I am getting this from webservice
"rateavg": "2.6111"
now i am getting this in a string.
How to do this that if it is coming 2.6 it will show 3 and if it will come 2.4 or 2.5 it will show 2 ?
How to get this i am not getting. please help me
Try This
float f=2.6;
NSLog(#"%.f",f);
Hope this helps.
I come up with this, a replica of your query:
NSString* str = #"2.611";
double duble = [str floatValue];
NSInteger final = 0;
if (duble > 2.5) {
final = ceil(duble);
}else{
final = floor(duble);
}
NSLog(#"%ld",(long)final);
So it a case of using either ceil or floor methods.
Edit: Since you want it for all doubles:
NSString* str = #"4.6";
double duble = [str floatValue];
NSInteger final = 0;
NSInteger temp = floor(duble);
double remainder = duble - temp;
if (remainder > 0.5) {
final = ceil(duble);
}else{
final = floor(duble);
}
NSLog(#"%ld",(long)final);
check this
float floatVal = 2.6111;
long roundedVal = lroundf(floatVal);
NSLog(#"%ld",roundedVal);
plz use this
lblHours.text =[NSString stringWithFormat:#"%.02f", [yourstrvalue doubleValue]];
update
NSString *a =#"2.67899";
NSString *b =[NSString stringWithFormat:#"%.01f", [a doubleValue]];
// b will contane only one vlue after decimal
NSArray *array = [b componentsSeparatedByString:#"."];
int yourRating;
if ([[array lastObject] integerValue] > 5) {
yourRating = [[array firstObject] intValue]+1;
}
else
{
yourRating = [[array firstObject] intValue];
}
NSLog(#"%d",yourRating);
Try below code I have tested it and work for every digits,
NSString *str = #"2.7";
NSArray *arr = [str componentsSeparatedByString:#"."];
NSString *firstDigit = [arr objectAtIndex:0];
NSString *secondDigit = [arr objectAtIndex:1];
if (secondDigit.length > 1) {
secondDigit = [secondDigit substringFromIndex:1];
}
int secondDigitIntValue = [secondDigit intValue];
int firstDigitIntValue = [firstDigit intValue];
if (secondDigitIntValue > 5) {
firstDigitIntValue = firstDigitIntValue + 1;
}
NSLog(#"final result : %d",firstDigitIntValue);
Or another solution - little bit short
NSString *str1 = #"2.444";
float my = [str1 floatValue];
NSString *resultString = [NSString stringWithFormat:#"%.f",my]; // if want result in string
NSLog(#"%#",resultString);
int resultInInt = [resultString intValue]; //if want result in integer
To round value to the nearest integer use roundf() function of math.
import math.h first:
#import "math.h"
Example,
float ValueToRoundPositive;
ValueToRoundPositive = 8.4;
int RoundedValue = (int)roundf(ValueToRoundPositive); //Output: 8
NSLog(#"roundf(%f) = %d", ValueToRoundPositive, RoundedValue);
float ValueToRoundNegative;
ValueToRoundNegative = -6.49;
int RoundedValueNegative = (int)roundf(ValueToRoundNegative); //Output: -6
NSLog(#"roundf(%f) = %d", ValueToRoundNegative, RoundedValueNegative);
Read doc here for more information:
http://developer.apple.com/library/mac/#documentation/Darwin/Reference/ManPages/man3/roundf.3.html
NSString *value = #"1.23456";
float floatvalue = value.floatValue;
int rounded = roundf(floatvalue);
NSLog(#"%d",rounded);
if you what the round with greater value please use ceil(floatvalue)
if you what the round with lesser value please use floor(floatvalue)
You can round off decimal values by using NSNumberFormatter
There are some examples you can go through:
NSNumberFormatter *format = [[NSNumberFormatter alloc] init];
[format setPositiveFormat:#"0.##"];
NSLog(#"%#", [format stringFromNumber:[NSNumber numberWithFloat:25.342]]);
NSLog(#"%#", [format stringFromNumber:[NSNumber numberWithFloat:25.3]]);
NSLog(#"%#", [format stringFromNumber:[NSNumber numberWithFloat:25.0]]);
Corresponding results:
2010-08-22 15:04:10.614 a.out[6954:903] 25.34
2010-08-22 15:04:10.616 a.out[6954:903] 25.3
2010-08-22 15:04:10.617 a.out[6954:903] 25
NSString* str = #"2.61111111";
double value = [str doubleValue];
2.5 -> 3: int num = value+0.5;
2.6 -> 3: int num = value+0.4;
Set as your need:
double factor = 0.4
if (value < 0) value *= -1;
int num = value+factor;
NSLog(#"%d",num);
Related
I wish to display HH:MM at a UILabel when I adjust a custom slider. Currently my custom slider is returning me float values, for example, 2.89, 24.87... I wish to take the float value say 24.87 and change it to 24:52 I got everything working at the following code but I think it is not the most efficient way. Can anyone improve it? Thank you
- (void)slideValueChanged:(id)control
{
NSLog(#"Slider value changed: (%.2f,%.2f)",
_rangeSlider.lowerValue, _rangeSlider.upperValue);
lblStart.text = [NSString stringWithFormat:#"Start Time : %#", [self floatToTime:_rangeSlider.lowerValue]];
lblEnd.text = [NSString stringWithFormat:#"End Time : %#",[self floatToTime:_rangeSlider.upperValue]];
}
- (NSString*)floatToTime:(float)floatTime {
NSInteger iHour = floatTime;
CGFloat floatMin = floatTime - iHour;
NSString *sHour = [NSString stringWithFormat:#"%li", (long)iHour];
if (floatMin == 0.99) { //=== When the float is 0.99, convert it to 0, if not 60*0.99 = 59.4, will never get to 0
floatMin = 0;
}else{
floatMin = floatMin * 60;
}
NSInteger iMin = floatMin; //=== Take the integer part of floatMin
NSString *sMin = [[NSString alloc] init];
if (iMin <10){ //=== Take care if 0,1,2,3,4,5,6,7,8,9 to be 00,01,02,03...
sMin = [NSString stringWithFormat: #"0%li", iMin];
}else{
sMin = [NSString stringWithFormat: #"%li", iMin];
}
NSString *strFloatTime = [NSString stringWithFormat:#"%#:%#", sHour,sMin];
return strFloatTime;
}
You can use a format to show two digits, this simplifies creating a time string:
CGFloat time = 24.87;
int hours = fabs(time);
int minutes = (int)((time - hours) * 60.0);
NSLog(#"Time: %02d:%02d", hours, minutes);
Result: "Time: 24:52"
'02' is the number of digits.
I am receiving data in the form of a string from a database like so:
NSString *strTemp = #"000014";
I need to add 1 to the above,
like 000014 + 1 = 000015
000015 + 1 = 000016
depending on some count.
like:
for(int i =1; i < 5; i++)
{
int iTemp = [strTemp intValue] +i; // here i am getting 15 as int no not like 000015, 000016, 000017 ETC
}
I even tried NSString *strWarNo = [NSString stringWithFormat:#"%07d", iTemp]; but leading numbers may not be constant ...like string from db will be anything #"0023" or #"0000056".
I need to add one to while number, not only integer number.
How I can achieve this?
You can have a category over NSString to achieve this. I tried following code and its working fine.
.h of the category
#import <Foundation/Foundation.h>
#interface NSString (Arithematic)
- (NSString*)stringByAddingNumber:(NSInteger)number;
#end
.m of the category
#import "NSString+Arithematic.h"
#implementation NSString (Arithematic)
- (NSString*)stringByAddingNumber:(NSInteger)number
{
//To keep the width same as original string
int numberLength = (int)self.length;
NSInteger originalNumber = self.integerValue;
originalNumber += number;
NSString *resultString = [NSString stringWithFormat:#"%0*ld",numberLength,originalNumber];
return resultString;
}
#end
Usage:
NSString *strTemp = #"000014";
for(int i =1; i < 5; i++)
{
strTemp = [strTemp stringByAddingNumber:i];
}
NSLog(#"result %#",strTemp);
Hope this helps.
There is a simple way of doing this by converting string into NSInteger and then add your desired value into it and then convert the integer into string by appending you desired amount of zeros before then number.
-(NSString *)addNumber:(NSInteger)number toMyString:(NSString)myNum{
NSInteger numb = myString.integerValue;
numb += myNum;
NSString myNewString = [NSString stringWithFormat:#"0%d",myNewString];
return myNum;
}
If you want to format numbers with leading zeros then use NSNumberFormatter.
Store the number as a number (not a String) and then treat it like a number.
When you need to display it use an NSNumberFormatter to add leading zeros.
You can read more about NSNumberFormatter and adding leading zeros here... NSNumberFormatter leading 0's and decimals
Add which number you have to add in "num" and pass your number string "strNumber"
EX . [self addNumber:10 andYourString:#"000014"];
-(void)addNumber:(int)num andYourString:(NSString *)strNumber {
NSString * str_your_number = strNumber;
NSString * prevous_char = [NSString stringWithFormat:#"%c",
[str_your_number characterAtIndex:0]];
int number_zero = 0;
BOOL is_leading_zero = true;
for(int i = 0 ; i < str_your_number.length ; i++){
NSString *theCharacter = [NSString stringWithFormat:#"%c", [str_your_number characterAtIndex:i]];
if(is_leading_zero == true){
if([prevous_char isEqualToString:theCharacter]) {
number_zero++;
prevous_char = theCharacter;
}
else {
is_leading_zero = false;
}
}
NSLog(#"%#",theCharacter);
}
NSLog(#"%d",number_zero);
NSInteger you_numb = strNumber.integerValue;
you_numb += num;
NSString * str_zero = #"";
for(int j = 0 ; j < number_zero ; j++) {
str_zero = [str_zero stringByAppendingString:#"0"];
}
NSString * final_str = [NSString stringWithFormat:#"%#%ld",str_zero,(long)you_numb];
NSLog(#"%#",final_str);
}
it work...
I want the concatenated NSString I have to be output in the format "00:00", the 0s being the digits in the concatenated string. And if there are not enough characters in the NSString, the other digits are made to be 0.
And if there are more than 4 digits than I want to only have the furthest right digits.
I have done this in Java before, I am assuming it's possible in Objective-C as well.
UIButton *button = sender;
NSString *concatenated = [self.input stringByAppendingString: button.titleLabel.text];
self.input = concatenated;
self.userOutput.text = self.input;
For example, I might get "89" as my concatenated string. I then want, self.input = 00:89.
OR
if I get 89374374 from my concatenated string, I then want self.input = 43:74.
I hope I am being clear
The following method should give the desired output:
- (NSString *)getFormattedTimeStringFromString:(NSString *)string
{
int input = [string intValue];
int mins = input % 100;
input /= 100;
int hours = input % 100;
return [NSString stringWithFormat:#"%02d:%02d", hours, mins];
}
You can use this by calling
self.input = [self getFormattedTimeStringFromString:concatenated];
Like this:
NSDateFormatter * df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"HH:mm"];
NSString *dateTimeStr = [df stringFromDate:[NSDate date]];
if ([concatenated length] == 2) {
self.input = [NSString stringWithFormat:#"00:%#",concatenated];
}
else
{
NSString *test = [concatenated substringFromIndex:[concatenated length] -4];
self.input = [NSString stringWithFormat:#"%#:%#",[test substringToIndex:2],[test substringFromIndex:[test length]-2]];
}
Please try above code it will fail if [concatenated length] is 3 or 1 , modify it accordingly
This question already has answers here:
How do I convert an integer to the corresponding words in objective-c?
(7 answers)
Closed 8 years ago.
I am not sure how to explain this but I need something like this and I'm not quite sure how to do it. I have a textfield where the user enters a number. For example "200". I got a label that must show "Two Hundred"(The number entered in Words )
Any ideas on how to do this?
Thanks in advance sorry for my bad english
try this:
//textField.text is 200
NSInteger someInt = [textField.text integerValue];
NSString *numberWord;
NSNumber *numberValue = [NSNumber numberWithInt:someInt];
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterSpellOutStyle];
numberWord = [numberFormatter stringFromNumber:numberValue];
NSLog(#"numberWord= %#", numberWord); // Answer: two hundred
yourLabel.text = numberWord;
You can use a NSNumberFormatter It can convert an NSNumber into its word representation.
NSNumber* number = #100;
NSString* textNumber;
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterSpellOutStyle];
textNumber = [numberFormatter stringFromNumber:number];
Here's something totally different. A bit more complex and weird, but you can fiddle around with it if you seek more manual control over the output. This is set up to serve a value up to 100,000 (to demonstrate a conditional set up).
Have fun:
int theInteger = 1,123;
int convert1000 = 0;
int convert100 = 0;
int convert10 = 0;
int convert1 = 0;
NSString * wordThousand = #"Thousand";
NSString * wordHundred = #"Hundred";
NSArray *wordsArraySingleDigit = [[NSArray alloc] initWithObjects:#"Zero",#"One",#"Two",#"Three",#"Four",#"Five",#"Six",#"Seven",#"Eight",#"Nine",nil];
NSArray *wordsArrayDoubleDigit = [[NSArray alloc] initWithObjects:#"Ten",#"Eleven",#"Twelve",...,#"Ninety Eight", #"Ninety Nine",nil];
convert1000 = (theInteger - (theInteger % 1000))/1000;
convert100 = ((theInteger - (convert1000 * 1000)) - ((theInteger - (convert1000 * 1000)) % 100))/100;
convert10 = ((theInteger - (convert1000 *1000)-(convert100 *100)) - ((theInteger -(convert1000 *1000) - (convert100 *100)) % 10))/10;
convert1 = (theInteger - (convert1000 *1000)-(convert100 *100) - (convert10 *10));
if (theInteger > = 10000 && < 100000){
NSString * convertedThousand = [wordsArrayDoubleDigit objectAtIndex : convert1000];
convertedThousand = [NSString stringWithFormat: #“%# %#“,convertedThousand,wordThousand];
NSLog (convertedThousand);
}
if (theInteger >= 1000 && <= 10000){
NSString * convertedThousand = [wordsArraySingleDigit objectAtIndex : convert1000];
convertedThousand = [NSString stringWithFormat: #“%# %#“,convertedThousand,wordThousand];
NSLog (convertedThousand);
}
NSString * convertedHundred = [wordsArraySingleDigit objectAtIndex : convert100];
convertedHundred = [NSString stringWithFormat: #“%# %#“, convertedHundred,wordHundred];
NSLog (convertedHundred);
NSString * convertedTen = [wordsArraySingleDigit objectAtIndex : convert10];
convertedTen = [NSString stringWithFormat: #“%#“, convertedTen];
NSLog (convertedTen);
NSString *convertedOne = [wordsArraySingleDigit objectAtIndex : convert1];
NSLog (convertedOne);
Hope this helps or gives you a starting point for an alternative approach.
I think you should account for every possibility and make a set of IF statements, for example, if the first digit of the number is 3, write "three", if the number has 4 digits, display "thousands"... of course you can organize your code to make the process easy.
I made a simple calculator and Everytime I hit calculate it'll give a an answer but gives six unnecessary zeros, my question, how can I remove those zeros?
NSString *firstString = textfieldone.text;
NSString *secondString = textfieldtwo.text;
NSString *LEGAL = #"0123456789";
NSCharacterSet *characterSet = [[NSCharacterSet characterSetWithCharactersInString:LEGAL] invertedSet];
NSString *filteredOne = [[firstString componentsSeparatedByCharactersInSet:characterSet]
componentsJoinedByString:#""];
NSString *filteredTwo = [[secondString componentsSeparatedByCharactersInSet:characterSet]
componentsJoinedByString:#""];
firstString = filteredOne;
secondString = filteredTwo;
//Here we are creating three doubles
double num1;
double num2;
double output;
//Here we are assigning the values
num1 = [firstString doubleValue];
num2 = [secondString doubleValue];
output = num1 + num2;
label.text = [NSString stringWithFormat:#"%f",output];
Example:
15 + 15 = 30.000000
I want to add that none of that is necessary if you use the %g specifier.
If you're displaying this by using a string, check the following approaches.
NSString
NSString * display = [NSString stringWithFormat:#"%f", number];
//This approach will return 30.0000000
NSString * display = [NSString stringWithFormat:#"%.2f", number];
//While this approach will return 30.00
Note: You can specify the number of decimals you want to return by adding a point and a number before the 'f'
-Edited-
In your case use the following approach:
label.text = [NSString stringWithFormat:#"%.0f", output];
//This will display your result with 0 decimal places, thus giving you '30'
Please try this out. This should suit your requirements completely.
NSString * String1 = [NSString stringWithFormat:#"%f",output];
NSArray *arrayString = [String1 componentsSeperatedByString:#"."];
float decimalpart = 0.0f;
if([arrayString count]>1)
{
decimalpart = [[arrayString objectAtIndex:1] floatValue];
}
//This will check if the decimal part is 00 like in case of 30.0000, only in that case it would strip values after decimal point. So output will be 30
if(decimalpart == 0.0f)
{
label.text = [NSString stringWithFormat:#"%.0f", output];
}
else if(decimalpart > 0.0f) //This will check if the decimal part is 00 like in case of 30.123456, only in that case it would shows values upto 2 digits after decimal point. So output will be 30.12
{
label.text = [NSString stringWithFormat:#"%.02f",output];
}
Let me know if you need more help.
Hope this helps you.