full XPath."
Delete the part before the table reference, but leave TWO "/"s before the table reference. Then, delete the reference to the specific row following "tr", i.e., the "[x]". This way you'll select the entire column - in this case "[6]"
Fiddle as necessary.

DXL ignoring the error if an attribute doesn't exist in a module

I am writing some DXL for use as a DXL column that for each object in a module, looks at the in-links and returns the link name. Then if the link name starts with "verif", it will get the object text from an attribute "TestResultFloating" in the linked module and show it in the current module, in the DXL column.
The problem I will have when I use this on the whole database (currently I am just using a sandbox) is that some of the modules linked through the "verif" link module will not contain the "TestResultFloating" attribute. For these I would like to oppress the 'unknown Object attribute (TestResultFloating)' error and instead display something like N/A for that Object in the current module.
Below is my code that currently works as long as the "TestResultFloating" attribute is present in the linked module, but will throw the error if the attribute is not present.
ModName_ mSrc
Object o = current
Object nObject
Object oSrc, oDest
LinkRef lr = null
Link l = null
string linkname = ""
string attrbName = "TestResultFloating"
for mSrc in (obj <- "*") do {
if (!open(mSrc)) {
read(fullName(mSrc), true)
}
}
for l in (obj <- "*") do {
oSrc = source(l)
linkname = name(module(l))
string linkmodname = upper(linkname[0:4])
if(linkmodname == "VERIF") {
string objText = oSrc."TestResultFloating"
display(objText)
}
}
I tried one way of doing it which I got from the dxl reference manual which was to check whether the attribute exists and then do the operation. This is what I added but it doesn't seem to work, I still get the same error "unknown Object attribute (TestResultFloating)"
What I tried is shown below:
if(linkmodname == "VERIF") {
if(exists attribute "TestResultFloating"){
string objText = oSrc."TestResultFloating"
display(objText)
}
else {
display("N/A")
}
}
Please also note that i'm very new to DOORS and DXL so if I am doing something drastically wrong or I am asking a simple question please forgive me.
There is a utility function called string probeAttr_(Object o, string attrName) that can be used for getting an attribute value if you are not sure whether the attribute is readable or whether it even exists.
This function and a lot of similar functions tailored for different circumstances can be found in the file "c:\Program Files\IBM\Rational\DOORS\9.6\lib\dxl\utils\attrutil.inc"

XmlSlurper parsing a query result

I have a query that bring back a cell in my table the has all xml in it. I have it so I can spit out what is in the cell without any delimiters. Now i need to actually take each individual element and link them with my object. Is there any easy way to do this?
def sql
def dataSource
static transactional = true
def pullLogs(String username, String id) {
if(username != null && id != null) {
sql = new Sql(dataSource)
println "Data source is: " + dataSource.toString()
def schema = dataSource.properties.defaultSchema
sql.query('select USERID, AUDIT_DETAILS from DEV.AUDIT_LOG T WHERE XMLEXISTS(\'\$s/*/user[id=\"' + id + '\" or username=\"'+username+'\"]\' passing T.AUDIT_DETAILS as \"s\") ORDER BY AUDIT_EVENT', []) { ResultSet rs ->
while (rs.next()) {
def auditDetails = new XmlSlurper().parseText(rs.getString('AUDIT_EVENT_DETAILS'))
println auditDetails.toString
}
}
sql.close()
}
}
now this will give me that cell with those audit details in it. Bad thing is that is just puts all the information from the field in on giant string without the element tags. How would I go through and assign the values to a object. I have been trying to work with this example http://gallemore.blogspot.com/2008/04/groovy-xmlslurper.html with no luck since that works with a file.
I have to be missing something. I tried running another parseText(auditDetails) but haven't had any luck on that.
Any suggestions?
EDIT:
The xml int that field looks like
<user><username>scottsmith</username><timestamp>tues 5th 2009</timestamp></user>
^ simular to how it is except mine is ALOT longer. It comes out as "scottsmithtue 5th 2009" so on and so forth. I need to actually take those tags and link them to my object instead of just printing them in one conjoined string.
Just do
auditDetails.username
Or
auditDetails.timestamp
To access the properties you require

help with oauthService and linkedin

I am trying to iterate over a list of parameters, in a grails controller. when I have a list, longer than one element, like this:
[D4L2DYJlSw, 8OXQWKDDvX]
the following code works fine:
def recipientId = params.email
recipientId.each { test->
System.print(test + "\n")
}
The output being:
A4L2DYJlSw
8OXQWKDDvX
But, if the list only has one item, the output is not the only item, but each letter in the list. for example, if my params list is :
A4L2DYJlSwD
using the same code as above, the output becomes:
A
4
L
2
D
Y
J
l
S
w
can anyone tell me what's going on and what I am doing wrong?
thanks
jason
I run at the same problem a while ago! My solution for that it was
def gameId = params.gameId
def selectedGameList = gameId.class.isArray() ? Game.getAll(gameId as List) : Game.get(gameId);
because in my case I was getting 1 or more game Ids as parameters!
What you can do is the same:
def recipientId = params.email
if(recipientId.class.isArray()){
// smtg
}else{
// smtg
}
Because what is happening here is, as soon as you call '.each' groovy transform that object in a list! and 'String AS LIST' in groovy means char_array of that string!
My guess would be (from what I've seen with groovy elsewhere) is that it is trying to figure out what the type for recipientId should be since you haven't given it one (and it's thus dynamic).
In your first example, groovy decided what got passed to the .each{} closure was a List<String>. The second example, as there is only one String, groovy decides the type should be String and .each{} knows how to iterate over a String too - it just converts it to a char[].
You could simply make recipientId a List<String> I think in this case.
You can also try like this:
def recipientId = params.email instanceof List ? params.email : [params.email]
recipientId.each { test-> System.print(test + "\n") }
It will handle both the cases ..
Grails provides a built-in way to guarantee that a specific parameter is a list, even when only one was submitted. This is actually the preferred way to get a list of items when the number of items may be 0, 1, or more:
def recipientId = params.list("email")
recipientId.each { test->
System.print(test + "\n")
}
The params object will wrap a single item as a list, or return the list if there is more than one.

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